SQL select max value in a group

Similar Questions

• If you select max value using over()

  Hi, I am unable to choose the query below max rated
  could you please help me in this
  

  with T as 
  (select 100001 ID , 'SLNG' RATING ,  'AA-' RAT_SYBL , 1 TYPE  FROM DUAL UNION ALL
  SELECT 100001   , 'SLNG'   ,  'AA--'  ,   2    FROM DUAL 
  )
  SELECT ID,RATING,CASE WHEN (RATING='SLNG')
                                           THEN  MAX(RAT_SYBL) OVER (PARTITION BY ID)
                                           ELSE NULL
                                           END AS SEL_RATING ,TYPE
   FROM T 

  I have the 2 lines of the above, but I don't need that single line to display
  Thank you

  I don't need that single line to display

  Maybe:

  SQL> with t as (
    select 100001 id, 'SLNG' rating, 'AA-' rat_sybl, 1 type from dual union all
           select 100001, 'SLNG', 'AA--', 2 from dual
  )
  --
  --
  select id, rating, sel_rating, type
    from (select id,
                 rating,
                 rat_sybl,
                 case when (rating = 'SLNG') then max (rat_sybl) over (partition by id) else null end as sel_rating,
                 type
            from t)
   where rat_sybl = sel_rating
  /
          ID RATING SEL_RATING       TYPE
  ---------- ------ ---------- ----------
      100001 SLNG   AA--                2
  1 row selected.
  

  ?

• Need to get Max Value day in a table with hourly data of SQL

  I have a table "tmp" with these columns:
  
  ID, date, time, value
  
  I want to get the 'time' when 'value' max is reached in each 'day '.
  
  the query:
  
  "SELECT id, day, hour, max (value) from group tmp by id, date, time"
  does not return the desired lines.
  
  You have an idea to get what I want?

  Maybe this:

  with tmp as
  ( select 1 id, trunc(sysdate) day, 10 hour, 100 value from dual union all
    select 2 id, trunc(sysdate) day, 11 hour, 110 value from dual union all
    select 3 id, trunc(sysdate) day, 12 hour, 120 value from dual union all
    select 4 id, trunc(sysdate) day, 13 hour, 130 value from dual union all
    select 5 id, trunc(sysdate-1) day, 10 hour, 100 value from dual union all
    select 6 id, trunc(sysdate-1) day, 11 hour, 90 value from dual union all
    select 7 id, trunc(sysdate-1) day, 12 hour, 150 value from dual union all
    select 8 id, trunc(sysdate-1) day, 13 hour, 100 value from dual )
  Select ID, Day, Hour, Value
  From Tmp
  Where (Day, Value) IN (
  Select Day, Max(Value)
  From Tmp
  Group by Day)
  

  Results:

          ID DAY             HOUR      VALUE
  ---------- --------- ---------- ----------
           7 08-DEC-08         12        150
           4 09-DEC-08         13        130
  
  2 rows selected.
  

  Kind regards
  Miguel

• Get the max value with other areas

  Hi all
  
  I have a table as below
  
  Value name
  - - - - - - - - - - - - - - - -
  A1 5
  A3 10
  A2 7
  A2 9
  A1 10
  
  What I get is the max (Value) and with the consolidation of its name
  
  Value name
  - - - - - - - - -
  A2 16
  
  Thank you
  Alex
  
  Published by: user8606416 on June 1, 2011 10:17
  
  Published by: user8606416 on June 1, 2011 10:26

  Depends on how you feel on one of the links of:

  SELECT name, value
  FROM (SELECT name, SUM(value)
        FROM table
        GROUP BY name
        ORDER BY 2 DESC)
  WHERE rownum = 1
  
  SELECT name, SUM(value)
  FROM table
  GROUP BY name
  HAVING SUM(value) >= ALL (SELECT SUM(value)
                            FROM table
                            GROUP BY name)
  

  among many other methods. The first takes a single arbitrary registration in the case of a tie, and the second shows all the related records.

