Need help to parse a string in data

Similar Questions

• Need help to split a string

  Hello

  IM needing help to cut a string like this... A, B, C, ADV, RAHEEM, MOUSTAFA, Gauthier,... compare letters he's be numbers, but I get by using a string... Need to divide and put each number into a vector, in all positions...

  Can someone help me?  ..

  I'm using labview 6...

  Here is the screenshot of my logic...

  Hi faelnpaiva,

  all you need is 'String of spreadsheet in table' with a ',' as the delimiter.

  

• Need help pulling a name string

  Hello I'm on Oracle 11 GR 1 material and have a strings of data like these:
  
  SMITH, KAY C. RN, FNP
  WESTON, DEBRA, L
  ASH, CHRISTOPHER, J., PA - C
  EYEBROWS, CATHERINE J MSN NOCD
  ASH, MICHELLE
  NASH, BOB MC T MD
  BROWN-JONES, LARRY RN
  
  I need to enter these:
  LAST_NAME
  FIRST NAME
  MI
  CODE (the first one)
  
  So, if we where to watch again the data after it is pulled apart, I would like to see this:

   
  LAST_NAME     FIRST_NAME     MI    CODE 
  SMITH         KAY            C     RN 
  WESTTON       DEBRA          L       
  ASH           CHRISTOPHER    J     PA-C 
  BROW          CATHERINE      J     MSN 
  ASH           MICHELLE 

  That's what I have (this code will be executed on an external Table with 1.5mil lines):

   
  select 
      substr('SMITH, KAY C. RN, FNP',1,instr('SMITH, KAY C. RN, FNP',',')-1) as LAST_NAME, 
      regexp_substr(SMITH, KAY C. RN, FNP', '[^, ]+ ') as FIRST_NAME 
  from dual; 

  I don't know how to get the rest.
  
  Thanks for any help
  
  Published by: Sky13 on September 23, 2011 12:04
  I added a few samples more

  Hello

  Look at the data and try to find some patterns. You will not be able to get everything right, but you may be able to make the most of them.
  I would look for things:
  There always at least 1 comma in the chain? Are you sure that what comes before the (first) comma is always a name?
  When there are 2 commas, codes never come before the 2nd comma?
  Codes always come after the names?
  What parts are sometimes missing? How many times they lack?
  Never just 1 character codes?
  Some codes occur very frequently?
  Is this practice to create a table of the most common codes, or even all the codes?

  It will be much easier in PL/SQL.
  You can write a procedure which takes 1 IN argument (the plain text) and 5 on arguemnts:
  (1) first name
  (2) first name
  (3) other initial
  (4) code
  (5) a number indicating what is the probability that the results are correct. For example, 100 may indicate a very simple string, such as "Dyer, Mary. You can print the with the lowest number for some person to review manually.

  Good luck!

• Need help with SQL/PL/SQL for Dates

  Hi Experts - need help with a SQL query.

  I need to insert some date fields in a table called CALENDAR_PERIOD.

  Current data in CALENDAR_PERIOD table with their data types:

  STARTPERIOD (DATE) YEAR (NUMBER) PERIOD_LABEL (Varchar2 255)

  02/11/2014 2014 2014/02/11 SUN

  03/11/2014 2014 14/03/11 MON

  04/11/2014 2014 11/04/14 MAR

  I have to increment above values up to the year 2025. I don't know how to write SQL and increment of these values.

  Ex: My next value should insert: 05/11/2015 2014 11/05/14 WED like that I need to insert data until 12 31, 2025.

  Can you please help me with PL/SQL block?

  Really appreciate your help!

  DB version:

  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  PL/SQL Release 11.2.0.3.0 - Production

  CORE Production 11.2.0.3.0

  AMT for IBM/AIX RISC System/6000: Version 11.2.0.3.0 - Production

  NLSRTL Version 11.2.0.3.0 - Production

  Thank you
  Sandy

  Hello Sandy,

  Maybe something like

  INSERT INTO calendar_period (startperiod, year, period_label)

  SELECT DATE '' 2014-11-04 + LEVEL

  , TO_NUMBER (TO_CHAR (DATE '' 2014-11-04 + LEVEL, "YYYY"))

  , TO_CHAR (DATE '' 2014-11-04 + LEVEL, "MM/DD/YY DY")

  OF the double

  CONNECT BY LEVEL<= date="" '2025-12-314="" -="" date="">

  ;

  ((mais je ne comprends pas pourquoi nous créons une telle table "année" et "period_label" peuvent être calculé à partir de startperiod))

  Best regards

  Bruno Vroman.

