LISTAGG help

Hello

We use this query

SELECT A.EMAIL, COUNT (B.VALUE), (B.COMP_LIST_ID, ",") LISTAGG Group (ORDER OF B.COMP_LIST_ID) as long AS value1 DASH_EMP_DATA, DASH_EMP_COMP B WHERE B.COMP_LIST_ID IN (SELECT ID FROM DASH_COMP_LIST WHERE COMP_OWNER = 'XYZ') AND A.ID = B.EMP_DATA_ID GROUP OF B.EMP_DATA_ID A.EMAIL ORDER OF A.EMAIL

output just like that

Email count (b.value) value1

------------------------------------------------------------------------------------------------------------

[email protected]                2                                              386,387

[email protected]                3                                              456,789,123

[email protected]                 1                                               654

We put out like this [Instead of ID value we have to the actual name of the component]

Email count (b.value) value1

------------------------------------------------------------------------------------------------------------

[email protected]                2                                               comp1,comp2

[email protected] 3 comp3 comp4, comp5

[email protected]                 1                                               comp5

table DASH_EMP_COMP does not have the name of the component

name of the component is stored in a SEPARATE dash_comp_list like this table

ID                                                  NAME

---------------------------------------------------------

386                                             COMP1

387                                              COMP2

---

---

----

We need out put as indicated above, kindly help

Thank you

Hello

Looks like you just need to join the additional table, so the name will be available for use as an argument to the LISTAGG, like this:

SELECT a.email

COUNTY (b.value)

LISTAGG (l.name, ',')

THE Group (ORDER BY b.comp_list_id) AS value1

OF dash_emp_data one

dash_emp_comp b

dash_comp_list l

WHERE b.comp_list_id IN ((in English only)

SELECT id

OF dash_comp_list

WHERE comp_owner = 'XYZ '.

)

AND a.id = b.emp_data_id

AND b.comp_list_id = l.id

GROUP BY b.emp_data_id

a.email

ORDER BY a.email

;

Depending on the relationship between dash_emp_comp and dash_comp_list, you may be able to do what the IN subquery with the join:

SELECT a.email

COUNTY (b.value)

LISTAGG (l.name, ',')

THE Group (ORDER BY b.comp_list_id) AS value1

OF dash_emp_data one

dash_emp_comp b

dash_comp_list l

WHERE a.id = b.emp_data_id

AND b.comp_list_id = l.id

AND l.comp_onwer = 'XYZ '.

GROUP BY b.emp_data_id

a.email

ORDER BY a.email

;

I hope that answers your question.

If this isn't the case, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.

Point where queries above are to produce erroneous results, and explain, using specific examples, how you get the right results from data provided in these places.

Always say what version of Oracle you are using (for example, 11.2.0.2.0).

See the FAQ forum: Re: 2. How can I ask a question on the forums?

Tags: Database

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    5 AND COLUMN_NAME LIKE '% E') a FROM EMP WHERE ROWNUM < = 3;

    A
    ----------------------------------------------------------------------------------------------------
    ENAME, EMPNO
    ENAME, EMPNO
    ENAME, EMPNO

    Thank you

    Here is an example of what you want to do:

    : c is of type cursor

    declare

    v varchar2 (4000);

    Start

    Select GROUP(ORDER BY COLUMN_NAME DESC) AS CONCATV ListAgg (column_name, ',')

    v

    of user_tab_cols

    WHERE TABLE_NAME = 'MYTABLE ';

    Open: c for 'select'. v. "from MYTABLE";

    end;

    ----

    Ramin Hashimzade

  • Listagg

    Hi all

    I see this example LISTAGG:
    SELECT deptno, LISTAGG(ename, ',') INTRA GROUP (ORDER BY ename) as employees FROM emp GROUP BY deptno;
    Can you help me convert my sql to this?

    Select group_concat (emp_name) from emp where dept_no = '10';

    Is this correct?
    Select LISTAGG(emp_name,',') INTRA GROUP (ORDER BY emp_name) emp where dept_no = '10';
    I can omit group by?

