missing documents

I would like to get her out only specific to my list.
expected results bb 100

select ename,sal from emp where (ename,sal)  in (('KING',5000),('ADAMS',1100),('bb','100'));

The above will give you only two records
'KING' 5000
"ADAMS' 1100

I need a bb 100 output that is missed record.
Actual production is to give all the records. How can I change the sql to find the records that do not exist in the table emp from my list.

Published by: 893185 on February 8, 2012 13:17

corrected the post above

Concerning

Etbin

Tags: Database

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Hello

I have not been able to access all of the properties of the content of a book like the book State, but I can get the "full name" of each one, the content of the book. As is the full path of the file to where InDesign thinks is the file, you can try to make an alias, if the file is not there it will fail. If you use a try you can take the file paths failed.

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created a new account, the original admin missing documents.

Hello
I've always been the only user of my computer and he used regularly until I got a laptop and you have not used my XP desktop in the month because of the lack of internet at home. long story short, friend house was stolen and they lost 6 laptops, so I offered him my office so that they always have something to use.

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Any help is very appreciated
Thank you

Hello
It is a response that I had when I had the same problem and it worked

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Find the missing documents and insert accordingly

Oracle version: Oracle Database 11g Express Edition Release 11.2.0.2.0 - Production
Hello gurus
I'm really grateful if someone would help out me. Thanks in advance
Examples of data
Drop, the creating and inserting in tables
drop table TYPE_MST;
drop table TYPE_VERSION;
-------------------------
Create Tables:
create the table TYPE_MST
(
Type_desc varchar2 (15)
);
-----------------
Table insert
insert into TYPE_MST
(
Select 'First' double
Union of all the
Select 'Second' double
Union of all the
Select 'Third' double
);
--------
create the table TYPE_VERSION
(
TYPE_DESC varchar2 (15).
MIN_AGE number (5),
MAX_AGE number (5),
VERSION_ID number (5)
);
---------
insert into TYPE_VERSION
(
Select 'First', 0, 5, 100 double
Union of all the
Select 'First', 5, 10, 100 double
Union of all the
Select 'First', 11,15, 100 double
);
---------
Queries against existing data
Select * from TYPE_VERSION;
The query result
TYPE_DESC, MIN_AGE, MAX_AGE, VERSION_ID
First                      0                5               100
First                      5                10             100
First                      11              15             100
My requirement is that system automatically inserts type_desc missing in TYPE_VERSION.
For example, we have 3 Type_Desc, first, second, third, but in the TYPE_VERSION table, we have data available for only 1 Type_Desc who is "First", this system should insert the missing data in this table using existing data.
I need result something like below:
Required result
TYPE_DESC, MIN_AGE, MAX_AGE, VERSION_ID
First                      0                5               100
First                      5                10             100
First                      11              15             100
Second 11 15 100
Second                   5                10             100
Second 11 15 100
Third                    0                5               100
Third                     5                10             100
Third 11 15 100
Thanks in advance
Concerning
Shu

Hello

It is still not clear what you want.

That's what you want for the examples you gave:

MERGE INTO dst type_version

WITH THE HELP OF)

SELECT DISTINCT

m.type_desc

v.min_age, v.max_age, v.version_id

OF type_mst m

CROSS JOIN type_version v

)                  src

WE (dst.type_desc = src.type_desc

AND dst.min_age = SRC. MIN_AGE

)

WHEN NOT MATCHED THEN INSERT

(dst.min_age, dst.max_age, dst.type_desc, dst.version_id)

VALUES (src.min_age, src.max_age, src.type_desc, src.version_id)

;

If she's going to do what you want in general depends on what you want in general. As long as I don't know the General rules you want to set up, I don't know if it makes them or not.

This does not seem a very good design. Why do you need a table with all possible combinations? Sounds like you're saying, for example, if 2 lines have the same value of min_age, then have the same values for max_age and version_id, too. This 3rd Normal violares form. Why not have a table with the possible values for min_age max_age version_id, and simply join cross which type_mst when you need to see all possible combinations?

