Need for outer join

Similar Questions

• Logic for Outer join

  Hi all

  Oracle Version: 11.2.0.2.0

  with tab1 as

  (

  Select 1 model_id 10 dealer_id 10 price null of double net_price

  Union all the

  Select 2 model_id 10 dealer_id 12 price null of double net_price

  Union all the

  Select 3 model_id 10 dealer_id 11 price of double

  Union all the

  Select 3 model_id 20 dealer_id 12 price of double

  )

  Select * de tab1

  with tab2 as

  (

  Select 10 dealer_id , 4 discount of double

  Union all the

  Select 20 dealer_id , 5 discount of double

  Union all the

  Select 30 dealer_id , 5 discount of double

  Union all the

  Select 40 dealer_id 10 discount of double

  )

  Select * de tab2

  with Master_table as

  (

  Select 1 model_id 10 dealer_id of double

  Union all the

  Select 2 model_id 20 dealer_id of double

  Union all the

  Select 2 model_id 10 dealer_id of double

  Union all the

  Select 5 model_id 20 dealer_id of double

  Union all the

  Select 3 model_id 10 dealer_id of double

  Union all the

  Select 1 model_id 30 dealer_id of double

  Union all the

  Select 2 model_id 40 dealer_id of double

  )

  Select * de master_table

  I have to calculate the net price which is = price - discount.

  For the combination model/dealer (from the main table) for which is there is no record in tab1 should be filled with the value NULL.

  Please find output as below

  The model ID

  Dealer_id

  Price

  Net price

  1

  10

  10

  6

  2

  10

  12

  8

  3

  10

  12

  7

  3

  20

  12

  8

  4

  20

  5

  20

  1

  30

  2

  40

  Hello

  Try this query,

  Select model_id, dealer_id, net_price price-discount price

  (

  Select b.discount, a.model_id, a.dealer_id, b.price of

  master_table one

  left outer join

  (select a.model_id, a.dealer_id, b.discount from tab1 a.price an outer join tab2 b on a.dealer_id = b.dealer_id left) b

  on a.model_id = b.model_id and a.dealer_id = b.dealer_id

  )

  out put will be

  MODEL_ID DEALER_ID PRICE NET_PRICE
  --------- --------- --------- ---------
  3        10        11         7
  2        10        12         8
  1        10        10         6
  2 20
  1 30
  2 40
  5 20

  7 selected lines.

• Left Outer Join DR.

  Hi Experts,

  I have a requirement that says - see the chart for the past 10 days, regardless the presence data table in fact.
  Lets consider an example - Time_dim product, are my dimension tables, Purchase_Order is my fact table.

  I did it for external Purchase_Order in left RPD with TIME_DIM and inner join with the PRODUCT table.  and execution of query of exit-
  Select T.Date, P.item, count (distinct PO.order_no)
  TIME_DIM t, PRODUCT P, PURCHASE_ORDER PO
  where T.date_key = PO.date_key
  and P.item = in. agenda
  and P.item = 'laptop ';

  The query generated by OBIEE left outer join, but when the condition P.item = "Notebook" included in the query, and if there are no orders for this product in one of the date, that date will not come in the result set.

  the query to be generated by the OBIEE is-

  
  Select T.Date, PO.item, count (distinct PO.order_no)
  TIME_DIM t,.
  (SELECT P.ITEM, IN. ORDER_NO
  PRODUCT P, PO PURCHASE_ORDER
  WHERE P.item = in. agenda
  and P.item = 'Laptop') IN.
  WHERE T.date_key = PO.date_key (+);

  How to design the RPD to achieve this. All pray to advise on this. Thanks in advance.

  Thank you
  Chantal

  Hello

  You are on 11.1.1.7?

  I would say that your condition can be made without using external and maintenance of product and the standard between the FACT dimension, time inner join join.

  If you enable your property analysis OBIEE "Include Null values" will automatically return all the elements of time and product matching your filter (so you'll need to add a filter on 'Date' to limit it to the last 10 days or you will have a unique day of your time dimension).

  If you filter then on "Laptop", even if there is not a single value in order for "Laptop" in the last 10 days, he will be there on the screen.

  Easy, clean and you keep your inner join between the facts and Dimensions.

  Take a look at this example, I just did on SampleApp 406:

  

  Selection of 12 months (year 2010) and a customer (id = 89) and income. The model has only an inner join. I activate the option "Include Null values" and here is the result.

  

  A line with cells only empty because there is not a single revenue for customer 89 in 2010. This is exactly your condition.

  Honestly, do not touch your model using the outer join, you will have more side effects than benefits. Every single scan will do the outer join and you'll have a lot of data 'empty' return of the DB (more large data set containing just the null values) and probably you need the outer join in 15 to 25% of your analysis.

  Keep things simple, it will be faster and easier to maintain.

• Create a view which limits a large table, but also allows an outer join?

