without using the listagg function

Similar Questions

• alternatives without using the regexp_replace function

  SELECT

  REGEXP_REPLACE (phone_number,

  "([[: digit:]] {3})------." ([[: digit:]] {3}). ([[: digit:]] {4})',

  "\2-\3 (\1)") "REGEXP_REPLACE.

  Employees;

  is there another without using the regexp_replace function...

  Another way

  (eliminating instr... function as your problem focuses on one length fixed)

  WITH t AS (SELECT '112.345.6789' FROM DUAL str).

  TT AS (SELECT REPLACE (str, '.') t str)

  SELECT ' (')

  || SUBSTR (str, 1, 3)

  || ') '

  || SUBSTR (str, 4, 3)

  || '-'

  || SUBSTR (str, 7)

  TT;

  See you soon,.

  Manik.

• help in the application without using the pivot function

  Hi gurus,
  
  Can you please help write the query without using the PIVOT function.
  

   WITH indata AS
           (SELECT 1 sn, '123:456,789,323:456,213,344,345:5454' x
              from dual
            UNION ALL
            SELECT 2, 'abcd:fgrfr,rfrf,rfred,tg:tg,tg:ophhh,op,vdfgbh:poijn' x from dual),
          instr AS
           (SELECT a.SN,
                   rownum RN,
                   B.column_value || CASE
                     WHEN B.column_value NOT LIKE '%:%' THEN
                      ':'
                   END column_value 
              FROM indata a,
                   TABLE(CAST(multiset
                              (SELECT trim(SUBSTR(x,
                                                  (CASE LEVEL
                                                    WHEN 1 THEN
                                                     1
                                                    ELSE
                                                     instr(x, ',', 1, LEVEL - 1) + 1
                                                  END),
                                                  (CASE instr(x, ',', 1, LEVEL)
                                                    WHEN 0 then
                                                     4000
                                                    ELSE
                                                     instr(x, ',', 1, LEVEL) - 1 -
                                                     (CASE LEVEL
                                                        WHEN 1 THEN
                                                         0
                                                        ELSE
                                                         instr(x,
                                                               ',',
                                                               1,
                                                               level - 1)
                                                      END)
                                                  END)))
                                 FROM dual
                               CONNECT BY level <=
                                          LENGTH(x) -
                                          LENGTH(REPLACE(x, ',', '')) + 1) AS
                              sys.odcivarchar2list)) b)
          SELECT  col1_val2,
                  col1_val1,
                  col2_val2,
                  col2_val1,              
                 systimestamp
            FROM (select SN,
                        ROW_NUMBER() over(partition by SN order by RN) RN,
                         SUBSTR(column_value, INSTR(column_value, ':') + 1) VAL1,
                         substr(column_value, 1, instr(column_value, ':') - 1) val2
                    FROM instr ) PIVOT(MAX(VAL1) VAL1, MAX(VAL2) VAL2 FOR SN IN(1 as col1,2 as col2));

  Thanks in advance!...
  
  Any help would be appreciated.

  user590978 wrote:

  Can you please help write the query without using the PIVOT function.

  with indata as (
                  select 1 sn,'123:456,789,323:456,213,344,345:5454' x from dual union all
                  select 2, 'abcd:fgrfr,rfrf,rfred,tg:tg,tg:ophhh,op,vdfgbh:poijn' x from dual
                 ),
           t1 as (
                  select  x
                    from  indata
                    where sn = 1
                 ),
           t2 as (
                  select  x
                    from  indata
                    where sn = 2
                 ),
           t3 as (
                  select  level lvl,
                          substr(
                                 x,
                                 instr(',' || x,',',1,level),
                                 instr(x || ',',',',1,level) - instr(',' || x,',',1,level)
                                ) col1
                    from  t1
                    connect by level <= length(x) - length(translate(x,'A,','A')) + 1
                 ),
           t4 as (
                  select  level lvl,
                          substr(
                                 x,
                                 instr(',' || x,',',1,level),
                                 instr(x || ',',',',1,level) - instr(',' || x,',',1,level)
                                ) col2
                    from  t2
                    connect by level <= length(x) - length(translate(x,'A,','A')) + 1
                 ),
           t5 as (
                  select  lvl,
                          substr(col1,1,instr(col1 || ':',':') - 1) col1_val1,
                          substr(col1,instr(col1 || ':',':') + 1) col1_val2
                    from  t3
                 ),
           t6 as (
                  select  lvl,
                          substr(col2,1,instr(col2 || ':',':') - 1) col2_val1,
                          substr(col2,instr(col2 || ':',':') + 1) col2_val2
                    from  t4
                 )
  select  col1_val1,
          col1_val2,
          col2_val1,
          col2_val2,
          systimestamp
    from      t5
          full join
              t6
          on (
              t6.lvl = t5.lvl
             )
    order by coalesce(t5.lvl,t6.lvl)
  /
  
