Keep the query results set all paging

Similar Questions

• The query results: extract all lines?

  I was looking for a feature that will allow me to choose to return "all records" in the query results window. The current behavior is fetching 50 files at a time (for example fetch 50 records when you scroll the results = s-l-o-w). What I would do, that is 'Recover all lines' and then use for the scroll bar to scroll "smoothly" to the last record. For example, the 8.0.6 Query Builder version has this feature and SQL Developer 3.0, if I right click on the results. I choose 'Count lines... ". ", looks like it would be a perfect place to put an option"retrieve all rows.

  If your application is to be able to quickly reach the last record in a query you can press Ctrl + Page Down (with emphasis in the grid of results) and you will automatically position your view to the last record in the query automatically go get all the results in the process.

  You have no need to do anything with the mouse scroll is actually the fastest way to reach the desired line.

• Problem with the query result set * STILL a QUESTION *.

  Summary
  
  What I am tring to do is to return output to the data points that currently have no values.
  
  * Here it is sample data for reasons explaining my question (my data set is MUCH bigger)
  
  xTable

  YEAR    PEOPLE    ITEMS    TYPE_NUMBER TYPE_DESC    CLASS
  2010       1                 1              REG              1 
  2010        2        3         2             MISC             1
  2010        5        4         3             WEEK           1
  2010                             1             REG              2
  2010                             2             MISC             2
  2010                             3             WEEK           2
  2009       1                 1              REG              1 
  2009        2        3         2             MISC             1
  2009        5        4         3             WEEK           1
  2009                             1             REG              2
  2009                             2             MISC             2
  2009                             3             WEEK           2
  
  ... (there's over 100 other unique CLASS values)

  Desired output

  YR     PEOPLE   ITEMS   TOTAL PEOPLE  TOTAL_ITEMS
  2010         -            -            -                        -                         --  (Class 2 result set)
  
  /* FYI, If i wanted the class 1 result set it would look like this:
  YR     PEOPLE   ITEMS   TOTAL PEOPLE  TOTAL_ITEMS
  2010        8       7             16                    14                       -- (Class 1 result set)*/

  Oracle: 10.2 G

          select 2010 as yr,
                       nvl(f.people,'-') as people
                       nvl(f.items,'-') as items  
                       nvl(to_char(sum(f.people)),'-') as total_people,
                       nvl(to_char(sum(f.items)),'-') as total_items,
                       from Xtable,
                            (2010 as yr,
                            sum(items)as items
                            sum(people) as people
                            from xTable
                            where person_id = 99999
                            and   type_number in (1,2,3)
                            and year = 2010
                            and class = 2 
                            or class = 1
                            ) f
                       where person_id = 99999
                       and type_number in (1,2,3)
                       and yr = f.yr
                       and (year <= 2010 or year = 2010)
                       and (class = 2 or class = 1)
                       group by 
                       f.people,
                       f.items

  Currently, the query above will return no rows.
  
  Published by: user652714 on February 2, 2010 13:04

  How about this?

  SQL> WITH    xTable AS
    2  (
    3          SELECT 2010 AS YEAR, 1 AS PEOPLE, 0 AS ITEMS, 1 AS TYPE_NUMBER, 'REG' AS TYPE_DESC, 1 AS CLASS FROM DUAL UNION ALL
    4          SELECT 2010 AS YEAR, 2 AS PEOPLE, 3 AS ITEMS, 2 AS TYPE_NUMBER, 'MISC' AS TYPE_DESC, 1 AS CLASS FROM DUAL UNION ALL
    5          SELECT 2010 AS YEAR, 5 AS PEOPLE, 4 AS ITEMS, 3 AS TYPE_NUMBER, 'WEEK' AS TYPE_DESC, 1 AS CLASS FROM DUAL UNION ALL
    6          SELECT 2010 AS YEAR, NULL AS PEOPLE, NULL AS ITEMS, 1 AS TYPE_NUMBER, 'REG' AS TYPE_DESC, 2 AS CLASS FROM DUAL UNION ALL
    7          SELECT 2010 AS YEAR, NULL AS PEOPLE, NULL AS ITEMS, 2 AS TYPE_NUMBER, 'MISC' AS TYPE_DESC, 2 AS CLASS FROM DUAL UNION ALL
    8          SELECT 2010 AS YEAR, NULL AS PEOPLE, NULL AS ITEMS, 3 AS TYPE_NUMBER, 'WEEK' AS TYPE_DESC, 2 AS CLASS FROM DUAL
    9  )
   10  -- END SAMPLE DATA
   11  SELECT  YEAR
   12  ,       NVL(TO_CHAR(SUM(PEOPLE)),'-')    AS PEOPLE
   13  ,       NVL(TO_CHAR(SUM(ITEMS)),'-')     AS ITEMS
   14  ,       CLASS
   15  FROM    xTable
   16  WHERE   CLASS IN (1,2)
   17  AND     YEAR = 2010
   18  GROUP BY YEAR
   19  ,       CLASS
   20  ORDER BY CLASS DESC;
  
                  YEAR PEOPLE ITEMS CLASS
  -------------------- ------ ----- -----
                  2010 -      -         2
                  2010 8      7         1
  

• Query result set...

