Need help with Oracle SQL merge records according to date and term dates

Hi all

I need help to find this little challenge.

I have groups and flags and effective dashboards and dates of term against these indicators according to the following example:

GroupName Flag_A Flag_B Eff_date Term_date
Group_ATHERETHERE2011010199991231
Group_ANN2010010120101231
Group_ANN2009010120091231
Group_ANN2006010120081231
Group_ANTHERE2004010120051231
Group_ATHERETHERE2003010120031231
Group_BNTHERE2004010199991231
Group_BNTHERE2003010120031231

As you can see, group_A had the same combination of (N, N) flag for three successive periods. I want to merge all the time periods with the same indicators in one. Where entry into force will be the most early (underlined) time period and end date will be later (underlined)

So the final result should look like this:

GroupName Flag_A Flag_B Eff_date Term_date
Group_ATHERETHERE2011010199991231
Group_ANN2006010120101231
Group_ANTHERE2004010120051231
Group_ATHERETHERE2003010120031231
Group_BNTHERE2003010199991231

Thanks for your help

Here's the DDL script

drop table TMP_group_test;

create table TMP_group_test (groupname varchar2 (8))

, flag_a varchar2 (1)

, flag_b varchar2 (1)

, eff_date varchar2 (8)

, term_date varchar2 (8)

);

insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20110101 ', ' 99991231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20100101 ', ' 20101231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20090101 ', ' 20091231');

insert into TMP_group_test values ('Group_A', 'n', ' n ', ' 20060101 ', ' 20081231');

insert into TMP_group_test values ('Group_A', 'n', 'Y', ' 20040101 ', ' 20051231');

insert into TMP_group_test values ('Group_A', 'Y', 'Y', ' 20030101 ', ' 20031231');

insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20040101 ', ' 99991231');

insert into TMP_group_test values ('Group_B', 'n', 'Y', ' 20030101 ', ' 20031231');

commit;

Post edited by: user13040446

It is the closest, I went to the solution


I create two rows;

Rnk1: partition by group name, order of eff_date / / desc: this grade will sort the records of the most recent and handed to zero for each group\

Rnk2: (dense) partition by group name, flag_A, flagb: this grade for each combination of group\flag gives a number so that they are classified as "families".

Then I use the function analytic min

Min (eff_date) more (partition of GroupName, rnk2): the idea is that, for each Member of the same family, the new date is the min of the family (and the max for the date of the term), at the end I just need separate so that the duplicates are gone

Now the problem. As you can see from the query below, records of 1 and 6 (as identified by rownum) are identified in the same family, because they have the same combination of flag, but they are not successive, so everyone must keep its own date of entry into force.

If only I can make the distinction between these two that would solve my problem


Query:


Select rowNum,GroupName, flag_a, flag_b, eff_date, term_date, rnk1, rnk2

, min (eff_date) more than (partition by GroupName rnk2( ) min_eff

Of

(

Select rowNum,

GroupName , flag_a , flag_b , eff_date , term_date

rank() more than (partition by GroupName stopped by eff_date desc) rnk1

DENSE_RANK() more than (partition by GroupName order by flag_A flag_B ( ) rnk2

de dsreports . tmp_group_test

) order by rowNum

Hello

user13040446 wrote:

Hi KSI.

Thanks for your comments, you were able to distinguish between these lines highlight, but lost lines 2,3,4 which are supposed to have the same date min = 20060101.

Please see the table wanted to see the final result I want to reach

Thanks again

This first answer is basically correct, but in the main query, you want to use the function MIN, not the analytical function aggregation and GROUP BY columns with common values, like this:

WITH got_output_group AS

(

SELECT GroupName, flag_a, flag_b, eff_date, term_date

ROW_NUMBER () OVER (PARTITION BY GroupName

ORDER BY eff_date

)

-ROW_NUMBER () OVER (PARTITION BY GroupName, flag_a, flag_b)

ORDER BY eff_date

) AS output_group

OF tmp_group_test

)

SELECT GroupName, flag_a, flag_b

MIN (eff_date) AS eff_date

MAX (term_date) AS term_date

OF got_output_group

GROUP BY GroupName, flag_a, flag_b

output_group

ORDER BY GroupName

eff_date DESC

;

The result I get is

GROUP_NA F F EFF_DATE TERM_DAT

-------- - - -------- --------

Group_A Y 20110101 99991231 Y

N Group_A 20101231 20060101 N

Group_A N 20051231 20040101 Y

Group_A Y Y 20031231-20030101

Group_B N Y 99991231 20030101

which is what you asked for.

