Join inner & outer join in a query

Similar Questions

• How to specify an outer join in the query designer

  I quickly built a large query with the query designer, and it works very well, but does not produce 9 disks on 2200 - so I need to change to an outer join.
  
  My problem is that I can't find a way to specify an outer join. I tried to change the query, query builder formed, but it won't let me.
  
  I know that I can capture the query, edit and run it in sql developer and that works fine, but I want to use the Query Builder as it is the fastest way I know to quickly add and remove items - my users don't know exactly what that it to include.
  
  I know it's kind of a trivial question, but I searched the forum, manual, the web and no luck
  
  Thanks for any help you can give
  
  Glenn

  Hi Glenn,.

  When you use the query designer to create the sql statement, you must click on the empty box to the right of the fields in each table to create the join. When you are finished, you should see a line drawn between the two tables. Click on this line, and a small window appears allowing you to select inner outer or right outer joins, left.

  When the report was created, however, you must change the statement. For example, if you use the query designer to join DEPT at EMP based on the DEPTNO field on the two tables, you get:

  select      "DEPT"."DEPTNO" as "DEPTNO",
        "DEPT"."DNAME" as "DNAME",
        "DEPT"."LOC" as "LOC",
        "EMP"."EMPNO" as "EMPNO",
        "EMP"."ENAME" as "ENAME",
        "EMP"."JOB" as "JOB",
        "EMP"."MGR" as "MGR",
        "EMP"."HIREDATE" as "HIREDATE"
   from      "EMP" "EMP",
        "DEPT" "DEPT"
   where   "DEPT"."DEPTNO"="EMP"."DEPTNO"
  

  This is to change:

  select      "DEPT"."DEPTNO" as "DEPTNO",
        "DEPT"."DNAME" as "DNAME",
        "DEPT"."LOC" as "LOC",
        "EMP"."EMPNO" as "EMPNO",
        "EMP"."ENAME" as "ENAME",
        "EMP"."JOB" as "JOB",
        "EMP"."MGR" as "MGR",
        "EMP"."HIREDATE" as "HIREDATE"
   from      "EMP" "EMP"
        LEFT OUTER JOIN "DEPT" "DEPT" ON "DEPT"."DEPTNO"="EMP"."DEPTNO"
  

  Andy

• LEFT OUTER JOIN, trigger after QUERY problem

  Hello
  
  Guide to please the following
  
  I wrote under query in QUERY after a BLOCK of TABULAR DATA, not as a single text element, called INVENTORY_ITEM
  
  Select c.cat |' '|| s.SubCat |' '|| L1.lvl1 POINT IN: DATABLOCK. INVENTORY_ITEM
  of itemcat c
  LEFT OUTER JOIN itemsubcat s on (c.catid = s.catid)
  LEFT OUTER JOIN lvl1 l1 on (s.subcatid = l1.subcatid)
  
  When I compile the module an error is generated
  
  «* ' Met the 'LEFT' symbol when waiting for one of the following values for the group with intersect less order start union where connect '.» *
  
  Top query works fine with ORACLE SQL DEVELOPER.
  
  Any solution please.
  
  Kind regards

  Difference

• Case Based Condition of inner join in SQL query

  Hi Experts,
  

  CREATE TABLE PRODUCT_PRICE(PRODUCT_ID INTEGER,PRICE FLOAT);
  INSERT INTO PRODUCT_PRICE VALUES(1,1);
  INSERT INTO PRODUCT_PRICE VALUES(2,2);
  INSERT INTO PRODUCT_PRICE VALUES(3,1);
  INSERT INTO PRODUCT_PRICE VALUES(4,1);
  INSERT INTO PRODUCT_PRICE VALUES(5,3);
  INSERT INTO PRODUCT_PRICE VALUES(0,4);

  CREATE TABLE PRODUCT_TABLE (PRODUCTID INTEGER,OTHERID INTEGER);
  INSERT INTO PRODUCT_TABLE VALUES (1,0);
  INSERT INTO PRODUCT_TABLE VALUES (2,0);
  INSERT INTO PRODUCT_TABLE VALUES (3,1);
  INSERT INTO PRODUCT_TABLE VALUES (4,1);
  INSERT INTO PRODUCT_TABLE VALUES (5,2);

  I need to match the product_id = 0 to get the price of the product when there is othersid in the product table (otherid > 0). For this I created the query below.
  