  I can't determine a good word in my question. So, I think that my pseudocode below will be sufficient for this purpose.
  
  Oracle version: 11.2 g
  
  Data set

  WITH temp AS
  (
   SELECT 1 col1, 1 day FROM dual UNION ALL
   SELECT 2 col1, 1 day FROM dual UNION ALL
   SELECT 3 col1, 1 day FROM dual UNION ALL
   SELECT 4 col1, 1 day FROM dual UNION ALL
   SELECT 5 col1, 1 day FROM dual UNION ALL
   SELECT 6 col1, 1 day FROM dual UNION ALL
   SELECT 7 col1, 2 day FROM dual UNION ALL
   SELECT 8 col1, 2 day FROM dual UNION ALL
   SELECT 9 col1, 2 day FROM dual UNION ALL
   SELECT 10 col1,2 day FROM dual 
  )
  SELECT *
    FROM temp

  The result of the above query:

  COL1     DAY
  1     1
  2     1
  3     1
  4     1
  5     1
  6     1
  7     2
  8     2
  9     2
  10     2

  You the WISH result set:

  DAY COL_TOTAL
  1   21  
  2   55   -- 21 + 33 (the sum of day 1 + the sum of day 2)

  I realize that I can get the desired result, set above the code below. However, for my I have several other data points and 100 separate days I need to do for their actual issue. In doing so, a statement of the UNION 100 isn't exactly going to work.

  WITH temp AS
  (
   SELECT 1 col1, 1 day FROM dual UNION ALL
   SELECT 2 col1, 1 day FROM dual UNION ALL
   SELECT 3 col1, 1 day FROM dual UNION ALL
   SELECT 4 col1, 1 day FROM dual UNION ALL
   SELECT 5 col1, 1 day FROM dual UNION ALL
   SELECT 6 col1, 1 day FROM dual UNION ALL
   SELECT 7 col1, 2 day FROM dual UNION ALL
   SELECT 8 col1, 2 day FROM dual UNION ALL
   SELECT 9 col1, 2 day FROM dual UNION ALL
   SELECT 10 col1,2 day FROM dual 
  )
  SELECT SUM(col1) AS col_total
    FROM temp
   WHERE day <= 1
  UNION ALL
  SELECT SUM(col1) AS col_total
    FROM temp
   WHERE day <= 2

  Published by: user652714 on August 13, 2012 21:55

  Hello

  I now see what you want. You can use this:

  select *
  from tt
  order by col_1;
  
       COL_1        DAY
  ---------- ----------
           1          1
           2          1
           3          1
           4          1
           5          1
           6          1
           7          2
           8          2
           9          2
          10          2
  
  10 rows selected.
  
  select day, sum(total) over  (order by  day) COL_TOTAL
  from
  (select day, sum(col_1) TOTAL
  from tt
  group by day
  );
  
      DAY  COL_TOTAL
  ---------- ----------
           1         21
           2         55
  
  2 rows selected.
  

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  I did the 2 larger site and how to keep the same size for all pages when I re - open the web browser?

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  So I created a function to dynamically access the data in the table. I use the item = results.rows.item (i) and that the data access with item.column line.

  column is a variable that will receive the value of a schema representative of column_name. When I alert (column) I get the column_name is correct, but when I used item.column my results are "not defined".

  any advice on how to solve this issue.

  I managed to solve this issue. The solution is the following: the normal way to access the data of the variable item = results.rows.item (i) is item.column (where the column is the name of the column in the database table. To access the data dynamically, I Specifies a var col1 to assign different values in col1. I then access the data in the database using point [col1] hope that makes sense. If you need a further explanation contact me at [email protected]

• Need help to understand the query result

  Hi gurus

  I was reading one of the question here in this forum and its link is below:

  Query required for scenario

  I had some confusion related to this code and don't understand the logic of the out put, see query below:

  Query

  with sub_services as

  (

  Select su_seq 12323, 'HLR1' so_id, 1 seq Union double all the

  Select su_seq 12323, "HLR2' so_id, seq 2 Union double all the

  Select su_seq 12323, "A09" so_id, seq 3 of all the double union

  Select su_seq 12333, "MO1" so_id, seq 4 Union double all the

  Select su_seq 12333, "MO2' so_id, seq 5 Union double all the

  Select su_seq 12333, "A09" so_id, 6 seq in union double all the

  Select su_seq 12333, 'M0CR' so_id, seq 7 Union double all the

  Select su_seq 12999, "LOL1' so_id, seq 8 Union double all the

  Select su_seq 12999, "LOL2' so_id, seq 9 double

  )

  Select *.

  of sub_services b

  where exists (select 1 from sub_services

  where su_seq = b.su_seq

  and so_id = 'A09.

