Number of rows in a data view
Hello
I have a data view that is bound to a table in a MS Access database.
How can I determine the number of rows that are in the data view?
Thank you
Chris
OK, I see the question... to version 8 of Acrobat sourceset Dom was locked so that if you try and change you will get security errors.
There is a good explantion in blog of Stefan Cameron located here:
http://Forms.stefcameron.com/2006/12/07/better-form-design-with-XFA-25/
Down is a solution for sunbathing with current versions.
The other option is to target your form for an earlier version, when this restriction did not exist. In the properties of the form vhoose a target version of the 7.0.5 and your code will work fine (no error).
Paul
Tags: Adobe LiveCycle
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Count the number of rows returned from each view in USER_VIEWS
For each USER_VIEWS view, I would return the name, creation date, last modified dateand the number of rows returned by this view.
Here's what I have so far:
Returns:col object_name format a20 select object_name, created, last_ddl_time from user_objects where object_type = 'VIEW'
How can I add a last column that counts the number of rows returned by this view?OBJECT_NAME CREATED LAST_DDL_TIME -------------------- --------- ------------- AISLE_AVG 11-FEB-12 11-FEB-12 COURSE_AVG 11-FEB-12 20-FEB-12 EXE_12_VIEW 11-FEB-12 21-FEB-12 L1_P2 17-FEB-12 17-FEB-12 L1_P3 17-FEB-12 17-FEB-12 L1_P4 17-FEB-12 17-FEB-12 L1_P5A 17-FEB-12 17-FEB-12 L1_P5B 17-FEB-12 17-FEB-12 LAB3_1A 12-FEB-12 20-FEB-12 LAB3_1B 12-FEB-12 20-FEB-12 LAB3_2A 12-FEB-12 20-FEB-12 LAB3_2B 12-FEB-12 20-FEB-12 LAB5_1 19-FEB-12 19-FEB-12 LAB5_2 19-FEB-12 19-FEB-12 LAB5_3 19-FEB-12 19-FEB-12 LAB5_4 19-FEB-12 19-FEB-12 LAB5_5 19-FEB-12 19-FEB-12 LAB5_TIMES 19-FEB-12 19-FEB-12 LAB6_1 19-FEB-12 19-FEB-12 LAB7_VIEW 20-FEB-12 20-FEB-12 PROGRAMS 11-FEB-12 21-FEB-12 STUDENT_GPA 11-FEB-12 21-FEB-12 22 rows selected
EDIT - here is a dump of my paintings, and here are my views.
Edit2 - this is possible by using the DECODE function, by chance?The function...
CREATE OR REPLACE FUNCTION view_row_count (view_name VARCHAR2) RETURN NUMBER AS retval NUMBER; BEGIN EXECUTE IMMEDIATE 'select count(*) from '||view_name INTO retval; RETURN retval; END view_row_count; /
And now the query...
select object_name, created, last_ddl_time, view_row_count(object_name) as view_row_count from user_objects where object_type = 'VIEW'
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How can I get number of rows in DB for view with "only up to line number.
Hi all
I use jdeveloper 11.1.1.3.0
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If I get iterator or view are of the object status is not true, it returns the value 100.
How can I get 1000?Given that you have set the limit line number for the VO, VO will always and forever don't have 100 records or less. If you want the total number in the comic book, you need to create an another VO that is not the count (*) or one that does not limit the number of rows.
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How Restict number of rows to download data in the excel worksheet
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Published by: 941334 on June 18, 2012 06:15Hello
U just above commenst xml on your instanceconfig.xml file below and then test it.
(1) prior to this step take a return to the top and start changes
Keep it under xml commnents n/b
50
in the same way of the PivotTable as
then save it and re start it services presentation bi so it will work as you expected.For info to learn more check out my blog
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Displays the number of rows in the table displaying a named criteria query data
I created a test named for my View, called 'Criteria1' and Criteria1 to create a group of ADF with Table query. I want to display the number of rows in result when a search is performed. How can I do?
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Hello
Wonder if you can help with my 2 problems
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CGH
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How to determine the number of rows in the database and save the result to a local variable?
