Local Variable is NOT being updated?

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  Why my photos are not being updated on my iPad if all my devices are signed in iCloud?

  On your iPad, tap settings > iCloud. Make sure the Photo is on.

  Additionally, make sure that your iPad uses the same account as your other devices iCloud to synchronize data.

• How is it my local variable is not updated its value compared to what is happening in the while loop?

  Hello

  I am trying to extract data from a time that my statements updated in what concerns the number of loop iteration. I tried to use the two local variables and travel records, but without success.

  I also did the following example: http://www.ni.com/white-paper/7585/en and it works like a charm.

  I've attached the PNG file with declaration of the local variable circled in red. Join a VI in the next respnose.

  Thank you

  No, the two while loops are stacked and not parallel, which means the outer loop cannot go to the next iteration until all code in this document, including the inside so that the loop is finished.

• local variable is not updated

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  in the example below, the upper loop is not always update the value of the stop command. Why is this?

  
  

• Why my static PL/SQL within SQL local variable is not transformed in space in the shared pool?

  Hello everyone,

  Oracle version: 12.1.0.1.0 - 64 bit

  OS: Linux Fedora Core 17 X86_64

  Description of the problem:

  I'm reading an interesting book of online oracle named: SQL in PL/SQL

  On page 11, it reads the following:

  In the absence of a compilation error, the PL/SQL compiler generates an equivalent statement of SQL regular text and stores this with the generated machine code. This instruction uses placeholders where the embedded SQL statement uses identifiers that have been resolved in the PL/SQL unit.

  What I understand of this (please, correct me if I'm wrong) is that whenever I write some static/embedded statement SQL within a PL/SQL block in which there are a few local variables in PL/SQL, and then final generated SQL statement (after resolution of identifier) will include placeholders (bind variables) instead of these identifiers the PL/SQL.

  I just wanted to see this in practice, so I made the following test:

  Test case:

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  system altered
  

  So, normally, after execution of the foregoing the shared_pool on my development environment is now empty.

  And then I run the following PL/SQL block

  <<b>>
  declare
      depid hr.employees.department_id%type := 100;
      cnt   pls_integer := 0;
  begin
      select
          count(*)
      into
          b.cnt
      from
          hr.employees t1
      where
          t1.department_id = b.depid;
  end;
  /
  --
  --
  column sql_id new_value sqlid_saved;
  --
  select
      v1.sql_id
  from
      v$sql v1
  where
      v1.sql_text like '%t1.department_id = b.depid%';
  --     
  -- 
  select
      v1.sql_text
  from
      v$sql v1
  where
      v1.sql_id = '&sqlid_saved';
  

  And the result was:

  SQL_ID
  -------------
  687dxvsmrwm9z
  g17tjb3f8t94y

  6 old: v1.sql_id = "& sqlid_saved"
  6 new: v1.sql_id = "g17tjb3f8t94y".

  SQL_TEXT
  --------------------------------------------------------------------------------
  < < b > > declare depid hr.employees.department_id%type: = 100;     CNT pls_in
  SEB: = 0; Start select count (*) in b.cnt of
  T1 hr. Employees where t1.department_id = b.depid; end;

  
  SQL >

  What I don't understand is the main part of the SQL_TEXT I put in red.

  Instead of

  T1.department_id = b.depid

  I expected to see something like

  T1.department_id = : B

  In other words, some bind variable, because depid is a local variable inside my PL/SQL block used in integrated/static SQL statement, so it must be converted to a reserved space in the shared pool instead of the original identifier.

  You kindly could you tell me what I misunderstood?

  Thanks in advance

  > But once again no variable binding in the stored/parsed SQL statement. That's what I don't understand.

  Submitted by PL/SQL SQL is "normalized", which includes (among other things) convert uppercase. Your query on v$ sql is looking for '% hr.employees% '.

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  Ahh, I see what you're missing today.  You have created a new Page, it adds the WebView and set its URL, but you have actually posted this page.  What kind of navigation you are trying to use here?  If you want to display a new page and allow the user to return to the previous, look here: https://developer.blackberry.com/native/documentation/ui/navigation/multiple_screens_stack.html

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  Yes,

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• Value of the session Variable does not get updates.

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  When to use cfoutput after these instruction to check the value of the Session variable, its gives me the initial value of 3. Form.Filter is the value from the drop-down list menu option selected.
  #FORM.filter # #Session.numTasksDisplayed # < cfoutput > < / cfoutput > < cfabort >
  
  Any help is appreciated.
  Thank you and best regards,
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• LabVIEW 2010 local variable behavior

  HI -.

  I upgraded to LabVIEW 2010 of 2009SP1 and the attached sub that VI no longer works correctly.  It is a case of State machine structure that is called inside a loop.  I will put a Boolean variable true local, then on the next appeal when the case changes the variable has been reset to false. He has not done this in LV2009.