  John

• Need to get the latest news for a group-max (value) of the non-null values

  Hello
  
  Here is my table and data
  
  SQL > desc method
  
  NUMBER OF SEQ_ID
  EMP_ID NUMBER
  ISSUE GUID
  FIRST NAME VARCHAR2 (30)
  LAST_NAME VARCHAR2 (30)
  E-MAIL VARCHAR2 (45)
  PHONENO VARCHAR2 (30)
  
  SQL > Select * method;
  
  SEQ_ID EMP_ID GUID FIRST_NAME LAST_NAME EMAIL PHONENO
  ------ - ----- ---- --------- --------------------------------------------------- ----------------------------------------- ------------------------------
  1 100 20 RAJA HHH 686678
  2 100 20 [email protected]
  3 100 20 RAJA 134555
  4 100 20 HAPPY [email protected]
  5 200 20 RAM
  6 200 20 JJJ 2345667
  7 200 20 RM GGG [email protected] 1234557
  8 200 20 [email protected] RRR
  
  8 selected lines
  
  
  I want the latest news on the employee, the group id comibnation for the rest of the columns.
  
  So I want to get the following result.
  
  100 20 RAVI HHH [email protected] 134555
  
  200 20 RRR GGG [email protected] 1234557
  
  
  If you note here for the family name, we take the previous value non-zero value Eg HHH column and is the same for all columns.
  
  It's the value of line max (seqid) for empid, combination of guid and if the column values are null, we must get the previous maximum value non-zero.
  
  The seqid is also there that the sequence.
  
  Please help me to get the result set.
  
  Thanks in advance.
  
  mjhraja.

  SQL> select emp_id, guid, max(first_name) first_name, max(last_name) last_name
    2    , max(email) email, max(phoneno) phoneno
    3  from (
    4    select emp_id, guid
    5      , first_value (first_name ignore nulls)
    6          over (partition by emp_id, guid order by seq_id desc) first_name
    7      , first_value (last_name ignore nulls)
    8          over (partition by emp_id, guid order by seq_id desc) last_name
    9      , first_value (email ignore nulls)
   10          over (partition by emp_id, guid order by seq_id desc) email
   11      , first_value (phoneno ignore nulls)
   12          over (partition by emp_id, guid order by seq_id desc) phoneno
   13    from emp_info
   14  )
   15  group by emp_id, guid
   16  /
  
      EMP_ID GUID FIRST_NAME LAST_NAME  EMAIL                PHONENO
  ---------- ---- ---------- ---------- -------------------- ----------
         100   20 RAVI       HHH        [email protected]         134555
         200   20 RRR        GGG        [email protected]       1234557
  
  SQL> 
  

• SQL, find the MAX value and placing it as a QVariant

  I have a database that is loaded and defines the customerID as 0 which is ideal when the database is not be saved and restored, etc.  The question I have is that I added the possibility to users to restore a backup in the app, and now I have to do a query to select MAX (customerID) so that there is no duplicate CustomerID when you add or save items.  Here is the following code, I knew that I must settle, specifically the 0 highlighted in red.  I need zero to be the new customerID max value:

  int SettingsStorage::load(int& lastID, GroupDataModel *model)
  {
      // number of locations loaded.
      QSettings settings(m_author, m_appName);
      int loadedCount = 0;
  
      QVariant items;
      // Get the last customer id first.
      // ID's will be generated by incrementing this number
      // Note values coming from settings should be cast to the
      // required type.
       lastID = settings.value(m_lastCustomerIDKey, 0).toInt();
      items = m_sda->execute("SELECT * from items ORDER BY datefield");
      qDebug()<< "the ID" << items;
      // Load all the locations from the database.
      foreach( const QVariant& temp, items.value() ) {
          Location *p;
          if (loadLocation(temp.value(), p)) {
              model->insert(p);
              loadedCount++;
          }
      }
      return loadedCount;
  }
  

  Ive tried the following, but it doesn't seem to do anything:

  int SettingsStorage::load(int& lastID, GroupDataModel *model)
  {
      // number of locations loaded.
      QSettings settings(m_author, m_appName);
      int loadedCount = 0;
  
      QVariant items;
      // Get the last customer id first.
      // ID's will be generated by incrementing this number
      // Note values coming from settings should be cast to the
      // required type.
       QVariant endID = m_sda->execute("Select MAX(customerID) from items")
       lastID = settings.value(m_lastCustomerIDKey, endID).toInt();
      items = m_sda->execute("SELECT * from items ORDER BY datefield");
      qDebug()<< "the ID" << items;
      // Load all the locations from the database.
      foreach( const QVariant& temp, items.value() ) {
          Location *p;
          if (loadLocation(temp.value(), p)) {
              model->insert(p);
              loadedCount++;
          }
      }
      return loadedCount;
  }
  

  Any help will be loved and marked solutions.

