number greater than 1

Similar Questions

• PHP make every number greater than the previous one by 2

  Hello! I want to enlarge my numbers by 2 like 2,4,6,8

  Here is the code I use:

  <? PHP

  $X = 5;

  While ($X < = 40) {}

  echo "$X < br / > ';

  $X++;

  }

  ? >

  and thanks for any help!

  I do not know Murray response is ALMOST correct (probaby just the. in the wrong place) but for now:

  $X = $X + 2;

• Number greater than varchar

  Hello
  I have a field in my application that allows users to enter a maximum of 20 characters, the field is persisted as varchar2 (20). When a user enters a value such as '34656', I get a jdbc exception, saying that the data could not be saved because the actual size of the data is 46 and the maximum is only 20. How can I fix it?
  
  Thank you.

  Hi natet.

  Looks like you continue on the wrong field in the varchar2 column (20)?

  Concerning
  Peter

• Display a value in the column only if the number is greater than 1

  I need to return a value in the only if column the the count is greater than 1 for the same column.

  Example table:

  FOOD_TYPE	Agenda	COST_TO_BUY	SELL_PRICE
  Ice cream	Chocolate	0.50	2.00
  Ice cream	Vanilla	0.50	2.00
  Ice cream	Strawberry	0.50	2.00
  Chicken	Wings	2.00	5.00
  Bovine meat	Steaks	8.00	15 h 00
  Bovine meat	Roast	10 h 00	6:00 pm

  In this example, I want to choose the POINT of FOOD_TYPE, SUM (COST_TO_BUY) AND SUM (SELL_PRICE), but I want only to select the ITEM if there is more than 1 points in the FOOD_TYPE.

  I tried all kinds of grouping and even including a case statement in select it as follows:

  CASE

  WHEN (COUNT (DISTINCT POINT) > 1)

  THEN THE POINT

  ELSE "

  END

  However, this is denied when I group because it forces me to use the POINT as a group and I can't use the set statement in the GROUP BY because it has an aggregate function.

  Help, please!

  with

  power as

  (select food_type 'Beef', 'Steaks' article, cost_to_buy 8.00 15.00 sell_price of all the double union)

  Select 'Beef', 'Roast', 10.00, 18.00 double Union all

  Select 'Chicken', 'Wings', 2.00, 5.00 double Union all

  Select 'Ice Cream', 'Chocolate', 0.50, 2.00 double Union all

  Select "Ice Cream", "Vanilla", 0.50, 2.00 double Union all

  Select "Ice Cream", "Strawberry", 0.50, 2.00 double

  )

  Select food_type 'Type of food. "

  cases where the head (separate) over (partition food_type) > 1 then end point "Item,"

  TO_CHAR (cost_to_buy, 'fm990.00') "Purchase cost"

  TO_CHAR (sell_price, 'fm990.00') 'selling price '.

  food

  food_type desc order

  Food Type	Item	Purchase cost	Sell Price
  Ice cream	Chocolate	0.50	2.00
  Ice cream	Strawberry	0.50	2.00
  Ice cream	Vanilla	0.50	2.00
  Chicken	-	2.00	5.00
  Bovine meat	Roast	10 h 00	6:00 pm
  Bovine meat	Steaks	8.00	15 h 00

  Concerning

  Etbin

• Keyboard failure - numbers greater than my letters on the kyboard quit working

  numbers greater than my letters on the kyboard stop working. nowwhen I pressed number it shows to whatever key I pressed last

  This sounds like a problem of keyboard input buffer . There are a number of issues pending with the keyboard buffer caused by software such as constant guard or GuardIDencryption. If you have installed the encryption of typing software, especially Comcastconstant guard, I can't recommend disabling/uninstalling software or specific assistance in support of the software publisher's web site.

• The APK from the version code must be greater than 100088

  Hello.

  When I tried to build android build phonegap apk I get this error since the game of google publish:

  The APK from the version code must be greater than 100088

  It's my config.xml file:

  <? XML version= "1.0" encoding= ' utf - 8'? >
  "" <widget id= "appname.app" version= "1.1.0" xmlns= 'http://www.w3.org/ns/widgets"" " xmlns:gap="http://phonegap.com/ns/1.0""">

  Version 1.1.0 of Penny, it was 1.0.8

  Thank you!