  SELECT 
      PRODUCT_ID,
      PRICE 
  FROM 
      PRODUCT_TABLE
      INNER JOIN PRODUCT_PRICE ON PRODUCT_ID=PRODUCTID
  WHERE
      OTHERID=0
  UNION ALL
  SELECT 
      PRODUCT_ID,
      PRICE 
  FROM 
      PRODUCT_TABLE
      INNER JOIN PRODUCT_PRICE ON PRODUCT_ID=0
  WHERE
      OTHERID>0;

  My Question is, is that any way the SQLQuery above can be simplified in CASES and INTERNAL CONDITION JOIN in a single SQL QUERY?
  
  I can work around something like that,
  

  SELECT 
      PRODUCT_ID,
      PRICE 
  FROM 
      PRODUCT_TABLE
      INNER JOIN PRODUCT_PRICE ON * CASE WHEN OTHERID>0 THEN PRODUCT_ID=0 ELSE PRODUCT_ID=PRODUCTID END*

  Thank you

  SELECT CASE WHEN PT.OTHERID = 0 THEN PT.PRODUCTID ELSE 0 END AS PRODUCT_ID, PP.PRICE
    FROM PRODUCT_TABLE PT,  PRODUCT_PRICE PP
      WHERE CASE WHEN PT.OTHERID =0 THEN PT.PRODUCTID ELSE 0 END = PP.PRODUCT_ID
  

  Should it?

• Join in a query

  Hello!
  
  I am neawby in SQL, and I have some problems with a request...
  
  I have a table called 'Artist' like this:
  

  ART_ID     ART_NAME         ART_DESCRIPTION
  1          Artist1          Desc1
  2          Artist2          Desc2
  3          Artist3          Desc3
  4          Artist4          Desc4

  And another table called 'Tour' like this:

  TOUR_ID   TOUR_DATE          TOUR_ART_ID
  1         10/10/2013         1
  2         14/07/2014         4

  And finally, I want to show something like this:
  

  ART_ID     ART_NAME         ART_DESCRIPTION         TOUR_DATE
  1          Artist1          Desc1                   10/10/2013
  2          Artist2          Desc2
  3          Artist3          Desc3
  4          Artist4          Desc4                   14/07/2014

  If no tour_date for this artist, I want to show the artist too.
  
  Thanks in advance!

  Try this:

  select art_id, art_name, art_description, tour_date
  from   artist
         left outer join tour on (art.art_id = tour.tour_art_id)
  

• join in the query

  Hello world
  
  My question today is 'can we join two queries.
  
  
  Select the name of database v$.
  
  Select bytes/1024/1024/1024, count (segment_name) in dba_segments where nom_segment = 'tablename ';
  
  
  could you guys please help me on with this one as well
  
  I actually want my output to be something like below
  
  Name byte count (segments_name)
  -------------------------------------------------------------------------
  1800 27 DB
  
  
  Concerning
  Shareef

  SELECT (select v$ v database name $) db,.
  Select bytes/1024/1024/1024, count (segment_name) in dba_segments where nom_segment = 'tablename ';

• join in the query with the result of a single line

  Hi all
  
  I have two tables

  create table item(item_id number primary key,
  item_desc varchar2(200));
  
  create table item_properties(item_id number references item(item_id),
  property_name varchar2(20),
  property_value varchar2(100));

  I insert the following records

  insert into items values(1,'CPU');
  insert into item_properties values(1,'RAM','2gb');
  insert into item_properties values(1,'PROCESSOR','2ghz');
  insert into item_properties values(1,'HARDDISK','2ghz');
  commit;

  now I want a query that produces the following results

  item_id      RAM      PROCESSOR         HARDDISK
  1              2gb        2ghz              2TB

  How to generate this result?
  I create a query, but it generates several lines, instead I need a single line like above.

  select i.item_id,p.property_value from items i , item_properties p
  where i.item_id=p.item_id and i.item_id=1;

  Kind thanks.
  