    Thank you...

    Select LISTAGG (emp_name, ',') IN GROUP (ORDER BY emp_name) from emp where dept_no = '10';

    I can omit group by?

    There is no GROUP of there is that ORDER BY. You need to order by oracle because they need to know in what order he will have to concat values. You can use different columns in ORDER BY. for example, if you want to concat the name in order of EMPNO, that you can use EMPNO in order.

  • need help for XMLAGG

    For this request below I need single quotes are required for each kintana_number

    and when I increase value < = 100 I get error as ORA-19011 how change above one get between apostrophes and avoid 0ra-19011
    Help, please

    SELECT DISTINCT RTRIM
    (XMLAGG
    (XMLELEMENT (e, p.kintana_number |)) ','). EXTRACT
    ('/ / text()')
    ),
    ','
    )
    PROJECT p where p.projectid < = 100


    Select
    listagg (kintana_number, ",") | " '
    WITHIN THE GROUP
    (ORDER BY kintana_number)
    Of
    project where the projectid < = 100
    I want each kintana_number singlequote after that each comma separated

    Published by: user13301356 on February 8, 2013 12:39 AM 
    SELECT dbms_xmlgen.convert(
         rtrim(
           extract(
             xmlagg(
               xmlelement(e, ''''|| p.kintana_number || ''',')
             )
           , '//text()'
           ).getclobval()
         , ','
         )
       , 1
       )
FROM project p ;

    Or, on Oracle 11:

    SELECT rtrim(
         xmlcast(
           xmlagg(
             xmlelement(e, ''''|| p.kintana_number || ''',')
           )
           as clob
         )
       , ','
       )
FROM project p ;

  • Help returns the array of query results

    Hi all... Pretty new to this so please forgive my ignorance. Running Oracle 11 g, trying to return results as in the example I give below. I don't know how the Sport field will have unique values, and I don't know how many unique values the year field is seen in the data. Does anyone have recommendations/suggestions?

    The structure of the table is:
    Year of sport
    Baseball 10-11
    Football 10-11
    Football 11-12
    Football 11-12
    Football 11-12
    Baseball 11-12

    The result should be sports in each year and should be grouped by year but shown as columns so:
    (GROUP OF the year)
    1, baseball 1, Football
    2, 1, Football Soccer 1, Baseball


    I hope that makes sense. Thanks for any help!
    ... Kaelon

    Does anyone have recommendations/suggestions?

    Maybe something like:

    SQL> with t as (
 select 'Baseball' sport, '10-11' year from dual union all
 select 'Football', '10-11' from dual union all
 select 'Football', '11-12' from dual union all
 select 'Football', '11-12' from dual union all
 select 'Soccer',   '11-12' from dual union all
 select 'Baseball', '11-12' from dual
)
--
--
select year, listagg(cnt || ', ' || sport, ' ') within group (order by cnt desc) sports from (
select count(*) cnt, sport, year from t
group by sport, year)
group by year
/
YEAR    SPORTS
------- ----------------------------------------
10-11   1, Baseball 1, Football
11-12   2, Football 1, Baseball 1, Soccer       

2 rows selected.

    ?

  • Oracle 11g LISTAGG function

    Hello

    Hello. I tried to use the new feature in Oracle 11 g: LISTAGG, but I received an error:

    SQL * more: Production release 11.2.0.1.0 Wed Mar 28 15:36:47 2012

    Copyright (c) 1982, 2010, Oracle. All rights reserved.

    Enter the user name: lbihrreader@LTMQA
    Enter the password:

    Connected to:
    Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
    SQL > SELECT DEVELOPMENTACTIVITY sc.
    SC.' SESSION '.
    LISTAGG (sc. CLASSDATE, ';') THE Group (ORDER BY sc. DEVELOPMENTACTIVITY, sc."SESSION")
    OF LTM. SESSIONCLASS sc
    WHERE sc. HRORGANIZATION = "800"
    AND TS. DELETEFLAG = "00000000000000000000000000000000"
    GROUP BY sc. DEVELOPMENTACTIVITY
    SC.' SESSION ';

    ERROR at line 3:
    ORA-00923: THE KEYWORD not found where expected

    Help, please.

