maximum value without a group of
I have data such as that below, but can't seem to get the maximum value of a line.ID SCORE STATUS ATTRNO
12 989 17 ACTIVE
12 122 17 INACTIVE
33 17 ACTIVE 1099
I want to be able to get out:
33 17 ACTIVE 1099
I'm not 'group by', because it returns all rows. Any guidance would be greatly appreciated.
Thank you!
What is information of primary key for this table?
Maybe you can go for this->
select *
fromm table1
where ID = (
select max(ID)
from table1
);
N.B.: Not tested...
Kind regards.
LOULOU.
Tags: Database
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:) JohnThis sounds like a job for and analytic function. Something like:
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2. the Group
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Kindly let me know if possible.
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Needing a maximum date using the group value of
I need a join_date of date value maximum for each Department. If max (join_date) has two records for each dept max (end_date) are to be considered. I used a select queryCreate table student (dept number(10), dep_name varchar2(10),join_date date,years_attended number(10),end_date date); insert into student values (1,'I',to_date('3/7/1917','MM/DD/YYYY'),4,to_date('8/26/1987','MM/DD/YYYY')); insert into student values (1,'I',to_date('1/1/1900','MM/DD/YYYY'),4,to_date('8/26/1932','MM/DD/YYYY')); insert into student values (1,'D',to_date('1/1/1920','MM/DD/YYYY'),5,to_date('8/26/1994','MM/DD/YYYY')); insert into student values (1,'C',to_date('1/1/1920','MM/DD/YYYY'),6,to_date('8/26/1945','MM/DD/YYYY')); insert into student values (2,'I',to_date('7/1/1900','MM/DD/YYYY'),3,to_date('8/26/1932','MM/DD/YYYY')); insert into student values (2,'I',to_date('8/16/1916','MM/DD/YYYY'),9,to_date('8/26/1923','MM/DD/YYYY')); insert into student values (2,'D',to_date('8/16/1916','MM/DD/YYYY'),10,to_date('8/26/1987','MM/DD/YYYY')); insert into student values (3,'I',to_date('3/7/1917','MM/DD/YYYY'),4,to_date('8/26/1987','MM/DD/YYYY')); insert into student values (3,'D',to_date('7/28/1920','MM/DD/YYYY'),6,to_date('8/26/1945','MM/DD/YYYY')); insert into student values (3,'I',to_date('7/28/1920','MM/DD/YYYY'),8,to_date('8/26/1965','MM/DD/YYYY')); insert into student values (4,'I',to_date('12/31/1924','MM/DD/YYYY'),2,to_date('8/26/1998','MM/DD/YYYY')); insert into student values (4,'I',to_date('6/10/1929','MM/DD/YYYY'),1,to_date('8/26/1943','MM/DD/YYYY')); insert into student values (4,'C',to_date('1/17/1927','MM/DD/YYYY'),4,to_date('8/26/1955','MM/DD/YYYY')); insert into student values (4,'C',to_date('6/10/1929','MM/DD/YYYY'),30,to_date('8/26/1967','MM/DD/YYYY')); insert into student values (5,'D',to_date('2/10/1931','MM/DD/YYYY'),2,to_date('8/26/1943','MM/DD/YYYY')); insert into student values (5,'I',to_date('2/10/1931','MM/DD/YYYY'),24,to_date('8/26/1962','MM/DD/YYYY')); commit;
gives me the following resultselect * from student where join_date in (select max(join_date) from student group by dept);
But I'm looking for the result that gives me only a maximum value for each column dept. First of all, it should look like to a maximum value of join_date, so two records even join_date max (end_date) are to be considered. The result should be sumthing like this1 D 1/1/1920 5 8/26/1994 1 C 1/1/1920 6 8/26/1945 2 I 8/16/1916 9 8/26/1923 2 D 8/16/1916 10 8/26/1987 3 D 7/28/1920 6 8/26/1945 3 I 7/28/1920 8 8/26/1965 4 I 6/10/1929 1 8/26/1943 4 C 6/10/1929 30 8/26/1967 5 D 2/10/1931 2 8/26/1943 5 I 2/10/1931 24 8/26/1962
Can you please tell me how to rewrite the select query for results above.1 D 1/1/1920 5 8/26/1994 2 D 8/16/1916 10 8/26/1987 3 I 7/28/1920 8 8/26/1965 4 C 6/10/1929 30 8/26/1967 5 I 2/10/1931 24 8/26/1962
Published by: user11872870 on August 2, 2011 17:29
Published by: user11872870 on August 2, 2011 17:36Hello
This is called a Query Top - N , and this is a way to do it:
WITH got_r_num AS ( SELECT student.* , ROW_NUMBER () OVER ( PARTITION BY dept ORDER BY join_date DESC , end_date DESC ) AS r_num FROM student ) SELECT dept, dep_name, join_date, years_attended, end_date FROM got_r_num WHERE r_num = 1 ORDER BY dept ;
Another way is similar to what you posted:
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I suspect that the first way (using ROW_NUMBER) will be faster.
In addition, the ROW_NUMBER approach is guaranteed to return only 1 line by Department using the approach of GROUP BY, if there is a link on join_date and end_date then it will return all the contenders in this Department. using ROW_NUMBER, it is easy to add expressions to tie-break as much as you want, and, if there is still a tie, it will be arbirarily pick, one lines involved in the tie as #1.Thanks for posting the CREATE TABLE and INSERT! It is very useful.
Published by: Frank Kulash, August 2, 2011 21:00
Added GROUP BY alternative -
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