  Published by: Maahjoor on May 7, 2013 12:22 AM

  select i.item_id,
         max(decode(p.property_name,'RAM',p.property_value)) ram,
         max(decode(p.property_name,'PROCESSOR',p.property_value)) processor,
         max(decode(p.property_name,'HARDDISK',p.property_value)) hd
  from items i , item_properties p
  where i.item_id=p.item_id
  and i.item_id=1
  group by i.item_id;
  

  Or pivot to 11g

  with details as
  (
  select i.item_id,p.property_name,p.property_value
  from item i , item_properties p
  where i.item_id=p.item_id
  and i.item_id=1
  )
  select *
  from details
  pivot
   (
     max(property_value) for property_name in ('RAM','PROCESSOR','HARDISK')
   );
  

  Published by: JAC on May 7, 2013 13:04

• Kindly help for mentioning out with an SQL query, thanks

  Hello

  Please find below the input grid and help me get the result. Thanks in advance.  [Seeks assistance of query tunned]

  with the temp as

  (select alert_id 100, 111 double branch_code)

  Union of all the

  Select double 100 111

  Union of all the

  Select double 100 222

  Union of all the

  Select double 101 333

  Union of all the

  Select double 101 444

  Union of all the

  Select double 101 555

  Union of all the

  Select double 102 666

  Union of all the

  Select double 102 666

  Union of all the

  Select 102 666 double)

  Select * Temp;

  Entry
  Alert_ID	Branch_code
  100	111
  100	111
  100	222
  101	333
  101	444
  101	555
  102	666
  102	666
  102	666

  Output
  Alert_id	Branch_code
  100	111 222
  101	333,444,555
  102	666

  Thanks a ton

  Arpit

  Oracle 11 g 2, with analysis of the table only once. .. Here's how:

  WITH temp1

  AS (SELECT alert_id,

  branch_code,

  ROW_NUMBER)

  COURSES (PARTITION BY alert_id ORDER BY branch_code)

  DSB

  TEMP

  GROUP BY alert_id, branch_code)

  SELECT alert_id,

  LISTAGG (branch_code, ",") WITHIN GROUP (ORDER BY DSB) branch_code

  OF temp1

  GROUP BY alert_id;

  ALERT_ID BRANCH_CODE

  100 111 222

  101 333,444,555

  102 666

  See you soon,.

  Manik.

• How create/update files when the original Version is based on a query of outer join?

  Hi gurus,
  
  
  I created a custom page where I use a table-style area where I question my VO records, based on a query of outer join. This query contains my table looks, where I would like to insert/update records, and joined the table of standard elements, which is external with my custom table.
  
  When I now question my files in the t, I have a record for each record in the table section, which is ok, but when I 'Refresh' some fields of my custom table and attempt to commit, I get the message "unable to complete the transaction on record. Cause: The record has been deleted by another user. "Action: cancel the transaction and re - query records to get new data.
  The reason why because a record is to be inserted rather than updating because in fact there is not yet in my custom table.
  
  The reason why I'm using the outer join, is because I don't want the user to create a record for each item one by one.
  There is no work around for this?
  
  Thanks in advance!
  
  
  BR
  Guy

  Hello
  You can try this.

  In your EntityImpl.java to extend OAPlsqlEntityImpl.

  Override the updateRow() method and coding your insert statement to insert into a table custom here.
  Don't forget, you must ignore the lines for which your custom table columns are null

  -Idris

• Query of queries: error when you try to fake Left Outer Join

  Hello

  I'm trying to reproduce a left outer join, combining two query of queries using a method I find here

  However, I get an error message...

  Here is the code I use...

