Need of a query:-Urgent

Similar Questions

• Urgent need for sql query

  Hi all
  Sorry I can't speak English very well
  =======================
  I have a table that contains two columns
  table name: total_sal
  column name: hire_date
  column name: salary
  
  table syntax
  
  create table total_sal (hire_date date
  number (6.2)) of salary;
  _________________________________________
  Example of data in table format
  
  hire_date | salary
  01/01/2011 | 1000
  01/02/2011 | 2000
  01/05/2011 | 500
  01/09/2011 | 400
  
  
  I NEED a SQL QUERY to display the table, as in this example
  
  OF | TO|||||||||||| TOTALSALAY
  01/01/2011 | 01/02/2011 | 3000
  07/05/2011 | 01/09/2011 | 900
  |||||||||||||||||||||||||||||||||| 3900

  /* Formatted on 9/23/2011 10:14:40 AM (QP5 v5.149.1003.31008) */
  WITH t
          AS (SELECT TO_DATE ('1/1/2011', 'mm/dd/yyyy') hire_date, 1000 salary
                FROM DUAL
              UNION
              SELECT TO_DATE ('2/1/2011', 'mm/dd/yyyy'), 2000 FROM DUAL
              UNION
              SELECT TO_DATE ('5/1/2011', 'mm/dd/yyyy'), 500 FROM DUAL
              UNION
              SELECT TO_DATE ('9/1/2011', 'mm/dd/yyyy'), 400 FROM DUAL)
  SELECT "From", "To", totalsalary
    FROM (SELECT hire_date "From",
                 LEAD (hire_date) OVER (ORDER BY hire_date) "To",
                 salary + LEAD (salary) OVER (ORDER BY hire_date) totalsalary,
                 ROW_NUMBER () OVER (ORDER BY hire_date) rn
            FROM t)
   WHERE MOD (rn, 2) = 1
  UNION ALL
  SELECT NULL, NULL, SUM (salary) FROM t
  

  From     To     TOTALSALARY
  1/1/2011     2/1/2011     3000
  5/1/2011     9/1/2011     900
            3900
  

• Need help for query flat_file type clobdata oracle table data.

  Hi Sir,
  
  I need help to query oracle table flat file data having given clob type.
  

  Oracle Version:
  
  Oracle Database 10g Express Edition Release 10.2.0.1.0 - Product
  PL/SQL Release 10.2.0.1.0 - Production
  "CORE     10.2.0.1.0     Production"
  TNS for 32-bit Windows: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  
  
  Source table
  
    CREATE TABLE order_details 
     (     QUEUE_SEQNUM NUMBER(10,0) NOT NULL ENABLE, 
       LINE_SEQNUM NUMBER(10,0) NOT NULL ENABLE, 
       CHAR_DATA CLOB, 
       OPTIMISTIC_LOCK_KEY NUMBER(20,0)
     ) 

  COLUMN FOR CHAR_DATA FLAT_FILE
  

  EU,6067AT,AT10,000000402004,NexiumGERDManagementProject,Z435,,ZZ29,NIS-GOLD,AT
  EU,6067AT,AT10,000000402038,NIS-OEU-ARI-2007/1,Z450,,ZZ29,NIS-OEU-ARI-2007/1,AT
  EU,6067AT,AT10,000000402039,SymbicortNISinCOPD,Z450,,ZZ29,NIS-REU-DUM-2007/1,AT
  EU,6067AT,AT10,000000402040,D1443L00044SeroquelXRRuby,Z450,,ZZ29,D1443L00044,AT
  EU,6067AT,AT10,000000402041,NIS-GEU-DUM-2008/1,Z450,,ZZ29,NIS-GEU-DUM-2008/1,AT
  EU,6067AT,AT10,000000402042,SonstigeAktivitätenLCM,Z450,,ZZ29,.,AT
  EU,6067AT,AT10,000000402134,D1680L00002Saxagliptin,Z450,,ZZ29,D1680L00002,AT
  EU,6067AT,AT10,000000402199,SeroquelWaveNIS,Z450,,ZZ29,NIS-NEU-DUM-2009/1,AT
  EU,6067AT,AT10,000000402313,SeroquelExtra(D1443L00082),Z450,,ZZ29,D1443L00082,AT
  EU,6067AT,AT10,000000402517,AtlanticD5130L00006(AZD6140),Z450,,ZZ29,D5130L00006,AT
  EU,6067AT,AT10,000000554494,ArimidexSt.Gallen(13+2),Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554495,ArimidexASCO(5delegates),Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554496,ArimidexSanAntonio6delegates,Z142,,ZZ09,,AT
  EU,6067AT,AT10,000000554497,ArimidexBreastCancerSummit(13+2),Z130,,ZZ09,,AT
  EU,6067AT,AT10,000000554498,ArimidexEIH(15delegates),Z130,,ZZ09,,AT
  EU,6067AT,AT10,000000554499,ArimidexNIFA(200delegates),Z135,,ZZ09,,AT
  EU,6067AT,AT10,000000554500,ArimidexNIFAworkshops(8x25),Z135,,ZZ09,,AT
  EU,6067AT,AT10,000000554501,ArimidexPraktischeGyn.Fortbildung,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554502,ArimidexAGO,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554503,ArimidexHämato/OnkologieKongress,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554504,ARIMIDEXGYNäKOLOGENKONGRESS,Z147,,ZZ09,,AT
  EU,6067AT,AT10,000000554505,ArimidexChirurgenkongress,Z147,,ZZ09,,AT