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Place the missing documents in the list of records with a rank value

Hi all

I have this table:

WITH taba AS (SELECT 99 AS id,
                     '2011-08-08' AS date_ini,
                     10 AS VALUE,
                     1 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 99 AS id,
                     '2011-09-08' AS date_ini,
                     11 AS VALUE,
                     2 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 99 AS id,
                     '2011-10-08' AS date_ini,
                     10 AS VALUE,
                     4 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 999 AS id,
                     '2011-08-08' AS date_ini,
                     10 AS VALUE,
                     1 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 999 AS id,
                     '2011-09-08' AS date_ini,
                     10 AS VALUE,
                     2 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 999 AS id,
                     '2011-10-08' AS date_ini,
                     10 AS VALUE,
                     3 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 9999 AS id,
                     '2011-08-08' AS date_ini,
                     10 AS VALUE,
                     2 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 9999 AS id,
                     '2011-09-08' AS date_ini,
                     15 AS VALUE,
                     3 AS RANK
                FROM DUAL
              UNION ALL
              SELECT 9999 AS id,
                     '2011-10-08' AS date_ini,
                     10 AS VALUE,
                     4 AS RANK
                FROM DUAL)
SELECT *
  FROM taba

And I need to return the same results but with the addition of records that have no rank. For new records the VALUE must always be zero (0) and the value of DATA_INI must have the same value as the order of the records immediately following. Just like that:

99       2011-08-08     10     1
99       2011-09-08     11     2
*99       2011-10-08     0     3*
99       2011-10-08     10     4
999      2011-08-08     10     1
999      2011-09-08     10     2
999      2011-10-08     10     3
*9999     2011-08-08     0     1*
9999     2011-08-08     10     2
9999     2011-09-08     15     3
9999     2011-10-08     10     4

I can do this using a loop procedure, but I want a filter query. ;)

Thanks in advance.
Filipe Almeida

Hi, Felipe,.

So, you want multiple copies of a few lines. In other words, if a value or rnk (RANK is not a column name right) is missing in a given id you want to with the next highest rnk and the same id line repeated 2 or maybe even several times. All copies will be identical, except that rnk will have the missing numbers, and the value will be 0 on all additional copies.

A way to do that is to join your table (or something very similar to it, as in the example below) to a Meter of Table , which is a table (or a result set, in this example) counts 1, 2, 3,... up to however many copies may be required.

WITH     got_rows_needed          AS
(
     SELECT     id, date_ini, value, rnk
     ,     rnk - LAG (rnk, 1, 0) OVER ( PARTITION BY  id
                                            ORDER BY          rnk
                            )         AS rows_needed
     FROM    taba
)
,     cntr               AS
(
     SELECT     LEVEL - 1     AS n
     FROM     (
               SELECT     MAX (rows_needed)     AS max_rows_needed
               FROM     got_rows_needed
          )
     CONNECT BY     LEVEL <= max_rows_needed
)
SELECT    r.id
,       r.date_ini
,       CASE
          WHEN  c.n  = 0
          THEN  r.value
          ELSE  0
         END               AS value
,       r.rnk - c.n          AS rnk
FROM       got_rows_needed  r
JOIN       cntr             c     ON  c.n  < r.rows_needed
ORDER BY  id
,            rnk
;

By elsewhere, store date information in a VARCHAR2 column, such as date_ini, is a very bad idea. Use a DATE column.

Published by: Frank Kulash, August 8, 2012 11:02

RANK is a keyword from Oracle. (It is the name of a built-in function). If you specify your own columns of RANK, it will confuse people reading the code, and it can result in compiler errors, too.
ID is also an Oracle keyword. To be sure, you can use another name, such as grp_id, instead of id.
It is best not to name your own objects with any name of fArrondi in v$ reserrved_words.keyword.

outer join does not give the expected results (missing documents)
Hello
I have problem with outer join in OBIEE 10 g.

I'm testing it on the model of simplified database

STAT table with some statistics of TYPEs
stat_date, id_type, num
..
..
26/03/2003, 20: 1
26/03/2003, 21: 1
26/03/2003, 23: 1
26/03/2003, 24, 1
26/03/2003, 25, 1
..
27/03/2003, 22, 1 <-different date here
..
..

Table TYPES
ID_type
..
..
20
21
22
23
24
25
..
..

Physical model
STAT >-TYPES

AM.
F1 (only Digital STAT table column (agg. County))
D1 (STAT_DATE of the STAT table column only)
D2 (source TYPES)

D1 - inner join - < F1
D2 - left outer join - < F1

I would like to create simple report filtered by date with number of each type.
I want to get this result
ID_type County
..     ..
..     ..
20 1
21 1
22 null
23 1
24 1
25 1
..     ..
..     ..

But I get this
ID_type County
..     ..
..     ..
20 1
21 1
23 1
24 1
25 1
..     ..
..     ..