  < cfquery dbtype = "query" name = "qry" >
  SELECT *.
  OF returnQry, returnQry2
  WHERE returnQry.mediumImage = returnQry2.mediumImage
  ORDER BY returnQry.name
  < / cfquery >
  
  < name cfquery = "returnQry3", dbtype = "#application.mx #" >
  SELECT *.
  OF trackmeanings t
  < / cfquery >

  < cfquery dbtype = "query" name = "endQry" >
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE qry.name = returnQry3.sNameTrack
  
  UNION
  
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE #qry.name # NOT IN (#QuotedValueList (returnQry3.sNameTrack) #)
  GROUP BY name, nameRcd, mediumImage
  < / cfquery >

  When I try to use the query output in a page, I get the error message "incorrect conditional expression, waiting for an a [as |]» null | between | in | "comparison condition.

  Anyone have any ideas?

  Thank you very much

  The items in the list should be cited.  Since you are using quotedvaluelist, it's weird that they aren't.  However, if you use cfqueryparam, list = Yes, you should have better luck.  Among other things, it will protect you against the apostrophe in names.

• difference between Inner Join join natural r

  Experts,

  I'm trying to understand the difference between Natural Join and inner join.

  Inner join: the following query provides 106 lines based on two tables

  SQL > SELECT EMPLOYEE_ID EID, last NAME, DEPT_NAME DEPARTMENT_NAME

  2 EMPLOYEES A, B MINISTRIES

  3. WHERE A.DEPARTMENT_ID = B.DEPARTMENT_ID

  4 order employee_id;

  Natural Join: This is the combination or combined result of all the columns in both tables.

  When I run the Sub statement, it combines employees and the table from department of a HR schema and provides only 32 ranks

  SQL > select employe_id, first_name, department_name

  2 departments of NATURAL JOIN employees;

  
  

  EMPLOYEE_ID NAME DEPARTMENT_NAME

  ----------- -------------------- -------------------

  Neena 101 Executive

  Lex 102 Executive

  104 Bruce IT

  David 105 HE

  question: why the NATURAL JOIN query omit the employee_id 103 and on what basis it omit a few other employee_id

  Thanks in advance

  Hello

  The main difference is that INNER JOIN is used in real life; NATURAL JOIN is used only in textbooks.

  More rigorously, FRANCKLIN JOIN is an inner join, involving all the columns that have the same name.  The hr.departments and hr.employees have 2 columns with the same name: department_id and manager_id, so

  OF hr.departments d

  NATURAL JOIN e hr.employees

  is equivalent to

  OF hr.departments d

  INNER JOIN hr.employees e ON e.department_id = d.deparment_id

  AND e.manager_id = d.manager_id

  or, using the old join syntax

  OF hr.departments d

  e hr.employees

  WHERE e.department_id = d.deparment_id

  AND e.manager_id = d.manager_id

• Join query with union

  Hi all
  
  I have two requests and I want to join this two query
  
  The column of the report should be like this
  

  item_number WK_30  WE_31

  1st request
  

  select 
  re.item_number, 
  nvl(le.quantity,0) - nvl(re.quantity,0) WK_30
  from BACKLOG_WEEK_WH_AFTR_ATP le, BACKLOG_ATP_GT_CW_IN re
  where le.item_number =re.item_number
  and to_number(substr(re.year_week,-2,2)) = to_number(to_char(sysdate,'IW'))+1

  2nd request
  

  select 
  re.item_number, 
  nvl(le.quantity,0) - nvl(re.quantity,0) WK_31
  from BACKLOG_WEEK_WH_AFTR_ATP le, BACKLOG_ATP_GT_CW_IN re
  where le.item_number =re.item_number
  and to_number(substr(re.year_week,-2,2)) = to_number(to_char(sysdate,'IW'))+2

  Thanks in advance
  
  Concerning

  Hello

  You are welcome.

  I think that the best way to understand that is to show what data is generated at each stage...

  1. we need to generate a list of lines that have every week, we are interested in swing on...