  -Thanks in advance

  I was wrong about executeAndWait(). Somehow, I decided that you use the SqlConnection object, but seems his SqlDataAccess. So disregard my previous post. Keep your execute method, but you must change your code to something like this:

  QVariant endID = m_sda->execute("select max(customerID) as m from items");
  
  QVariantList vlist = endID.value();
  QVariantMap vmap = vlist.first().toMap();
  
  lastID = vmap["m"].toInt(&ok);
  

  So I changed your SQL query slightly and added "that m" so I will have something to refer later.

  Then I cast QVariantList because it is where are the results.

  Then because we know its going to be the only record, I took the 1st element in the list and converted to QVariantMap.

  Last step is to get the maximum.

  Should work this time

• select statement nested within the group to get the owner of max

  Hello
  
  I have a table with columns ID, PAGE_NUM, MOD_DATE, USER_ID, etc..
  
  I want a single query which groups recorded by PAGE_NUM and return lines as follows:
  
  PAGE_NUM, count (PAGE_NUM), max (MOD_DATE) and USER_ID associated with max (MOD_DATE).
  
  I can make three 1, but do not know how to get the USER_ID associated with max (MOD_DATE) in a query. Maybe its faster when even make 2 requests?
  
  Andy

  Hello

  user9990110 wrote:
  Hello

  I use Oracle + Hibernate. Hibernation uses HQL which is the most common subset of sql. Then she runs through a parser to convert in SQL for Oracle. I think that this request should be friendly HQL, and I go search if the LAST is supported or not. Otherwise, it must be a scalar subquery, and that's what I was trying to figure out how to do when I posted. I didn't know that there is a faster way without the subquery. In addition, Hibernate has a native SQL mode too, but I found that it works the native sql through his monitor too, and if she doesn't like him for some reason, it throws an exception. So I'm not sure LAST will work for me, and I know that don't TopN.

  All this sounds like a good reason to use a view. Hibernation will think that you simply reference another table.

  So if you could show me the scalar subquery..., I know working with Hibernate.

  Here is how to do this with a scalar subquery:

  SELECT       page_num
  ,       COUNT (page_num)     AS cnt
  ,       MAX (mod_date)     AS last_mod_date
  ,       (   SELECT  MIN (user_id)
             FROM    table_x     s
             WHERE   page_num     = x.page_num
             AND     mod_date     = ( SELECT  MAX (mod_date)
                                      FROM    table_x
                          WHERE   page_num     = s.page_num
                        )
         )                        AS last_mod_user_id
  FROM       table_x     x
  GROUP BY  page_num
  ;
  

  Furthermore, what does DENSE_RANK?

  Nothing of what I know. It is a mandatory keyword that should be used with the FIRST and LAST. (It is not identical to the analytical DENSE_RANK function.)

  Is it possible to write your original with LAST request but without dense_rank?

  N °

• Select the MAX value

  My goal here is to select the id of the half of the class more recently taken for a given student. Are the session id in the format (1, yy, 2/5/7 - spring, and autumn)-, 2004 summer semester would be 1045. A half of 1095 ID would be newer than that of 1042.
  
  I wrote the following, but it doesn't quite know how I want it. He returned several lines where ideally he doesn't return a single line. I tried to limit 1 and some other things around him, but I always get an error whenever I try to run that. I also tried to add ' where rowcount < 2 "but this 1045 statements, not 1095. I think it gets the number of rows before it does the calculation of MAX.
  
  Any ideas?
  

  select MAX(grades.semester_id)
  from grades
  join requirements
  on (grades.COURSE_ID=requirements.COURSE_ID)
  where requirements.CERT_ID = '1'
  and student_id = '0000006'
  group by grades.course_id

  Hello

  Try this:

  SELECT grades.semester_id
    FROM grades
    JOIN requirements ON (grades.COURSE_ID = requirements.COURSE_ID)
   WHERE requirements.CERT_ID = '1'
     AND student_id = '0000006'
     AND rownum <= 1
   ORDER BY grades.semester_id DESC
  

  Kind regards

• Select max (length) - how to display the length of a group MAX

  Hello
  
  I have a table with the name of DVD and names of files on the DVD.
  I would like to know how to change this query to get another column, MAX_LENGHT, the MAXIMUM length of the name of FILE to a DVD of return
  This doesn't work request

  select DVD, FILENAME, (SELECT max(length(FILENAME)) / 2 + 4 FROM TABLE) AS MAX_LENGHT from TABLE

