Loss of data for the network flow

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• 'the settings saved on this computer for the network do not match the requirements of the network.

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  Hello Arturito1,

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• ' Error' the settings saved on this computer for the network do not match the requirements of the network "while trying to connect to the wireless network

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  Connection Wi - Fi comes with a warning that 'the settings saved on this computer for the network do not match the requirements of the network"what should I do to get a connection?

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• Need to retrieve the data for the current date.

  Hello

  I have a table which then retrieves information when using this command.

  Select ta_acct, shift, created_on track_alerts;

  Technicolor A 24 March 14

  Technicolor A 24 March 14

  Technicolor A 24 March 14

  Technicolor A 24 March 14

  Manitoba telecom a 24 March 14 system

  Technicolor A 24 March 14

  I used this statement to retrieve the data for the given date.

  Select ta_acct, shift, created_on track_alerts where created_on = 24 March 14 ';

  Its not data recovery.

  Need help.

  Kind regards

  Prasad K T,.

  984002170

  Prasad K T wrote:

  Yes the created data type is date.

  CREATED_ON

  DATE

  Partha thanks it works now.

  Select ta_acct, shift, created_on in track_alerts where to move is: Shift and TRUNC (created_on) = TO_DATE('24-MAR-2014','DD-MON-YYYY');

  Still, I made a small change to my querry.

  Select ta_acct, shift, created_on track_alerts where to move is: shft and TRUNC (created_on) = TO_DATE (select double sysdate,'MON-DD-YYYY "");

  For this statement, it does not work.

  of course not...

  first: sysdate returns a date so no need of conversion here

  and

  second SYSDATE includes time, so your application should look like this:

  Select ta_acct, shift, created_on in track_alerts where to move is: Shift and TRUNC (created_on) = trunc (sysdate)

  or

  Select ta_acct, shift, created_on in track_alerts where to move is: shft and created_on > = trunc (sysdate) and created_on<>

  HTH

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• How to get the date for the first Monday of each month

  Dear members,
  
  How to get the date for the first Monday of each month.
  
  I wrote the following code
  
  SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL
  
  But he looks at complex bith.
  
  Abhishek
  
  Published by: 9999999 on 8 March 2013 04:30

  Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

  select  sysdate current_date,
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    from  dual
  /
  
  CURRENT_D FIRST_MON
  --------- ---------
  08-MAR-13 04-MAR-13
  
  SQL> 
  

  Here is the list of the first Monday of the month of this year:

  with t as(
            select  add_months(date '2013-1-1',level-1) dt
              from  dual
              connect by level <= 12
           )
  select  dt first_of_the_month,
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    from  t
  /
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-JAN-13 07-JAN-13
  01-FEB-13 04-FEB-13
  01-MAR-13 04-MAR-13
  01-APR-13 01-APR-13
  01-MAY-13 06-MAY-13
  01-JUN-13 03-JUN-13
  01-JUL-13 01-JUL-13
  01-AUG-13 05-AUG-13
  01-SEP-13 02-SEP-13
  01-OCT-13 07-OCT-13
  01-NOV-13 04-NOV-13
  
  FIRST_OF_ FIRST_MON
  --------- ---------
  01-DEC-13 02-DEC-13
  
  12 rows selected.
  
  SQL> 
  

  SY.