  (   SELECT
          to_number(to_char(sysdate,'IW')) + ROWNUM year_week_num
      FROM
          DUAL
      CONNECT BY LEVEL <= 5
  ) row_gen
  
  YEAR_WEEK_NUM
  -------------
             30
             31
             32
             33
             34
  

  2. must be added BACKLOG_WEEK_WH_AFTR_ATP lines in the calculations for the first week in the report

  SELECT
      le.item_number,
      le.quantity,
      to_number(to_char(sysdate,'IW'))+1 year_week_num
  FROM
      BACKLOG_WEEK_WH_AFTR_ATP le
  UNION ALL
  SELECT
      re.item_number,
      -re.quantity,
      to_number(substr(re.year_week,-2,2)) year_week_num
  FROM
      BACKLOG_ATP_GT_CW_IN re
  /
  ITEM_NUMBE   QUANTITY YEAR_WEEK_NUM
  ---------- ---------- -------------
  ITEM_1            200            30
  ITEM_2            600            30
  ITEM_1           -200            30
  ITEM_1           -100            33
  ITEM_2           -300            30
  ITEM_2           -200            32
  ITEM_3           -800            30
  ITEM_3           -400            34
  

  3. we must now repeat weekly, generated by the request of row_gen against all of the item_numbers returned by the above query and match them if possible to get the amount. Where there is no entry in BACKLOG_WEEK_WH_AFTR_ATP or BACKLOG_ATP_GT_CW_IN for a number of the week, we should use 0 as the quantity. The Partition Outer Join does for us.

  SQL>         select
    2              re.item_number,
    3              row_gen.year_week_num,
    4              NVL(re.quantity,0) qty
    5          from
    6              (   SELECT
    7                      to_number(to_char(sysdate,'IW')) + ROWNUM year_week_num
    8                  FROM
    9                      DUAL
   10                  CONNECT BY LEVEL <= 5
   11              ) row_gen LEFT OUTER JOIN
   12                      (   SELECT
   13                              le.item_number,
   14                              le.quantity,
   15                              to_number(to_char(sysdate,'IW'))+1 year_week_num
   16                          FROM
   17                              BACKLOG_WEEK_WH_AFTR_ATP le
   18                          UNION ALL
   19                          SELECT
   20                              re.item_number,
   21                              -re.quantity,
   22                              to_number(substr(re.year_week,-2,2)) year_week_num
   23                          FROM
   24                              BACKLOG_ATP_GT_CW_IN re
   25                       ) re
   26                  PARTITION BY (re.item_number)
   27                  ON ( row_gen.year_week_num = re.year_week_num)
   28  /
  
  ITEM_NUMBE YEAR_WEEK_NUM        QTY
  ---------- ------------- ----------
  ITEM_1                30        200
  ITEM_1                30       -200
  ITEM_1                31          0
  ITEM_1                32          0
  ITEM_1                33       -100
  ITEM_1                34          0
  ITEM_2                30       -300
  ITEM_2                30        600
  ITEM_2                31          0
  ITEM_2                32       -200
  ITEM_2                33          0
  ITEM_2                34          0
  ITEM_3                30       -800
  ITEM_3                31          0
  ITEM_3                32          0
  ITEM_3                33          0
  ITEM_3                34       -400
  
  17 rows selected.
  

  4. now, we have the base dataset that we need - she has all the amounts with the right directions so that we can simply add everything up as a sum of sumulative. That's what makes OVER(PARTITION BY re.item_number ORDER BY row_gen.year_week_num) SUM (NVL(re.quantity,0)) bit. He said baseically are all lines seen so far in the result set for each item number...