Hello
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Export of DataPump API - number of rows exported using
Hello
I'm working on the procedure to export data in the table before deleting the partition. It will be run by the Scheduler of the data, that's why I want to run the datapump job using the API.
I wonder, if it is possible to get the number of rows exported. I would compare with the number of rows in a partition before you delete the partition.
Thank you
Krystian
Hello
Don't know exactly how you want the number of rows per partition that have been exported, but here are a few ideas:
1. create a log file by using 'add_file ':
-Add a log file
dbms_datapump.add_file (h, ' DEPTJOB.log ', a', NULL,)
dbms_datapump.Ku$ _file_type_log_file);
It is also in my example included below. Here is the content after the DEPTJOB.log workload (situated in Oracle Directory object would be "in my example):
$ cat /tmp/DEPTJOB.log
Departure 'SCOTT '. "" DEPTJOB ":
Object type TABLE_EXPORT/TABLE/TABLE processing
Processing object type TABLE_EXPORT/TABLE/TABLE_DATA
. . "exported"SCOTT" DEPT': 'SYS_P1581' 5,929 KB 2 lines
. . "exported"SCOTT" DEPT': 'SYS_P1582' 5,914 KB 1 lines
. . "exported"SCOTT" DEPT': 'SYS_P1583' 5,906 KB 1 lines
Table main 'SCOTT '. "' DEPTJOB ' properly load/unloaded
******************************************************************************
Empty the files together for SCOTT. DEPTJOB is:
/tmp/Dept.dmp
Job 'SCOTT '. "" DEPTJOB "managed to 00:00
You can then review or extract the information from the log file.
2. save the master table and the query for the busy lines.
Use the parameter "KEEP_MASTER":
-Keep the main table to be deleted after employment ends
dbms_datapump.set_parameter(h,'KEEP_MASTER',1);
Here's my example, the request to the main table is at the end.
$ sqlplus scott/tiger @deptapi
SQL * more: version 12.2.0.0.2 Beta on Fri Jan 22 12:55:52 2016
Copyright (c) 1982, 2015, Oracle. All rights reserved.
Last successful login time: Friday, January 22, 2016 12:55:05-08:00
Connected to:
Database Oracle 12 c Enterprise Edition Release 12.2.0.0.2 - 64-bit Beta
With the options of partitioning, OLAP, advanced analytics and Real Application Testing
Connected.
SQL > SET FEEDBACK 1
SQL > SET 10 NUMLARGEUR
SQL > SET LINESIZE 2000
SQL > SET TRIMSPOOL ON
SQL > SET TAB OFF
SQL > SET PAGESIZE 100
SQL > SET SERVEROUTPUT ON
SQL >
SQL > Rem save on the old table of scott.dept
SQL > dept and rename it dept_old.
Renamed table.
SQL >
SQL > Rem re-create it with partitions
SQL > CREATE TABLE dept (deptno NUMBER varchar (14) dname, loc varchar (13)) PARTITION INTO 3 PARTITIONS HASH (deptno)
2.
Table created.
SQL >
SQL > Rem fill the dept table
SQL > insert into dept select * from dept_old;
4 lines were created.
SQL >
SQL > Rem now create datapump job export SCOTT. DEPT. using the API
SQL > DECLARE
2: NUMBER; -Handle Datapump
3 jobState VARCHAR2 (30); -To keep track of job status
4 ind NUMBER; -Index of the loop
5 the ku$ _LogEntry; -For error messages and work in PROGRESS
6 js ku$ _JobStatus; -The State of the work of get_status
7 jd ku$ _JobDesc; -The get_status job description
8 m ku$ _Status; -The status returned by get_status object
9 sql_stmt VARCHAR2 (1024);
nom_partition 10-VARCHAR2 (50);
11 rows_completed NUMBER;
12
BEGIN 13
14-
15 run the Installer based on the operation to perform.