• Need help to parse the xml string to populate the drop-down list

  Here is my: problem

  I have a hidden text field that contains the text of an xml

  <>facilities
  < building >
  < name > Building A < / name >
  < name > building B < / name >
  < name > building C < / name >
  < name > building D < / name >
  < name > building E < / name >
  < name > building F < / name >
  < name > building G < / name >
  < name > building H < / name >
  < / build >
  < / facilities >

  My goal is to read this with JavaScript xml string to populate a drop-down list with values of element (name). Does anyone know how script that?

  Attached is a sample .xdp

  See you soon,.

  Jesse

  Here is an example of change. I put the code click on the button, so you can see it in operation... You can place this code in the event that makes sense for you. I also added another field to show the DOM (this is for debugging purposes and you can remove this field if you want).

  Paul

• Need help with a Citadel of DIAdem data store opening.

  Hello

  I was wondering if someone can help me to connect to a Citadel of DIAdem data store. I've read all the online help and cannot operate.

  On my PC, I use DIAdem v11.1 and v6.1 Lookout installed as a plugin. I am trying to connect to a data of Citadel store 5 on a server visible in the image below, specifically the default database on HPSERVER1. The installation of MAX on HPSERVER1 tells me that there are 2 versions of LabVIEW Run-Time installed, 8.2.1 and 9.0.1 (I don't know if this is relevant).

  

  When I select \\hpserver1\default_database, I then set the properties as follows:

  

  In the Advanced section, I'm the deadline set to 90 seconds. When I hit OK, then I get the following message, which then brings back me to the previous screen.

  

  Any help is very appreciated,

  David.

  Hi David,

  6.2 Lookout CLIENT is for people who do not have installed Lookout but still want to connect to a database of Citadel with DIAdem.  This works for databases Citadel created by Lookout as long as those created by LabVIEW DCS, is said by the way.

  In your case, you have already installed Lookout, you don't need this additional client software.  There is no improvement in functionality in this interface between 6.1 and 6.2, so you do not miss anything, and youre data import is already working.

  I don't know about lookout not appearing is not in the License Manager, etc.  I'm sorry.

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• Need help saving the computer to paste data in Vista

  I want to back up my computer to a data key.  I followed the instructions until I got to the bit where I need to plug in the stick and two ports, it came on J: /.  How to locate the E: / drive?

  Thank you.

  Carol

  * original title - E: / drive - how can I find? *

  If the stick is confirmed as J:\ disc, why you need it to be drive E:\?  Just use the drive letter assigned to it and you'll be fine.

  If you want to know about drive E:\ (whatever it is), and then click Start / Contol Panel / administrative tools / computer management / disk management and search for E:\ drive.  If she's not here, I don't know how to explain why the system has assigned drive J:\ to the key, but it makes no real difference he'll change from computer to computer depending on what is installed (but it willl always be able to access).

  I hope this helps.

  Good luck!

  Lorien - MCSA/MCSE/network + / has + - if this post solves your problem, please click the 'Mark as answer' or 'Useful' button at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.

• How to parse a string to date

  Hello

  I have the string as Wednessday, June 13, 2009 | 12 AM GMT, I want to analyze and convert data type Date. I did the same on J2SE, but class SimpleDateFormat does not parse method in RIM API.

  Please suggest.

  Thank you

  RJ

  If you are looking for an answer on how to do it in Java, you're the best post your question in the Java development forums.

• Need help for the conversion of the Date

  Hi all

  Your expert input is much appreciated.

  Have a problem where it is my master table structure, whenever there is an update/delete/insert on the main table
  There's a trigger that insert an entry in the Audit table.
  
  SQL > cpp_Master Desc;
  Number of Ent_id
  Date of Ent_date
  
  SQL > Desc Cpp_Master_Audit
  Number of Ent_id
  Date of Ent_date,
  Insert_type varchar2 (1)
  
  The problem is that when we insert the Sub record in the table, the ent_date column appears in this way.
  
