Number of days between two Dates in the Correct month
I am trying to write a SELECT statement that returns the number of days spent on a project.Here's my problem. I have a table with several columns of date (start_date, end_date, etc.) as well as several other columns. Here is an example of the table.
PROJECT... START_DATE... END_DATE
123 ................. 1ST JANUARY 13... 15 JANUARY 13
456 ................. 25 JANUARY 13... FEBRUARY 5, 13
789 ................. 30 JANUARY 13... FEBRUARY 5, 13
999 ................. 1ST FEBRUARY 13... FEBRUARY 8, 13
I'm counting the number of days spent on projects in each month. For example, with the above data, I would come back...
MONTHS... PROJECT_DAYS
Jan ............. 24
Feb ............. 18
I tried to use a CASE statement, but I'm having a hard time to understand. Any help would be greatly appreciated!
Published by: 987079 on February 8, 2013 13:12
An option would be something like
1 with project as (
2 select 123 project_id, date '2013-01-01' start_date, date '2013-01-15' end_date from dual union all
3 select 456, date '2013-01-25', date '2013-02-05' from dual union all
4 select 789, date '2013-01-30', date '2013-02-05' from dual union all
5 select 999, date '2013-02-01', date '2013-02-08' from dual
6 ),
7 all_days as (
8 select start_date + level - 1 dt
9 from (select min(start_date) start_date,
10 max(end_date) end_date
11 from project)
12 connect by level <= end_date - start_date + 1
13 )
14 select trunc(dt,'MM'),
15 count(*)
16 from all_days ad
17 join project p on (ad.dt between p.start_date and p.end_date)
18 group by trunc(dt,'MM')
19* order by trunc(dt,'MM')
SQL> /
TRUNC(DT,'MM') COUNT(*)
------------------- ----------
2013-01-01 00:00:00 24
2013-02-01 00:00:00 18
Justin
Tags: Database
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