ID_type 22 is missing

!!!

I NORMALLY GET RESULT ONLY IF I DELETE RECORD ' 27/03/2003 22' OF MY FACT TABLE.

!!!

I have the filter on the date column D1
STAT_DATE = 26/03/2003 or STAT_DATE is null

BI Server running this SQL query

Select distinct D1.c1 as c1,
D1. C2 C2
Of
(select count (T17840. NUM) in c1.
T17867.ID_TYPE C2
Of
Left outer join of TYPES T17867
STAT T17840 on T17840.ID_TYPE = T17867.ID_TYPE
where (T17840. STAT_DATE in (TO_DATE ('2003-03-26', 'YYYY-MM-DD')) or T17840. STAT_DATE is null)
T17867.ID_TYPE group
) D1

Can you give me some advice?

Thank you
Hi cardel,

I think that you can achieve your goal if you build a dimension of the array STAT form, you can create a table Alias in the physical layer and then to join the table of facts (external to the left). In this way, I think that you can solve your problem.

Let me know.

Kind regards
Gianluca

Missing documents for Oracle 11 g TDE database master key?
I looked through all the "Oracle Database 11 g Release 2 (11.2) Documentation" searching for details of the main encryption key used for transparent encryption of data (TDE) with HSM. It there was only one very brief reference that says that it uses the AES.

What has surprised me is that no word was mentioned of the AES mode (CBC, ECB, etc.) and the key length for the master key that was generated using the following command when it could have been an important information for most. I missed something? Does anyone have any ideas?

SQL > ALTER SYSTEM SET ENCRYPTION KEY IDENTIFIED BY 'user_Id:password '.
Develop,

Oracle TDE specifically requests the HSM via PKCS #11 to generate a key AES 256.

HTH, Peter

Missing documents (column RN) in another table

Thanks in advance

I have 2 tables Table_aa2 and table_aa3

where the region and RN given lines are common

I want to join on 2 tables and get the missing line of RN number

(1) for example

Example 1
select * from table_aa3 where region = 1 order by region,rn 

A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4

In tha above query I want to display the RN = 2 from Table_aa2 for Region = 1 by joing above output from table_aa3

A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
*2     0.1     0.2     159     168     1     2*
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4

Example 2

select * from table_aa3 where region in(1,2) order by region,rn 

A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4
5     0.2     0.3     320     250     2     1
7     0.2     0.3     388     379     2     3
8     0.3     0.4     379     388     2     4
9     0.4     0.5     388     400     2     5
10     1.5     0.6     499     500     2     6

In tha above query I want to display the RN = 2,6 from Table_aa2 for Region = 1,2 (by joing above output from table_aa3)

A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
*2     0.1     0.2     159     168     1     2*
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4
5     0.2     0.3     320     250     2     1
*6     0.3     0.4     250     380     2     2*
7     0.2     0.3     388     379     2     3
8     0.3     0.4     379     388     2     4
9     0.4     0.5     388     400     2     5
10     1.5     0.6     499     500     2     6

Example 3
select * from table_aa3 where region in(1,3) order by region,rn 


A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4
11     0.5     0.6     420     448     3     1
12     0.6     0.7     520     530     3     2
13     0.7     0.8     540     550     3     3
14     0.9     1     560     570     3     4

In tha above query I want to display the RN = 2 from Table_aa2 for Region = 19by joing above output from table_aa3)

A     BEG     END     PROF     AVERAGE     REGION     RN
1     0     0.1     159     159     1     1
*2     0.1     0.2     159     168     1     2*
3     0.2     0.3     179     159     1     3
4     0.1     0.2     250     300     1     4
11     0.5     0.6     420     448     3     1
12     0.6     0.7     520     530     3     2
13     0.7     0.8     540     550     3     3
14     0.9     1     560     570     3     4

create the table TABLE_AA2
(
A NUMBER,
PLEASE THE NUMBER,
NUMBER OF END,
NUMBER OF TEACHER,
AVERAGE NUMBER,
NUMBER OF THE REGION,
NUMBER OF RN
)
;