  EXPECTED RESULTS:
  

  AFFIRM_CODE COMPANY_CODE INTERNAL_ORDER_CODE INTERNAL_ORDER_DESC ENIGMA_ACTIVITY             SUB_ACTIVITY_CODE IN_AFF_IND ORDER_TYPE EXTERNAL_ORDER COUNTRY        
  EU          6067AT       AT10                 000000402004       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT             
  EU          6068AT       AT11                 000000402005       NEXIUMGERDMANAGEMENTPROJECT     Z435           NULL        ZZ29       NIS-GOLD        AT             

  Sorry, my bad. Without database at hand, I'll try 'baby steps' (borrowed from Frank) so you don't confuse it with errors that I might add (happens far too often already, but at least you won't "swallow" as forum members think is one of the main goals of this fighter - help her learn - providing not only the proverbial fish.)
  Search the Forum - your problem is one of its best sellers. Watching {message identifier: = 10694602} ("split string into" was the key word used in research) you can try something as

  select table_row,
         level clob_row,
         regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) the_line
    from (select to_char(queue_seqnum)||':'||to_char(line_seqnum) table_row,
                 char_data
            from order_details
         )
   connect by regexp_substr(char_data,'[^' || chr(13) || chr(10) || ']+',1,level) is not null
          and prior char_data = char_data
          and prior table_row = table_row
          and prior sys_guid() is not null
  

  to get all the s the_lineall CLOB and after that the use of the example even to get your columns of each the_line.

  Concerning

  Etbin

  Edited by: Etbin on 3.2.2013 09:01

  .. .but I m connected to do things according to the instructions, I can't do something.

  Used to happen to me too and I did as told to the but only after explaining any disadvantages, I was aware of in time. The last sentence is usually: "O.K. now be just and Don't come back with that kind of thing when it turns out that this isn't the right thing."
  rp0428 post - something to remember.

• Need to SQL query to filter records by limited rows and certain condition

  Hello guru (s).
  
  I need a SQL query for help.
  For an example table t1 as below, I want to find the maximum of 5 larger, but there should be no more than 2 name of the same position. The "BOLD" is the response of desire.
  
  Name Position size
  N1 P1 5
  N2 P2 50
  N3 P3 500
  N4 P1 6
  N5 P2 60
  N6 P3 600
  N7 P1 7
  N8 P2 70
  N9 P3 700
  
  Thank you.

  not tested!

  select name,position,size,
    from (select name,position,size,
                 row_number() over (order by size desc) a_count
            from (select name,position,size,
                         row_number() over (partition by position order by size desc) a_count
                    from your_table
                 )
           where a_count <= 2
         )
   where a_count <= 5
  

  Concerning

  Etbin

• Need help with query SQL Inline views + Group

  Hello gurus,
  
  I would really appreciate your time and effort on this application. I have the following data set.
  
  Reference_No---Check_Number---Check_Date---description---Invoice_Number---Invoice_Type---Paid_Amount---Vendor_Number
  1234567 11223 - 05/07/2008 -paid for cleaning- 44345563-I-* 20.00 *---19
  1234567 11223 - 05/07/2008 - 44345563 -a--10,00---19 ofbad quality adjustment
  7654321 11223 - 05/07/2008 - setting the last billing cycle - 23543556 - A - 50.00 - 19
  4653456 11223 - 05/07/2008 - paid for cleaning - 35654765 - I - 30, 00-19
  
  Please ignore '-' added for clarity
  
  I'm writing a paid_amount based on Reference_No, Check_Number, Payment_Date, Invoice_Number, aggregate query Invoice_Type, Vendor_Number and display description with Invoice_type 'I' when there are multiple records with the same Reference_No, Check_Number, Payment_Date, Invoice_Type, Invoice_Number, Vendor_Number. When there are no more records I want to display the respective Description.
  