  COL1_VAL1  COL1_VAL2  COL2_VAL1  COL2_VAL2  SYSTIMESTAMP
  ---------- ---------- ---------- ---------- -------------------------------------
  123        456        abcd       fgrfr      23-OCT-12 11.50.12.015000 AM -04:00
  789                   rfrf                  23-OCT-12 11.50.12.015000 AM -04:00
  323        456        rfred                 23-OCT-12 11.50.12.015000 AM -04:00
  213                   tg         tg         23-OCT-12 11.50.12.015000 AM -04:00
  344                   tg         ophhh      23-OCT-12 11.50.12.015000 AM -04:00
  345        5454       op                    23-OCT-12 11.50.12.015000 AM -04:00
                        vdfgbh     poijn      23-OCT-12 11.50.12.015000 AM -04:00
  
  7 rows selected.
  
  SQL> 
  

  SY.

• count the number of lines without using the count function

  Hello
  How count the number of lines without using the count function?
  
  Thank you

  Assuming that your statistics table are updated:

  select num_rows
  from   all_tables
  where  table_name = 'YOUR_TABLE_NAME_IN_UPPERCASE';  
  

  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14237/statviews_2105.htm#REFRN20286

• How to get distinct records by using the ListAgg OBIEE report function?

  Hi all

  I get a correct result as mentioned below. But I don't see duplicates in my result here, in my example, I get duplicate for the name of the employee 'Pat '. So how to get Distinct values by using the LISTAGG function?

  Data set of sample with the Department and its employees

  Service employee

  ----------      ----------

  Marketing Michael

  Pat of marketing

  Pat of marketing

  Pat of marketing

  Purchase of Den

  Purchase of Alexander

  Purchase of Shelli

  Purchase of Sigal

  Guy of purchase

  Purchase of Karen

  Using the ListAgg function, we can convert it to:

  Employees of the Department

  -----------     -------------------------------------

  Marketing of Pat, Pat, Pat, Michael

  Purchase of Sigal, Shelli, Karen, Guy, Den, Alexander

  I tried a lot of things, but I'm not able to understand how exactly this can be achieved, if anyone has any idea or suggestions please do share, thanks in advance.

  After much research, I found the solution & I want to share what he finds very useful, we can create SQL logic in the Advanced tab, as below and after you click Rescan, and then you will get your desired results.

  SELECT saw_0, Evaluate_Aggr T1.dept ("ListAgg(%1,'' & '') intra group (about 1%)") ("as long as VarChar (1000), T1.emp) saw_1 FROM)

  SELECT 'emp_dept '. "the Department dept,

  'emp_dept '. "' employee ' emp

  IN THE "DOMAIN".

  GROUP BY dept, emp

  ) T1 GROUP FROM T1.dept ORDER BY saw_0

  Also note here that we have good anti-aliasing for columns parent (ex: saw_0, saw_1), another by mistake oracle bi server.

• How doi send texts using the speech function without hitting the Send button?

  using the speech function in texting, how to send the text without actually pushing the Send button? When I say 'send' or 'send message' he just keeps typing

  "Hey, Siri, send a message to Bob. Siri will then ask you what you want text Bob. Once you stop dictating, Siri will ask then if you're ready to send the message. Say, "Yes." It's really very nice.

  If you are already in the message app and using speech-to-text, you must press the Send button.

• I want the single update query without using the function.

  I want to update sells_table selling_code field with product_code date product table max.
  In the product table, there are several product_code date wise.
  
  I did with below charly with the use of the service, but we can do in the query what a single update
  without using the function.
  
