Iteration through array of complex data on different properties object

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  Ivan.Chen wrote:

  As I found in the following article:

  http://digital.NI.com/public.nsf/WebSearch/FB001AA027C8998386256AAD006C142D?OpenDocument

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  A LVRefNum is really just a single int32 value. Its meaning is useless for other environments than those who created it so that you Michael not any what in C/C++ caller but pass it back to other functions in your DLL, but this often isn't a problem at all.

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  #define Private (T) typedef struct T # _t {void * p ;} * T}

  Private (LVRefNum);

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• Error renaming dates to an associative array of type date

  Hi all

  I am facing issue while assigning dates in an associative array of type date:

  Oracle version:

  SQL > select * from v version $;

  BANNER
  ----------------------------------------------------------------
  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
  PL/SQL Release 10.2.0.1.0 - Production
  CORE 10.2.0.1.0 Production
  AMT for Linux: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production

  Stored procedure, I try to write is as follows

  1. create or replace procedure (jp1)
  2. p_start_date default date trunc(sysdate,'MM')
  3. p_end_date date default trunc (sysdate)
  4. )
  5. is
  6. number of l_no_of_days;
  7. type t_date_id is table of date
  8. index by pls_integer;
  9. l_date_id_arr t_date_id;
  10. Start
  11. l_no_of_days: = p_end_date - p_start_date;
  12. for i from 0
  14. .. l_no_of_days - 1
  15. loop
  16. l_date_id_arr: = p_start_date + i;
  17. dbms_output.put_line (p_start_date + i);
  18. end loop;
  19. end;
  20. /

  I get error on line 14 when compiling it. and the error message is as follows:

  JP1 PROCEDURAL errors:

  LINE/COL ERROR
  -------- -----------------------------------------------------------------
  14/5 PL/SQL: statement ignored
  14/22 PLS-00382: expression is of the wrong type

  While studying this, I tried the value of (p_start_date + i) using dbms_output.put_line and the output is so date itself.

  1. create or replace procedure (jp1)
  2. p_start_date default date trunc(sysdate,'MM')
  3. p_end_date date default trunc (sysdate)
  4. )
  5. is
  6. number of l_no_of_days;
  7. type t_date_id is table of date
  8. index by pls_integer;
  9. l_date_id_arr t_date_id;
  10. Start
  11. l_no_of_days: = p_end_date - p_start_date;

  12. for i from 0... l_no_of_days-1

  13. loop
  14. -l_date_id_arr: = p_start_date + i;
  15. dbms_output.put_line (p_start_date + i);
  16. end loop;
  17. end;
  18. /

  output of the

  1. exec jp1

  is as follows:

  1ST DECEMBER 13

  2 DECEMBER 13

  3 DECEMBER 13

  DECEMBER 4, 13

  5 DECEMBER 13

  DECEMBER 6, 13

  7 DECEMBER 13

  DECEMBER 8, 13

  9 DECEMBER 13

  DECEMBER 10, 13

  DECEMBER 11, 13

  DECEMBER 12, 13

  13 DECEMBER 13

  14 DECEMBER 13

  15 DECEMBER 13

  16 DECEMBER 13

  17 DECEMBER 13

  18 DECEMBER 13

  I see the release date itself. so why he throws error while the same assignment to an associative array of type date.

  I tried Google too for the same but without success.

  Any help is appreciated in this regard not or any pointer another thread on the internet or in this forum.

  Thanks in advance

  Jagdeep Seven

  Read associative arrays:

  1. create or replace procedure (jp1)
  2. p_start_date default date trunc(sysdate,'MM')
  3. p_end_date date default trunc (sysdate)
  4. ) is
  5. number of l_no_of_days;
  6. type t_date_id is table of date
  7. index by pls_integer;
  8. l_date_id_arr t_date_id;
  9. Start
  10. l_no_of_days: = p_end_date - p_start_date;
  11. because me in 0.l_no_of_days - 1
  12. loop
  13. l_date_id_arr (I): = p_start_date + i;
  14. dbms_output.put_line (p_start_date + i);
  15. end loop;
  16. end;

  ----

  Ramin Hashimzade

• How to display rows of data in different columns?

  I'm new to SQL and currently, that's what I try to do:

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  I have a table like this:

  CREATE TABLE TRIPLEG)

  T # NUMBER (10) NOT NULL,

  STEP # NUMBER (2) NOT NULL,

  DEPARTURE VARCHAR (30) NOT NULL,

  VARCHAR (30) DESTINATION NOT NULL,.

  CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (T #, LEG #).

  TRIPLEG_UNIQUE UNIQUE CONSTRAINT (T #, DEPARTURE, DESTINATION).

  CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (T #) REFERENCES TRIP(T#));

  INSERT INTO TRIPLEG VALUES (1, 1, 'Sydney', 'Melbourne');

  INSERT INTO TRIPLEG VALUES (1, 2, 'Melbourne', 'Adélaïde');

  The result should be something like this:

  > T # | ORIGIN | DESTINATION1 |  DESTINATION2

  > 1 | SYDNEY | MELBORUNE | ADELAIDE

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  I replaced the syntax "where" with the syntax 'account '. The reason why I do this is because I want to only display records with a number of travel of less than 3. By defining where the legs #.<=3, the="" result="" will="" be="" all="" the="" records="" of="" the="" tripleg="" table="" since="" each="" record="" could="" also="" have="" leg#="" is="">

  The answer is:

  with t as (SELECT t #,)

  REGEXP_REPLACE)

  LISTAGG (start |) '->' || destination, ' ')

  THE Group (ORDER BY t #, leg #).

  '([^ ]+) \1+',

  "\1") str

  OF tripleg

  HAVING COUNT (T #)<>

  GROUP BY t #)

  Select T #, regexp_substr (str, ' [^->] +', 1, 1) departure

  , regexp_substr (str, ' [^->] +', 1, 2) destination_1

  , regexp_substr (str, ' [^->] +' 1, 3) destination_2

  , regexp_substr (str, ' [^->] +' 1, 4) destination_3

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• Working with complex data types in web services...

  Hi all
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  Concerning
  Lokesh

  Hi Lokesh,
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  Kind regards
  André