  DESIRED RESULT
  

  DVD    FILENAME     MAX LENGHT
  DVD1     Alina     8
  DVD1     Aidan     8
  DVD1     Aiden     8
  DVD1     Akira     8
  DVD1     Alex     8
  DVD1     Alyssa     8
  DVD1     Arianna     8
  DVD1     Ashley     8
  DVD1     Ava     8
  DVD1     Benjamin8
  DVD1     Bianca     8
  DVD1     Blake     8
  DVD1     Brandon     8
  DVD1     Brayden     8
  DVD1     Brayden     8
  DVD1     Brianna     8
  DVD1     Brielle     8
  DVD1     Brooklyn8
  DVD2     Dakota     11
  DVD2     Dalia     11
  DVD2     Daniel     11
  DVD2     Dante     11
  DVD2     David     11
  DVD2     Diego     11
  DVD2     Dingbang11
  DVD2     Dominic     11
  DVD2     Dylan     11
  DVD2     Chase     11
  DVD2     Chloe     11
  DVD2     Christopher     11
  DVD2     Claire     11
  DVD2     Cole     11
  DVD2     Connor     11

  Thank you
  
  Roseline

  You can use the analytic version of the function max:

  SELECT  DVD
  ,       FILENAME
  ,       MAX(LENGTH(FILENAME)) OVER (PARTITION BY DVD) AS MAX_LENGTH
  FROM    TABLE
  

• Update based on the max value of different tables.

  {code}

  create the table rule_table (number rule_id);

  insert into rule_table values (10);

  insert into rule_table values (20);

  insert into rule_table values (30);

  insert into rule_table values (40);

  create the table auth_table (number of auth_id, rule_id number);

  insert into auth_table values (1000, 10);

  insert into auth_table values (2000, 10);

  insert into auth_table values (3000, 10);

  insert into auth_table values (4000, 20);

  insert into auth_table values (5000, 20);

  insert into auth_table values (6000, 30);

  insert into auth_table values (7000, 30);

  insert into auth_table values (8000, 40);

  insert into auth_table values (9000, 40);

  create the table pay_table (pay_id number, auth_id number, pay_indicator number);

  insert into pay_table values (11111, 1000, 0);

  insert into pay_table values (22222, 1000, 1);

  insert into pay_table values (33333, 1000, 0);

  insert into pay_table values (44444, 2000, 0);

  insert into pay_table values (55555, 2000, 1).

  insert into pay_table values (66666, 2000, 0);

  insert into pay_table values (77777, 3000, 0);

  insert into pay_table values (88888, 3000, 0);

  insert into pay_table values (99999, 4000, 0);

  insert into pay_table values (111111, 4000, 0);

  insert into pay_table values (222222, 5000, 0);

  insert into pay_table values (333333, 5000, 0);

  insert into pay_table values (444444, 6000, 0);

  insert into pay_table values (555555, 7000, 1);

  insert into pay_table values (666666, 8000, 0);

  insert into pay_table values (777777, 9000, 0);

  insert into pay_table values (888888, 9000, 1);

  create the table rule_pay (rule_id number, pay_max_indicator number);

  insert into rule_pay values (10, 0);

  insert into rule_pay (20, 0) values;

  insert into rule_pay (30, 0) values;

  insert into rule_pay (40, 0) values;

  {code}

  My intention is:

  for every find of rule_id on the maximum pay_indicator (tables 3 query to get the max Show pay_indicator below) and on the other table I have to update this value max based on rule_id.

  with max_tab

  as

  (

  Select a.rule_id, max (pay_indicator) pay_indicator

  rule_table a.,

  b auth_table,

  c pay_table

  where a.rule_id = b.rule_id

  and b.auth_id = c.auth_id

  A.rule_id group

  )

  Update rule_pay

  Set pay_max_indicator = (select max_tab.pay_indicator

  of max_tab

  where max_tab.rule_id = rule_pay.rule_id)

  where

  rule_id in (select rule_id from max_tab);

  The above query does not.

  Any help or suggestions are greatly appreciated.

  Something like that?