  Oracle 10.2.0.4

  CREATE TABLE MY_PAY_ITEMS

  (EMP VARCHAR2 (8) NOT NULL)

  , PAY_PRD VARCHAR2 (8) NOT NULL

  , KEY1 VARCHAR2 (8) NOT NULL

  , KEY2 VARCHAR2 (8) NOT NULL

  , LN_ITEM VARCHAR2 (4) NOT NULL

  , ITEM_AMT NUMBER (24.2) NOT NULL

  VARCHAR2 (100) FILL NON-NULL)

  INSERT INTO MY_PAY_ITEMS

  SELECT A.EMP

  B.PAY_PRD

  C.KEY1

  D.KEY2

  E.LN_ITEM

  F.ITEM_AMT

  , '                      '

  FROM (SELECT TO_CHAR (ROWNUM, ' 00000000') 'EMP' FROM DUAL CONNECT BY LEVEL < = 50) has

  , (SELECT '2010-' |) To_char(rowNum,'00') 'PAY_PRD' FROM DUAL CONNECT BY LEVEL < = 52) B

  , (SELECT TO_CHAR (ROWNUM, ' 000') 'KEY1' FROM DUAL CONNECT BY LEVEL < = 8) C

  , (SELECT TO_CHAR (ROWNUM, ' 000') 'Key2' FROM DUAL CONNECT BY LEVEL < = 5) D

  , (SELECT TO_CHAR(ROWNUM,'000') 'LN_ITEM' FROM DUAL CONNECT BY LEVEL < = 20) E

  (round (DBMS_RANDOM. VALUE * 400.2) "ITEM_AMT" of the double) F

  CREATE A UNIQUE INDEX MY_PAY_ITEMS ON MY_PAY_ITEMS (MEP, PAY_PRD, KEY1, KEY2, LN_ITEM)

  CREATE TABLE MY_ITEM_DISPLAY

  (THE VARCHAR2 (4) OF DISPLAY_CODE NOT NULL)

  , NUMBER (2) SEQUENCE NON-NULL

  , COLUMN_ITEM1 VARCHAR2 (4) not null

  , COLUMN_ITEM2 VARCHAR2 (4) not null

  , COLUMN_ITEM3 VARCHAR2 (4) not null

  COLUMN_ITEM4 VARCHAR2 (4) not null)

  INSERT INTO MY_ITEM_DISPLAY VALUES ('01 ', 10, '001', '003', '004',' 005');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('01 ', 20 '007', '013', '004',' 009');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('01', 30 ' 001', '004', '009',' 011');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('01', 40, '801 ', ' 304 ', 209',' 111');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('02 ', 10, '001', '003', '004',' 005');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('02 ', 20 '007', '013', '004',' 009');

  INSERT INTO MY_ITEM_DISPLAY VALUES ('02', 30 ' 001', '004', '009',' 011');

  MY_PAY_ITEMS is a table that stores line of payslip items.  It has a total area of 500,000,000 lines.

  PEM is the unique id, we have about 200,000 employees (with about 50,000 being active today).

  PAY_PRD is a weekly pointer (2010-01, 2010-02, 2010-52), we have the 2004 data and add a new pay period each week.  2010 01 is defined as the first Monday in 2010 for the first Sunday in 2010, etc.

  Key1 is an internal key, it follows the chronology in the pay period.

  KEY2 is a child of KEY1, there follows the sequence of events in KEY1.

  LN_ITEM is the component of actual compensation resulting from the event, on average, a person produces 20 lines per event.  Note that in this example, everyone gets the same LN_ITEM values, but in practice it is selected 20 of 300

  ITEM_AMT is the net salary per command line.

  FILLING is a set of fields that are unrelated to this issue, but act as a brake on the charges of the line.

  MY_ITEM_DISPLAY is an array that describes how some screens should display items.  The screen itself is a grid of 4 poles, with the content of each cell is defined as a LN_ITEMS search to retrieve the relevant LN_AMT.

  We have an application that receives a DISPLAY_CODE and an EMP.  It automatically creates an sql statement in the sense of

  SELECT * FROM MY_VIEW WHERE DISPLAY_CODE =: 1 AND EMP =: 2

  and returns the output to the user.

  My challenge is that I need to rewrite MY_VIEW as follows:

  (1) (select the relevant lines from MY_ITEM_DISPLAY where DISPLAY_CODE =: 1)

  (2) select the relevant all MY_PAY_ITEMS lines that meet the criteria

  (a) EMP =: 2

  (b) PAY_PRD = (a more recent for EMP and sysdate, so if he got last paid 2010-04, return 2010-04)

  (c) KEY1 = (highest key1 in EMP and PAY_PRD)

  (d) KEY2 = (highest key2 in KEY1, PAY_PRD and EMP)

  (3) I then need to cross reference to create tabular output

  (4) Finally, I have to return a 0 line where there is no LN_ITEMs (DISPLAY_CODE 01, 40 sequence contains possible values for this scenario)

  The following query is part of it (but not the PAY_PRD, KEY1, KEy2)

  Select * from)

  SELECT A.DISPLAY_CODE

  B.EMP

  A.SEQUENCE

  , MAX (DECODE (B.LN_ITEM, A.COLUMN_ITEM1, B.ITEM_AMT, 0)) 'COL1 '.

