modeling of the table partitions

Similar Questions

• Why cannot create the table partitioned successfully?

  Why cannot create the table partitioned successfully?

  SQL> create table hr.gps_log_his
  (id number,
  name varchar2(10),
  time date)
  tablespace ts_log_his
  PARTITION BY RANGE (TIME)
  (PARTITION udp_part09110707 VALUES LESS THAN (TO_DATE('09110708','yymmddhh24')),
  PARTITION udp_part09110708 VALUES LESS THAN (TO_DATE('09110709','yymmddhh24')),
  PARTITION udp_part09110709 VALUES LESS THAN (TO_DATE('09110710','yymmddhh24')),
  PARTITION udp_part09110710 VALUES LESS THAN (maxvalue)
  );
  
  (PARTITION udp_part09110707 VALUES LESS THAN (TO_DATE('09110708','yymmddhh24')),
  Error on line 7: 
  ORA-14120: DATE columns did not specify the complete partitioning limits.

  The detailed error message is as follows:

  ORA-14120: incompletely specified partition bound for a DATE column
  
  Cause: An attempt was made to use a date expression whose format does not fully
  (i.e. day, month, and year (including century)) specify a date as a partition bound
  for a DATE column. The format may have been specified explicitly (using TO_DATE()
  function) or implicitly (NLS_DATE_FORMAT).
  
  Action: Ensure that date format used in a partition bound for a DATE column supports
  complete specification of a date (i.e. day, month, and year (including century)). If
  NLS_DATE_FORMAT does not support complete (i.e. including the century) specification
  of the year, use TO_DATE() (e.g. TO_DATE('01-01-1999', 'MM-DD-YYYY') to fully
  express the desired date. 
  

  Action: Change to_date('09110708','yymmddhh24') to
  to_date('2009110708','yyyymmddhh24')

• Renaming / deletion model leaves the table

  Hello
  
  When you use OracleUtils to rename a model, table, on which the model is based remains the same.
  I don't know whether the expected behavior, but it raises a question.
  
  Lets say a template has been created through before ModelOracleSem with the name of 'Test '. A table "Test_tpl" was also created.
  Then, you call:
  OracleUtils.renameModel (oracle, "Test", "Test2");
  
  The model is renamed successfully, but the underlying table is 'test_tpl '.
  The problem is that if you try to create a new template called "Test" through ModelOracleSem.createOracleSemModel, it fails with the following result:
  java.sql.SQLException: none of these RDF models: TEST
  at oracle.spatial.rdf.client.jena.GraphOracleSem.retrieveModelId(GraphOracleSem.java:1889)
  to oracle.spatial.rdf.client.jena.GraphOracleSem. < init > (GraphOracleSem.java:1074)
  to oracle.spatial.rdf.client.jena.GraphOracleSem. < init > (GraphOracleSem.java:705)
  to oracle.spatial.rdf.client.jena.GraphOracleSem. < init > (GraphOracleSem.java:528)
  at oracle.spatial.rdf.client.jena.ModelOracleSem.createOracleSemModel (ModelOracleSem.java:75)
  
  I used the following workaround solution:
  
  OracleUtils.renameModel (oracle, oldModelName, newModelName);
  oracle.executeSQL ("RENAME" + oldModelName + "_TPL OF" + newModelName + "_TPL");
  
  But how can I be sure that the underlying table is indeed oldModelName_TPL?
  
  Thank you
  Concerning
  
  Julien

  Hi Julien,

  This is the expected behavior. The main reason is that, as a general rule, there is no clear correlation between the application table name and the name of the model. However, in the adapter Jena, unless otherwise stated in the GraphOracleSem constructor, the table name is given as [NomModele] _TPL (same with the table names: _NS [NomModele]).

  So, if you use the Jena adaptor, your solution is very good - I would recommend renaming the namespace table as well.

  Also, you can use the GraphOracleSem.getApplicationTableName () function before you rename it for sure.

  Kind regards
  Vladimir

• How to model in the tables of aggregate SPR with different years of data

  Can someone let me know how to accomplish the following in OBIEE?
  