  SQL > INSERT INTO CED.cpp_Master (ENT_ID, Ent_date)
  VALUES (6030902, TO_DATE (1 JANUARY 01 00:00:00 ', ' HH24: PUT DD/MM/YYYY "));

  SQL > SELECT * FROM CED.cpp_Master;

  6030902 01/01/0001

  SQL > SELECT * FROM CDS. Cpp_Master_Audit;

  6030902 01/01/0001

  But when I update the date is coming up as below

  SQL > update ced.cpp_Master set Ent_date = to_date (' 1 March 01', ' dd-mon-YYYY "") where ent_id = '6030902';
  SQL > commit;

  Tried under updates so

  (

  Update ced.cpp_Master set Ent_date = ' March 1 01' where ent_id = '6030902';

  Update ced.cpp_Master set Ent_date = to_char (' 1 March 01', ' dd-mon-YYYY "") where ent_id = '6030902';

  )

  Whenever the output below always. (Insert has no problem, just update a problem)

  I wonder why when there is an insertion of the date value is "01/01/01" in (Cpp_Master_Audit), but when I update the date value is "01/01/2001" ".

  I need the value to insert as "01/01/01", as all that was updated in Master table (Cpp_Master)

  SQL > SELECT * FROM CED.cpp_Master;

  6030902 01/01/2001

  
  
  My request to trigger:
  
  CREATE OR REPLACE TRIGGER CDS. CPP_AUDT
  AFTER INSERT OR UPDATE OR DELETE
  ON CED.cpp_Master REFERENCING OLD AS OLD AGAIN AS NEW
  FOR EACH LINE
  DECLARE
  l_action_code VARCHAR2 (1);
  BEGIN

  IF THE INSERTION
  THEN
  l_action_code: = 'I ';
  ELSIF UPDATE
  THEN
  l_action_code: = 'U ';
  ON THE OTHER
  l_action_code: = ';
  END IF;

  IF (l_action_code = 'I'
  OR l_action_code = '
  OR (l_action_code = 'U'
  AND (NVL (: OLD.)) ENT_ID, 0) NVL <>(: NEW.) ENT_ID, 0)
  OR NVL (TO_CHAR (: OLD.)) Ent_date, ' mm/dd/yyyy'),
  'X') <>
  NVL (TO_CHAR (: NEW.)) Ent_date, ' mm/dd/yyyy'),
  « X »)
  )))
  THEN
  INSERT IN DEC. () Cpp_Master_Audit
  ENT_ID, Ent_date, Insert_type
  )
  VALUES (DECODE (: OLD.ent_id, NULL,: NEW.ent_id,: OLD.ent_id),)
  DECODE (l_action_code, 'I',: NEW.) Ent_date, 'd', NULL, 'U', DECODE (: NEW.) Ent_date,: OLD. Ent_date, NULL,: NEW. Ent_date)),
  Insert_type l_action_code);

  END IF;
  END;
  /

  You wrote that ent_date is of type DATE

  SQL > cpp_Master Desc;

  Number of Ent_id

  Date of Ent_date

  so DO NOT fill with a chain, but with a date, and you have correct data in it.

  This:

  Update ced.cpp_Master set Ent_date = 1 March 01 ' where ent_id = '6030902';

  is simply wrong that fill you your column DATE with a string and your NUMBER column with a string filter too.
  

  
  

  Use

  Update ced.cpp_Master

  Set Ent_date = TO_DATE('01-MAR-0001','DD-MON-YYYY') where ent_id = 6030902;

  and you will have no problems (as long as the NLS_DATE_LANGUAGE parameter is set correctly to support abbreviations English months)

  HTH
  

• Need help with the code to add dates to form

  Hello fans forum

  I am new to make forms and understood how to auto add the date, but I need the shape to change the date for each copy made.

  For example, is today 08/06/2012 if I print 10 copies of the form it will display 10 pages from 08/06/2012 to 17/06/2012. If the code exists for this I would be very gratefull to one who helps, I also wouldn't mind if this is not possible for manually inputing start / end dates.

