Link person based on the address or the name
Version: Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production
I have the following scenario, where I'm trying to bind the person based on Addr_id / Addr_id_comp / Org_id.
I want to create a flag as 1 that tells me that they are related. This time with the example below, the indicator returns 0.
WITH Link_address_t AS (SELECT Person_id 6439
77131101 we_Addr_id,
183818078 we_addr_id_comp,
we_org_id 9287841
OF THE DOUBLE
UNION ALL
SELECT Person_id 6439,
393426140 we_Addr_id,
394052621 we_addr_id_comp,
we_org_id 918388
OF THE DOUBLE
UNION ALL
SELECT Person_id 6439,
77131101 we_Addr_id,
394052621 we_addr_id_comp,
we_org_id 918388
THE DOUBLE)
SELECT Person_id,
we_addr_id,
we_addr_id_comp,
we_org_id,
CASE
WHERE (we_addr_id = PRIOR we_addr_id
OR we_addr_id_comp = PRIOR we_addr_id_comp
GOLD we_org_id = PRIOR we_org_id)
THEN
1
ON THE OTHER
0
END
Flag
OF Link_address_t
START BY Person_id = 6439
CONNECT NOCYCLE Person_id = Person_id PRIOR
Power required
PERSON_ID WE_ADDR_ID WE_ADDR_ID_COMP WE_ORG_ID FLAG
6439 77131101 183818078 9287841 1
6439 393426140 394052621 918388 1
6439 77131101 394052621 918388 1
I don't see why you use a hierarchical query here. That seems to be what you want (notice that I added a primary key column to your original table):
WITH Link_address_t AS (SELECT 1 pk,
6439 Person_id,
77131101 we_Addr_id,
183818078 we_addr_id_comp,
we_org_id 9287841
OF THE DOUBLE
UNION ALL
SELECT 2 pk,
6439 Person_id,
393426140 we_Addr_id,
394052621 we_addr_id_comp,
we_org_id 918388
OF THE DOUBLE
UNION ALL
SELECT 3 pk
6439 Person_id,
77131101 we_Addr_id,
394052621 we_addr_id_comp,
we_org_id 918388
THE DOUBLE)
SELECT Person_id,
we_addr_id,
we_addr_id_comp,
we_org_id,
CASE
WHEN THERE ARE (SELECT 99
OF link_address_t la2
WHERE la2.person_id = la.person_id
AND la2.pk! = la.pk
AND (la2.we_Addr_id = la.we_addr_id
OR la2.we_Addr_id_comp = la.we_addr_id_comp
GOLD la2.we_org_id = la.we_org_id)) THEN 1
0 OTHERWISE
END indicator
OF the Link_address_t
WHERE Person_id = 6439
Tags: Database
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Find the name and the table constraint type based on the name of the field
I have a field name or a column with me... I want to find the name of the table is a primary key... Any request to make this work so that the running costs are low...
Currently, I mix dba_constraints and ALL_TAB_COLUMNS to get this... is possible to extract the data of a process cost effective single table/any other is appreciated
You must include the USER/ALL_CONSTRAINTS with USER/ALL_CONS_COLUMNS to achieve your desired results. For your specific condition, you can try this query.
Select constraint_name
column_name
de)
Select c.constraint_name
cc.column_name
count on column_count (c.constraint_name score) (cc.column_name)
from user_constraints c
Join user_cons_columns cc
on c.constraint_name = cc.constraint_name
where constraint_type = 'P '.
)
where column_name = 'EMPNO '.
and column_count = 1;
I used USER_CONSTRAINTS and USER_CONS_COLUMNS. If you use ALL or DBA dictionary table add join OWNER condition as well.
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Set the export file based on the name of the Collection?
I would like to be able to parameters predefined export that would save the selected pictures in a subfolder within my file of export with the name of the subfolder automatically value corresponds to the collection (or a set of collection) name. Is this possible? I tried looking at the name of custom folder options but could not quite see how do so any help is appreciated.
So, if my parent export file is say c:\Photos\Exports and the collection my name is 'Summer2012', I want to automatically export all the photos in this collection at c:\Photos\Exports\Summer2012. Is this possible or should I set manually each time?
I would like to automate this is to say that I can't wait to put up the pictures, I could go ahead and export them without having to edit a lot and then manually cut and paste of c:\Photos\Exports in a Summer2012 folder. If later, I apply alterations to photos, it would be much more convenient to use a predefined export, knowing that they would automatically update the files in the Summer2012 folder, rather than having to do another manual cut and paste every time or manually select the folder if you choose the option "Choose the folder" later. Is there another way to do what I'm looking for? Thank you.
OhPinchy wrote:
Thank you, Richard. That tool looks very practical, but it seems that you must manually recreate the structure of collections in there - not a large number as you just need to do once offshore, but before to go this route I just want to confirm if there is a possibility to do it dynamically/automatically?
Unfortunately, there is a dynamic method or automatic integrated with Lr. I'm not even sure the plugin SDK supports Jeffrey otherwise (the author of the plugin you're looking at) would have incorporated the feature.
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