  , MAX (DECODE (B.LN_ITEM, A.COLUMN_ITEM2, B.ITEM_AMT, 0)) 'COL2 '.

  , MAX (DECODE (B.LN_ITEM, A.COLUMN_ITEM3, B.ITEM_AMT, 0)) 'COL3 '.

  , MAX (DECODE (B.LN_ITEM, A.COLUMN_ITEM4, B.ITEM_AMT, 0)) 'COL4 '.

  OF MY_ITEM_DISPLAY A, MY_PAY_ITEMS B

  WHERE B.PAY_PRD = ' 2010-03'

  GROUP OF A.DISPLAY_CODE, B.EMP, A.SEQUENCE)

  WHERE DISPLAY_CODE = '01'

  AND EMP = '0000011'

  SEQUENCE ORDER

  My questions

  (1) how I do PAY_PRD, KEY1, KEY2 forced, can I use a form any of ROW_NUMBER() FUNCTION?

  (2) how can I deal with the fact that none of the 4 LN_ITEMS column can exist (see sequence 40, none of these can exist)...  Ideally the SQL above should return

  01, 0000011, 10, < a digit - > < number > - < a digit - > < some number >

  01, 0000011, 20, < a digit - > < number > - < a digit - > < some number >

  01, 0000011, 30, < a number--> < number > - < number > - < number > -

  01, 0000011, 40, 0, 0, 0, 0

  I tried a UNION, but it prevented the view to eliminate most of the MY_PAY_ITEMS lines, because it solves ALL MY_PAY_ITEMS instead of simply retrieve lines for the EMP passed to the view.  The same seems to be true for outer joins.

  Hi Paula,

  It does not handle SEQNUM 40, it's just that your second set of test data did not SEQNUM 40. When I put in the first set of values MY_ITEM_DISPLAY, I get:

  DISP EMP SEQUENCE COL1 COL2 COL3 COL4

  ---- -------- ---------- ---------- ---------- ---------- ----------

  01 00000011 10 101.1 103.1 105.1 104.1

  01 00000011 20 107.1 113.1 104.1 109,1

  01 00000011 30 101.1 104.1 109.1 99.99

  01 00000011 40 0 0 0 0

  If this isn't the issue, you will need to explain the requirement of "outer join" and what you want more. Apart from his return nothing if there is absolutely no element of remuneration of the employee, this query will always return a line for each line MY_ITEM_DISPLAY for the display_code. If there is absolutely no data, no return line seems reasonable.

• What is the Assembly of 4 or 5 tables FULL OUTER JOIN logic?

  the query is as below:
  
  as you can see, I need FULL OUTER JOIN, these 5 tables and get a column from each table that is based on three common columns (ORG_iD, CUST_ID, CURRENT_DT).
  
  And I wonder what is the logic of the 5 FULL OUTER JOIN table?
  It will return if there is a folder that exists in the single table COL1? or table, COL2 and COL3 and so on. Basically any combination of these 5 tables.
  
  

      SELECT (CASE WHEN COL1.ORG_ID IS NOT NULL THEN COL1.ORG_ID
                   WHEN COL2.ORG_ID IS NOT NULL THEN COL2.ORG_ID
                   WHEN COL3.ORG_ID IS NOT NULL THEN COL3.ORG_ID
                   WHEN COL4.ORG_ID IS NOT NULL THEN COL4.ORG_ID
                   ELSE COL5.ORG_ID 
              END) ORG_ID,
              (CASE WHEN COL1.CUST_ID IS NOT NULL THEN COL1.CUST_ID
                   WHEN COL2.CUST_ID IS NOT NULL THEN COL2.CUST_ID
                   WHEN COL3.CUST_ID IS NOT NULL THEN COL3.CUST_ID
                   WHEN COL4.CUST_ID IS NOT NULL THEN COL4.CUST_ID
                   ELSE COL5.CUST_ID
              END) CUST_ID, 
              (CASE WHEN COL1.CURRENT_DT IS NOT NULL THEN COL1.CURRENT_DT
                   WHEN COL2.CURRENT_DT IS NOT NULL THEN COL2.CURRENT_DT
                   WHEN COL3.CURRENT_DT IS NOT NULL THEN COL3.CURRENT_DT
                   WHEN COL4.CURRENT_DT IS NOT NULL THEN COL4.CURRENT_DT
                   ELSE COL5.CURRENT_DT 
              END) CURRENT_DT, 
            'VENDORS' as ITEM_NAME,
            V_AGE_IND as ACCT_AGE_IND,  
            COL1.AMT_ZSHT,  
            COL2.AMT_YFYS,  
            COL3.AMT_YFYS, 
            COL4.AMT_YFYS,  
            COL5.AMT_BZL,  
            'NAV',
            sysdate
      FROM COL1  
                FULL OUTER JOIN COL2 ON (COL1.ORG_ID=COL2.ORG_ID AND COL1.CURRENT_DT=COL2.CURRENT_DT AND COL1.CUST_ID=COL2.CUST_ID)  
                FULL OUTER JOIN COL3 ON (COL2.ORG_ID=COL3.ORG_ID AND COL2.CURRENT_DT=COL3.CURRENT_DT AND COL2.CUST_ID=COL3.CUST_ID)  
                FULL OUTER JOIN COL4 ON (COL3.ORG_ID=COL4.ORG_ID AND COL3.CURRENT_DT=COL4.CURRENT_DT AND COL3.CUST_ID=COL4.CUST_ID)  
                FULL OUTER JOIN COL5 ON (COL4.ORG_ID=COL5.ORG_ID AND COL4.CURRENT_DT=COL5.CURRENT_DT AND COL4.CUST_ID=COL5.CUST_ID)  