  Someone tell me immediately I have a race condition, but these local variables are not be written anywhere else, just in these separate cases.

  See the attached code, specifically, the local variable 'Activate' is to reset during the passage of the 'turn on' case for case "power."

  Anyone else seen elsewhere deliver, or can shed some light?

  I've corrected the VI by writing the value in each case, but this different behavior I wonder what are the other issues lurking in LV2010?

  Thank you

  This code looks more like a kind of a motor of Action that a state machine, but not quite.  It is called several times since a state machine, and he decides who will be the next State according to the entries.  Instead of using all local variables, I would use shift registers not initialized (Nothing cable on the left side).  They hold their value of one call to the other.  A case more will need to be added in this case.  An event of default without a name, which would set the initial values of all the shift registers.  Make the default case and does the same name.  It will be called first automatically because the shift register is not initialized, then the default value will be called.  Inside the default case, set all the shift fits to the desired values.  Next time the Subvi is called, these values will always be there.  As long as nothing is wired on the left side, everything is wired for the shift state register will be the next case called.

  See attached vi.  It's broken because I have this thread not to indicators.

• Structure of the event to local variable

  Hello

  I use a control structure and the table event to detect changes in the value of table.

  At the beginning, I have made changes in the table (for execution) and structure of the detected event.

  The next step was adding a parallel while loop in which I write for the control array (using the local variable).

  During execution the layout of the table changed indeed, but the structure of the event is a not detect it.

  I have attached 2 digits: 1) loop of the structure of the event 2) the parallel loop.

  It is possible works in such a way?

  How can I make the structure of the event to detect changes in the software in the control array?

  Thank you

  Leonid

  Changes made via a local variable are not the user events, so the structure of the event will not detect by definition. You must write to the command by using the property node "Value (follow the signs).

  That said, your small watch of your code starts to raise red flags in my mind with the use of variable and global variable local. While it's not bad, their abuse can lead to the poor programming architecture and race conditions. Perhaps you should consider downloading your VI any kind can someone take a look and offer suggestions on improving it.

• Initialize controls/indicators: invoke node-local variables Vales. Which is faster?

  Hi all

  I would like to get the opinion of the people. This thought just happened for me while I was reading some materials the other day.

  And I have not found any topic which talks specifically about speed after searching the forum.

  It is faster to initialize your controls/indicators using Invoke node OR write directly to the initial value of your local variables?

  From my experience (not large), I have always used the invoke node to initialize controls or indicators.

  But when I but this question, I did a simple reference point and it seems the local variable approach is faster, especially

  If you have the large number of orders/lights to initialize.

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  I thought since you need to set the initial state by default for the node to invoke anyway, why not just write the desired initial value

  your local variables?

  I would appreciate if someone can express his own opinion based on their experience and knowledge.

  Thank you ~ ~

  I may need another Cup of coffee this morning, you are in fact callling the reset by default on each individual control.  My last despises, it is that you use the default method Vals.Reinitialize VI all failing.  It will probably be a bit faster than the method on individual controls.  Still not instant, if.

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• Change local variable boolian Programaticaly

  Hi all

  I came across something today, that I have ever dealt with in Labview...

  I downloaded a driver of instrument for a power supply, and got it working OK (using VISA on the USB communication).

  The example program pilot itself works very well and is a quasi State machine.  It it turns on and off and adjusts the voltage and current correctly, as it should.

  Then I need to edit the .VI to add a time on another timer .VI.  I wrote that the small simple VI and it works properly as it should.

  It's just a boolian power timer.  Lights at 08:00 daily, stops at noon every day.

  The problem I have is the boolian called variable "Output (T:Enable)" which is located in the .VI power supply example is a Panel button, but it is called several times as a local variable.

  (once again, I did not write this part and please no lectures on why you should never use a local variable...)

  When you change the State of the button "Output (T:Enable)" Panel, the power supply turns on and off as it should.

  The problem comes when I try to control this value boolian using my timer VI.  I've tried several things, and using debug, I can't 'Output (T:Enable)"to change state.

  The value will change ONLY if the button is pressed or not.

  ATTENTION: The illustrated local variable condition is also a security in case of short or overload, power off if the name cannot be changed.

  Is there a way I can trigger "Output (T:Enable)" using 'My exit timer' but always make sure that stop you it if there is a short circuit?

  This left me speechless... I tried several different things and just can not understand.  Any help would be appreciated.

  

  Thank you!

  The guy

  Hello guy!

  You are not sure, I understand the problem in its full extent, but I'm guessing that you want to trigger the event that controls the output (T: Enable)? If you want to programmatically, create a node of the control property and use the property "value (follow the signs). Writing of a local variable will not draw the event, although this will change the value of the façade.