          select
              re.item_number,
              row_gen.year_week_num,
              NVL(re.quantity,0) qty,
              SUM(NVL(re.quantity,0)) OVER(PARTITION BY re.item_number ORDER BY row_gen.year_week_num) quantity
          from
              (   SELECT
                      to_number(to_char(sysdate,'IW')) + ROWNUM year_week_num
                  FROM
                      DUAL
                  CONNECT BY LEVEL <= 5
              ) row_gen LEFT OUTER JOIN
                      (   SELECT
                              le.item_number,
                              le.quantity,
                              to_number(to_char(sysdate,'IW'))+1 year_week_num
                          FROM
                              BACKLOG_WEEK_WH_AFTR_ATP le
                          UNION ALL
                          SELECT
                              re.item_number,
                              -re.quantity,
                              to_number(substr(re.year_week,-2,2)) year_week_num
                          FROM
                              BACKLOG_ATP_GT_CW_IN re
                       ) re
                  PARTITION BY (re.item_number)
                  ON ( row_gen.year_week_num = re.year_week_num)
  /
  ITEM_NUMBE YEAR_WEEK_NUM        QTY   QUANTITY
  ---------- ------------- ---------- ----------
  ITEM_1                30        200          0
  ITEM_1                30       -200          0
  ITEM_1                31          0          0
  ITEM_1                32          0          0
  ITEM_1                33       -100       -100
  ITEM_1                34          0       -100
  ITEM_2                30       -300        300
  ITEM_2                30        600        300
  ITEM_2                31          0        300
  ITEM_2                32       -200        100
  ITEM_2                33          0        100
  ITEM_2                34          0        100
  ITEM_3                30       -800       -800
  ITEM_3                31          0       -800
  ITEM_3                32          0       -800
  ITEM_3                33          0       -800
  ITEM_3                34       -400      -1200
  

  5. we can now rotate these data in columns - however, there is a small problem. For points 1 and 2 we have 2 lines for the week 30, running in the quantity column total is the same for both because the two lines appear at the same point in the game as defined by the order by clause. This means before rotate us, we must select one of the lines - or the other will do, they are both correct. If we do not have, the effect will be to double the cumulative sum (for point 1 is 0, so it does not appear) for this, we can use the ROW_NUMBER function...

          select
              re.item_number,
              row_gen.year_week_num,
              NVL(re.quantity,0) qty,
              SUM(NVL(re.quantity,0)) OVER(PARTITION BY re.item_number ORDER BY row_gen.year_week_num) quantity,
              ROW_NUMBER() OVER(PARTITION BY re.item_number, row_gen.year_week_num ORDER BY NULL) rn
          from
              (   SELECT
                      to_number(to_char(sysdate,'IW')) + ROWNUM year_week_num
                  FROM
                      DUAL
                  CONNECT BY LEVEL <= 5
              ) row_gen LEFT OUTER JOIN
                      (   SELECT
                              le.item_number,
                              le.quantity,
                              to_number(to_char(sysdate,'IW'))+1 year_week_num
                          FROM
                              BACKLOG_WEEK_WH_AFTR_ATP le
                          UNION ALL
                          SELECT
                              re.item_number,
                              -re.quantity,
                              to_number(substr(re.year_week,-2,2)) year_week_num
                          FROM
                              BACKLOG_ATP_GT_CW_IN re
                       ) re
                  PARTITION BY (re.item_number)
                  ON ( row_gen.year_week_num = re.year_week_num)
  /
  ITEM_NUMBE YEAR_WEEK_NUM        QTY   QUANTITY         RN
  ---------- ------------- ---------- ---------- ----------
  ITEM_1                30        200          0          1
  ITEM_1                30       -200          0          2
  ITEM_1                31          0          0          1
  ITEM_1                32          0          0          1
  ITEM_1                33       -100       -100          1
  ITEM_1                34          0       -100          1
  ITEM_2                30       -300        300          1
  ITEM_2                30        600        300          2
  ITEM_2                31          0        300          1
  ITEM_2                32       -200        100          1
  ITEM_2                33          0        100          1
  ITEM_2                34          0        100          1
  ITEM_3                30       -800       -800          1
  ITEM_3                31          0       -800          1
  ITEM_3                32          0       -800          1
  ITEM_3                33          0       -800          1
  ITEM_3                34       -400      -1200          1
  

  6. so now that we have a way to select one of the duplicate lines, we can move forward a pivot data by ensuring that us choose only 'first' line for each element for each week...