16-
17 h: = dbms_datapump.open ('EXPORT', 'TABLE', NULL, 'DEPTJOB', NULL);
18 dbms_datapump.add_file (h, 'dept.dmp', 'd', NULL,
dbms_datapump.Ku$ _file_type_dump_file 19, 1);
20
21 --- Add a logfile
22 dbms_datapump.add_file (h, ' DEPTJOB.log ', a', NULL,)
23 dbms_datapump.ku$ _file_type_log_file);
24
25 dbms_datapump.metadata_filter (h, 'SCHEMA_EXPR', ' IN ("SCOTT") ");
26 dbms_datapump.metadata_filter (h, 'NAME_LIST', "'DEPT"');
27
28
29-
30 start work.
31-
32 dbms_datapump.set_parameter (h, 'SILENT', 'banner');
33
34 -keep the main table to be deleted after employment ends
35 dbms_datapump.set_parameter(h,'KEEP_MASTER',1);
36
37 dbms_datapump.start_job (h);
38
39-
40 - run to grabbing the output of the job and write in the output log.
41-
42 jobState: = "UNDEFINED";
43 WHILE (jobState! = "COMPLETED") AND (jobState! = "STOPPED")
44 LOOP
45 dbms_datapump.get_status (h,
dbms_datapump.Ku$ _status_job_error 46.
dbms_datapump.Ku$ _status_wip 47, -1, jobState, m);
48
49 --
50. If we received messages WIP or error for the work, display them.
51 --
52 IF (BITAND(sts.mask,dbms_datapump.ku$_status_wip)! = 0)
53 THEN
54: = sts.wip;
55 ON THE OTHER
56 IF (bitand(sts.mask,dbms_datapump.ku$_status_job_error)! = 0)
57 THEN
58: = sts.error;
59 ON THE OTHER
the 60: = NULL;
61 END IF;
62 END IF;
63
64 the IS NOT NULL IF
65 THEN
66 ind: = the. FIRST;
67 then AS ind IS NOT NULL
68 LOOP
69 dbms_output.put_line ((ind). LogText);
70 ind: = the. Next (IND);
LOOP END 71;
72 END IF;
73 END LOOP;
74
75-
76 - release work.
77-
78 dbms_datapump.detach (h);
79
80-
81. all exceptions that spread at this point will be captured.
82 - the details are extracted from get_status and displayed.
83-
EXCEPTION OF 84
85, SO THAN OTHERS THEN
BEGIN 86
87 dbms_datapump.get_status (h,
dbms_datapump.Ku$ _status_job_error, 0-88,.
89 jobState, sts);
90 IF (BITAND(sts.mask,dbms_datapump.ku$_status_job_error)! = 0)
91 THEN
the 92: = sts.error;
93 the IS NOT NULL IF
94 THEN
95 ind: = the. FIRST;
96 although ind IS NOT NULL
LOOP OF 97
98 dbms_output.put_line ((ind). LogText);
99 ind: = the. Next (IND);
100 END LOOP;
101 END IF;
102 END IF;
103
BEGIN 104
105 DBMS_DATAPUMP. STOP_JOB (m, 1, 0, 0);
EXCEPTION OF 106
107. WHEN OTHER NULL THEN;
END 108;
109
110 EXCEPTION
111, SO THAN OTHERS THEN
112 dbms_output.put_line ('ORA-00000: an unexpected exception during ' |)
113 ' Manager of exceptions. ' ||
114 ' sqlcode = ' | TO_CHAR (SQLCODE));
END 115;
END 116;
117.
Departure 'SCOTT '. "" DEPTJOB ":
Object type TABLE_EXPORT/TABLE/TABLE processing
Processing object type TABLE_EXPORT/TABLE/TABLE_DATA
. . "exported"SCOTT" DEPT': 'SYS_P1581' 5,929 KB 2 lines
. . "exported"SCOTT" DEPT': 'SYS_P1582' 5,914 KB 1 lines
. . "exported"SCOTT" DEPT': 'SYS_P1583' 5,906 KB 1 lines
Table main 'SCOTT '. "' DEPTJOB ' properly load/unloaded
******************************************************************************
Empty the files together for SCOTT. DEPTJOB is:
/tmp/Dept.dmp
Job 'SCOTT '. "" DEPTJOB "managed to 00:00
PL/SQL procedure successfully completed.