  I want to create a table of logical facts with multiple sources of logical table. I have a global table that only stores the data of the current year. OBIEE, if a user creates a report using data from the current year, I hit the global table of the query. However, my facts database table stores data annually. If a user creates a report using data from previous periods, I want the application to hit the base of facts table.
  
  And if you're curious, that the aggregate contains only data of the current year as the ETL needs to do a full charge every night because of the complexity. The high volume of data and the amount of time it takes to complete this comprehensive way we only have time to fill in the data of the current year.
  
  Thanks in advance.

  Hello

  See Fragmentation in the link below

  http://108obiee.blogspot.com/2009/01/fragmentation-in-OBIEE.html

  Kind regards
  Sandeep

• the date format when downloading Excel at the table of the ADF.

  Hello

  Am using jdeveloper 11.1.1.6.0

  Downloads some data from Excel to my adf:table.

  In my excel I have a Date column, which has the date in the format of ' mm/dd/yyyy hh: mm: a ' (01/12/2013-04:33). I need the same format to download in my af:table.

  This is the code that I used my bean.

  	Formatter DateFormat = new SimpleDateFormat ("mm/dd/yy hh: mm");
  	Say string = theToken;
  	Date date1 = formatter.parse (say);
  	System.out.println ("///Date///" + date1);   Here're the value that Kill Jan 01 05:19 IST 2013 rw.setAttribute ("Date1", date1);

  But in my page user interface, it just shows as dd/mm/yyyy.

  The Date in my af:table attribute is TimeStamp (6).

  Kind regards

  Prasad K T,.

  + 919840021070

  Prasad,

  Your models are not added. The abbreviation for months is "MM" not "mm". If excel uses a specific model, why don't you use the same to analyze the data?

  Then write the date in a table and display it on a page are different actions. You must specify to the timestamp for the model in the table.

  Timo

• Table Partitioned parallelized vs

  Hello
  (11.2 server, OS = OL5)
  
  I have a table that contains more than 50 million lines. I created this table with option 'parallel degree (x).
  
  It seems that the time required to execute a query on this table does not change when I share that, for example partition range dividing the table to 3 partitions.
  
  (access the request a unique index in the table and the query criteria match exactly one of the partitions)
  
  the question:
  1. What is the difference of strategy parallelism between «Parallel degree...» "and the"Division "?
  2. which of them are better in what scenario?
  3. is it better to use PARALLEL_AUTOMATIC_TUNING?
  4 and especially why the performance doesn't change even with a local index on the partitions?
  
  Thank you
  SMSK.

  >
  It seems that the time required to execute a query on this table does not change when I share that, for example partition range dividing the table to 3 partitions
  . . .
  (access the request a unique index in the table and the query criteria match exactly one of the partitions
  . . .
  @Adam Martin: thanks, but I was explained to question 4 that the performance does not change when I toggle locality index.
  >
  I do not see why it would be necessarily change just of partitioning. What is your reason to think so?

  If the index access is used it is basically to get the IDENTIFIER of a line of interest. The line can then be retrieved using the ROWID. The recovery time will be essentially the same way regardless of the line in a partitioned table or non-partitioned table, and regardless of whether the line of partition. This is because the ROWID is (simple explanation here) a FILE ID (which file?), a BLOCK number (relative block in the file) and a LINE NUMBER (which line in the block. It doesn't matter if the segment that is the block is a segment of the table, partitioned table segment, segment index, etc.

  It is the only factor that COULD change the time of the query when the index is used if the access of the index itself is more effective when the table is partitioned when the table is not partitioned.

  Clearly if it is an overall index, there is a change since the index access itself will be the same.

  The only factor now that MIGHT change the time of the request is so if 1) the index is changed locally and 2) the local index has a different structure than the old index that allows to find the best performing required index entries.

  You have not published information on the index of structure, so let me give you an analogy which shows a scenario where it is clear that the access to the index would not change.

  Assume that the overall index is analogous to a catalogue of cards with 26 entries - one for each letter of the alphabet. My query accesses the entries beginning with the letter 'F' As discussed above in table access to aid a ROWID obtained from the index will be the same, if the table is partitioned or not.