Fast loading TABLE_AA2...
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (1, 0,.1, 159, 159, 1, 1);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (2,.1,.2,, 159, 168, 1, 2);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (3,.2,.3, 179, 159, 1, 3);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (4,.1,.2,, 250, 300, 1, 4);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (5,.2,.3, 320, 250, 2, 1);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (6,.3,.4,, 250, 380, 2, 2);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (7,.2,.3,, 379, 388, 2, 3);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (8,.3,.4,, 379, 388, 2, 4);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (9,.4,.5, 388, 400, 2, 5);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (10, 1.5,.6,, 499, 500, 2, 6);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (11,.5,.6, 420, 448, 3, 1);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (12,.6,.7, 520, 530, 3, 2);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (13,.7,.8, 540, 550, 3, 3);
insert into TABLE_AA2 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (1, 14,.9, 560, 570, 3, 4);
commit;

create the table TABLE_AA3
(
A NUMBER,
PLEASE THE NUMBER,
NUMBER OF END,
NUMBER OF TEACHER,
AVERAGE NUMBER,
NUMBER OF THE REGION,
NUMBER OF RN
)
;

Fast loading TABLE_AA3...
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (1, 0,.1, 159, 159, 1, 1);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (3,.2,.3, 179, 159, 1, 3);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (4,.1,.2,, 250, 300, 1, 4);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (5,.2,.3, 320, 250, 2, 1);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (7,.2,.3,, 379, 388, 2, 3);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (8,.3,.4,, 379, 388, 2, 4);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (9,.4,.5, 388, 400, 2, 5);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (10, 1.5,.6,, 499, 500, 2, 6);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (11,.5,.6, 420, 448, 3, 1);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (12,.6,.7, 520, 530, 3, 2);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (13,.7,.8, 540, 550, 3, 3);
insert into TABLE_AA3 (A, START, END, TEACHER, MEDIUM, REGION, RN)
values (1, 14,.9, 560, 570, 3, 4);
commit;

Published by: user1849 on September 8, 2009 15:05

user1849 wrote:
I'm missing RN = 2 Table_aa2 when I use under request

select nvl(a3.a,a2.a) a
, nvl(a3.beg,a2.beg) beg
, nvl(a3.end,a2.end) end
, nvl(a3.prof,a2.prof) prof
, nvl(a3.average,a2.average) average
, nvl(a3.region,a2.region) region
, nvl(a3.rn,a2.rn) rn
from table_aa2 a2
, table_aa3 a3
where a2.a(+)= a3.a
      and a3.region = 1
      and a3.region = a2.region
      and a3.rn in(1,3)
order by a

Do not change the outer join, and then use the one I've provided ;-)

Kind regards
Rob.

Help on query for missing documents
Thanks in advance
Can you tell me what is wrong with the query below
**************************************************************************************************************************
WITH missing_time_n AS
(
SELECT m.*
, ROW_NUMBER () OVER (PARTITION OF TRUNC (m.date_time, 'MI') ORDER BY m.date_time, m.description1, m.descript2) AS r_num
OF missing_time m
)
AS extrema
(
SELECT MIN (a.date_time) AS earliest_date_time, MAX (a.date_time) AS latest_date_time FROM a missing_time_n
)
all_minutes AS
(
Earliest_date_time SELECT + ((NIVEAU-1) / (24 * 60)) AS Date_Time FROM extrema
CONNECTION OF LEVEL < = 1 + ((latest_date_time-earliest_date_time) *(24 * 60))
)
two_rows AS
(
SELECT LEVEL AS n, "missing time" | Description (LEVEL) AS to_char dual CONNECT BY LEVEL OF < = 2
)
SELECT NVL (mn.date_time, am.date_time), (mn.description1, tr.description), NVL NVL (mn.descript2, tr.description)
To all_minutes:
CROSS JOIN two_rows tr
FULL OUTER JOIN missing_time_n mn ON am.date_time = TRUNC (mn.date_time, 'MI')
AND tr.n = mn.r_num
ORDER BY mn.date_time, am.date_time, mn.r_num, tr.n
**************************************************************************************************************************

I want to display my output and insert records of missing time

Original request

In this query 09:01 and 09:03 are missing for the same date

SQL > SELECT * FROM MISSING_TIME;

DATE_TIME DESCRIPTION1 DESCRIPT2

--------------------------------------------------------------------------------

--------------------------------------------------------------------------------
------------------------------
25/09/2003 09:00 test1 test2
25/09/2003 09:00 test2 test3
25/09/2003 09:02 test1 test2
25/09/2003 09:02 test2 test3
25/09/2003 09:04 test1 test2
25/09/2003 09:04 test2 test3

6 selected lines

My output

I want to display my output and thus place time records missing (09:01 and 09:03)