  SQL > select * from rule_pay;

  RULE_ID PAY_MAX_INDICATOR

  -------------------- --------------------

  10                    0

  20                    0

  30                    0

  40                    0

  SQL > fusion in rule_pay PR

  2. using (select a.rule_id, max (pay_indicator) pay_indicator

  rule_table 3A,

  auth_table 4 b,

  pay_table 5 c

  6 where a.rule_id = b.rule_id

  7 and b.auth_id = c.auth_id

  Group 8 by a.rule_id

  9        ) u

  10 on (u.rule_id = rp.rule_id)

  11 when matched, then update

  12 set rp.pay_max_indicator = u.pay_indicator

  13;

  4 lines merged.

  SQL > select * from rule_pay;

  RULE_ID PAY_MAX_INDICATOR

  -------------------- --------------------

  10                    1

  20                    0

  30                    1

  40                    1

  BTW, you can't put a WITH clause before an update.  It can only precede a select statement.

• mark the first value of a group

  I get the following
  

  16:57:28 >r
    1  with my_table as
    2       (
    3      select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    4      select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    5      select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
    6      select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    7      select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    8      select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    9      select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
   10      select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
   11      select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   12      select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   13      select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   14      select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   15      select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   16      select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   17      select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
   18  select case when pera = 'M012013' then '*' end mark,
   19         pera, snr, pnr, name, f_name
   20  from (
   21        select pera, snr, pnr, name, f_name,
   22               max(case when pera = 'M012013' then 'Y' end)
   23                 over(partition by upper(name||f_name)) m_flag,
   24               count(*) over(partition by upper(name||f_name)) cnt
   25        from my_table
   26       )
   27  where m_flag = 'Y'
   28  and cnt > 1
   29* order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc
  
  MARK  PERA           SNR        PNR NAME   F_NAME
  ----- ------- ---------- ---------- ------ ------
  *     M012013   10674834         15 Tester Toni
  *     M012013   10674833         15 Tester Toni
        M092012   15965177         15 Tester Toni
  *     M012013   22345789         50 Meier  Otto
  *     M012013   12345678         50 Meier  Otto
        M082012   10584352         50 Meier  Otto

  I would like to mark only the first value in the group with an asterisk as follows.
  

  MARK  PERA           SNR        PNR NAME   F_NAME
  ----- ------- ---------- ---------- ------ ------
  *     M012013   10674834         15 Tester Toni
        M012013   10674833         15 Tester Toni
        M092012   15965177         15 Tester Toni
  *     M012013   22345789         50 Meier  Otto
        M012013   12345678         50 Meier  Otto
        M082012   10584352         50 Meier  Otto

  Perhaps this example might be useful for you. the code uses the same code that you published with additional analytical query to return the row grouping for the name, the NRP and columns pera. then use that line number to determine which will be placed at the first mark.

  SQL>   with my_table as
    2         (
    3        select 'M082012' pera, to_number(10584338) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    4        select 'M092012' pera, to_number(15965177) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    5        select 'M082012' pera, to_number(14254501) snr, to_number(20) pnr, 'Wallen' name, 'Monika' f_name from dual union all
    6        select 'M082012' pera, to_number(10584339) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    7        select 'M092012' pera, to_number(15965178) snr, to_number(10) pnr, 'Beule' name, 'Anna' f_name from dual union all
    8        select 'M012013' pera, to_number(10674833) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
    9        select 'M012013' pera, to_number(10674834) snr, to_number(15) pnr, 'Tester' name, 'Toni' f_name from dual union all
   10        select 'M012013' pera, to_number(10539210) snr, to_number(30) pnr, 'Klose' name, 'Werner' f_name from dual union all
   11        select 'M012013' pera, to_number(12345678) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   12        select 'M012013' pera, to_number(22345789) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   13        select 'M082012' pera, to_number(10584346) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   14        select 'M062012' pera, to_number(10550971) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   15        select 'M092012' pera, to_number(15965185) snr, to_number(77) pnr, 'Carl' name, 'Frank' f_name from dual union all
   16        select 'M082012' pera, to_number(10584352) snr, to_number(50) pnr, 'Meier' name, 'Otto' f_name from dual union all
   17        select 'M092012' pera, to_number(15965191) snr, to_number(80) pnr, 'Duster' name, 'Hucke' f_name from dual)
   18    select case when pera = 'M012013' and rn = 1 then '*' end mark,
   19           pera,
   20           snr,
   21           pnr,
   22           name,
   23           f_name
   24      from (select pera, snr, pnr, name, f_name,
   25                   row_number() over (partition by pera, pnr, name, f_name order by pera, pnr, name) rn
   26              from (select pera, snr, pnr, name, f_name,
   27                           max(case when pera = 'M012013' then 'Y' end)
   28                           over(partition by upper(name||f_name)) m_flag,
   29                           count(*) over(partition by upper(name||f_name)) cnt
   30                      from my_table)
   31                     where m_flag = 'Y'
   32                       and cnt > 1
   33             order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc)
   34    order by 4,5,6, to_number(substr(pera,4,4)||substr(pera,2,2)) desc;
  