  So now I have the partition table and have 26 partitions - one for each letter of the alphabet.

  With the help of the global index of the access to the partition of 'F' will be the same.

  Now, if I create a local index (instead of global) it's almost as if I now 26 index, one for each letter of the alphabet. The first entry for the 'F' in the global index can be found by reading the root node and perhaps one or two other nodes - then that an index scan can be performed.

  The first entry for the 'F' in the local index is at the beginning of the index - no need to jump or to do a binary search to ignore the 'A', 'B', etc. entered.

  This time difference is microscopic.

  Once I found the first entry for the 'F' either in the overall index, or local 'F' remaining entries in the index are consecutive, so access time will be the same.

  I don't know if there is a structural difference between the indices and the that you tried, but the above should show if the structure (order) has not changed it would not be a noticeable difference in access.

• OBIEE 10G - repository Business Model adding fact Table

  Hello
  
  I tried to search the forum for problems similar to this one, but did not find any thread that responded to my doubts.
  
  I'll try to explain this very well (without images it's complicated). Suppose we have a schema with the following tables:
  
  Dim_1, Dim_2, Dim_3, Dim_4, Dim_5, Fact_1, Fact_2
  
  Fact_1 is connected to Dim_1, Dim_2 and Dim_3
  Fact_2 is connected to Dim_2, Dim_3, Dim_4 and Dim_5
  
  And on the business of the repository model, we already have a model with the following tables:
  
  Dim_1, Dim_2, Dim_3 and Fact_1. It was the State of the repository, the last time that we have saved.
  
  Now, I want to add to the activity model, the table Fact_2 and the Dims that connect with Fact_2. What should I do here?
  
  If I drag the physical layer only the tables (Dim_4, Dim_5 and Fact_2 like Dim_1 and Dim_2 already exist in the business model) when I check on the business model of the table Fact_2 and direct joins diagram I see only joins Dim_4 and Dim_5 and not joined to the other two dimesion tables (Dim_1 and Dim_2). I don't know if OBIEE will always act as these joins are made or if I'm having problems when I'm working on presentation services.
  
  If I drag the physical layer, the tables (Dim_2, Dim_3, Dim_4, Dim_5 and Fact_2) I'll see all the joins, but I'll have on repeated business model tables, something like this:
  
  Dim_1, Dim_2, Dim_2, #1, Dim_3, Dim_3, #1, Dim_4, Dim_5, Fact_1 and Fact_2
  
  So what is the solution here? I have to redo everything I want to add something, and this situation occurs? Isn't his smart and there must be a better solution. I know that I can start direct joins manually, but that is the best solution that I can find in this situation?
  
  I hope that I was clear :)
  
  Thank you

  Hello

  I have proposed this approach because your layer of MDB was already designed with fact1 joins. If you have already designed MDB, once you drag fact1, fact2 & Sun 1-5 (after physical joins) complex join will be automatically created in MDB. Now that you're at halfway, it is the only way to include the tables.

  Rgds,
  DpKa

• I can't understand the reasoning behind the tables to ID CS5. Can you help me?

  I can make tables ID CS5 works, but I do not understand how they work. I should mention that I am a heavy user of FrameMaker, so I'm sure I have some faulty assumptions.

  In FrameMaker, I'm used to the use of the table styles to automate the formatting of the table. All the table set in the form of information - for example, styles of text for titles table, headers, and body; rules; intercellular. etc. - is built in the style of table and applied with a single click. The text style information drawn from pre-existing paragraph styles that are associated with the table style. All very simple. But in InDesign, things seem much more complicated.

  InDesign a of table and Cell Styles. I'm not clear on the relationship between the two. You can specify to power and styles of shading in both. I don't understand this.

  I got more predictable results, with cell Styles, so I took most of my formatting information. But Cell Styles are not autonomous entities. Even if you create them, then add them to the Style Table, they must be associated with a pre-existing paragraph style. This looks like a duplication of efforts - two distinct styles (cell and paragraph) apply the same text formatting information. The cell Style includes power and info of the shading, but that shouldn't be necessary since that information can theoretically be entered in the Style of the Table.