  UPDATE sells_table
  SET selling_code = MAXDATEPRODUCT (ctd_vpk_product_code)
  WHERE NVL(update_product_flag,0) = 0;
  
  (P_product IN VARCHAR2) RETURN of HVL.maxdateproduct NUMBER FUNCTION to CREATE or REPLACE
  IS
  max_date_product VARCHAR2 (100);
  BEGIN
  BEGIN
  SELECT NVL (TRIM (product_code), 0)
  IN max_date_product
  FROM (SELECT product_code, xref_end_dt)
  PRODUCT
  WHERE TO_NUMBER (p_product) = pr.item_id
  ORDER BY xref_end_dt DESC)
  WHERE ROWNUM = 1; -He'll be back a single line - max date product code
  EXCEPTION
  WHILE OTHERS
  THEN
  RETURN 0;
  END;
  
  RETURN max_date_product;
  
  END maxdateproduct;
  
  Thanks in advance.

  Hello

  Something like that.

  update setlls_table st
          set selling_code =(select nvl(trim(product_code)) from
                                (select product_code
                                        , rank() over (partition by item_id order by xref_end_dt DESC) rn
                                     from product
                                 ) pr
                                 where rn =1
                                       and pr.item_id = st.ctd_vpk_product_code
                             ) where NVL(update_product_flag,0) = 0 ;
  

  That such is not tested due to lack of sampling input.

  Concerning
  Anurag Tibrewal.

• How can I transfer Favorites from one computer to another without using the Sync feature?

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• SDO_NN cannot be assessed without using the index when put inside subquery

  Hi all

  I met a problem when you use the function sdo_nn to find the nearest neighbor. Here is my scenario:

  _ I have 2 customer and store tables.

  Customer table _ a client_ID and a 2D sdo_geom point

  _ Store table has store_ID and a 2D polygon sdo_geom.

  In the beginning, I have this query to find the nearest store to each customer as below:

  Select s.STORE_ID, c.CLIENT_ID

  store customer, s c

  where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE";

  _It works as expected when it returns a table showing the nearest store each customer.

  _Now I want to count the number of customers who have the same nearest store:

  Select / * + INDEX (store store_spatial_idx, client_spatial_idx client) * / count (nearest_store. CLIENT_ID)

  from (select s.STORE_ID, c.CLIENT_ID

  store customer, s c

  where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE") nearest_store

  Group of nearest_store. STORE_ID;

  This query generates the following error:

  Error report-

  SQL error: ORA-13249: SDO_NN cannot be assessed without using the index

  ORA-06512: at the 'MDSYS. MD", line 1723

  ORA-06512: at the 'MDSYS. MDERR", line 17

  ORA-06512: at the 'MDSYS. PRVT_IDX', line 9

  13249 00000 - '%s '.

  I'm pretty new to spatial databases and hope get help to go further. Thank you in advance!

  Hello Pinball,

  Oracle space tends to be a quite complex with many variables and moving parts.  We chatted about the group to a sort of FAQ or guidelines to help people like you submit questions that actually answers.  First of all, you really have to tell us the version of Oracle you are using.  Particularly the problems involving the optimizer, version down to the exact defined patch number is a good idea.  Secondly, you took the time to submit the question so I guess you want a response.  If you really want to see the answer and then providing an example is one of the most important things that you can do.  I'm going to do here for you, but in general people on this forum come and go and are often pushed into lurkitude, so if you want the coax to provide you with an example of work is the key.

  DROP TABLE store1 PURGE;
  CREATE TABLE store1(
      store_id INTEGER NOT NULL
     ,shape    MDSYS.SDO_GEOMETRY
     ,PRIMARY KEY(store_id)
  );
  
  DROP TABLE client2 PURGE;
  CREATE TABLE client2(
      client_id INTEGER NOT NULL
     ,shape    MDSYS.SDO_GEOMETRY
     ,PRIMARY KEY(client_id)
  );
  
  CREATE OR REPLACE PROCEDURE seeder(
      p_client_count IN NUMBER
     ,p_store_count IN NUMBER
  )
  AS
    sdo_foo MDSYS.SDO_GEOMETRY;
    int_counter NUMBER;
    FUNCTION random_point
    RETURN MDSYS.SDO_GEOMETRY
    AS
        num_x1 NUMBER;
        num_y1 NUMBER;
  
