Need to separate the line using regexp_replace, when there is no string "<; BR >;".
Hello
This is the first time I post on this forum. Currently I have some data in a column, for example:
AMF PICK STITCHING 1/16 < BR > NO CUSTOM IMITATION BTNHOLE < BR > < BR > TAG
What I want to do is to divide it when it hits < BR > he actually makes a new line and removes the < BR >, so it should eventually appear as follows:
AMF PICK STITCH 1/16
NO IMITATION BTNHOLE
CUSTOM LABEL
I have the following, but it does not work:
with the trial as
(select 'AMF PICK STITCH 1/16 < BR > No. IMITATION BTNHOLE < BR > LABEL PERSONALIZED < BR > ' double str)
)
Select regexp_substr (str, ' [^ < BR >] +', 1, rownum) alteration
of the test
connect by level < = length (regexp_replace (str, ' [^ < BR >] + "")) + 1
I am currently on Oracle 11 g and PL/SQL developer coding.
It is not quite clear what you want.
Either you want 3 lines or a line with 3 breaks.
[^
] May not be what you want it to be.
It defines a list of characters is not a match.
Thus, each <,>, B, R, would be a step match independently as part of the
.
What you might try is:
Select regexp_substr (str '(.*?)
1, level, null, 1) alteration
of the test
connect by level<= regexp_count="" (str,="">=>
')
If you want 3 ranks as the result.
,>
Tags: Database
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