  In addition, Cell Styles using limits you to the style of a paragraph per cell. In some cases, I need two - data or text, followed by a few chips. When this happens, that I had to remove the cell Style and directly apply a paragraph style. Looks funky.

  I don't want to get too deep into the weeds with specific puzzles I encountered; It is sufficient to say that I do not understand how the table and Cell Styles interact and how best to use them to create and format tables efficiently. Does anyone of you understand the reasoning behind the ID tables? Can you provide a source that explains it? There must be a system, a set of operating principles that are consistent, but I was not able to discern them.

  Sincere thanks,

  -Donna Reynolds

  Hi, Donna.

  I don't know a good reference for how table styles fit together, but I think that your problems would be solved more easily if you gave a specific example of what was confusing you.

  It is true that there is overlap between the table and cell styles. This is because they are modeled on the Table Options and Options of the cell, and there is an overlap. For example, the shot of the table and the outer race of the external cells are the same things.

  Most of the time, you can avoid this confusion - in the Style of your Table, do not define anything except for where you need to replace your cell style information, such as the outside of the table. You cannot set the padding on a style to a table in the table, because you cannot set the padding in the Table Options. Except for the stuff that relates to the entire table, such as the alternation of the contours of row/column.

  So set your fillings in cell styles and use this style in the Style of the Table.

  In your cell styles, do not specify a paragraph style. Use (ignore). It is important that a cell should dictate a particular paragraph style, then use it. But it's probably him better not reach otherwise.

  Is it that help at all?

• ODI-26174 error when try to turn the Table in the model

  Hello

  I got a strange error when I try to turn the table in the model.

  I created the new user (with subsidies), I created the new physics and logic diagram.

  I created new model also. When I try to reverse table I ODI-26174 database connection is not available error

  I tried to measure option using RKM reverse .it. But why it has not been reversed by using option Standart?

  ava.sql.SQLException: i/o error: the network adapter could not establish the connection

  at oracle.odi.jdbc.datasource.LoginTimeoutDatasourceAdapter.doGetConnection(LoginTimeoutDatasourceAdapter.java:133)

  at oracle.odi.jdbc.datasource.LoginTimeoutDatasourceAdapter.getConnection(LoginTimeoutDatasourceAdapter.java:62)

  at oracle.odi.core.datasource.dwgobject.support.OnConnectOnDisconnectDataSourceAdapter.getConnection(OnConnectOnDisconnectDataSourceAdapter.java:74)

  at com.sunopsis.sql.SnpsConnection.testConnection(SnpsConnection.java:1128)

  Any Solution for this?

  Concerning

  AETL

  Hi aetl,.

  If you open the database server in the physical topology and click 'test connection', is it effective?

  If this isn't the case, you must set your connection details, maybe check that the tnsnames.ora is correct and that the network access is ok (including firewalls,...). You can try a tnsping on your database.

  Kind regards

  JeromeFr

• Get the only table name in model executing the revese engineer but columns do not come

  Get the only table name in model executing the revese engineer but columns do not come. I used the standard procedure.  Please let me know why I am not getting column in my model.

  I have attached the screen shot for the same thing.

  This is a table or a synonym? In the case of synonym or try to add the property as it appears below thread.

  Reverse engineering a synonym in ODI 11 G.

  Or maybe go with personal setbacks.

• Partitioned global index on partitioned table range, but the index partition does not work

  Hello:

  I was creating an index partitioned on table partitioned and partitioned index does not work.

  create table table_range)

  CUST_FIRST_NAME VARCHAR2 (20).