  Any ideas?
  
  Thank you

  Hello

  When you perform a JOIN EXTERNAL COMPLETE multi - build that way, whenever you add a new table, you can just join the previous table because this table could be all NULL values for a given row. You can reach each new table to the first table, either, for the same reason. You must enclose each new table with all previous tables, like this:

  FULL OUTER JOIN COL2 ON  COL2.ORG_ID     =           COL1.ORG_ID
                 AND COL2.CURRENT_DT =           COL1.CURRENT_DT
                 AND COL2.CUST_ID    =           COL1.CUST_ID
  FULL OUTER JOIN COL3 ON  COL3.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID)
                 AND COL3.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT)
                 AND COL3.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID)
  FULL OUTER JOIN COL3 ON  COL4.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID,     COL3.ORG_ID)
                 AND COL4.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT, COL3.CURRENT_DT)
                 AND COL4.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID,    COL3.CUST_ID)
  FULL OUTER JOIN COL3 ON  COL5.ORG_ID     = COLAESCE (COL1.ORG_ID,     COL2.ORG_ID,     COL3.ORG_ID,     COL4.ORG_ID)
                 AND COL5.CURRENT_DT = COALESCE (COL1.CURRENT_DT, COL2.CURRENT_DT, COL3.CURRENT_DT, COL4.CURRENT_DT)
                 AND COL5.CUST_ID    = COALESCE (COL1.CUST_ID,    COL2.CUST_ID,    COL3.CUST_ID,    COL4.CUST_ID)  
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements), and the results you want from this data.
  Explain how you get these results from these data.
  Always tell what version of Oracle you are using.

• Outer join

  Hi all

  I have a question where I need two outer join tables and there are a few filters based on the input parameters. In my example below, I need to know the difference between query 1 and 2. Query 1 does not have the data, but the fact of application 2. Please provide details

  CREATE TABLE test1 
  (
   col1 NUMBER(10),
   col2 VARCHAR2(10)
  );
  
  
  INSERT INTO test1 VALUES(1,'Demo');
  
  
  CREATE TABLE test2 
  (
   col1 NUMBER(10),
   col2 VARCHAR2(10)
  );
  
  
  INSERT INTO test2 VALUES(2,'Demo2');
  
  
  --Query 1
  SELECT * 
  FROM test1,test2
  WHERE test1.col1 = 1
  AND test2.col1(+) = 3;
  
  
  --Query 2
  SELECT * 
  FROM test1,test2
  WHERE test1.col1 = 1
  AND test2.col1(+) = 3
  AND test1.col1 = test2.col1(+);
  

  In your first query, you make a Cartesian (but with a weird syntax) product with a table with no line.
  If the result is nothing.

  In the second query you added a join condition and do a left outer join.

  If the result contains the rows in the left table.

  As you can see by simply adding a predicate with not enough to define a join.

  ANSI JOIN syntax would be that this is possible.

• Problem with XMLTABLE and LEFT OUTER JOIN

  Hi all.
  
  I have a problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns the correct result, but in 10g it doesn't, it is illustrated as a INNER JOIN.
  

  SELECT * FROM v$version;
  
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
  PL/SQL Release 11.2.0.1.0 - Production
  "CORE     11.2.0.1.0     Production"
  TNS for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  --test for 11g
  
  CREATE TABLE XML_TEST(
       ID NUMBER(2,0),
       XML XMLTYPE
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       1,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g1</id>
                           <dat>data1</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       2,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g2</id>
                           <dat>data2</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       3,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g3</id>
                           <dat>data3</dat>
                      </fields>
                      <fields>
                           <id>g4</id>
                           <dat>data4</dat>
                      </fields>
                      <fields>
                           <dat>data5</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4
  3     data5          

  This is all nice, now the problem:
  

  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
  PL/SQL Release 10.2.0.1.0 - Production
  "CORE     10.2.0.1.0     Production"
  TNS for HPUX: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  --exactly the same environment as 11g (tables and rows)
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4

  As you can see in 10g that I don't have the last row, it seems that Oracle 10 g does not recognize the LEFT OUTER JOIN.
  
  Is this a bug?, Metalink says that sometimes we can have an ORA-0600, but in this case there is no error results returned, just incorrect.
  