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    ---------------------------------------------------------------------------------------------------------------------------------
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    pp.startpp + 9
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    THEN
    pp.startpp + 10
    A SUPERIOR TIME (SUBSTR (s.Day12, 0, 4)) = "FRLO".
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    pp.startpp + 11
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    ----------------------------------------------------------------------------------------------
    OUTPUT CURRENT
    EMPID STARTDATE, STARTTIME ENDTIME HOURS MINUTES
    753738, 25/03/2013, 8, 0
    753740, 25/03/2013, 8, 0
    753748, 25/03/2013, 8, 0

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    753738, 25/03/2013, 8, 0
    753740, 25/03/2013, 8, 0
    753748, 25/03/2013, 8, 0
    753738, 26/03/2013, 8, 0
    753740, 26/03/2013, 8, 0
    753740, 28/03/2013, 8, 0
    753748, on 01/01/2013, 8, 0
    753738, on 03/04/2013, 8, 0
    753748, on 03/04/2013, 8, 0

    -----------------------------------------------------------------------------------------------
    CREATE THE TABLE PROGRAMS
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    PERIODID VARCHAR2 (6 BYTE) NOT NULL,
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    DAY4 VARCHAR2 (50 BYTE),
    DAY5 VARCHAR2 (50 BYTE),
    DAY6 VARCHAR2 (50 BYTE),
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    JOUR8 VARCHAR2 (50 BYTE),
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    DAY10 VARCHAR2 (50 BYTE),
    DAY 11 VARCHAR2 (50 BYTE).
    DAY12 VARCHAR2 (50 BYTE),
    J13 VARCHAR2 (50 BYTE),
    DAY14 VARCHAR2 (50 BYTE),
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    NOPTIND2 INTEGER DEFAULT 0,
    NOPTIND3 INTEGER DEFAULT 0,
    NOPTIND4 INTEGER DEFAULT 0,
    NOPTIND5 INTEGER DEFAULT 0,
    NOPTIND6 INTEGER DEFAULT 0,
    NOPTIND7 INTEGER DEFAULT 0,
    NOPTIND8 INTEGER DEFAULT 0,
    NOPTIND9 INTEGER DEFAULT 0,
    NOPTIND10 INTEGER DEFAULT 0,
    NOPTIND11 INTEGER DEFAULT 0,
    NOPTIND12 INTEGER DEFAULT 0,
    NOPTIND13 INTEGER DEFAULT 0,
    NOPTIND14 INTEGER DEFAULT 0
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    (
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    Insert in CALENDARS
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    NOPTIND3, NOPTIND4, NOPTIND5, NOPTIND6, NOPTIND7,
    NOPTIND8, NOPTIND9, NOPTIND10, NOPTIND11, NOPTIND12,
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    "1530', '1530', 'X', 0, 0,
    0, 0, 0, 0, 0,
    0, 0, 0, 0, 0,
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    Insert in CALENDARS
    (SCHEDULEID, EMPID, PERIODID, DAY1, AREAID
    DAY 2, DAY 3, DAY 4, DAY5 DAY6.
    DAY7 JOUR8, DAY9, DAY10, DAY 11,.
    J13, DAY14 DAY12, NOPTIND1, NOPTIND2,
    NOPTIND3, NOPTIND4, NOPTIND5, NOPTIND6, NOPTIND7,
    NOPTIND8, NOPTIND9, NOPTIND10, NOPTIND11, NOPTIND12,
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    "FRLO < 1530 > ', ' < 1530 FRLO > ', '1530', 'FRLO', '1530',
    'X', 'X', '1530', '1530', ' 1530',
    "1530', '1530', 'X', 0, 0,
    0, 0, 0, 0, 0,
    0, 0, 0, 0, 0,
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    DAY 2, DAY 3, DAY 4, DAY5 DAY6.
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    J13, DAY14 DAY12, NOPTIND1, NOPTIND2,
    NOPTIND3, NOPTIND4, NOPTIND5, NOPTIND6, NOPTIND7,
    NOPTIND8, NOPTIND9, NOPTIND10, NOPTIND11, NOPTIND12,
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    'X', 'X', ' FRLO < 1530 > ', '1530', 'FRLO ',.
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    0, 0, 0, 0, 0,
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    COMMIT;

    Insert into PAYPERIODS
    (PERIODID, STARTPP)
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    COMMIT;

    Hello

    I think you want:

    SELECT
      s.empid,
      pp.startpp,
      startdate,
      NULL starttime,
      NULL endtime,
      8 hours,
      0 minutes
    FROM schedules s
    JOIN payperiods pp
    ON pp.periodid = s.periodid
    WHERE UPPER (SUBSTR (s.Day1, 0, 4)) = 'FRLO'
    
    UNION
    SELECT
      s.empid,
      pp.startpp + 1,
      startdate,
      NULL starttime,
      NULL endtime,
      8 hours,
      0 minutes
    FROM schedules s
    JOIN payperiods pp
    ON pp.periodid = s.periodid
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    Kind regards

    Peter

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    A002          D4          3rd Jan 2009
    A002          D5          6rd Jan 2009
    
    A003          E6          6rd Jan 2009
    A003          E6          7rd Jan 2009
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    Concerning

    Learner

    Published by: learner1 on October 26, 2009 13:33

    Published by: learner1 on October 26, 2009 13:34

    Published by: learner1 on October 26, 2009 13:36

    Published by: learner1 on October 26, 2009 13:36 (added code tag)

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