  CUST_GENDER CHAR (1),

  CUST_CITY VARCHAR2 (30),

  COUNTRY_ISO_CODE CHAR (2),

  COUNTRY_NAME VARCHAR2 (40),

  COUNTRY_SUBREGION VARCHAR2 (30),

  PROD_ID NUMBER NOT NULL,

  CUST_ID NUMBER NOT NULL,

  TIME_ID DATE NOT NULL,

  CHANNEL_ID NUMBER NOT NULL,

  PROMO_ID NUMBER OF NON-NULL,

  QUANTITY_SOLD NUMBER (10.2) NOT NULL,

  AMOUNT_SOLD NUMBER (10.2) NOT NULL

  )

  partition by (range (time_id)

  lower partition p1 values (u01 tablespace to_date('2001/01/01','YYYY/MM/DD')),

  lower partition (to_date('2002/01/01','YYYY/MM/DD')) tablespace u02 p2 values

  );

  create index ind_table_range on table2 (prod_id)

  () global partition range (prod_id)

  values less than (100) partition p1,

  lower partition p2 values (maxvalue)

  );

  SQL > select TABLE_NAME, SUBPARTITION_COUNT, HIGH_VALUE, nom_partition NUM_ROWS of user_tab_partitions;

  TABLE_NAME NOM_PARTITION SUBPARTITION_COUNT HIGH_VALUE NUM_ROWS

  ----------- ---------------- ------------------ -------------------------------------------------------------------------------- ----------

  TABLE_RANGE P2 0 TO_DATE (' 2002-01-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIA 259418)

  TABLE_RANGE P1 0 TO_DATE (' 2001-01-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIA 659425)

  SQL > select INDEX_NAME, NUM_ROWS nom_partition, HIGH_VALUE user_ind_partitions;

  INDEX_NAME NOM_PARTITION HIGH_VALUE NUM_ROWS

  ------------------------------ ------------------------------ -------------------------- ----------

  P1 IND_TABLE_RANGE 100 479520

  IND_TABLE_RANGE P2 MAXVALUE 439323

  SQL > EXECUTE DBMS_STATS. GATHER_TABLE_STATS (USER, 'TABLE_RANGE');

  SQL > EXECUTE DBMS_STATS. GATHER_TABLE_STATS (USER, 'TABLE_RANGE', GRANULARITY = > 'PARTITION');

  SQL > EXECUTE DBMS_STATS. GATHER_INDEX_STATS (USER, 'IND_TABLE_RANGE');

  SQL > EXECUTE DBMS_STATS. GATHER_INDEX_STATS (USER, 'IND_TABLE_RANGE', GRANULARITY = > 'PARTITION');

  SQL > set autotrace traceonly

  SQL > alter shared_pool RAS system;

  SQL > changes the system built-in buffer_cache;

  SQL > select * from table_range

  where prod_id = 127;

  ---------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  ---------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |             | 16469 |  1334K |  3579 (1) | 00:00:43 |       |       |

  |   1.  RANGE OF PARTITION ALL THE |             | 16469 |  1334K |  3579 (1) | 00:00:43 |     1.     2.

  |*  2 |   TABLE ACCESS FULL | TABLE_RANGE | 16469 |  1334K |  3579 (1) | 00:00:43 |     1.     2.

  ---------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  2 - filter ("PROD_ID" = 127)

  Statistics

  ----------------------------------------------------------

  320 recursive calls

  2 db block Gets

  13352 consistent gets

  11820 physical reads

  0 redo size

  855198 bytes sent via SQL * Net to client

  12135 bytes received via SQL * Net from client

  1067 SQL * Net back and forth to and from the client

  61 sorts (memory)

  0 sorts (disk)

  15984 rows processed

  Once the sentence you say ' does not ' and then you go to paste plans that seem to show that it "works".

  What gives?

  In fact, if you look at the plans - think Oracle you have 16 k rows in the table and he'll be back k 12 rows for your select statement. In this case, Oracle is picking up the right plan - full scan 16 ranks of k is a lot less work to digitize the index lines k 12 followed by the research of rank k 12 rowid.

• Partitioning of an existing Table using the EXCHANGE PARTITION

  Hi all

  I have one unpartitioned table I partitioned by Exchange, this table has several indexes and constraints (primary and foreign).