  )

  order by 2;

  The query result

  12323 A09 3

  12333 6 A09

  12323 HLR1 1

  12323 HLR2 2

  12333 M0CR 7

  12333 4 MO1

  12333 5 MO2

  According to my understanding, the above query should return records in red only because of her is below command

  It exists (select 1 from sub_services

  where su_seq = b.su_seq

  and so_id = 'A09.

  but don't know why he's back 7 files, can someone help me understand the result...

  It is query is functionally identical to the PL/SQL block, but much more effective.

  declare

  number of l_res;

  Start

  for line (select *)

  sub_services) loop

  Start

  Select 1 from l_res

  of sub_services

  where su_seq = row.su_seq and

  so_id = "A09" and

  rownum = 1;

  exception when

  NO_DATA_FOUND then

  null;

  end;

  end loop;

  end;

  Essentially every row in the outer query are tested against him exists query.  Given the correlation between two requests is based only on su_seq each line with a su_seq value returned by him is returned in the output.

  Another way to think he uses instead a join condition.  This query is equivalent to the query to exist

  Select the main

  of main sub_services

  Join select (separate su_seq

  of sub_services

  where so_id = "A09") cond

  We main.su_seq = cond.su_seq;

  John

• JSON to the sql result set

  Hi all

  I have this requirement to convert the JSON format in the result set (with the lines and columns).

  is their in any case I can achieve this?

  I was able to successfully convert the sql result set in JSON format but difficult time to do the reverse.

  Flexibility:

  At some point, I expect the lines to return no more than 2 & about 50 columns maximum.

  Therefore, the JSON itself can be stored in varchar2 (4000) and not need to use CLOB. (If necessary to be passed as an argument to the function).

  Oracle version: 11.2.0.3

  Kind regards

  AAG

  There are at least the son on this site below:

  https://community.Oracle.com/thread/2505918

  https://community.Oracle.com/thread/3634280

  https://community.Oracle.com/thread/3557925

  https://community.Oracle.com/thread/2510292

• new to 4.02, no grid or column names in the query results

  It is a bit strange, I have SQL Developer 4.02 just installed, and I don't see grid or column names in the query results.  Don't see anything useful in tools > Preferences, what don't get me?

  The worksheet gives you a couple of different ways to run a query...

  1. instruction execute sheet icon toolbar (large green arrow, or Ctrl + Enter).

  This produces a results tab of the query with the data displayed in a grid.

  2. worksheet icon toolbar Execute the Script (the small tip of the green arrow on lined paper, or F5).

  This produces a tab out of the Script with the data displayed on the printer.

  If execution of the statement to Execute the Script, using some SQL * most orders will remove the column headers:

  1. set the position

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  Kind regards

  Gary

  SQL DeveloperTeam

• How to get SQL Developer 4.1 to display the query result?

  SQL DEV 4.0.3.16.84 execution of a SELECT statement is stored in a .sql file causes the window of the query result of pop-up indicating the result of a SELECT statement.  SQL DEV 4.1 is not to do so.

  Oops on my part; my SQL formatting has been the root cause.  I got used to insert split without any character of comment lines in front of them.  For example:

  ==================================================

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  The foregoing indicates the behavior described.

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• How to clear the search query result set

  I dropped a search with the table query. When I search a value it is the display of the result, but when I click on the reset button, only the query Panel is reset to zero and not the table. What can I do to reset the table component associated with the query?

  When I click on the reset button, only the query panel goes to zero and no table.

  It will be reset nt table.

  What can I do to reset the table component

  Use of the component range reset. to do so.

  http://jobinesh.blogspot.in/2009/10/reset-content-of-Web-page.html
  http://myadfnotebook.blogspot.in/2011/05/making-reset-button-in-afquery.html trickles you want
  http://andrejusb.blogspot.in/2009/09/programmatical-reset-for-query-results.html

  -edited lately

  Published by: ADF7 on February 22, 2012 12:58 AM

• Need help to build the query/pl-sql block to get the query result and the name of column from DB table in the form of key-value pairs.

  Hi Experts,

  I have a DB table has columns of more than 50.

  I question this table, it should only return one line at any time. as sqldeveloper below image.

  

  here, I need to build block pl/sql-query, Discover the column in the table as a key and query result as values.