  The query should return the following data set
  
  Reference_No---Check_Number---Check_Date---description---Invoice_Number---Invoice_Type---Paid_Amount---Vendor_Number
  1234567 11223 - 05/07/2008 -paid for cleaning- 44345563-I-* 10.00 *---19
  7654321 11223 - 05/07/2008 - setting the last billing cycle - 23543556 - A - 50.00 - 19
  4653456 11223 - 05/07/2008 - paid for cleaning - 35654765 - I - 30, 00-19
  Here's my query. I'm a little lost.
  
  Select b., A.sequence_id, A.check_date, A.check_number, A.invoice_number, A.amount, A.vendor_number
  de)
  Select sequence_id, check_number, check_date, invoice_number, sum (paid_amount) sum, vendor_number
  of the INVOICE
  Sequence_id group check_date, check_number, invoice_number, vendor_number
  ) A, B OF INVOICE
  where A.sequence_id = B.sequence_id
  
  
  Thank you
  Nick

  It seems that this is a duplicate thread - correct me if I am wrong in this case->

  Need help with query SQL Inline views + Group

  Kind regards.

  LOULOU.

• Need help with query

  Have the rank as below,

  name of the sum

  100 A1

  -A2 200

  A3 300

  50 A1

  -A2 700

  A3 80

  10 A1

  -A2 90

  30 A3

  Need to query to extract the output like this:

  B1                     B2

  A1 + a3 (Sum) A2 (sum)

  Please help me out of this...

  Hello

  It is difficult to understand what you want... A guess based on many assumptions:

  -B1 and B2 are column headers,
  -"A1 + A3" and "A2" in the 'exit' is simply to indicate that you want the sum of the amounts for the first names.

  -Some of the AI have all their amounts > = 0, others have their amounts<=>
  -You want to make the sum of all positive numbers in the first column and all the negatives in the second column

  SELECT SUM (GREATEST (0, t.amount)) b1

  , B2 SUM (LESS (0, t.amount))

  MYTABLE t

  ;

  (I think there is only a bit of luck it's really what you want, but provide a full test case and the output that you really want and why not, try to explain / explicit rules, then we can give better help)

  Best regards

  Bruno Vroman.

• need of a query

  I have a requirement...

  I have to delete the data in a table that is not present in another table

  I wrote a query like this

  remove a and b where not EXISTS (select account_id of aaa where a.account_id = b.acc);

  I need a query without using the EXISTS operator...

  No, you can not join, but you actually do what needs to be done using a correlated subquery.

  What is the problem you're trying to solve?  You can reach both what you want, what is the problem with the help of these EXISTS and IN?

• Need to extract query text in each row tags

  I need to display a list of tags used in particular the text for each line. After sample data can give clear you the idea.

  DB version:

  ========

  Oracle Database 11 g Enterprise Edition Release 11.2.0.4.0 - 64 bit Production

  Sample data:

  ==========

  WITH txt_data AS)

  SELECT the 1 id, txt "your price #toy_name # is #price_amt #.» FROM DUAL

  UNION ALL

  SELECT id 2, "it's product tag #pdt_tag #." It is a client #clt_tag tag # and finally this notice tag #adv_tag #. ' txt FROM DUAL

  UNION ALL

  SELECT 3 id, "Hi Mr. #clt_name #." txt FROM DUAL

  )

  SELECT * FROM txt_data;

  Power required:

  ============

  ID	TAGS
  1	#toy_name #, #price_amt #.
  2	#pdt_tag #, #clt_tag #, #adv_tag #.
  3	#clt_name #.

  To implement this I used the technique of factoring of the recursive subquery for a static data (row). Seen the query below.

  WITH tag_list (ip_str, case, tag) as)

  SELECT ' this is product #pdt_tag tag #. It is a client #clt_tag tag # and finally this notice tag #adv_tag #. ' AS ip_str, 0 accident AS, null AS tag FROM DUAL

  UNION ALL

  SELECT ip_str, here + 1, REGEXP_SUBSTR (ip_str, ' (#. *?)) (#)', 1, case + 1) OF tag_list WHERE REGEXP_SUBSTR (ip_str, ' (#. *?)) (#)', 1, case + 1) IS NOT NULL

  ), SELECT WMSYS. WM_CONCAT (tag) OF tag_list WHERE case > 0;

  But when I use this technique for the data in the table, it gives me the error. Given below.