  ALTER TABLE notpart_table ADD (
      CONSTRAINT PK_KCESPITI PRIMARY KEY (K_CESP, TIPORD)
          USING INDEX TABLESPACE TBLS_CONTA,
      CONSTRAINT FK_KCONTO_CE FOREIGN KEY (K_CONTO) REFERENCES xxxx (K_CONTO));
  
  CREATE INDEX IX_NFATTURA_CE ON notpart_tab (ANNO_FATTURA, K_REGISTRO, K_REGFA, TIPORD)
      TABLESPACE TBLS_CONTA;
  
  
  
  
  

  after Create a partitioned Table Destination

  notpart_table2, I created the same constraints and indexes defined in notpart_table

  
  

  When I run

  
  

  ALTER TABLE notpart_table2
    EXCHANGE PARTITION PART_notpart_table2
    WITH TABLE notpart_table
    WITHOUT VALIDATION
    UPDATE GLOBAL INDEXES;
  
  
  
  

  I get: ora-02266

  Why?

  Thanks in advance for any help

  
  

  Post edited by: vigilant Rosario

  It is not exactly what you have. Very probably not partitioned table, you are partitioning is the parent to another table table:

  SQL > create table tbl1 (id number)
  2.

  Table created.

  SQL > alter table tbl1
  2 Add the constraint tbl1_pk
  3 primary key
  4.

  Modified table.

  SQL > create table tbl2 (id number)
  2.

  Table created.

  SQL > alter table tbl2
  2 Add the constraint tbl1_fk1
  3 foreign key
  4 references tbl1
  5.

  Modified table.

  SQL > insert into tbl1 values (1)
  2.

  1 line of creation.

  SQL > insert into tbl2 values (1)
  2.

  1 line of creation.

  SQL > create table tbl1_part (id number)
  2 partition by range (id)
  3 (partition p1 values less than (1000000))
  4.

  Table created.

  SQL >
  SQL > alter table tbl1_part
  Exchange 2 partition p1
  3 with table tbl1
  4 without validation
  5 update global indexes
  6.
  with table tbl1
  *
  ERROR at line 3:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys

  SQL >

  If so, of the foreign key and recreate it pointing to the partitioned table as parent after finished partitioning the table.

  SY.

• Create triggers in the table, sequence, insert and update with "model"?

  It must be of rtfm, trial and error thing but you wanted to ask, is it possible to have models or similar automation for the following scenario:

  1.), I add the table to the logic model

  2.) Using glossary I transform a relational model that was recovered / synchronized with the data dictionary

  3.) then I have the new table to add

  -but

  I would then have auto-DDL of to be synchronized to database:

  -create sequence for the id column

  -create table

  -create indexes for the id column pk

  -Create triggers for insert and update

  -l' idea is to have db_created_dt and db_modified_dt defined in the table, so that each table has them to the fields of record etc.

  -activate the triggers

  Each of them following the same naming convention.

  Similarity with approx. generator Apex workshop utils sql create table of the copy paste "excel" that creates 'id' - column + sequence and insert the trigger.

  rgrds Paavo

  Hi Paavo,

  most of the steps can be made in one or other way

  -create sequence for the id column

  -create table

  -create indexes for the id column pk

  If you want to start in the logic model and you don't want to have the ID column in the logic model and select 'Create the surrogate key' checkbox in the dialog entity - you will get an identity column in the relational model and the version of database and settings in ' preferences > Data Modeler > model > physics > Oracle "you can set the sequence generation and the trigger for taking in load.

  fields of record defined in the table, so that each table has them

  You can add the same set of columns in all tables with the transformation script 'model of Table... ».

  You can also look here Oracle SQL Developer Data Modeler 4.1 user - defined DDL generation using transformation scripts

  to see how to grant your DDL generation using the transformation script. DM comes with example to generate separate tables of logging and triggers. You can create your build script of triggers that support logging in these common columns.