  MARK PERA           SNR        PNR NAME   F_NAME
  ---- ------- ---------- ---------- ------ ------
  *    M012013   10674834         15 Tester Toni
       M012013   10674833         15 Tester Toni
       M092012   15965177         15 Tester Toni
  *    M012013   22345789         50 Meier  Otto
       M012013   12345678         50 Meier  Otto
       M082012   10584352         50 Meier  Otto
  
  6 rows selected
  
  SQL> 
  

• Subquery scalar to select max

  Hi all
  
  Oracle Version
  11.2.0.1.0
  
  
  I need to write a query update one table based on the following criteria:
  

  create table trades (tid number, descp varchar2(20));
  
  create table trade_descp (tid number, aud_desc varchar2(20), c_date date)
  
  
  insert into trades
  values
  (1,NULL)
  
  insert into trades
  values
  (3,NULL)
  
  insert into trades
  values
  (4,NULL)
  
  insert into trade_descp values
  (1,'abdc(M)','1-Jan-2012')
  
  insert into trade_descp values
  (1,'abdc(M)','1-Jan-2013')
  
  insert into trade_descp values
  (1,'abdc(N)','1-Jan-2014')

  The output I need is to update the table of trades with a description with the maximum date of trade_descp table based on a filter for example descp like "%M %.
  There is an index on the column tid trade_descp table (with huge files).
  
  Can this be achieved in direct SQL.
  
  
  Thank you and best regards,
  Nik

  Nikhil Juneja wrote:
  but that is a full table of trade_descp table scan. Can we make us of the index built on the TID column?

  SQL> merge
    2    into trades a
    3    using (
    4           select  tid,
    5                   max(aud_desc) keep(dense_rank last order by c_date) descp
    6             from  trade_descp
    7             where aud_desc like '%M%'
    8             group by tid
    9          ) b
   10      on (
   11          b.tid = a.tid
   12         )
   13    when matched
   14      then update
   15              set a.descp = b.descp
   16  /
  
  1 row merged.
  
  SQL> select  *
    2    from  trades
    3  /
  
         TID DESCP
  ---------- --------------------
           1 abdc(M)
           3
           4
  
  SQL> explain plan for
    2  merge
    3    into trades a
    4    using (
    5           select  tid,
    6                   max(aud_desc) keep(dense_rank last order by c_date) descp
    7             from  trade_descp
    8             where aud_desc like '%M%'
    9             group by tid
   10          ) b
   11      on (
   12          b.tid = a.tid
   13         )
   14    when matched
   15      then update
   16              set a.descp = b.descp
   17  /
  
  Explained.
  
  SQL> @?\rdbms\admin\utlxpls
  
  PLAN_TABLE_OUTPUT
  -----------------------------------------------------------------------------------------------------------------------------
  Plan hash value: 1775522890
  
  ----------------------------------------------------------------------------------------------------
  | Id  | Operation                       | Name             | Rows  | Bytes | Cost (%CPU)| Time     |
  ----------------------------------------------------------------------------------------------------
  |   0 | MERGE STATEMENT                 |                  |     2 |    48 |     5  (20)| 00:00:01 |
  |   1 |  MERGE                          | TRADES           |       |       |            |          |
  |   2 |   VIEW                          |                  |       |       |            |          |
  |   3 |    SORT GROUP BY                |                  |     2 |   142 |     5  (20)| 00:00:01 |
  |   4 |     NESTED LOOPS                |                  |       |       |            |          |
  |   5 |      NESTED LOOPS               |                  |     2 |   142 |     4   (0)| 00:00:01 |
  |   6 |       TABLE ACCESS FULL         | TRADES           |     3 |   111 |     3   (0)| 00:00:01 |
  |*  7 |       INDEX RANGE SCAN          | TRADE_DESCP_IDX1 |     3 |       |     0   (0)| 00:00:01 |
  |*  8 |      TABLE ACCESS BY INDEX ROWID| TRADE_DESCP      |     1 |    34 |     1   (0)| 00:00:01 |
  ----------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     7 - access("TID"="A"."TID")
     8 - filter("AUD_DESC" IS NOT NULL AND "AUD_DESC" LIKE '%M%')
  
  Note
  -----
     - dynamic sampling used for this statement (level=2)
  
  25 rows selected.
  