    BEGIN
        num_x1 := dbms_random.value(-179,179);
        num_y1 := dbms_random.value(-89,89);
  
        RETURN MDSYS.SDO_GEOMETRY(
            2001
           ,8265
           ,MDSYS.SDO_POINT_TYPE(
                num_x1
               ,num_y1
               ,NULL
            )
           ,NULL
           ,NULL
        );
  
    END random_point;
  
  BEGIN
    int_counter := 1;
    FOR i IN 1 .. p_client_count
    LOOP
        -- Create a client point
        sdo_foo := random_point();
        INSERT INTO client2
        VALUES (
            int_counter
           ,sdo_foo
        );
        int_counter := int_counter + 1;
  
    END LOOP;
  
    int_counter := 1;
    FOR i IN 1 .. p_store_count
    LOOP
        -- Create a store polygon of some kind
        sdo_foo := MDSYS.SDO_GEOM.SDO_ARC_DENSIFY(
            MDSYS.SDO_GEOM.SDO_BUFFER(
                random_point()
               ,5000
               ,0.05
            )
           ,0.05
           ,'arc_tolerance=0.05'
        );
        INSERT INTO store1
        VALUES (
            int_counter
           ,sdo_foo
        );
        int_counter := int_counter + 1;
  
    END LOOP;
  
    COMMIT;
  
  END seeder;
  /
  
  BEGIN
    seeder(10000,200);
  END;
  /
  
  BEGIN
    INSERT INTO user_sdo_geom_metadata(
        table_name
       ,column_name
       ,diminfo
       ,srid
    ) VALUES (
        'STORE1'
       ,'SHAPE'
       ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05))
       ,8265
    );
  
    COMMIT;
  
  EXCEPTION
    WHEN OTHERS
    THEN
        NULL;
  
  END;
  /
  
  BEGIN
    INSERT INTO user_sdo_geom_metadata(
        table_name
       ,column_name
       ,diminfo
       ,srid
    ) VALUES (
        'CLIENT2'
       ,'SHAPE'
       ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05))
       ,8265
    );
  
    COMMIT;
  
  EXCEPTION
    WHEN OTHERS
    THEN
       NULL;
  
  END;
  /
  
  CREATE INDEX store1_spx ON store1
  (shape)
  INDEXTYPE IS MDSYS.SPATIAL_INDEX
  NOPARALLEL;
  
  CREATE INDEX client2_spx ON client2
  (shape)
  INDEXTYPE IS MDSYS.SPATIAL_INDEX
  NOPARALLEL;
  
  /* Works as expected */
  SELECT
  s.store_id
  ,c.client_id
  ,MDSYS.SDO_NN_DISTANCE(1)
  FROM
  store1 s
  ,client2 c
  WHERE
  MDSYS.SDO_NN(
      s.shape
     ,c.shape
     ,'sdo_num_res=1'
     ,1
  ) = 'TRUE';
  
  /* No worky? Works for me */
  SELECT
  ns.store_id
  ,COUNT(ns.client_id)
  FROM (
     SELECT
      s.store_id
     ,c.client_id
     FROM
      store1 s
     ,client2 c
     WHERE
     MDSYS.SDO_NN(
         s.shape
        ,c.shape
        ,'sdo_num_res=1'
        ,1
     ) = 'TRUE'
  ) ns
  GROUP BY
  ns.store_id
  ORDER BY
  ns.store_id;
  

  So I wrote this about 12 c (12.1.0.2.0) and everything works fine for me.  Then I moved back from 11 GR 2 (11.2.0.4.0) and of course, there are questions.  So I guess that you don't use flavor of 11g.  So at this point we can look at the docs and see for 11g, have you often need to specify which table is the head and that is the one that has the spatial index to use.
  http://docs.Oracle.com/CD/E11882_01/AppDev.112/e11830/sdo_operat.htm#SPATL1032

  Its rather interesting that the optimizer of 12 c knows what you want, when I had to squint myself at your request and to play a little with the refining.  Note that SDO_NN is sensitive, because the geometry of the main table should come second in the operator.  I did not know that on the top of my head.