  Help, please.
  
  Kind regards.

  What about try the original Oracle method for outer joins? Using (+) without the extra space

  XMLTABLE(...COLUMNS ... id XMLTYPE PATH ... ) x,
  XMLTABLE(... PASSING x.id ...) (+) y
  

• outer join: difference between two queries

  Below two queries which should give the same results in my opinion. I want that all records of u_protocol and the pval.u_protocol_variable_value value if necessary.
  
  Why the outer join in query2 does not work as in query1?
  
  
  Query1:

  select p.u_protocol_id, i.u_protocol_variable_value
  from lims_sys.u_protocol p,
  (
     select pval.u_protocol_id, pval.u_protocol_variable_value
     from lims_sys.u_protocol_variable pvar, lims_sys.u_protocol_value_user pval
     where pvar.u_protocol_variable_id = pval.u_protocol_variable_id
     and pvar.name = 'VALUE_Protocol_Group'
  ) i   
  where p.u_protocol_id  = i.u_protocol_id (+)

  Query2:

  select prt.u_protocol_id, pval.u_protocol_variable_value
  from lims_sys.u_protocol prt, lims_sys.u_protocol_variable pvar, lims_sys.u_protocol_value_user pval
  where pvar.u_protocol_variable_id = pval.u_protocol_variable_id
  and prt.u_protocol_id = pval.u_protocol_id (+)
  and pvar.name = 'VALUE_Protocol_Group'

  Hello

  When you perform an outer join, all conditions on the tables in option must be outer join conditions. Otherwise, the effect is an inner join.
  There is one exception: cascade of outer joins, external-junction b of a and c is outside attached to b. In this case, in the b - c join only columns of c are marked with the sign +.

  Re - write to obtain the same results as query1, query2 like this:

  select  prt.u_protocol_id
  ,      pval.u_protocol_variable_value
  from     lims_sys.u_protocol          prt
  ,      lims_sys.u_protocol_variable     pvar
  ,      lims_sys.u_protocol_value_user pval
  where     pvar.u_protocol_variable_id (+)     = pval.u_protocol_variable_id     -- cascading outer join
  and     prt.u_protocol_id           = pval.u_protocol_id (+)
  and     pvar.name (+)               = 'VALUE_Protocol_Group'     -- (+) added
  ;
  

  I find the syntax ANSI easier to use for all the joins and much easier for outer joins.

• need help for an outer join query

  Hi friends...
  I have oracle 10g...
  I have a question which involve is joining three tables...
  
  the query is as follows:

  SELECT DISTINCT MU.MKT_ID                  "PAR ID",
                     MU.MKT_ID                  "ROOT ID",
                   MSU.SPEC_ID                "ID",
                 SU.SPEC_DESC                "DESC",
             SU.SPEC_CD          "SPEC CD"
  
                FROM IPOADM_BATCH.MKT_UV1        MU,
                       IPOADM_BATCH.MKT_SPEC_UV1   MSU,
               IPOADM_BATCH.SPEC_UV1       SU
  
                 WHERE MSU.MKT_ID  = MU.MKT_ID
             AND MSU.SPEC_ID = SU.SPEC_ID
           AND SU.SPEC_GRP_OR_CMPSTN_CD = 'C';

  in my front end application has some delete operations that removes specific data of the IPOADM_BATCH. MKT_SPEC_UV1 due to which the above query is nor fetch all rows.
  the relationship between the tables is clearly from the above query...
  
  I have the data in IPOADM_BATCH. MKT_UV1 and IPOADM_BATCH. Table of SPEC_UV1 after the delete operation
  
  now, I want the query above to retrieve data from IPOADM_BATCH. MKT_UV1 with small changes to the above query even if there is no data in IPOADM_BATCH. MKT_SPEC_UV1.
  
  I thought that if I use an outer join I can get it, but here I have to join three tables-join condition is based on the table that doesn't have a data...
  
  
  so please help me guys how can I change the query to get my desired out put...

  Hello

  There are several different things you could mean by it.

  Here's how to join the tables to get one of them:

  SELECT DISTINCT  mu.mkt_id                  "PAR ID",
                   mu.mkt_id                  "ROOT ID",
                   msu.spec_id                "ID",
                   su.spec_desc               "DESC",
                   su.spec_cd                   "SPEC CD"
  FROM           ipoadm_batch.mkt_uv1        mu
  LEFT OUTER JOIN      ipoadm_batch.mkt_spec_uv1   msu  ON   msu.mkt_id               = mu.mkt_id
  LEFT OUTER JOIN  ipoadm_batch.spec_uv1       su       ON   msu.spec_id              = su.spec_id
                                                AND  su.spec_grp_or_cmpstn_cd = 'C'
  ;
  

  If it does not matter what it is that you want, and then after a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) for all the tables and the results desired from these data.
  Highlight a few places where the above querry is the production of incorrect results of your sample data and explains how to get the correct results in these places.

• SSRS for lack of outer join with the Oracle data source

  It seems to be a problem with the Oracle driver used in the Reporting SERVICES query designer.