  SQL> 
  

  SY.

• Select max in a specific range only?

  Hello experts and pros of sql!
  
  I guess that I need your help on a problem I've been struggling with for hours now.
  
  I have the following query, which, in the final version will be written in the pl/sql code:
  

  SELECT
       CNT_GEBIET,
       CNT_GEBIET DISPLAY,
       CNT_GEBIET BUTTON,
       STR_NAME,
       decode(STR_ART_GEBIETE,'Vogelschutz','SPA','FFH','FFH','FFH und Vogelschutz','FFH & SPA') STR_ART_GEBIETE,
       STR_REG_KART_TEAMS,
       STR_BESCHREIBUNG,
       BOOL_ANZEIGEN,
       STR_FEDERFUEHRENDE,
       K.INT_VERFAHREN,
       STR_VERFAHREN,
       D.ST_BIOGEO,
       D.STR_GEBIET,
       E.STR_BIOGEO,
       E.INT_BIOGEO,
  case when to_char(min(L.DATE_GP_RT_END), 'YYYY') < to_char(sysdate, 'YYYY')  then 'red'
  else 'green' end as mxcolour,
  case when to_char(min(L.DATE_R_AT_END), 'YYYY') <= to_char(sysdate, 'YYYY') then 'green'
  when to_char(min(L.DATE_R_V_END), 'YYYY') > to_char(min(L.DATE_GP_V_END), 'YYYY') then 'red'
  else 'black' end as mxcolour_r_date,
     to_char(min(L.DATE_GP_AT_START), 'YYYY')  DATE_GP_AT_START,
     to_char(min(L.DATE_R_AT_END), 'YYYY')  DATE_R_AT_END,
     to_char(min(L.DATE_GP_V_START), 'YYYY')  DATE_GP_V_START,
     to_char(min(L.DATE_R_V_END), 'YYYY')  DATE_R_V_END,
     to_char(min(L.DATE_GP_RT_START), 'YYYY')  DATE_GP_RT_START,
     to_char(min(L.DATE_R_RT_END), 'YYYY')  DATE_R_RT_END,
     I.GEB,
     I.STR_REGBEZE,
     H.ALF,
     I.LNG_REG_KART_TEAMS,
  
     MAX(NVL(M.LNG_ARBEITSSCHRITT,21)) LNG_ARBEITSSCHRITT
  
  FROM VT_TBL_ARBEIT_ZU_GEBIET M
  RIGHT OUTER JOIN (
    VT_TBL_GEBIET K
    INNER JOIN VT_TBL_ART_GEBIETE B ON B.CNT_ART_GEBIETE = K.INT_ART_GEBIET
    INNER JOIN VT_TBL_FEDERFUEHRENDE C ON C.CNT_FEDERFUEHRENDE = K.LNG_FEDER
    INNER JOIN VT_TBL_GEBIET_ZU_BIOGEO D ON D.STR_GEBIET = K.CNT_GEBIET
    INNER JOIN VT_TBL_BIOGEO E ON D.ST_BIOGEO = E.INT_BIOGEO
    INNER JOIN VT_TBL_VERFAHREN F ON F.CNT_VERFAHREN = K.INT_VERFAHREN
    INNER JOIN VT_TBL_REG_KART_TEAMS G ON G.CNT_REG_KART_TEAMS = K.INT_REG_KART_TEAMS
    INNER JOIN VT_TBL_GEBIET_ZU_ALF H ON H.GEBIET = K.CNT_GEBIET
    INNER JOIN TBL_REGBEZE I ON I.GEB = K.CNT_GEBIET
        AND I.LNG_REG_KART_TEAMS = G.CNT_REG_KART_TEAMS
  ) ON M.LNG_GEBIET = K.CNT_GEBIET
  LEFT OUTER JOIN TBL_ARBEITSSCHRITTE_NEU A
    ON M.LNG_ARBEITSSCHRITT = A.CNT_ARBEITSSCHRITT
  left outer join vt_tbl_arbeit_crit_date l on l.lng_gebiet = k.cnt_gebiet
     where k.cnt_gebiet not like '%Test%' and nvl(m.lng_arbeitsschritt,21) not in (1,4,13,23,28,31,45,54,60,66,73,78) and nvl(l.lng_arbeitsschritt,1) = 1
  GROUP BY
      CNT_GEBIET,
      STR_NAME,
      STR_ART_GEBIETE,
      STR_REG_KART_TEAMS,
      LNG_REG_KART_TEAMS,
      H.ALF,
      STR_BESCHREIBUNG,
      BOOL_ANZEIGEN,
      STR_FEDERFUEHRENDE,
      D.ST_BIOGEO,
      D.STR_GEBIET,
      E.STR_BIOGEO,
      E.INT_BIOGEO,
      F.STR_VERFAHREN,
      K.INT_VERFAHREN,
      I.GEB,
      I.STR_REGBEZE,
      L.DATE_GP_AT_START,
      L.DATE_R_AT_END,
      L.DATE_GP_V_START,
      L.DATE_R_V_END,
      L.DATE_GP_RT_START,
      L.DATE_R_RT_END