  WITH txt_data AS)

  SELECT the 1 id, txt "your price #toy_name # is #price_amt #.» FROM DUAL

  UNION ALL

  SELECT id 2, "it's product tag #pdt_tag #." It is a client #clt_tag tag # and finally this notice tag #adv_tag #. ' txt FROM DUAL

  UNION ALL

  SELECT 3 id, "Hi Mr. #clt_name #." txt FROM DUAL

  )

  SELECT t.id,

  (WITH tag_list (ip_str, case, tag) as ())

  SELECT t.TXT AS ip_str, 0 accident AS, null AS tag FROM DUAL

  UNION ALL

  SELECT ip_str, here + 1, REGEXP_SUBSTR (ip_str, ' (#. *?)) (#)', 1, case + 1) OF tag_list WHERE REGEXP_SUBSTR (ip_str, ' (#. *?)) (#)', 1, case + 1) IS NOT NULL

  ), SELECT WMSYS. WM_CONCAT (tag) OF tag_list WHERE case > 0) as tags

  OF txt_data t.

  ORA-00904: "T". "" TXT ": invalid identifier

  00904, 00000 - '% s: invalid identifier '.

  * Cause:

  * Action:

  Error on line: column 50: 17

  Issues related to the:

  ----------------

  1. help reach my goal (with your own logic, whatever my technique)

  2. What is the problem with my technique above? Cannot use us WITH the clause in the selection list?

  Thanks in advance

  Personally I would rewrite the expression of regexp as ' #[^ #] * #'

  In addition, we can get rid of the place where the main expression

  with tag_list (ip_str, case, tag) as)

  SELECT TXT AS ip_str, 1 match AS

  REGEXP_SUBSTR(txt, '#[^#]*#', 1, 1) AS tag

  of txt_data

  UNION ALL

  SELECT ip_str, here + 1

  , REGEXP_SUBSTR (ip_str, ' #[^ #] * #', 1, case + 1)

  OF tag_list

  WHERE REGEXP_SUBSTR(ip_str, '#[^#]*#', 1, occurrence + 1) IS NOT NULL

  )

  SELECT

  ip_str

  , listagg (tag, ',') within the Group (by instance) s

  OF tag_list

  Ip_str group

  Finally, you can save a regexp_substr

  with tag_list (ip_str, case, tag) as)

  SELECT TXT AS ip_str, 1 match AS

  REGEXP_SUBSTR(txt, '#[^#]*#', 1, 1) AS tag

  of txt_data

  UNION ALL

  SELECT ip_str, here + 1

  , REGEXP_SUBSTR (ip_str, ' #[^ #] * #', 1, case + 1)

  OF tag_list

  )

  cycle tag cyl set default 1 0

  SELECT

  ip_str

  , listagg (tag, ',') within the Group (by instance) s

  OF tag_list

  Ip_str group

• need help hard query

  Hello

  I'm trying to find out who is the manager who have more number of carried forward under him of emp table

  can you please help me how to find... I searched the forum and I tried some queries but does not work...

  Thank you

  ASP.

  Hello

  You need to display the results of the sample such that people who want to help you can recreate the problem and test their ideas.  Do you think that people can run what you posted?  You must post CREATE TABLE and INSERT statements or equivalent SB.

  Once more, if you use a commonly available table, for example scott.emp, just say.

  Explain how you get these results.  For example, "when I say 'Manager', I mean the employee identified in the mgr column; It does not matter if job = 'MANAGER' or not.  In this issue, I'm only interested in direct subordinates.  For example, the KING (empno = 7839) is Manager, directly or indirectly, the other 13 lines in the table, but only 3 of these lines have mgr = 7839.  There are 5 lines having mgr = 7698 (for BLAKE), so I want BLAKE rather than KING. »

  Here's a way to do it:

  WITH got_rnk AS

  (

  SELECT m.empno, m.ename, m.job - or other columns of your choice

  EARL of (e.mgr) AS reportee_count

  , EVALUATE () OVER (ORDER OF COUNT (*) / / DESC) AS rnk

  FROM scott.emp m

  LEFT OUTER JOIN scott.emp e ON e.mgr = m.empno

  GROUP OF m.empno, m.ename, m.job

  )

  SELECT reportee_count, empno, ename

  OF got_rnk

  WHERE rnk = 1

  ;

  Exit from scott.emp (in the case that is different from what you have posted);

  EMPNO, ENAME, JOB REPORTEE_COUNT

  ---------- ---------- --------- --------------

  7698 BLAKE MANAGER 5

  If there be a tie for the line with the majority of direct reports, the above query will display all the contenders.