DATE_TIME DESCRIPTION1 DESCRIPT2

--------------------------------------------------------------------------------
25/09/2003 09:00 test1 test2
25/09/2003 09:00 test2 test3
2008-09-25 09:01 lack of time lack of time 1 1
2008-09-25 09:01 missing Time2 missing time2
25/09/2003 09:02 test1 test2
25/09/2003 09:02 test2 test3
2008-09-25 09:03 lack time lack of time 1 1
2008-09-25 09:03 missing Time2 missing time2
25/09/2003 09:04 test1 test2
25/09/2003 09:04 test2 test3
**************************************************************************************************************************
create table missing_time (date_time date, description1 varchar2 (30), descript2 varchar2 (30));

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:00 ',' yyyy/mm/dd hh24:mi:ss'), "test1", "test2");

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:00 ',' yyyy/mm/dd hh24:mi:ss'), "test2", "test3");

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:02 ',' yyyy/mm/dd hh24:mi:ss'), "test1", "test2");

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:02 ',' yyyy/mm/dd hh24:mi:ss'), "test2", "test3");

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:04 ',' yyyy/mm/dd hh24:mi:ss'), "test1", "test2");

insert into missing_time (description1, date_time, descript2)
values (to_date (' 25/09/2003 09:00 ',' yyyy/mm/dd hh24:mi:ss'), "test2", "test3");
**************************************************************************************************************************
Your problem is the following:

two_rows AS
(SELECT LEVEL n, "Missing time" |) To_char (LEVEL) FROM DUAL description
CONNECT BY LEVEL<=>

You try to FORCE two lines when the time is missing, hwt if there were three as in the data you provided?

Remove this bogus query you will get the best results:

SQL > SELECT am.date_time, am.n,.
2 NVL (mn.description1, ' lack of time ' | ') description1 am.n),
NVL 3 (mn.descript2, ' lack of time ' | ') description2 am.n)
4. A - all_minutes I
() 5
6. SELECT earliest_date_time
7 + ((LEVEL-1) / (24 * 60)) Date_Time, LEVEL n
8 FROM)
9. SELECT MIN (a.date_time) AS earliest_date_time,
10 MAX (a.date_time) AS latest_date_time
11 FROM missing_time one)
12 CONNECT BY LEVEL<= 1="" +="" ((latest_date_time="" -="" earliest_date_time)="" *="" (24="" *="" 60)))="">
13-, - two_rows I
14--(SÉLECTIONNEZ NIVEAU AS n, «Temps manquant» ||) Description of AS (LEVEL) to_char FROM DUAL
15 - CONNECT BY LEVEL<= 2)="">
16,-FULL OUTER JOIN
(17)
18 SELECT m.*, ROW_NUMBER () OVER (PARTITION OF TRUNC (m.date_time, 'MI') ORDER BY m.date_time)
19, m.description1, m.descript2) AS r_num
Minutes FROM missing_time m 20)
21 WHERE am.date_time = TRUNC ((+), 'MI' mn.date_time)
22 - AND tr.n (+) = mn.r_num
23 ORDER BY am.date_time, am.n
24.

DATE_TIME DESCRIPTION1 DESCRIPTION2 N
---------------- ---------- -------------------- --------------------
25/09/2003 09:00 1 test1 test2
25/09/2003 09:00 1 test2 test3
25/09/2003 09:00 1 test2 test3
25/09/2003 09:01 missing 2 time 2 lack of time 2
25/09/2003 09:02 3 test1 test2
25/09/2003 09:02 3 test2 test3
25/09/2003 09:03 miss 4 time 4 lack time 4
25/09/2003 09:04 5 test1 test2

8 selected lines.

Missing documents for Pix V7 and ASDM V5

Just upgraded one of my Pix to V7.

Now I'm looking for the "Cisco Pix Firewall and VPN Configuration Guide" and "the Cisco PIX Firewall command reference" for version 7, but I couldn't find them on the cisco site.

Any idea where I could find them?

Maybe I need to use the ASA guides instead?

And I was unable to find documentation on how to install ASDM... When I upgraded to 6.3 I've had trouble finding the PDM 3.0 installation guide...

All the tracks would contribute to

www.Cisco.com

right side

Old Site Technology-Documentation

Network security

Select "Cisco Secure PIX Firewall.

http://www.Cisco.com/univercd/CC/TD/doc/product/iaabu/PIX/index.htm

missing documents

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