  My problem is that I want to select MAX (M.LNG_ARBEITSSCHRITT) while the max value is supposed to be limited to a specific range.
  
  Indeed, the 1,4,13,23,28,31,45,46,54,60,66,73,78 values should not take into account.
  
  Can you please show me how to specify a range of values that can be used for the calculation of the max (m.lng_arbeitsschritt)?
  
  I appreciate your help and your entry!
  
  Thank you to have a look at this post!
  
  Kind regards
  
  SEB

  Try:

  max(case when M.LNG_ARBEITSSCHRITT not in (1,4,13,23,28,31,45,46,54,60,66,73,78) then M.LNG_ARBEITSSCHRITT end)
  

• Max value return value despite where clause is not not really looking for the reason

  Hello

  Using oracle 11.2.0.3

  Select 'A '.

  of the double

  where 1 = 2

  No returns no row, as expected

  Select max ('A')

  of the double

  where 1 = 2 - that is to say isn't true

  Returns the line with null

  Why is this?

  Thank you

  Hello

  user5716448 wrote:

  Hello

  Thanks for the reply.

  I guess that's rule ageneral wait even if no line because of the place where the condition.

  where 1 = 2 - that is to say isn't true

  Thank you

  Yes, if there are no rows in the table, or no line meets the conditions in the WHERE clause, it would be logical that the query return lines exactly 0, but it is also logical that the query returns exactly 1 row.  People who have designed SQL apperantly thought return 1 row was most helpful.

  If you want the query to return 0 rows when there is no data, you can GROUP BY a constant.  For example:

  SELECT MAX (hiredate) AS last_hitedate

  FROM scott.emp

  WHERE deptno = & deptno_wanted

  GROUP 0

  ;

  If there are any rows that meet the condition in the WHERE clause, then the query will produce 1 row, but if no rows meet this condition, then the query will return 0 rows.

  Personally, I'm happy that they designed this way SQL.  I find it rather convenient that the aggregates without GROUP BY clause will return 1 row.  I do things like

  SELECT COUNT (*)

  FROM table_x;

  often, when I want to know if a table has been filled or not.  Seeing a 0 for the output is much clearer that does not get any results.

• Select Max (date) multiple records

  I'm having a problem getting the last value for several gauges.  Here's my query:

  SELECT parameter_id,

  TS_ID,

  value,

  Location_id,

  Date_Time

  Of

  MyTable

  JOIN IN-HOUSE

  mytable2

  WE

  TS_ID = ts_id

  WHERE

  TS_ID LIKE '% - rev.

  unit_id = ("pi")

  the value IS NOT NULL

  Location_id as "xxxx".

  Date_Time =

  (SELECT Max (date_time)

  My TABLE

  GROUP BY parameter_id)

  ;
  

  Hello

  A scalar subquery, such as the expression to the right of the sign =

  Date_Time = (SELECT...)

  must produce (at most) only 1 row.  If the subquery produces 2 or more lines, it will trigger an error.

  Given that you are using "GROUP BY parameter_id" in the subquery, it will produce a separate line of output for each distinct value of parameter_id.  You can use a correlated subquery at that time, that only looks like a parameter_id, or you can use a subquery IN, like this:

  WHERE (parameter_id, Date_Time) IN

  (

  SELECT parameter_id

  MAX (date_time)

  FROM MyTable

  GROUP BY parameter_id

  )

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002