  You are (or were) more likely using the gradle build tool. It's OK, but the number of versioncode (not the version string!) it messes up.

  Game Google wants your versioncode higher because of gradle 100088 increases quickly.

  Including a

  preference

  with name =

  Android-versionCode

  and the value =

  100089

  in your config.xml file and rebuild.

• give meaning to cases where minimum effective_start_date is greater than the current date

  Hi guys, I'm not a developer oracle as such, but I'm trying to get some information from oracle to send to other systems of the company, since we are dealing with oracle HRMS as the master system for employee information.

  In particular, we would like to create people in our training and the security system when they are created in oracle.

  I was told that the oracle per_all_people_f object acts as a slowly changing dimension of type 2, where a person can have several versions, which only is always the current version and the current version can be retrieved using the standard parttern of "date of current between the effective start date and actual end date. So far so good.
  
  However, I can see there are cases where the minimum 'effective_start_date' is greater than the current date. It is, indeed, equal to their start_date. I guess start_date represents "the first day of work" of the person.

  But this means then there is no "current" information known to people who have not yet really started working for the company again. This seems odd. How can I have someone for whom we have no information "currently correct? I was told that the effective_start_date of the line is automatically set to their "first day of work" date on which the information is entered into the system, IE, the user to enter information doesn't have the ability to say 'this is the current version of the data for that person, who starts at a date in the future. "

  For this reason, I cannot know these new people (who have been entered in oracle, but did not have actually to their first day of work still) training system. But we would obviously get people established in related systems so that they can use all of these systems on their first day of work.

  Have I misunderstood something here? How can there be no correct version for a person at the date and time?

  Hello

  How normally "inform you" the training system on a new person record? If it's a kind of report or an interface, it may be useful changed to examine a number of days in the future, for example + 7

  It is important to understand when you look at an Oracle HRMS instance through enforcement (i.e. the ' front end'), you look at the data on a date date (of the session) - by default, the date is the system date, but it is possible for a user to change this date to be in the future or the past as they see fit. The ability to implement the records in person in the future is a great feature to have, of course, but it must be understood that in this situation, at the date of the day the person's file logically does not exist yet from the point of view of the MFC features. Behind the scenes, however, in the per_all_people_f of the table, the line exist. Similarly, future update of changes to a person (e.g. marital status from Single to married) could be implemented, and the change in status would be visible if the session has been scheduled on a date or after the date of the marriage. As correctly observe you, behind the scenes, the table will hold all historic entries for this person_id with contiguous effective_start_date and effective_end_date beaches.

  Either way, date_start value is not related to as such hiring date; It is actually the value of effective_start_date earlier for the person_id. All changes, regardless of how many or what the effective_start_date is in each case, will always carry this same start_date value. It * may * be identical to the hiring date (certainly the fact that you configure their hire date person records would cause that), but if the person has been created as a postulant effective from 1 September and was then hired has effect from 21 September, column start_date value would be still 1 September. The record of the person would be visible when the current date is on or after this date - the only difference is that they show that an employee until the 21st.

  I hope this helps, but it is possible, that I just confused you more!

  Clive

• Google app renewed the question. The APK from the version code must be greater than 1000000

  Hello

  I am updating a previous AIr based Android app with a new version.

  I got the following error

  The APK from the version code must be greater than 1000000.

  
  

  The problem is that I carefully replace the application version number, but it keep gave me this address.

  
  

  Any clue?
  

  OK, found the solution

  I had to add several ZERO to the version number to be able to successfully download the APK

• By selecting a row if count is greater than 4

  Hello
  
  I use Oracle 10.2.0.4.0 version
  

  CREATE TABLE DMM.QUES
  (
    CASENAME        VARCHAR2(100 BYTE),
    CASENUMBER      VARCHAR2(20 BYTE),
    COVERAGE        VARCHAR2(10 BYTE),
    DIVISIONNUMBER  VARCHAR2(6 BYTE),
    CLASSNUMBER     number,
    TIER            VARCHAR2(2 BYTE),
    MONTHLYRATE     NUMBER
    )