  SELECT
      item_number,
      SUM
      (   CASE
              WHEN year_week_num = to_number(to_char(sysdate,'IW'))+1 THEN
                  quantity
          END
      ) plus_1,
      SUM
      (   CASE
              WHEN year_week_num = to_number(to_char(sysdate,'IW'))+2 THEN
                  quantity
          END
      ) plus_2,
      SUM
      (   CASE
              WHEN year_week_num = to_number(to_char(sysdate,'IW'))+3 THEN
                  quantity
          END
      ) plus_3,
      SUM
      (   CASE
              WHEN year_week_num = to_number(to_char(sysdate,'IW'))+4 THEN
                  quantity
          END
      ) plus_4,
      SUM
      (   CASE
              WHEN year_week_num = to_number(to_char(sysdate,'IW'))+5 THEN
                  quantity
          END
      ) plus_5
  FROM
      (   select
              re.item_number,
              row_gen.year_week_num,
              SUM(NVL(re.quantity,0)) OVER(PARTITION BY re.item_number ORDER BY row_gen.year_week_num) quantity,
              ROW_NUMBER() OVER(PARTITION BY re.item_number, row_gen.year_week_num ORDER BY NULL) rn
          from
              (   SELECT
                      to_number(to_char(sysdate,'IW')) + ROWNUM year_week_num
                  FROM
                      DUAL
                  CONNECT BY LEVEL <= 5
              ) row_gen LEFT OUTER JOIN
                      (   SELECT
                              le.item_number,
                              le.quantity,
                              to_number(to_char(sysdate,'IW'))+1 year_week_num
                          FROM
                              BACKLOG_WEEK_WH_AFTR_ATP le
                          UNION ALL
                          SELECT
                              re.item_number,
                              -re.quantity,
                              to_number(substr(re.year_week,-2,2)) year_week_num
                          FROM
                              BACKLOG_ATP_GT_CW_IN re
                       ) re
                  PARTITION BY (re.item_number)
                  ON ( row_gen.year_week_num = re.year_week_num)
      )
  WHERE
      rn = 1
  GROUP BY
      item_number
  

  You need not add a join between BACKLOG_WEEK_WH_AFTR_ATP and BACKLOG_ATP_GT_CW_IN, because we are all summed up in the article number and all item numbers, we have selected two tables. The aggregation ensures that the quantities are added together against the item number.

  HTH

  David

• query using the JOIN

  Hello
  
  
  my appearance of the table structure:
  
  Column names:
  
  Road
  BU
  sub_bu
  report_order
  sub_bu_order
  q1py
  
  My query is:
  
  Select road, bu, Sub_bu, report_order, sub_bu_order, q1py, case
  When sub_bu = 'ISS' then (select q1py from STG where 'a.sub_bu =' ESS and a.rhead = b.rhead)
  When sub_bu = "TS" then (select q1py from STG where 'a.sub_bu =' Services and a.rhead = b.rhead)
  When sub_bu = "SW" then (select q1py from STG where a.sub_bu = 'SW' and a.rhead = b.rhead)
  otherwise NULL end as q1py_bu,
  case
  When sub_bu = 'ISS' then (select q1py from STG where a.sub_bu = 'TSG' and a.rhead = b.rhead)
  When sub_bu as 'R & D' and road in ('Region owned opex', '% of income', "opex Région", "Région opex %") then
  (select q1py from STG where a.sub_bu like 'STG' and a.rhead = b.rhead)
  ANY other purpose like STG q1py_tot b where report_order = 1
  
  Result:
  
  Bu road report_order sub_bu_order q1py q1py_bu q1py_tot sub_bu
  order ESS ISS 1162 1 1 1778,4 2953.9
  
  Here I use the sub query to produce the result. I need to give the same result by using JOINS.
  