SQL >
SQL > table main query Rem for number of lines completed
SQL > column nom_partition format a10
SQL > format 9999 column lines
SQL > SELECT nom_partition, COMPLETED_ROWS FROM SCOTT . DEPTJOB WHERE BASE_OBJECT_NAME = "DEPT";
PARTITION_ COMPLETED_ROWS
---------- --------------
SYS_P1581 2
SYS_P1583 1
SYS_P1582 1
3 selected lines.
SQL >
SQL > "EXIT";
3. you might even extract information of the call from the command line:
$ sqlplus scott/tiger @deptapi.sql | grep 'exported ' | AWK ' {print "Table:" $4, 'charge' $7, $8} '
Table: 'SCOTT '. "" DEPT ":"SYS_P1581"loaded 2 rows
Table: 'SCOTT '. "' DEPT ': 'SYS_P1583' loaded 1 lines
Table: 'SCOTT '. "' DEPT ': 'SYS_P1582' loaded 1 lines
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number of rows in table is not updated in RPD obiee 11.1.1.9?
Hello
I'm working on obiee 11.1.1.9.
When I'm trying to update the rows in the table to the RPD, I'm getting following error. ;
I tried so many times. But still I don't get number of rows tables.
Please help me.
Thanks in advance,
A.Kavya.
Hello
As you say, I checked the side DB. I am using Toad. while I see the table & script data in abrowser schem, I get the error message like "access violation at address 01c688df in module toad.exe" on the opening of the browser (73231) editor or contours. to do this, I installed the new version of Toad .so I did nt get any errors at the level of the RPD. I get the number of rows updated successfully.
Thank you best regards &,.
A.Kavya.
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Hi all
We try to add new proposal for a salary of some employees from form August 1, 2015 (the Date of the beginning of employee)
There is no existing salary proposal doesn't exist for these employees.
We get below error.
ORA-01422: exact fetch returns more than the requested number of rows in the hr_maintain_proposal_swi procedure insert_salary_proposal package
Help, please.
Thank you
Tarun
Hi John,.
If it helps, take a look at the following note:
ORA-01422 exact Fetch returns more than number of lines requested in Hr_maintain_proposal_swi (Doc ID 1673527.1)
Kind regards
Rajen
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Dynamic calculation of the number of days between two dates in a table
Hello
I'm working on request where I dynamically calculate the number of days between two dates in a table.
The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.
APEX version: 5.0
Hi BO123,
BO123 wrote:
Hello
I'm working on request where I dynamically calculate the number of days between two dates in a table.
The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.
APEX version: 5.0
one of the way to do this by calling ajax on change of end_date.
See the sample code given below to fetch the resulting duration and making the field read only after calculation
Step 1: Change your page
under CSS-> Inline, put the code below
.row_item_disabled { cursor: default; opacity: 0.5; filter: alpha(opacity=50); pointer-events: none; }
Step 2: Create on demand Ajax process I say CALC_DURATION
Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call
Declare p_start_date date; p_end_date date; p_duration number; Begin p_start_date := to_date(apex_application.g_x01); p_end_date := to_date(apex_application.g_x02); --do your calculation and assign the output to the variable p_duration select p_end_date - p_start_date into p_duration from dual; -- return calculated duration sys.htp.p(p_duration); End;
Step 3: Create the javascript function
Change your page-> the function and the declaration of the Global Variable-> put the javascript function
You must extract the rowid in the first place, for which you want to set the time, see line 2
assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration
See no line no 8 how set the value returned by the process of ajax at the duration column
Replace your column to the respective column identifiers in the code below
function f_calulate_duration(pThis) { var row_id = pThis.id.substr(4); var start_date = $('#f06_'+row_id).val(); apex.server.process ( "CALC_DURATION", { x01: start_date,x02: $(pThis).val() }, { success: function( pData ) { // set duration to duration column $('#f08_'+row_id).val(pData); // disable duration column $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); } }); }
Step 4: choose the end date call the javascript function
Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below
onchange="javascript:f_calulate_duration(this);"
hope this helps you,
Kind regards
Jitendra
-
I created a table and partitioned on the date of the entry and added a local partitioned index.
Now, I use a query to extract "num_rows" of user_tab_partitions to know the number of rows in each partition.
Getting this value as null num_rows, wonder why?