  INSERT orders

  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','health', '456J','123',null,.25)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','dental', '456J','123','ee',.45)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','dental', '456J','123','es',.45)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','dental', '456J','123','ec',.46)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','dental', '456J','123','fa',.49)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','life', '456J','123',null,.49)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','life', '456J','123',null,.49)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','life', '456J','123','cc',.34)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','life', '456J','123','dd',.49)
  insert into QUES (CASENAME,CASENUMBER,  COVERAGE,  DIVISIONNUMBER,  CLASSNUMBER,  TIER,MONTHLYRATE)
  values ('ABC','123J','life', '456J','123',null,.55)

  Select * from c
  

  ABC     123J     health     456J     123          0.25
  ABC     123J     dental     456J     123     ee     0.45
  ABC     123J     dental     456J     123     es     0.45
  ABC     123J     dental     456J     123     ec     0.46
  ABC     123J     dental     456J     123     fa     0.49
  ABC     123J     life     456J     123          0.49
  ABC     123J     life     456J     123          0.49
  ABC     123J     life     456J     123     cc     0.34
  ABC     123J     life     456J     123     dd     0.49
  ABC     123J     life     456J     123          0.55

  Power required

  ABC     123J     health     456J     123          0.25
  ABC     123J     dental     456J     123     ee     0.45
  ABC     123J     dental     456J     123     es     0.45
  ABC     123J     dental     456J     123     ec     0.46
  ABC     123J     dental     456J     123     fa     0.49
  ABC     123J     life     456J     123          0.49

  for a combination of classnumber and coverage, if count is greater than 4 then I must return only one record.
  in the example above 123/Life, we have a number of 5. so I need to show that a single folder and can be any folder.
  
  Please let me know where I can read on other similar examples.
  
  Thanks in advance.

  This:?

  SQL> select casename, casenumber, coverage, divisionnumber, classnumber, tier, monthlyrate
    from (select q.*,
                 count (*) over (partition by classnumber, coverage) cnt,
                 row_number () over (partition by classnumber, coverage order by 1) rn
            from ques q)
   where cnt <= 4
      or (cnt > 4
      and rn = 1)
  /
  CASENAME             CASENUMBER                     COVERAGE        DIVISIONNUMBER CLASSNUMBER TIER MONTHLYRATE
  -------------------- ------------------------------ --------------- -------------- ----------- ---- -----------
  ABC                  123J                           dental          456J                   123 fa           .49
  ABC                  123J                           dental          456J                   123 ec           .46
  ABC                  123J                           dental          456J                   123 es           .45
  ABC                  123J                           dental          456J                   123 ee           .45
  ABC                  123J                           health          456J                   123              .25
  ABC                  123J                           life            456J                   123              .55
  
  6 rows selected.
  

• Find the minimum value in digital array that is greater than 0

  So far I have;

  $pfpp = min ($pflist);

  $pflist is the array of digital values and contains about 0.

  I need to change to $pfpp = min ($pflist); to return the lowest number which is greater than zero.

  I am stuck, can anyone help?

  Thank you

  Change the values in the table so I can't sort them in ascending order.

  Of course you can.  Or you can copy the table into a temporary array.

  $temp = $pflist;

  sort ($temp, SORT_NUMERIC)

  foreach ($temp as $value) {}

  If $value > 0; $number = $value; break;

  }

  echo "entry of zero smaller in pflist is $number";

• Password length must be greater than 6

  Dear people,
  I use Oracle 10 g when trying to create a form. I have a namesly of PASSWORD.when user text field to provide the password length must be greater than 6 a message alert will be lifted out.accordingly I wrote the following code in WHEN-VALIDATE-ITEM as follows.
  

  declare
       a number;
  begin
       if length(:block3.text_item5) <= 6 then
            a:=show_alert('ALERT19');
            clear_item;
       end if;
       end;

  Its working fine.but, my need is if the length of the password is less than 6, it should display the alert message and control should turn to the same element, and the element must be cleared.but since I wrote this in W-V-I control trigger moves to the next item.how to avoid it? What trigger should I use instead of this WHEN-VALIDATE-ITEM trigger? pls suggest me.
  
  
  Regarding
  Vids

  Hello
  You cannot use CLEAR_ITEM/FIELD in WHEN-VALIDATE-ITEM trigger because it is the restricted procedure see Help Forms.