• I need help for query AVG

  I need help with a simple query in an ORACLE database. I tried a lot of things that I found on the internet, but none of them worked for me.

  The following query retrieves four lines:

  SELECT sampled_date AS VALUE1, VALUE2 AS result, 0 as value3

  Of asw_lab

  WHERE template_result = 'A' AND analysis = 'B' AND ROWNUM < 5

  ORDER BY sampled_date DESC;

  I would like to calculate a moving average of the last four values with the date of the sample of the last line.

  For example, I have this result for the query above:

  Value1 value2 value3

  01/04/14-16:00 1 0

  01/04/14 15:00 2 0

  01/04/14 14:00 3 0

  01/04/14 13:00 4 0

  I want to extract the below my average/query calculation result:

  Value1 value2 value3

  01/04/14-16:00 2.5 0

  Can you help me create a request to that effect?

  Thank you

  Maybe it's

  Select max (VALUE1) VALUE1, VALUE2 avg (VALUE2), avg (VALUE3) value3

  Of

  (

  SELECT sampled_date AS VALUE1, VALUE2 AS result, 0 as value3

  Of asw_lab

  WHERE template_result = 'A' AND analysis = 'B' AND ROWNUM<>

  )

• Need help with query Cumulative difference

  Hi all

  I need help with a query and my requirement is as below

  {code}

  ROWNO

  ORDERS

  VALUE

  1	10	900
  2	11	700
  3	12	500
  4	13	400

  {/ code}

  I have need to query which will display the cumulative difference for example I value tell 10000 numbers opening

  now I need for each of the lines of cumulative difference

  {code}

  ROWNO ORDERS DIFF

  1 10 10000 - 900 = 9100

  2 11 9100 - 700 = 8400

  3 12 8400 - 500 = 7900

  4 13 7900 - 400 = 7500

  {/ code}

  WITH commands LIKE (10 SELECT order_id, 900 double UNION ALL val
  11. SELECT, 700 FROM dual UNION ALL
  SELECT 12, 500 FROM dual UNION ALL
  Select 13, 400 double)

  SELECT row_number() over (ORDER BY order_id ASC) AS rowno
  order_id
  sum (val) 10000 - OVER (ORDER BY order_id ASC) AS diff
  orders

  /

  HTH

• Need help for query joining views

  Hi all

  I need to run a query that joins a number of tables with multiple instances of the same view.  For example, a view named MY_VALUES, is an array of key / value resembles the following:

  Application_ID Attirbute_Description value

  1 1 000 basic benefit

  1 multiplier 1 0.5

  1 Multiplier_2 1.2

  1 total profit 1,115

  2 1 025 basic benefit

  2 multiplier 1 0,268

  2 Multiplier_2 1.3

  Total profit 2 1.4500

  Say I want a query that selects basic earnings and a multiplier 1 for Application ID 1, as well as, other information from a table called APPLICATION that has a relationship to display pk - fk. I would do the following:

  Select the application. Name, mv1.value, mv2.value

  from dbo. App APPLICATION, dbo. MY_VALUES mv1, dbo. Mv2 MY_VALUES

  where app.id = mv1.application_id and mv1.attribute_description = "Basic benefits"

  and app.id = mv2.application and mv2.attribute_description = id 'multiplier 1'.

  and app.id = 1

  My actual query is similar to this. However, I have many other attributes of the notice I need to select, which requires that the view be attached to several times. After 16 these joins, the request is fine. After 17, however, the query runs always, never return a result within 45 minutes I have let it run.

  Is there a better way to write such a request or an indicator of optimization that would be useful here?

  Any help is greatly appreciated.

  ....

  For this type of application, it is often best to extract multiple lines in a single request on the view and their pivot in the output.

  For example

  Select the application. Name

  , max (CASE when mv.attribute_description = "Core service" then mv.value any other purpose) BaseBenefit

  , max (CASE when mv.attribute_description = 'Multiplier 1' then mv.value any other purpose) Multiplier1

  , max (CASE when mv.attribute_description = 'Multiplier 2' then mv.value any other purpose) Multiplier2

  , max (CASE when mv.attribute_description = 'Multiplier 3' then mv.value end to another null) Multiplier3

  from dbo. App APPLICATION, dbo. MY_VALUES mv

  where app.id = mv1.application_id

  and mv.attribute_description IN ('benefits of home', 'multiplier 'multiplier 'multiplier 3' 2' 1')

  and app.id = 1

  This runs often much better than several joins to the table for the view or the value of the attribute.