  When you use an Oracle data source, if I create an outer join in the graphic designer, it automatically inserts '{OJ' before the join and '} ' after her.  This is an incorrect syntax for Oracle and refuses to start.  The curly braces and the JO editable in designer text, but if I go back to the graphic designer and immediately to reintegrate them.

  Only, this has started to happen a year or two ago - before that it worked, but with the old (+) syntax.

  Can it not be healed?  It makes things very difficult.

  -Geoff

  Hi Geoff,

  Thanks for posting in the Microsoft Community.

  However, the question you posted would be better suited in the Forums of the Oracle Support; We recommend that you post your query in Oracle Support Forums to get help:

  https://forums.Oracle.com/forums/main.jspa;JSESSIONID=8d92100c30d8fb401bcbd10b46c38c9ddf1a3242549a.e34SbxmSbNyKai0Lc3mPbhmSc3aNe0? CategoryID = 84

  If you have any other questions or you need Windows guru, do not hesitate to post your questions and we will be happy to help you.

• Need help with outer join

  Hello

  I have a requirement in which I need to get data from a third table where a date of the third table is higher than a date in the second array.

  Ex:

  SELECT t1.column1, t3.column2
  FROM t1, t2, t3
  WHERE t1.id = t2.foreign_id
  AND t1.id ( + ) = t3.foreign_id
  AND t3.some_date_column > t2.another_date_column
  
  

  However, using the query above returns no results if the date condition is not met. I still need to show t1.column1 and a null t3.column2.

  How should I do this?

  Thank you

  Allen

  Edit: Added information about the requirement.

  Hi Allen

  1. SELECT t1.column1, t3.column2
  2. T1, t2, t3
  3. WHERE t1.id = t2.foreign_id
  4. AND t1.id = t3.foreign_id (+)
  5. AND t3.some_date_column (+) > t2.another_date_column

  I guess that this t1.column1 must not be null. Or am I wrong? The + sign must be placed on the side where draws are accepted. You must repeat it for each condition on the table.

  Alternativlely you can use the LEFT OUT JOIN syntax. If the two columns are allowed null you need a FULL OUTER JOIN.

  BTW: The join to t2 is not required if a refefernce constraint forced.

• need help with outer join filter.

  Need a little help to filter a result set and I can't seem to find a good way to do this.
  

  /*table*/
  
  create table invoice( farinvc_invh_code varchar2(100),
                                farinvc_item varchar2(100),
                                farinvc_po varchar2(100)
                                )
     create table po( 
          supplier_number varchar2(60),
          supplier_invoice_no varchar2(60),
          po_number varchar2(60),
          run_date varchar2(60),
          PO_LINE_NUMBER varchar2(60) );

  /*data*/
  
  INSERT INTO "INVOICE" (FARINVC_INVH_CODE, FARINVC_ITEM, FARINVC_PO_ITEM) VALUES ('I0554164', '1', 'P0142245');
  INSERT INTO "INVOICE" (FARINVC_INVH_CODE, FARINVC_ITEM, FARINVC_PO_ITEM) VALUES ('I0554164', '3', 'P0142245');
  INSERT INTO "INVOICE" (FARINVC_INVH_CODE, FARINVC_ITEM, FARINVC_PO) VALUES ('I0554165', '1', 'P0142246');
  INSERT INTO "INVOICE" (FARINVC_INVH_CODE, FARINVC_ITEM, FARINVC_PO) VALUES ('I0554165', '2', 'P0142246');
  
  
  
  
  
  INSERT INTO "PO" (SUPPLIER_NUMBER, SUPPLIER_INVOICE_NO, PO_NUMBER, RUN_DATE, PO_LINE_NUMBER) VALUES ('914100121', '529132260', 'P0142245', '21-NOV-12', '1');
  INSERT INTO "PO" (SUPPLIER_NUMBER, SUPPLIER_INVOICE_NO, PO_NUMBER, RUN_DATE, PO_LINE_NUMBER) VALUES ('914100121', '529137831', 'P0142245', '21-NOV-12', '3');
  INSERT INTO "PO" (SUPPLIER_NUMBER, SUPPLIER_INVOICE_NO, PO_NUMBER, RUN_DATE, PO_LINE_NUMBER) VALUES ('914100121', '529137831', 'P0142245', '21-NOV-12', '2');
  INSERT INTO "PO" (SUPPLIER_NUMBER, SUPPLIER_INVOICE_NO, PO_NUMBER, RUN_DATE, PO_LINE_NUMBER) VALUES ('914100122', '145678', 'P0142246', '22-NOV-12', '1');
  INSERT INTO "PO" (SUPPLIER_NUMBER, SUPPLIER_INVOICE_NO, PO_NUMBER, RUN_DATE, PO_LINE_NUMBER) VALUES ('914100122', '145679', 'P0142246', '22-NOV-12', '2');

  query execution of im.
  