  Philippe

• Cannot add the table to partition to partition

  Hi guys,.

  my version of oracle is 11 GR 2

  I created the table with the following DDL

  CREATE TABLE PERSON

  (

  ID_PERSON VARCHAR2 (10 BYTE) NOT NULL,

  NAME_PREFIX VARCHAR2 (5 BYTE),

  NAME_LAST VARCHAR2 (40 BYTE) NOT NULL,

  NAME_FIRST VARCHAR2 (30 BYTE) NOT NULL,

  NAME_MID VARCHAR2 (30 BYTE),

  NAME_SUFF VARCHAR2 (5 BYTE),

  CD_GENDER VARCHAR2 (1 BYTE),

  DATE OF DATE_BIRTH,

  FL_AGE18 VARCHAR2 (1 BYTE),

  ID_SSN VARCHAR2 (BYTE 9),

  ID_DMV VARCHAR2 (20 BYTE),

  ID_PH_NBR VARCHAR2 (10 BYTE),

  ID_ALIEN VARCHAR2 (10 BYTE),

  ID_TRIBAL VARCHAR2 (10 BYTE),

  NAME_TRIBAL VARCHAR2 (40 BYTE),

  ID_CITY VARCHAR2 (5 BYTE) NOT NULL,

  ID_AD_RESIDENCE NUMBER (38),

  ID_AD_MAIL NUMBER (38),

  CD_NVRA VARCHAR2 (5 BYTE),

  DATE OF DATE_ACCEPT,

  DATE OF DATE_EFFECT,

  CD_STATUS VARCHAR2 (2 BYTE),

  CD_STAT_REASON VARCHAR2 (50 BYTE),

  DATE OF DATE_STAT_CHANGED,

  DATE OF DATE_LAST_ACTIVE,

  FL_RESI_PF VARCHAR2 (1 BYTE),

  CD_RESI_PF VARCHAR2 (4 BYTE),

  CD_RESI_OTH_PF VARCHAR2 (40 BYTE),

  FL_ID_PROVIDED VARCHAR2 (1 BYTE),

  FL_ID_NEVER_ISSUED VARCHAR2 (1 BYTE),

  CD_ID_VALIDATION VARCHAR2 (2 BYTE),

  DATE OF DATE_ID_VALIDATION,

  FL_SIGNATURE VARCHAR2 (1 BYTE),

  FL_US_CITIZEN VARCHAR2 (2 BYTE),

  CD_CITIZEN_PF VARCHAR2 (5 BYTE),

  FL_ACP_PERSON VARCHAR2 (1 BYTE),

  ID_ACP VARCHAR2 (BYTE 9),

  DATE OF DATE_ACP_START,

  DATE OF DATE_ACP_END,

  FL_POLL_WORKER VARCHAR2 (1 BYTE),

  FL_CHALLENGE VARCHAR2 (1 BYTE),

  FL_PREHAVA_PERSON VARCHAR2 (1 BYTE),

  DATE OF DATE_DEATH,

  FL_ELIGIBLE_DELETE VARCHAR2 (1 BYTE),

  FL_ELIGIBLE_PURGE VARCHAR2 (1 BYTE),

  FL_DISABLED VARCHAR2 (1 BYTE),

  FL_ELDERLY VARCHAR2 (1 BYTE),

  NAME_SEARCH VARCHAR2 (40 BYTE),

  AD_SORT_NUM VARCHAR2 (20 BYTE),

  ID_VALID_OTHER VARCHAR2 (50 BYTE),

  ID_UVI VARCHAR2 (16 BYTE),

  ID_CITYSHIP VARCHAR2 (5 BYTE),

  FL_PROTECTIVE_ORDE VARCHAR2 (1 BYTE),

  FL_INACTIVE VARCHAR2 (1 BYTE),

  FL_OVERRIDDEN VARCHAR2 (1 BYTE),

  FL_ALT_REG_SIGN VARCHAR2 (1 BYTE),

  FL_PERMANENT_ABSEN VARCHAR2 (1 BYTE),

  CD_SPEC_STATUS VARCHAR2 (1 BYTE),

  FL_UOCAVA_COMMUNICATION VARCHAR2 (1 BYTE),

  AD_UOCAVA_EMAIL VARCHAR2 (254 BYTE),

  CD_PARTY VARCHAR2 (5 BYTE),

  DATE OF DATE_PARTY_ENROLL,

  DATE OF DATE_ACCEPT_ORIGINAL,

  DATE OF DATE_MOVED,

  DATE_CHANGED DATE,

  AD_EMAIL VARCHAR2 (254 BYTE),

  CD_RACE VARCHAR2 (5 BYTE),

  FL_CITIZEN_HEARING VARCHAR2 (1 BYTE),

  ID_USER VARCHAR2 (20 BYTE),

  TM_STAMP TIMESTAMP (6).