  Currently I have print 15-30 copies of the form and hand write each of the dates but I get just to busy to do it. Also I can't print one a day, it must be in batches.

  Thanks in advance.

  I think that you misunderstood my comment about the Console window. Please see the Console window tutorial link in my previous answer. The Acrobat JavaScript Console window is internal to Acrobat, so there is no system restrictions that may prevent you from using it. It's a perfect place to run short automation scripts that do things like print separate copies.

  George also underscores a great solution, put the script in a (non-printable) button on the document itself. However, due to security restrictions this solution can be a bit tricky, but no more so than using the Console window. Each solution takes a little extra effort.

  The problem with having multiple pages, it's that you must manually create a document with pages already in it.  It is certainly a feasible solution, it comes you limit the number of pages that you have already created manually.  At least one solution AcroForm. If you re-create your form as a dynamic LiveCycle, then creating new pages on the fly is not a problem.

  None of these solutions will work fine, the real trick is to increment the date.

  Here's a short script that begins with today's date and adds a day for each iteration of the loop and then prints

  One day in milliseconds

  var nOneDay = 24 * 60 * 60 * 1000;

  var nToday = (new Date()) .getTime ();

  for (var i = 0; i)<>

  {

  oTheDate = new Date (nToday + i * nOneDay);

  Date format

  cTheDate = util.printd("mm/dd/yyyy",oTheDate);

  this.getField("MyDate").value = cTheDate;

  This.Print)

  }

  This same loop could be used to fill in a form on the page - multi (repeated) fields.

  Using the util.scand () function, this loop could be setup to start at an arbitrary date.

  See you soon,.

• [Help] Need help to remove a string in the text file

  Hi all

  I have a text like this

  REPORT

  Wednesday, June 10, 2015 14:31:56

  **********************************************************************************

  HOST: 10.9.1.185

  TestVM is turned off

  **********************************************************************************

  HOST: 10.9.0.84

  All virtual machines are turned off

  **********************************************************************************

  HOST: 10.9.0.85

  **********************************************************************************

  HOST: 10.9.0.86

  I want to remove the

  **********************************************************************************

  HOST: 10.9.0.85

  **********************************************************************************

  HOST: 10.9.0.86

  because there is no information after the HOST 10.9.0.85 or: 10.9.0.86

  It will reduce the content of the report

  I need a script to delete this text

  Could someone help me?

  Thank you for your help

  What generates the report? It is probably easier to just do not write to the file in the first place...

• Need help to try to "include vector data" when you save an EPS? Anyone?

  Although I've done several times before, I just can't understand why the checkbox "include vector data" is grayed out.  I work in CMYK mode - I placed my business as a smart object as usual - logo and none of my layers have applied effects.  Scratching my head right now.  It is a format large poster so I will certainly need to fix this somehow.  Any guidance would be greatly appreciated.

  You must have a layer with a vector mask applied to the function is displayed.

• Need help with the query string manipulation

  Hello
  
  With the help of 10.1.0.4.2
  
  Given a table called PREFIX_CODES that contains a column called PREFIX_CODE
  with the following data:
  
  PREFIX_CODE - VARCHAR2 (20)
  -------------------
  AAA
  BENAMER
  CARTER
  
  and another table called SUBSCRIBERS with a column called SUBSCRIBER_ID
  with the following data:
  
  SUBSCRIBER_ID - VARCHAR2 (30)
  ---------------------
  BBBB-123456
  AAA-444444
  DD-2222222
  EEEE-888888
  
  Is there a query that will pull all the SUBSCRIBER_ID that begin with
  each of the PREFIX_CODES? The following query is not valid, but it
  This will give you an idea of what I'm trying to do:
  
  SELECT SUBSCRIBER_ID
  SUBSCRIBERS
  WHERE AS SUBSCRIBER_ID (SELECT PREFIX_CODE |) » %'
  OF PREFIX_CODES)
  
  Using the data from above, I would like that the query to return:
  
  BBBB-123456
  AAA-444444
  
  Thanks for your help!

  Hello

  Welcome to the forum!