  If someone help me, by using JOINS instead of QUERY SUB and produce the same result
  
  
  
  Thanks in advance

  Maybe you can use SQL as below. (B-)

  select Rhead,bu,Sub_bu,report_order,sub_bu_order,q1py,
  case
  when sub_bu='ISS'
  then max(case when sub_bu='ESS' then q1py end)
  over(partition by rhead)
  when sub_bu='TS'
  then max(case when sub_bu='Services' then q1py end)
  over(partition by rhead)
  when sub_bu='SW'
  then max(case when sub_bu='SW' then q1py end)
  over(partition by rhead)
  end as q1py_bu
  from tsg
   where report_order=1;
  

• Select the list, joins

  HY!

  I have a list of selection with a query like this:

  select A._NAME as display_value,A._ID as return_value
    from A;
  

  Works fine of course.

  But I want to make this more dynamic list.

  I need to perform a join with another table, but it does not accept my request.

  It is not possible:

  select A._NAME as display_value, A._ID as return_value, A.AnotherIDWichINeedForAJoin
    from A;
  

  I get this error:

  Impossible to analyze the query SQL LOV!

  ORA-00904: "A". "" AnotherIDWichINeedForAJoin ": invalid identifier

  Is it not possible to make a join in a query select list?

  Is there another way to make a selection list that can manage the entry of a session (for example with a join) variable?

  Thanks for the help,

  ILB.

  It is possible to do a join, Yes, but in a query select list, you can have two values, a display and a return value, you have three, which will give an error. Always write and test your query in SQL or SQL Workshop first developer and make sure it works it before using it in the APEX, so you are sure that your request is correct.

• Join ANSI join VS. Oracle (old join)

  Hello
  I have a request on the old version of join for oracle
  its not take more then 30 dry running, I tried to change to an ANSI join query
  but then he tooks 400 seconds, I would like to know how Oracle is to solve the two querys?
  Im running the application on a different server where the tables.
  
  These are the querys
  
  
  Qry 1 - old join
  Select cp.account_no,
  CPC.id_value Subscr_no,
  cce.Component_id,
  CCE.active_dt,
  CP. Package_instance_id_serv
  Of Cmf_Packages@arborp01 cp,.
  Cmf_Package_Components@arborp01 code of criminal procedure
  cmf_component_elements@arborp01 EAC,
  customer_contracts@arborp01 cc
  Where cp. Package_instance_id = cpc. Package_instance_id
  And cp. Package_instance_id_serv = cpc. Package_instance_id_serv
  And cpc.component_instance_id = cce.component_instance_id
  And cpc.component_instance_id_serv = cce.component_instance_id_serv
  And cce.association_id = cc.tracking_id
  And cpc.Component_id in (60584,90474,90475)
  And the EAC. Package_status = 1
  And the EAC. Inactive_dt is null
  And cce.association_type = 2
  
  Qry2 - join ANSI
  Select
  CP.account_no,
  CPC.id_value Subscr_no,
  cce.Component_id,
  CCE.active_dt,
  CP. Package_instance_id_serv
  Of Cmf_Packages@arborp01 cp
  Join Cmf_Package_Components@arborp01 cpc
  on (cp. Package_instance_id = cpc. Package_instance_id
  And cp. Package_instance_id_serv = cpc. Package_instance_id_serv)
  Join cmf_component_elements@arborp01 EAC
  on (cpc.component_instance_id = cce.component_instance_id
  And cpc.component_instance_id_serv = cce.component_instance_id_serv)
  Join Customer_contracts@arborp01 cc on cce.association_id = cc.tracking_id
  Where cpc.Component_id in (60584,90474,90475)
  And the EAC. Package_status = 1
  And the EAC. Inactive_dt is null
  And cce.association_type = 2
  
  
  An aplogize for my eanglish.
  Thank you

  Do you mean that the remote servers are running 8i?

  8i supported SQL 99 join syntax. So I would be quite surprised if forcing the instance of Oracle 9i local to do joins, representing the query Exchange plan.

  Justin