Is it possible to combine and sort data in a foreach loop 2?

Hello

I have a rtf model in which I need to display the data in a table of the xml data file. I used 2 loops for each to show 2 portlets as xml data. Thus, there are 2 lines in the table with the first row with a foreach for portlet1 lines loop and second loop for each line retrieves lines from portlet2 to an xml file. Now I have to data table by date tro. Is it possible to combine and sort the data in those 2 loops for each?

Thank you

Hi Aditya,

Received your mail, responded with the required solution

don't use two separate loops, convert them to a single and sorting.

Let me know how it works ;)

It should work :)

Tags: Business Intelligence

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    I need help to find this little challenge.

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    Post edited by: user13040446

    It is the closest, I went to the solution


    I create two rows;

    Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\

    Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".

    Then I use the function analytic min

    Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone

    Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.

    If only I can make the distinction between these two that would solve my problem


    Query:


    Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2

    , min (eff_date) more than (partition by GroupName rnk2( ) min_eff

    Of

    (

    Select rowNum,

    GroupName , flag_a , flag_b , eff_date , term_date

    rank() more than (partition by GroupName stopped by eff_date desc) rnk1

    DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2

    de dsreports . tmp_group_test

    ) order by rowNum

    Hello

    user13040446 wrote:

    Hi KSI.

    Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.

    Please see the table wanted to see the final result I want to reach

    Thanks again

    This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:

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    (

    SELECT GroupName, flag_a, flag_b, eff_date, term_date

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    ORDER BY eff_date

    )

    -ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)

    ORDER BY eff_date

    ) AS output_group

    OF tmp_group_test

    )

    SELECT GroupName, flag_a, flag_b

    MIN (eff_date) AS eff_date

    MAX (term_date) AS term_date

    OF got_output_group

    GROUP BY GroupName, flag_a, flag_b

    output_group

    ORDER BY GroupName

    eff_date DESC

    ;

    The result I get is

    GROUP_NA F F EFF_DATE TERM_DAT

    -------- - - -------- --------

    Group_A Y 20110101 99991231 Y

    N Group_A 20101231 20060101 N

    Group_A N 20051231 20040101 Y

    Group_A Y Y 20031231-20030101

    Group_B N Y 99991231 20030101

    which is what you asked for.

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