  You were on the right track. To find if a given subscriber corresponds to any prefix_code, you can do an EXISTS subquery:

  SELECT     subscriber_id
  FROM     subsribers     s
  WHERE     EXISTS ( SELECT  NULL
                    FROM      prefix_codes
             WHERE      s.subscriber_id     LIKE prefix_code || '%'
              )
  ;
  

  This will tell you if at least a prefix code. It won't tell you exactly how many, or what they were.
  Your message, I'm guessing that there may be more than one, and you can deduct the subscriber_id itself, then the above query should work for you.

• Need help to split the string into two fields

  Can someone share your thoughts by dividing the prod_info string below into two fields

  For example:-TABLE of PROD

  SOURCE TABLE

  SNO	PROD_INFO
  1	20 OZ SIMILAC
  2	HW PRO 10
  3	REX 10 OZ
  4	AAA 10
  5	BBB 2000
  6	CCC 10 LB
  7	DDD 2021
  8	EE 12 KG
  9	KK 11111
  10	ZZ ABC FAC 11
  11	RKW DD CC 12 OZ
  12	12KJ 12 LBS.

  EXPECTED RESULTS

  SNO	PROD_INFO	PROD_VAL
  1	SIMILAC	20 OZ
  2	HW PDR	10
  3	REX	10 OZ
  4	AAA	10
  5	BBB	2000
  6	CCC	10 LB
  7	DDD	2021
  8	EA	12 KG
  9	KK	11111
  10	AEC ABC ZZ	11
  11	RKW DD CC	12 OZ
  12	12KJ	12 LBS.

  with

  as Prod

  (select 1 sno, "SIMILAC 20 OZ" prod_info of all the double union)

  Select 2, 'HW PDR 10' from dual union all

  Select 3, 'REX 10 OZ' from dual union all

  Select option 4, "AAA 10' from dual union all

  Select 5, "BBB 2000"of the dual union all

  Select 6, 'CCC 10 LBS' double union all

  Select 7, 'DDD 2021' from dual union all

  Select 8, 'EE 12 KG' from dual union all

  Select 9, 'KK 11111' Union double all the

  choose 10, "ZZ ABC FAC 11' from dual union all

  Select 11, 'CC DD RKW 12 OZ' from dual union all

  Order 12, '12KJ LB 12' double

  )

  Select sno,

  (prod_info regexp_substr(prod_info,'^((\d*|\w*)[^[:digit:]].*) \d',1,1,null,1).

  regexp_substr (prod_info,' prod_value (\d+.*)$',1,1,null,1))

  Prod

  SNO	PROD_INFO	PROD_VALUE
  1	SIMILAC	20 OZ
  2	HW PDR	10
  3	REX	10 OZ
  4	AAA	10
  5	BBB	2000
  6	CCC	10 LB
  7	DDD	2021
  8	EA	12 KG
  9	KK	11111
  10	AEC ABC ZZ	11
  11	RKW DD CC	12 OZ
  12	12KJ	12 LBS.

  Concerning

  Etbin

• Need help with debugging case manipulation statement &amp; date

  Hi people,
  
  Can you get it someone please let me know what I am doing wrong?
  
  Select to_date (23-seven.-10', 'DD-MON-yy') expiry_date,.
  TO_DATE (23-sep-09', 'DD-MON-yy') order_date,.
  TO_DATE (23-seven.-10', 'DD-MON-yy')-to_date (23-sep-09', 'DD-MON-yy') diff,.
  (case diff
  When < 365 then 'low '.
  When > 365 then 'high '.
  other 'similar '.
  end)
  Double;
  
  
  ORA-00936: lack of expression
  00936 00000 - "missing expression.
  * Cause:
  * Action:
  Error on line: column 5:18
  
  
  Thanks in advance
  
  rogers42

  Here you go

  WITH temp_tab AS
      (SELECT to_date('23-sep-09',      'DD-MON-yy') order_date,
           to_date('23-sep-10',      'DD-MON-yy') -to_date('23-sep-09',      'DD-MON-yy') diff,
           to_date('23-sep-10',      'DD-MON-yy') expiry_date
       FROM dual)
  SELECT(
  CASE
  WHEN diff < 365 THEN 'low'
  WHEN diff > 365 THEN 'high'
  ELSE 'same'
  END)
  FROM temp_tab;