    Thank you
    Helen

    In addition,

    THE Group (ORDER BY sc. DEVELOPMENTACTIVITY, sc."SESSION")

    doesn't make much sense in terms of ORDER BY. "" "You been group by sc. DEVELOPMENTACTIVITY, sc." SESSION "all GROUP lines will have same DEVELOPMENTACTIVITY, sc. ms." SESSION. " In any case, use:

    SELECT sc.DEVELOPMENTACTIVITY
,sc."SESSION"
,rtrim(xmlagg(xmlelement(s,sc.CLASSDATE,';').extract('//text()') order by sc.CLASSDATE),',')
FROM LTM.SESSIONCLASS sc
WHERE sc.HRORGANIZATION = '800'
AND sc.DELETEFLAG = '00000000000000000000000000000000'
GROUP BY sc.DEVELOPMENTACTIVITY
,sc."SESSION";

    For example:

    select  deptno,
        job,
        rtrim(xmlagg(xmlelement(s,sal,';').extract('//text()') order by sal),',') list
from emp
group by deptno,job
/

    DEPTNO JOB       LIST
---------- --------- -------------------------
        10 CLERK     1300;
        10 MANAGER   2450;
        10 PRESIDENT 5000;
        20 CLERK     800;1100;
        20 ANALYST   3000;3000;
        20 MANAGER   2975;
        30 CLERK     950;
        30 MANAGER   2850;
        30 SALESMAN  1250;1250;1500;1600;

9 rows selected.

SQL>

    SY.

  • concatenation of listagg with the boy?

    Hi people;

    I need to CONCATENATE interval of integers like this:
    1 - 1 = 1
    1-10, 2-3, 1-1 = 1-10
    1-10, 12-14 is 1-10, 12-14

    I have a global temporary table with a range (of type varchar2) by folder:
    RANGES
1 - 10
3 - 4
1 - 1
45 - 100
    I know that listagg (I'm on 11g):
    select LISTAGG(ranges, ', ') WITHIN GROUP (ORDER BY ranges) as a_validity_range from TMP_VALIDITY_RANGES;

A_VALIDITY_RANGE                                                                                                                                                                                      
-------------------------------------------------------------------------------------
1 - 1, 1 - 10, 3 - 4, 45 - 100
    I need to have the result: a_validity_range = 10-1, 45-100

    Please help me :)

    Published by: Moostiq on May 10, 2011 14:10

    Maybe something in that direction...

    SQL> ed
Wrote file afiedt.buf

  1  with t as (select '1 - 10' as rng from dual union all
  2             select '3 - 4' from dual union all
  3             select '1 - 1' from dual union all
  4             select '45 - 100' from dual)
  5  --
  6  -- end of test data
  7  --
  8      --
  9      -- determine lo and hi values from each range
 10      --
 11      ,x as (select rng, to_number(regexp_substr(rng,'^[0-9]+')) lo, to_number(regexp_substr(rng,'[0-9]+$')) hi from t)
 12      --
 13      -- generate all lists of numbers from each range
 14      --
 15      ,y as (select rng, lo+rn-1 as nm
 16             from   x cross join (select rownum rn from dual connect by rownum <= (select max(hi-lo)+1 from x))
 17             where lo+rn-1 <= hi)
 18      --
 19      -- roll up the new ranges
 20      --
 21      ,z as (select min(nm)||' - '||max(nm) rng
 22             from (select distinct nm from y order by nm)
 23             group by nm-rownum
 24             order by 1)
 25  --
 26  -- finally concatenate the ranges together
 27  --
 28  select ltrim(sys_connect_by_path(rng,', '),', ') as ranges
 29  from   (select rng, rownum as rn from z)
 30  where connect_by_isleaf = 1
 31  connect by rn = prior rn + 1
 32* start with rn = 1
SQL> /

RANGES
--------------------------------------------------------------------------------------------------------------------------
1 - 10, 45 - 100

SQL>

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