May result by analytic function that follows

Hi all

I am currently using oracle 10g.

create table
CREATE TABLE fortest
(  PROD             VARCHAR2(40 BYTE),
  prodvalues     number);
INSERT statement
insert into fortest values ('dental',10)
   insert into fortest values ('dental',4)
    insert into fortest values ('dental',13)
     insert into fortest values ('dental',3)
      insert into fortest values ('vision',2)
       insert into fortest values ('vision',11)
       insert into fortest values ('vision',33) 
        insert into fortest values ('vision',7)
I need the output as follows
prod        prodvalues <5         prodvalues >=5 and less than 10               prodvalues >=10
dental         2                                     0                                      2
vision         1                                     1                                      2
first column should give me separate prod, prodvalues5 column: should give me the number of similar prod with prodvalues less than 5, same thirdcolumn should have County of similar prod with prodvalues > = 5 and prodvalue < 10 and so on.

Please, not the names of columns of the output tables are just for reference, and I will not use them.


Thanks in advance.

Hi Bob,

You don't have to use analytical functions. Here's a solution that doesn't use analytical functions:

with temp as (select prod, case
                           when prodvalues <=5 then 1
                           else                    0
                           end  as prod5,
                           case
                           when prodvalues >=5 and prodvalues <10 then 1
                           else                    0
                           end  as prod5_10,
                           case
                           when prodvalues >= 10 then 1
                           else                    0
                           end  as prod10
                           from fortest)
                           select prod,sum(prod5) as prod5 ,  sum(prod5_10) as prod5_10 ,sum(prod10) as prod10
                           from temp
                           group by prod

Tags: Database

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group by day, sid, content, page_order - rn
order by day, sid, content, group_number;

  • Analytical function?

    Hello

    I have two tables b rates and transactions (b).

    For each b.FS, I want to know new amount (b.amt time a.rate to the corresponding line of FS b and if a.na is valid based on the flag of the exclusion and the interval defined in the table's).

    It is much easier to explain with an example.

    So here we go...

    Exclude_flag = E (exclude): for b.fs = 433638, b.na = 80000. I have 2 lines in the table for this fs.  Both have E exclude_flag (exclude).  I want to go on all the lines in this FS in the table in a query and I return only one row in the result, if and only if b.na falls out of scope of a.na_min_value and a.na_max_values.  In this example, it falls outside the range excluded for both lines (first two lines of the table a).

    Similarly, exclude_flag = I (Include). for b.fs = 432828, b.na = 17200. I have 2 lines in the table for this fs.  Both have an exclude_flag of I (include).  I want to go on all the lines in this FS in the table in a query and I return only one row in the result, if and only if b.na is between a.na_min_value and a.na_max_values.  In this example, it falls in the range of both the range include for the two lines (line 6 and 7 of the table a).

    The following query gives me two lines for each b.fs.  It is possible to get what I'm looking for simply using sql (possibly write the analytical function?) or I have to write the pl/sql routine for this?

    WITH rates_table

    Did YOU (select ' E' include_exclude_flag, "81000 ' na_min_value, na_max_value '81999', '433638' FS, 0.8 of double rate

    UNION

    Select 'E' include_exclude_flag, na_min_value '84000', na_max_value '84999', '433638' FS, 0.8 of double rate

    UNION

    Select 'I' include_exclude_flag, na_min_value '12000', na_max_value '12999', '432828' FS, rate 0.25 double

    UNION

    Select 'I' include_exclude_flag, na_min_value '13000', na_max_value '13999', '432828' FS, rate 0.25 double

    UNION

    Select 'I' include_exclude_flag, na_min_value '15000', na_max_value '15000', '432828' FS, rate 0.25 double

    UNION

    Select 'I' include_exclude_flag, na_min_value '16100', na_max_value '18000', '432828' FS, rate 0.25 double

    UNION

    Select 'I' include_exclude_flag, '17100' na_min_value, na_max_value '18000', '432828' FS, rate 0.25 double

    UNION

    Select 'I' include_exclude_flag, na_min_value '02440', na_max_value '02470', '016532' FS, 0.35 rate double

    UNION

    Select 'E' include_exclude_flag, na_min_value ' 21000 ', '21000' na_max_value, ' 200020' FS, 0.35 double rate).

    transaction_table AS

    (select '433638' FS '80000' NA, 300 double amt)

    Union

    Select '432828' FS '17200' NA, amt 500 double

    )

    Select * from rates_table a, transaction_table b

    where 1 = 1

    and ((b.na PAS entre a.na_min_value et a.na_max_value et a.include_exclude_flag = «E») GOLD ())

    b.na between a.na_min_value and a.na_max_value and a.include_exclude_flag = 'I'))

    and b.fs = a.fs

    ;

    Any help is greatly appreciated.  I use oracle 11i

    @OP,

    For this kind of problems, we get the number of rows that satisfy the required conditions or who do not meet the required conditions. And then eliminate the line that should be eliminated.

