Is there an easy way to view all the elements of the façade which are hidden in a pragmatic way?

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  Hi, experts, I am a newbie.
  
  are there any easy ways to get the number of months in a year in a date range?
  
  I would like to write a user-defined function.
  
  the input parameters are startdate, enddate, year
  
  the output is a number, not a month.
  
  for example, case 1
  
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  case 2:
  
  StartDate = 10032009 (DDMMYYYY)
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  If the year 2009, the output is 10
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  Thank you very much!

  Hello

  You can (also) try this:

  SQL> with s as (
    2  ------------ Sample data -------------
    3  select to_date('01032009','ddmmyyyy') startdt, to_date('28022010','ddmmyyyy') enddt, 2009 yr from dual
    4  union all
    5  select to_date('01032009','ddmmyyyy') startdt, to_date('28022010','ddmmyyyy') enddt, 2010 yr from dual
    6  union all
    7  select to_date('10032009','ddmmyyyy') startdt, to_date('15032010','ddmmyyyy') enddt, 2009 yr from dual
    8  union all
    9  select to_date('10032009','ddmmyyyy') startdt, to_date('15032010','ddmmyyyy') enddt, 2010 yr from dual
   10  ------------ Sample data -------------
   11  )
   12  select startdt, enddt, yr,
   13  months_between(
   14          least(trunc(to_date(yr+1,'yyyy'),'year') , add_months(trunc(enddt,'month'),1))
   15          , greatest(trunc(to_date(yr,'yyyy'),'year') , trunc(startdt,'month'))
   16  ) nbmonths
   17  from s;
  
  STARTDT    ENDDT              YR   NBMONTHS
  ---------- ---------- ---------- ----------
  01/03/2009 28/02/2010       2009         10
  01/03/2009 28/02/2010       2010          2
  10/03/2009 15/03/2010       2009         10
  10/03/2009 15/03/2010       2010          3
  

  It's pretty simple. (no connection with, without functions SQL only integrated multicast, etc...)

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  JES
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  I suggest you another go to Firefox 4.0 comfortable for you, and it would be
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• Is there an easy way to get a Date/time string seconds?

  I have 2 strings of the format depending on whether I would like to convert in seconds (since 1900). I need this value to set the t0 in a field.

  Date: ' 30/06/2014 '.

  "Time: '16:06 ' 08."

  Is there a CVI function that will do this conversion for me? If not, is there an easy way to do it?

  Thank you!

  This code should do what you want:

  
  
  
  static time_t  calt;
  
  struct Shared  tm tm;
  
  public static char    msg [64];
  
  public static int     AA, mm, DD, hh, mn ss;
  
  strcpy (msg, ' 2014/06/30 16:06:08 ');
  Extract the date/time string component
  
  Scan (msg, "%d [x] %d [x] %d [x] %d [x] [x] %d %d", & mm, dd, and yy, & hh, & mn, &ss);)
  Transfer to a struct tm components
  
  TM.tm_hour = hh;
  
  TM.tm_min  = mn;
  
  TM.tm_sec  = ss;
  
  TM.tm_year = yy - 1900;
  
  TM.tm_mon  = mm - 1;
  
  TM.tm_mday = dd;
  Obrtain calendar
  
  CALT = 0;
  
  CALT = mktime (&tm);)