  
  SELECT
  /*+ LEADING(c) INDEX(s store1_spx)  */
   s.store_id
  ,c.client_id
  ,MDSYS.SDO_NN_DISTANCE(1)
  FROM
   store1 s
  ,client2 c
  WHERE
  MDSYS.SDO_NN(
      s.shape
     ,c.shape
     ,'sdo_num_res=1'
     ,1
  ) = 'TRUE';
  
  SELECT
   ns.store_id
  ,COUNT(ns.client_id)
  FROM (
     SELECT
     /*+ LEADING(c) INDEX(s store1_spx)  */
      s.store_id
     ,c.client_id
     ,MDSYS.SDO_NN_DISTANCE(1)
     FROM
      store1 s
     ,client2 c
     WHERE
     MDSYS.SDO_NN(
         s.shape
        ,c.shape
        ,'sdo_num_res=1'
        ,1
     ) = 'TRUE'
  ) ns
  GROUP BY
  ns.store_id
  ORDER BY
  ns.store_id;
  

  So I think that is your answer.  Give it a shot and see if this fits the Bill.  Of course, moving to 12 c would be useful for such things.  It would be interesting to collect more examples of this kind of space thing where 12 c is the answer. Also, would be nice if we could mark somehow this discussion as applying only to 11g and earlier versions.

  See you soon,.

  Paul

• Interactive report editable without using the Collection

  Hi Experts,

  I use Oracle Apex 4.2.5

  Is it possible to create an interactive report that can be changed in the same page? If the user edit a field, it must get updated in this table.

  Let me know if this is possible without assistance from the Collections of the Apex

  BR,

  Patrick

  Paul Broughton says:

  Hi Patrick,

  I also agree there is no out of the box solution, I need this for an application and I used elements of the APEX of the APEX_ITEM API

  Here is a very basic example that I have not tested, but you have a question, something like:

  [code]

  Select

  APEX_ITEM. DISPLAY_AND_SAVE (1, empno) as patient_id,

  APEX_ITEM. TEXT (2, ename) as ename

  Of

  EMP;

  [/ code]

  Make sure you use columns of standard report as your column types.

  When you click on submit you'd have a process similar to the following:

  [code]

  Start

  BECAUSE me in 1... APEX_APPLICATION. G_F01. COUNTING LOOP

  Update emp

  set ename = apex_application.g_f02 (i)

  where empno = apex_application.g_f01 (i);

  end loop;

  end;

  [/ code]

  That's assuming you don't need inline editing.  If you do this will require an even more customized solution, but the way above requires no collections.

  Thank you

  Paul

  Hi Paul,.

  I think that IR out-of-box features do not work correctly when you use the APEX_ITEM functions in the query.

  Here's another one you could use APEX 4.2

  Yet another way to create & quot; editable interactive report & quot;

  Kind regards

  Jari

• Do I need to use the NVL function for this request?

  I seem to have some problems using the NVL function on a date. I'm trying to create a query pulls back just a date a file was sent between the sysdate and the date_sent more a minute. Here is the code I use...
  
  Oracle: 10.2 G
  

  SELECT date_sent as date_sent
  INTO    iDateSent
  FROM    tableX
  WHERE  file_id= 9999
  AND    date_sent BETWEEN sysdate AND date_sent + 1/1440; 

  Currently Output (null):

  DATE_SENT

  Desired output when date_sent is null:

  DATE_SENT
  0:0:000 0:00:00

  Note:
  date_sent column is in a normal date - same format as sysdate format.
  
  The problem I encounter is when date_sent is null, the stored procedure, I built crashes because date_sent returns a null and a null value cannot be stored in the variable 'iDateSent '. I was thinking about using the NVL function here to resolve, however, I'm not entirely sure who will work with the above query. Any thoughts?
  
  Published by: user652714 on July 9, 2010 12:58
  
  Published by: user652714 on July 9, 2010 13:11

  Hello

  you said: "desired output when date_sent is null: date_sent: 0".
  It is not possible to have a date of 'zero '.

  "and a null value cannot be stored in the variable 'iDateSent'. '.

  I do not think: If this variable is declared normally (without any not null not constrained to this topic) so that it can contain a null value. (it's 99% of the time in PL/SQL).