• Need a SQL query

  Hi friends,

  Can someone me posts sub queries SQL:

  1 need a query to find locked users and name of the table to each scheme.

  2. a query need to know the user using tables in each schema.

  Thank you

  Lazar T

  Hello

  1. What do you mean under the user table and it is locked?

  2 search for locked objects

  SELECT a.sid,a.serial#, a.username,c.os_user_name,a.terminal,
b.object_id,substr(b.object_name,1,40) object_name,sysdate
from v$session a, dba_objects b, v$locked_object c
where a.sid = c.session_id
and b.object_id = c.object_id

  ----

  Ramin Hashimzde

• Need a sql query to get several dates in rows

  Hi all

  I need a query to get the dates of the last 7 days and each dates must be in a line...

  but select sysdate double... gives a line...

  Output of expexcted

  Dates:

  October 1, 2013

  30 sep-2013

  29 sep-2013

  28 sep-2013

  27 sep-2013

  26 sep-2013

  Try:

  SQL > SELECT sysdate-7 + LEVEL FROM DUAL

  2. CONNECT BY LEVEL<=>

  3 * ORDER BY 1 DESC

  SQL > /.

  SYSDATE-LEVEL 7 +.

  -----------------------------

  October 1, 2013 13:04:52

  30 - Sep - 2013 13:04:52

  29 - Sep - 2013 13:04:52

  28 - Sep - 2013 13:04:52

  27 - Sep - 2013 13:04:52

  26 - Sep - 2013 13:04:52

  25 - Sep - 2013 13:04:52

  7 selected lines.

• Need of below query output

  WITH rcv_transactions 
       AS (SELECT 1001      TRANSACTIONS_ID, 
                  -1        PARENT_TRANSACTION_ID, 
                  'RECEIVE' TRANSACTION_TYPE, 
                  NULL      LPN_ID, 
                  'LPN01'   TRANSFER_LPN_ID 
           FROM   dual 
           UNION ALL 
           SELECT 1002, 
                  1001, 
                  'DELIVER', 
                  'LPN01', 
                  'LPN01' 
           FROM   dual 
           UNION ALL 
           SELECT 1003, 
                  -1, 
                  'RECEIVE', 
                  NULL, 
                  'LPN01' 
           FROM   dual) 
  SELECT * 
  FROM   rcv_transactions; 
  
  My output for the above query is 
  
  transactions_id   parent_transaction_id   transaction_type     lpn_id     transfer_lpn_id
  ---------------------------------------------------------------------------
  1001                        -1                          receive                                 lpn01
  1002                    1001                           deliver                  lpn01      lpn01
  1003                         -1                         receive                                lpn01
  
  
  I want the output as below:
   TRANSACTIONS_ID,   PARENT_TRANSACTION_ID,  TRANSACTION_TYPE,     LPN_ID,     TRANSFER_LPN_ID, 
  1003                                    -1                                   RECEIVE                                   LPN01
  
  i.e., I want the transactions id which are only 'receive' and not 'deliver' for the particular transfer_lpn_id
  
  in the above scenario 1001 is received and delivered in 1002. 
  
  But 1003 is only received. so  I need the output of 1003

  WITH rcv_transactions AS (SELECT 1001 TRANSACTIONS_ID,
                                   -1 PARENT_TRANSACTION_ID,
                                   'RECEIVE' TRANSACTION_TYPE,
                                   NULL LPN_ID,
                                   'LPN01' TRANSFER_LPN_ID
                              FROM DUAL
                            UNION ALL
                            SELECT 1002,
                                   1001,
                                   'DELIVER',
                                   'LPN01',
                                   'LPN01'
                              FROM DUAL
                            UNION ALL
                            SELECT 1003,
                                   -1,
                                   'RECEIVE',
                                   NULL,
                                   'LPN01'
                              FROM DUAL)
  SELECT *
    FROM rcv_transactions rcv_out
   WHERE rcv_out.transaction_type = 'RECEIVE'
         AND NOT EXISTS
                (SELECT 1
                   FROM rcv_transactions
                  WHERE parent_transaction_id = rcv_out.TRANSACTIONS_ID)