  Eg:     Key                         -  Value

  TASK_EVENT_ID - 1765

  EVENT_TYPE - ASR_UPDATE

  ... etc until all of the columns in my table.

  Experts please comment on that point, appreciate your help on this.

  Thank you

  -Vincent.

  Here is an approach using DBMS_SQL to iterate over the columns of key / value to assign... (Little code snipped for brevity)

  create or replace procedure (task_expired)

  v_store_id in full,

  v_task_action_id in full,

  v_job_id in full

  )

  as

  -[SNIP code...]

  v_sql VARCHAR2 (4000): = ' select * from my_table where PK = 123';  -Your SQL here!

  v_v_val VARCHAR2 (4000);

  v_n_val NUMBER;

  v_d_val DATE;

  v_ret NUMBER;

  c NUMBER;

  d NUMBER;

  col_cnt INTEGER.

  f BOOLEAN;

  rec_tab DBMS_SQL. DESC_TAB;

  col_num NUMBER;

  vAsString VARCHAR2 (4000);

  BEGIN

  -[SNIP code...]

  Message_properties. CORRELATION: = "EDF_EVENT";

  MSG: = SYS. AQ$ _JMS_BYTES_MESSAGE. Construct();

  Msg.set_string_property ('queueName', ' shipping/csi_cth');

  Msg.set_string_property ('MODE', 'CR8');

  c: = DBMS_SQL. OPEN_CURSOR;

  DBMS_SQL. PARSE (c, v_sql, DBMS_SQL. NATIVE);

  d: = DBMS_SQL. Execute (c);

  DBMS_SQL. DESCRIBE_COLUMNS (c, col_cnt, rec_tab);

  1.col_cnt J

  LOOP

  CASE rec_tab (j) .col_type

  WHEN 2 THEN

  DBMS_SQL. DEFINE_COLUMN (c, j, v_n_val);      -Number

  WHEN 12 CAN

  DBMS_SQL. DEFINE_COLUMN (c, j, v_d_val);      -Date

  ON THE OTHER

  DBMS_SQL. DEFINE_COLUMN (c, j, v_v_val, 2000);   -Else treat as varchar2

  END CASE;

  END LOOP;

  LOOP

  v_ret: = DBMS_SQL. FETCH_ROWS (c);

  WHEN OUTPUT v_ret = 0;

  1.col_cnt J

  LOOP

  -Fetch each column to the correct data type based on coltype

  CASE rec_tab (j) .col_type

  WHEN 2 THEN

  DBMS_SQL. COLUMN_VALUE (c, j, v_n_val);

  vAsString: = to_char (v_n_val);

  WHEN 12 CAN

  DBMS_SQL. COLUMN_VALUE (c, j, v_d_val);

  vAsString: = to_char (v_d_val, ' DD/MM/YYYY HH24:MI:SS');

  ON THE OTHER

  DBMS_SQL. COLUMN_VALUE (c, j, v_v_val);

  vAsString: = v_v_val;

  END CASE;

  Msg.set_string_property (rec_tab (j) .col_name, vAsString);

  END LOOP;

  END LOOP;

  DBMS_SQL. CLOSE_CURSOR (c);

  DBMS_AQ. ENQUEUE (queue_name-online 'cbus.aqjms_common',

  Enqueue_options => Enqueue_options,

  Message_properties => Message_properties,

  Payload-online msg,

  Msgid => Message_handle);

  dbms_output.put_line ('00 Msgid =' |) Message_handle);

  dbms_output.put_line('===Done=');

  -[SNIP code...]

  END;

  /

• Unable to produce the query results

  Hi all

  Hello. I'm aunable write a query that can produce reuls froe below question. An account can have several part relationship.

  Here is the data for the x table

  PartyID - AcctNo - indicator - RoleCode

  1111      -----     123   ------     Y         -------  110

  1112    -------     123   ------    N        --------- 120

  1113     ------     123   ------   N          --------   130

  1114     -------   124     -----   N        --------    100

  1115    --------   124    ------- N         ---------   110

  1116   ---------   124      ----   N       ---------    100

  1115      --------  125             Y       -------        100

  1116      -------    125             N      ------         110

  1117      -------   126            Y         -----        100

  Query should return these AcctNo is not any indicator = 'Y' and RoleCode did not have 100. In this case the results should be

  AcctNo

  123

  124

  Thanks in advance

  Don

  Hello

  885137 wrote:

  Hi, Frank, here is creation and insertion of table scripts. ...

  Thank you.

  So what's the problem with the query I posted in response #1?  (You must use the correct name of the table, of course).  Specify where he makes incorrect results and explain why these results are false.

• How to keep the style of setting shaped tables that you paste IN when copying old pictures?

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