  DATE OF DATE_LAST_CONTACT,

  NAME_PREV_LAST VARCHAR2 (40 BYTE),

  NAME_PREV_SEARCH VARCHAR2 (40 BYTE),

  DATE OF DATE_REG

  )

  TABLESPACE PERSON_DATA

  PCTUSED 0

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  LOGGING

  PARTITION BY RANGE (ID_CITY)

  (

  P_PERSON_1 PARTITION VALUES LESS THAN ('1')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_2 PARTITION VALUES LESS THAN ('2')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_3 PARTITION VALUES LESS THAN ('3')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_4 PARTITION VALUES LESS THAN ('4')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_5 PARTITION VALUES LESS THAN ('5')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_6 PARTITION VALUES LESS THAN ('6')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_7 PARTITION VALUES LESS THAN ('7')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_8 PARTITION VALUES LESS THAN ('8')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  ),

  P_PERSON_9 PARTITION VALUES LESS THAN ('9')

  LOGGING

  NOCOMPRESS

  TABLESPACE PERSON_DATA

  PCTFREE 10

  INITRANS 1

  MAXTRANS 255

  STORAGE)

  64K INITIALS

  ACCORDING TO 1 M

  MINEXTENTS 1

  MAXEXTENTS UNLIMITED

  DEFAULT USER_TABLES

  )

  )

  NOCOMPRESS

  NOCACHE

  NOPARALLEL

  MONITORING

  ALLOW THE MOVEMENT OF THE LINE;

  I tried to add the partition with the highest value 10

  change the voter table add partition P_PERSON_10 lower (10);

  change the voter table add partition P_PERSON_10 lower (10)

  Error on line 11

  ORA-14074: partition bound must gather greater than that of the last partition

  I want to add 100 to leave with max 100 value, please help me in this regard.

  Split partition also get the error

  Thanks in advance

  Kind regards

  REDA

  ID_CITY a VARCHAR2 is not a number.  Thus, although "less than ('10')" is correct for a VARCHAR2 ("equal or superior (10)"), where do you think the value '2' would go? '2' less than '10' is? Where would the '21' value?  Where would '56'?  Tip: '21' is less than '3' and 56 'is less than 6'.

  Also your first partition is defined as "less than ('1')", which makes no sense.

  Hemant K Collette

• Problems with highlighting of the rows of the table through RTF-model

  Hello!

  Peace im new in the world of BI Publisher. For the moment, I try to create and RTF-model with the Office AddIn for Word Bi-editeur (2010). I want to create a table based on a table of a pdf document existing already. I have all the data in the right format and order and just worked fine - until I wanted to change the background color of some specific lines.
  If I add that a statement such as

  <? If: Variable = "Expressionstring?" > <? attribute@InContext:background-color;' #FFFF80 '? > <? end if? >

  the context of the evolution of the entry. But the fact the line height. It develops. The expressions more that I use more it grows. That of not good, because the table is so great that it only fits on a single page with fine lines... I tried to apply a height specified in the line through the word, but it does not work.
  I searched a couple hours and still didn't find anything regarding this problem. I appreciate any ideas how to solve this problem.

  Tounsiiaa in advance

  Gabriel

  To help those who have a similar problem: it's just like sfr.farhan.fani wrote. I try to give you a general expression:

  
  

  <? If@row:ROWNAME=VALUE? > (this should work with = > etc do not forget the ' ' for strings etc..)

  < xsl: attribute name = 'background-color' xdofo:ctx = 'incontext' > lightgray < / xsl: attribute > (lightgray can be changed to hexa% and %valeurs)

  <? end if? >

  Hello

  Try the following expression

  5000? >

  LightGray