  I think it's that your SQL retrieves no rows, to manage what you should put an exception handler:

  begin
  SELECT date_sent as date_sent
  INTO    iDateSent
  FROM    tableX
  WHERE  file_id= 9999
  AND    date_sent BETWEEN sysdate AND date_sent + 1/1440;
  exception when NO_DATA_FOUND then
   iDateSent:=null;
  end;
  

  So what you can do if you don't want the date empty a nvl:

  return(nvl(iDateSent,sysdate));  -- or another date ...
  

  Published by: user11268895 on July 9, 2010 22:09

• Problem in the export using the QUERY functionality

  Problem in the export using the QUERY functionality
  
  
  I'm trying to export some rows in a table using the query functionality
  and I have some errors... I'm using the syntax is
  
  system@orcl QUERY = scott.emp expdp: '"WHERE emp_no = 123455" '
  DIRECTORY = data_pump_dir DUMPFILE = data_pump.dmp
  LOGFILE = data_pump_12345.log INDEX = n
  
  Can someone tell me please the problem with that statement
  
  I also tried to use the simple export
  
  exp file system@orcl = orcl_export.dmp log = orcl_export.log
  tables = Scott.EMP index = QUERY = n------"WHERE emp_no\ = 123455\"
  
  and this error
  
  EXP-00008: ORACLE error 904
  ORA-00904: identify invalid
  
  My os is Solaris
  Please let me know what the problem

  Hello

  Try to create parfile and use that, otherwise, you will need to escape each clause correctly to run exp or expdp successfully.

  test.par

  tables=emp
  query="WHERE emp_no=123455"
  
  or
  tables=myobjects
  query="WHERE owner='SYS'"
  
  $> exp username/password parfile=test.par
  
  Export: Release 10.2.0.1.0 - Production on Thu Mar 19 10:17:48 2009
  
  Copyright (c) 1982, 2005, Oracle.  All rights reserved.
  
  Connected to: Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
  With the Partitioning, OLAP and Data Mining Scoring Engine options
  Export done in WE8MSWIN1252 character set and AL16UTF16 NCHAR character set
  
  About to export specified tables via Conventional Path ...
  . . exporting table                      MYOBJECTS      22650 rows exported
  Export terminated successfully without warnings.
  

  Concerning

  Published by: OrionNet on March 19, 2009 10:21

• How can I access Siri on my iMac without using the icon?

  How can I access Siri on my iMac without using the icon?  Can I say "Hey Siri"?

  There is no option "Hey Siri" on a Mac because they do not have the necessary pickups. You must use the icon in the menu bar or Dock.

• Can I get the contacts and email from an old record without using the Migration Wizard?

  Can I recover Contacts and messaging of an old record without using the Migration Wizard? Disc of the user in question has been very corrupted with several programs having a weird behavior. Migration wizard migrated corrupt files, so, even a clean install with only migrated users gave rise to an unusable installation.

  I have now all own installed now, but need old email files and contacts. How can I transfer this information a copy of the old/bad drive and only this info?

  Yes. With the old drive mounted and available, open Mail and choose import mailboxes... from the file menu of mail. In the dialog box import data from , choose Apple Mail.

  Navigate to the Mail folder to the user of the old library drive. According to the version of courier used, you might see folders named V2 and / or V3. Choose the applicable folder, and then click Choose.

• No start page, Google rises and there is no way out without using the Task Manager.

  I used to get the Google search engine at the start of Firefox, with bookmarks bar in side bars and tool at the top. Now, all I get is a Google search page, with a few buttons on the top like images, etc. There is no way to close the program without using the Task Manager. I downloaded the latest version of Firefox and installed, but the problem has not disappeared. Operating system is Windows XP Professional

  Make sure that you run not Firefox mode full screen (press F11 or Fn + F11 to toggle; Mac: Ctrl + Shift + F).

  • https://support.Mozilla.org/KB/how-to-use-full-screen

  It is possible that the screen is too wide or too high and bars scrolling down.

  • Use Restore or expand in the context menu of the taskbar icon to set the focus to the Firefox application if you do not see the window of Firefox.
  • Open the system menu of the window of Firefox via Alt + space and see if you can move and resize the window (use the arrows on the keyboard).

  If it works, then first close all other open windows of Firefox and then close Firefox via "file > exit/Quit" to save the setting.

  If the above didn't help then see:

  • http://KB.mozillazine.org/Corrupt_localstore.RDF