  

  SELECT  farinvc_invh_code,
                  supplier_number,
                  supplier_invoice_no,
                  farinvc_item, 
                  farinvc_po ,
                  po_number,
                  run_date,
                  PO_LINE_NUMBER
          FROM INVOICE, PO
          WHERE PO_NUMBER = FARINVC_PO(+)
          AND FARINVC_ITEM(+) = PO_LINE_NUMBER
          

  result

  "FARINVC_INVH_CODE"           "SUPPLIER_NUMBER"             "SUPPLIER_INVOICE_NO"         "FARINVC_ITEM"                "FARINVC_PO"                  "PO_NUMBER"                   "RUN_DATE"                    "PO_LINE_NUMBER"              
  "I0554165"                    "914100122"                   "145678"                      "1"                           "P0142246"                    "P0142246"                    "22-NOV-12"                   "1"                           
  "I0554165"                    "914100122"                   "145679"                      "2"                           "P0142246"                    "P0142246"                    "22-NOV-12"                   "2"                           
  "I0554164"                    "914100121"                   "529132260"                   "1"                           "P0142245"                    "P0142245"                    "21-NOV-12"                   "1"                           
  "I0554164"                    "914100121"                   "529137831"                   "3"                           "P0142245"                    "P0142245"                    "21-NOV-12"                   "3"                           
  ""                            "914100121"                   "529137831"                   ""                            ""                            "P0142245"                    "21-NOV-12"                   "2"                           

  It is a much larger table, and I took an excerpt in order to keep things clear and understanding. I would like to filter the result set to only show lines that have po numbers are the same and line are the same but there is an additional element. in other words as such.

  "FARINVC_INVH_CODE"           "SUPPLIER_NUMBER"             "SUPPLIER_INVOICE_NO"         "FARINVC_ITEM"                "FARINVC_PO"                  "PO_NUMBER"                   "RUN_DATE"                    "PO_LINE_NUMBER"              
  "I0554164"                    "914100121"                   "529132260"                   "1"                           "P0142245"                    "P0142245"                    "21-NOV-12"                   "1"                           
  "I0554164"                    "914100121"                   "529137831"                   "3"                           "P0142245"                    "P0142245"                    "21-NOV-12"                   "3"                           
  ""                            "914100121"                   "529137831"                   ""                            ""                            "P0142245"                    "21-NOV-12"                   "2"                           

  Hello

  Let me assure you that I understand.
  Last time, we were looking for the PO_NUMBERs who have been partially put into correspondence , i.e. groups of rows in the order table with the same po_number, which some had corresponding lines in the table Bill, and some of whom have not. It was essential that there is at least 1 line and 1 row without connections with the same purchase order.
  Now that you are interested SUPPLIER_INVOICE_NOs who are partially paired, i.e. groups of rows in the table of po with the same po_number and supplier_invoice_no, some of which have corresponding lines in the invoice table, and some are not. ("Supplier_Invoice_No" is quite a mouthful. "We'll abbreviate as sin in the future.) However, the final selection is based on po_numbers: If a po_number has partially matched sins, then we are interested all po_number. For example, the result set must include = 529132260 SIN, even if that sin is completely, because there is a partially matching sin (529137831) with the same po_number (P0142245).

  As this problem revolves around partially matching sins, let's call them Cardinal sins . We can calculate match_cnt and total_cnt based NAS as well as po_number. Then, we can use another analytic function so see if the po_number has all cardinal_sins, like this:

  WITH    joined_data     AS
  (
       SELECT     i.farinvc_invh_code
       ,     p.supplier_number
       ,     p.supplier_invoice_no
       ,     i.farinvc_item
       ,     i.farinvc_po
       ,     p.po_number
       ,     p.run_date
       ,     p.po_line_number
       ,     COUNT (i.farinvc_po) OVER ( PARTITION BY  p.po_number
                                          ,                  p.supplier_invoice_no
                             )     AS match_cnt
       ,     COUNT (*)           OVER ( PARTITION BY  p.po_number
                                          ,                  p.supplier_invoice_no
                                        )     AS total_cnt
       FROM           po       p
       LEFT OUTER JOIN  invoice  i  ON   i.farinvc_po    = p.po_number
                                    AND  i.farinvc_item  = p.po_line_number
  )
  ,     got_cardinal_sin_cnt     AS
  (
       SELECT  joined_data.*
       ,     SUM ( CASE
                      WHEN  match_cnt  >= 1
                   AND     match_cnt  <  total_cnt
                   THEN  1
                  END
                ) OVER (PARTITION BY  po_number)     AS cardinal_sin_cnt
       FROM    joined_data
  )
  SELECT    farinvc_invh_code
  ,       supplier_number
  ,       supplier_invoice_no
  ,       farinvc_item
  ,       farinvc_po
  ,       po_number
  ,       run_date
  ,       po_line_number
  FROM       got_cardinal_sin_cnt
  WHERE       cardinal_sin_cnt     > 0
  ORDER BY  po_number
  ,            farinvc_item
  ;
  

• whenever I try to load need for speed underground 2, I get this error with vista can someone help me figure out please. __

  Problem event name: APPCRASH
  Application name: need for Speed Underground 2.exe
  Application version: 0.0.0.0
  Application timestamp: 417d8e48
  Fault Module name: need for Speed Underground 2.exe
  Fault Module Version: 0.0.0.0
  Timestamp of Module error: 417d8e48
  Exception code: c0000005
  Exception offset: 001d24c0
  OS version: 6.0.6001.2.1.0.256.1
  Locale ID: 1033
  Additional information 1: a613
  More information 2: 55689aa387c807ab900bd44bfa935768
  3 more information: b5ed
  Additional information 4: d06b121c03be15a74ebeeadaf13834df

  Hi Leinenweaverp,

  Welcome to Microsoft Vista answers Forum!