    As below, I calculate four counts (number of join lines)

    EOBCNT - excluded and Out of Bound

    EIBCNT - excluded and in the limit

    IOBCNT - included and Out of Bound

    IIBCNT - included and within the limits

    Once those are calculated, simply return the lines that have EIBCNT and IOBCNT are zero.

    For Ex:

    > WITH

    rates_table

    AS LONG AS)

    Select 'E' include_exclude_flag, na_min_value '79999', na_max_value '79999', '433638' FS, 0.8 double UNION rates

    -Select 'E' include_exclude_flag, na_min_value ' 79999', na_max_value '80000', '433638' FS, 0.8 double UNION rate - TEST - THE

    -If you uncomment the last line and then 433638 will not be returned

    Select 'E' include_exclude_flag, "81000 ' na_min_value, na_max_value '81999', '433638' FS, 0.8 double UNION rates

    Select 'E' include_exclude_flag, na_min_value '84000', na_max_value '84999', '433638' FS, 0.8 double UNION rates

    Select 'I' include_exclude_flag, na_min_value '12000', na_max_value '12999', '432828' FS, 0.25 rate double UNION

    Select 'I' include_exclude_flag, na_min_value '13000', na_max_value '13999', '432828' FS, 0.25 rate double UNION

    Select 'I' include_exclude_flag, na_min_value '15000', na_max_value '15000', '432828' FS, 0.25 rate double UNION

    Select 'I' include_exclude_flag, na_min_value '16100', na_max_value '18000', '432828' FS, 0.25 rate double UNION

    Select 'I' include_exclude_flag, '17100' na_min_value, na_max_value '18000', '432828' FS, 0.25 rate double UNION

    Select 'I' include_exclude_flag, na_min_value '02440', na_max_value '02470', '016532' FS, 0.35 rate double UNION

    Select 'E' include_exclude_flag, na_min_value ' 21000 ', '21000' na_max_value, ' 200020' FS, 0.35 double rate).

    transaction_table AS

    (select '433638' FS '80000' NA, amt 300 Union double

    Select '432828' FS '17200' NA, amt 500 double

    )

    getcnts as)

    SELECT a.*

    b.na, b.amt

    , sum (case when (b.na NOT BETWEEN a.na_min_value)

    AND a.na_max_value

    AND a.include_exclude_flag = 'E '.

    end) then 1 else 0) on (a.fs partition) Eobcnt

    , sum (case when (b.na NOT BETWEEN a.na_min_value)

    AND a.na_max_value

    AND a.include_exclude_flag = 'I '.

    end) then 1 else 0) on (a.fs partition) Iobcnt

    , sum (case when (b.na BETWEEN a.na_min_value)

    AND a.na_max_value

    AND a.include_exclude_flag = 'E '.

    end) then 1 else 0) on (a.fs partition) Eibcnt

    , sum (case when (b.na BETWEEN a.na_min_value)

    AND a.na_max_value

    AND a.include_exclude_flag = 'I '.

    end) then 1 else 0) on (a.fs partition) Iibcnt

    OF rates_table one

    transaction_table b

    WHERE b.fs = a.fs

    )

    getrows as)

    Select x.*, row_number() on

    (partition by order of fs with null desc) getcnts rn x

    where IOBCNT = 0 and eibcnt = 0 - remove lines that are not needed (IF and ONLY if)

    )

    Select * from getrows

    where rn = 1 - to limit a SINGLE row (arbitrarily)

    INCLUDE_EXCLUDE_FLAG NA_MIN_VALUE NA_MAX_VALUE FS RATE NA AMT EOBCNT IOBCNT EIBCNT IIBCNT RN

    -------------------- ------------ ------------ ------ ---------- ----- ---------- ---------- ---------- ---------- ---------- ----------

    433638 84999 84000.8 E 80000 300 3 0 0 0 1

    I hope this helps.