  You can try you code like below.

  declare
        a number;
  begin
        if length(:block3.text_item5) <= 6 then
             a:=show_alert('ALERT19');
             :block3.text_item5:=NULL;
             RAISE FORM_TRIGGER_FAILURE;
        end if;
  end;
  

  -Clément

• How to create a default profile for all users of a computer under Windows 7/Vista for Firefox versions greater than 8? I would that all new users on a computer to get the same values by default, homepage, bookmarks, etc...

  I found some help on older versions of Firefox, but I can't seem to find anything for the latest versions greater than 8. There must be a way to do this for imaging large scale.

  Have you created a defaults\profile in the folder of the program Firefox (C:\Program Files\Mozilla Firefox\)?

  All files in this folder will be moved into each newly created profile folder.

  To give the prefs a default, it is best to do this via a mozilla.cfg file.

  Use a mozilla.cfg file in the Firefox program folder to lock the prefs or specify default values.
  
  Place a local file - settings.js in the defaults\pref folder where you will also find the channel - prefs.js to specify using mozilla.cfg file.

  pref("general.config.filename", "mozilla.cfg");
  pref("general.config.obscure_value", 0); // use this to disable the byte-shift
  

  See:

  • http://KB.mozillazine.org/Locking_preferences

  You can use these functions in mozilla.cfg:

  defaultPref();  // set new default value
  pref();         // set pref, but allow changes in current session
  lockPref();     // lock pref, disallow changes
  

• relaxation led when the value is greater than

  Hey everybody! I have to do a project and im stuck because I'm a noobler with regard to labview. I'm using labview 6 and got to watch the pressure and temperature of a reactor in time. I need to create a system in which if a value is greater than it triggers an alarm (perhaps led can show it) or is less than a certain limit. I mean it should trigger an alarm when the temperature or pressure is beyond 100 and less than 10. And after that to generate a text document in which it is specified the time and date at which these values were exceeded. I also use randomly generated values. Can I get help please? I'm not manage it by myself)

  Line and force. as Norbert said.

  You won't get much sympathy on overloaded around here.  Three things occurred to me that I read your messages:

  1. You will be in trouble when you get a job if you think that you will be not always charged.
  2. If I help you, you'll probably end up working for me and I still have to do your homework.
  3. You'll be fine.  Engineers outsource their work all the time.

  

• IMAQ_USB - 1074396024 (coverage Minimum value must be greater than zero)

  Hello

  I have problems to use a USB WebCam when I try to run an executable file in a PC that not have installed LabVIEW. The error code that is displayed is 1074396024 (coverage Minimum value must be greater than zero).

  When I run it on a PC that installed, LabVIEW everythings works great!

  Someone has an idea to help me? The sample program is attached.

  Thks

  Hey neat,

  To run your executable file in a free LabVIEW PC, you must install LAbVIEW Run-Time Engine and Vision Run-Time Engine.

  http://digital.NI.com/public.nsf/allkb/3EB8C8AFC1593B4A8625712E0002869B

  Engine performance vision application for permit.

  Best regards

  Abel Souza

  Engineering applications

  National Instruments Brazil

• Read byte with a value up to 127 lire byte with an ASCII value greater than 7F (127 dec)

  Hello

  I have to read a byte with a value greater than 127, Labview turn 27.

  In help I saw that Labview provides a description of ASCII that pour values ranging up to ' 127.

  What do I need to do?

  LabVIEW 6.1

  Windows XP

  Hello

  I want to read a byte with a maximum value of 127, but Labiew reurn arround 27 value

  How do I do?

  

  Rigid wrote:

  Thanks for your help. I'm not changing lyke I understand (my English is poor quiet...)

  I have another program that communicate with the instrument. I know byte (6) must be greater than 18 (greater than 7F actually).

  But with Labview, I'm only 18.

  While it might be higher than 18 x, an I8 is signed, and therefore it cannot be greater than x7F - it has a range of-128 to 127. A U8 is not signed, and it's why he has a range from 0 to xFF. However, x 18 is the same if you treat as signed or not signed. I don't see how LabVIEW can read a wrong value on the serial port. Are you sure you're looking at the correct byte? Your code shows that you split the chain twice. Are you sure that you do this properly?

  Given that you use on Windows you can recheck the chain received using PortMon. Allows you to see what is actually received by the driver for the serial port on Windows.

  P.S. I actually meant the whole byte function.