  I would like to ask you a few questions in order to get a better understanding of this issue.

  ·         Were you able to load this game before and play on it?

  Here are some steps that may help you.

  First of all, I suggest that you perform a clean boot on the computer and install the game and make sure if you are able to load the game and play on it, you can start Windows Vista by using a minimal set of drivers and startup programs. This type of boot is known as a "clean boot". A clean boot helps eliminate software conflicts.

  The following link has steps showing how to perform the clean boot: http://support.microsoft.com/kb/929135

  (1) perform the clean boot (check the link to perform the clean boot)

  (2) enable half the services

  (3) determine whether the problem returns

  (4) enable half of the startup items

  (5) determine if the problem returns

  (6) repeat the steps above until you find out which program or service is causing the issue

  After you determine the startup item or the service that is causing the problem, contact the manufacturer of the program to determine if the problem can be solved. Or, run the System Configuration utility, and then click to clear the check box of the element of the problem.

  Reset the computer to start as usual:

  When you are finished troubleshooting, follow these steps to reset the computer to start as usual:

  1. click on start, type msconfig.exe in the start search box and press ENTER.

  If you are prompted for an administrator password or for confirmation, type your password, or click on continue.

  2. on the general tab, click the Normal startup option, and then click OK.

  3. When you are prompted to restart the computer, click on restart.

  If the problem persists, I suggest that you contact the manufacturer of the game for further assistance, you can check the link: http://www.nfscars.net/home/index.aspx

  Hope this information is useful.

  Thank you, and in what concerns:
  Swathi B - Microsoft technical support.
  Visit our Microsoft answers feedback Forum and let us know what you think.

• Help for a LEFT OUTER JOIN query

  Hello, all,.

  I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.

  Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:

  tableA
  blogID        blogTitle       blogBody      dateEntered
  1             This is a test  More text...  2016-05-20 11:11:11
  2             More testing    Still more!   2016-05-19 10:10:10
  3             Third charm!!   Blah, blah.   2016-05-18 09:09:09
  

  tableC
  commID        userID          userText      dateEntered
  10            Bravo           I like it!    2016-05-20 11:21:31
  11            Charlie         I don't!      2016-05-20 11:31:51
  12            Alpha           Do it again!  2016-05-19 10:20:30
  13            Bravo           Still more?   2016-05-19 10:30:50
  14            Charlie         So, what?     2016-05-19 10:35:45
  15            Bravo           Blah, what?   2016-05-18 09:10:11
  16            Alpha           Magic number! 2016-05-18 09:11:13
  

  tableB
  blogID        commID
  1             10
  1             11
  1             12
  2             13
  2             14
  3             15
  3             16
  
  
  
  

  I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry.  But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.

  Here is an example of pseudo-SQL of what I'm trying.

  SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total
  FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID
                LEFT OUTER JOIN tableC c ON c.commID = b.commID
  WHERE a.blogID = '1'
  GROUP BY blogID, blogTitle, blogBody
  ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
  

  I'm sure it's something simple, but I just DO NOT see it.  Can you help me?

  V/r,

  ^_^

  Try:

  GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
  

  See you soon

  Eddie

• Looking for right outer join help

  Hello

  Can anyone help me re - write the query using right below outer join (join ansi) instead of using the (+) symbol.

  Select cd.sku_id waitm,

  Decode (cl.invn_lock_code, NULL, 'OH', cl.invn_lock_code) WLOCN,

  Sum (CD.actl_qty) WQOH

  cd, a.case_lock cl, a.case_hdr ch, a.item_master im a.case_dtl

  where cd.case_nbr = ch.case_nbr

  and cl.case_nbr (+) = ch.case_nbr

  and cd.sku_id = im.sku_id

  and ch.stat_code < = '64'

  Cd.sku_id group,

  IM.sku_brcd,

  Decode (cl.invn_lock_code, NULL, 'OH', cl.invn_lock_code)

  order of cd.sku_id

  Kind regards

  Gannu

  Maybe something like this:

  of a.case_dtl cd

  Join a.case_hdr ch on (cd.case_nbr = ch.case_nbr)

  Join a.item_master im on (cd.sku_id = im.sku_id)

  join a.case_lock cl left (cl.case_nbr = ch.case_nbr)

  where ch.stat_code<=>

  I know you asked for right outer join, but I tend to write like that.  You can certainly change if you wish.