  • Return one row of an analytic function

    Hello

    I pulled the following query:

    Select ID_STORNO, first_value (COD_CONTATTO) ON (Partition of COD_CONTATTO

    order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT

    rows between unbounded preceding and following unbounded)

    as COD_CONTATTO_LAST

    of WT_STR_ESG_CONTATTO;

    The result is:

    2160603C1-H83J1N
    2160603C8-9FOHXJS
    2258072C1-H83J1N

    But I just need to take the following lines

    2160603C8-9FOHXJS
    2258072C1-H83J1N

    Because for the same value of ID_STORNO, I just need to get a value of COD_CONTATTO (to select the best value using COD_PRIORITY and FT_DAT_OPEN_CNT). What is wrong inside the query? I just use 2 or 3 times the oracle analytic functions.

    Best regards

    As SomeoneElse... you need a where clause clause in order to choose the ones you want.

    To do this, the typical is to select a column that you use for this reason, such as:

    "I want to just the first record in each group..."

    Select id_storno, cod_contatto_last from)

    Select ID_STORNO, first_value (COD_CONTATTO) ON (Partition of COD_CONTATTO

    order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT

    rows between unbounded preceding and following unbounded)

    as COD_CONTATTO_LAST,

    ROW_NUMBER() OVER (Partition of COD_CONTATTO

    order of COD_PRIORITY asc, desc FT_DAT_OPEN_CNT

    rows between unbounded preceding and following unbounded)

    as rnum

    of WT_STR_ESG_CONTATTO

    )

    where rnum = 1

    /

    I prefer to use rownumber in this case, so I always have a rnum = 1...

    Usually, you must use the same partition/command by as your other folders (it is usually a good idea... maybe not, depending on your needs, however)

  • Analytical functions, model indexes and multiple dimensions.

    I don't understand the notion of analytic functions (windowing clause) in the regulation of a model clause. I discovered an ordinary table as one-dimensional, and I can understand the concept of window, just like a line on a segment line. However with the models, there are several dimensions, so I guess that the window to become a kind of cube, instead of a line segment. But I'm not.

    For example, I have a matrix sparse 2D, with 5 values non-zero:
    select * from field
  where f is not null

X     Y     F
-----------------
5     8     X
6     6     X
6     8     X
7     7     X
7     8     X
    I guess that the following clause of the model
    with t as(
  select *
    from field
   model
     reference old_field
       on
       (
         select * from field
       )
       dimension by (x, y)
       measures     (f)
     main new_field
       dimension by (x, y)
       measures     (cast(f as varchar2(3)) f)
       rules
       (
         f[x,y] = max(old_field.f) over (order by old_field.y range between 1 preceding and 1 following)
       ))
select * from t
  where f is not null
    to assign for each cell up among its neighbors vertical 2. Just like
    0 0 0      0 X 0
0 X 0  ->  X X 0
X 0 0      X X 0
    But the real result is all NULL values.

    Hello

    with a as
(
select
level L
from
dual
connect by level < 4
)

select
     X
     ,Y
     ,Z
     ,X*3+Y

from
     a          A1
     ,A     A2

model
     dimension by ( A1.L X, A2.L Y )
     MEASURES (0 Z)
     RULES
     (
     Z[X,Y] = COUNT(Z) OVER (ORDER BY X * 3 + Y RANGE BETWEEN 1 PRECEDING AND 1 FOLLOWING)
     )

X Y Z X*3+Y
- - - -----
1 1 2     4
1 2 3     5
1 3 3     6
2 1 3     7
2 2 3     8
2 3 3     9
3 1 3    10
3 2 3    11
3 3 2    12 

 9 rows selected

    for x, y = 1.1, there is no previous rank if it is not counted. current line + line = 2
    for x, y = 1, 2, the previous line + line current + more rank = 3
    for x, y = 1.3 the previous line + line current + more rank = 3
    for x, y = 2, 1, the previous line + line current + more rank = 3
    ...
    for x, y = 3, 2 the previous line + line current + more rank = 3
    for x, y = 3, 3 the stored previous + current line = 2. There is no next line.

    What exectly not understand you?

    Kind regards
    Peter

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