After looking to explain the Plan after interrogation ("select * from my_table1 where entry_date = 1 January 2015" ;))
to find out if she actually partitioned table and its data in different partitions, I interpreted in effect because the query plan had a line like Partition_range (Single).
My Question is:
(a) is actually partitioned data (have I misinterpreted the Explain plan)
(b) why is the num_rows null column in the query (Pasted below)
(c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?
The following code Snippet:
----------------------------------------------------------------------------------------------
create the table my_table1
(
roll_no number constraint my_table1_pk primary key,
date of entry_date
)
partition of range (entry_date)
(
PARTITION data_p1 VALUES LESS THAN (TO_DATE (December 31, 2014 ',' DD-MM-YYYY ""));
PARTITION data_p2 VALUES LESS THAN (MAXVALUE)
);
create an index only my_table1_indx on my_table1 (entry_date) local;----------------------------------------------------------------------------------------------
I now insert two lines:
insert into my_table1 values (1, to_date ('01-01-2015', ' dd-mm-yyyy'));
insert into my_table1 values (2, to_date('01-02-2015','dd-mm-yyyy'));----------------------------------------------------------------------------------------------
These have been inserted successfully, now using the query below shows num_rows column as null. I don't know why?
SELECT table_name, num_rows, high_value, nom_partition
Of user_tab_partitions
where table_name = 'MY_TABLE1 '.
ORDER BY table_name, nom_partition;----------------------------------------------------------------------------------------------
(a) is actually partitioned data (have I misinterpreted the Explain plan)
Yes, it is partitioned. You can query this particular partition SELECT * FROM my_table1 (data_p1) PARTITION to check that.
(b) why is the num_rows null column in the query (Pasted below)
As already mentioned that you have not collected statistics.
(c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?
In fact, you have created two types of indexes without knowing (can be)! One is not partitioned (although this column is not partition key) and another is partitioned (LOCAL). They are MY_TABLE1_PK and MY_TABLE1_INDX. You can check that USER_INDEXES.
You can read this article to get an early jump on the partitioning of decision. Partition: Partition decisions
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Number of Saturdays between two dates
Hello
How can I get number of Saturdays between two dates, including the two dates?
for example number of Saturdays between 09/05/2014 and 10/05/2014 is five
Help, please
I use oracle 10g
SQL> with t 2 as 3 ( 4 select to_date('05/09/2014 ', 'dd/mm/yyyy') from_dt 5 , to_date('05/10/2014 ', 'dd/mm/yyyy') to_dt 6 from dual 7 ) 8 select to_char(from_dt + (level-1), 'fmDay') day_ 9 , count(*) cnt 10 from t 11 connect 12 by level <= to_dt - from_dt + 1 13 group 14 by to_char(from_dt + (level-1), 'fmDay'); DAY_ CNT --------- ---------- Saturday 5 Thursday 4 Tuesday 4 Friday 5 Wednesday 4 Monday 4 Sunday 5 7 rows selected. SQL>
-
See the number of rows affected the performance of sqlplus to a sql file
Hello
It's just we have a sql file that contains a bunch of select/update/insert statements.
I have a unix script that calls sqlplus on this sql file. However, at the exit I don't get the number of rows affected.
Without adding any code in the input sql file, how can I change the code of sqlplus shell script to print the number of rows affected for each statement in the sql file?
${ORACLE_HOME}/bin/sqlplus -L >> ${LOG_FILE} 2>&1 << EOF ${ORAID}/${ORAPASS}@${ORAINS} whenever sqlerror exit sql.sqlcode; set echo on; set feedback off; set serveroutput on; @${SQL_FILE}; exit; EOF RC=$?
The SQL_FILE of entry content is:
select 12 "col1" from dual; select 'abcd' "col2" from dual; select; select 13 'col3' from dual;
The result of the race of sqlplus is (LOG_FILE):
SQL*Plus: Release 11.2.0.2.0 Production on Fri Jun 6 14:28:00 2014 Copyright (c) 1982, 2010, Oracle. All rights reserved. Enter user-name: Connected to: Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production With the Partitioning, Real Application Clusters, Automatic Storage Management, OLAP, Data Mining and Real Application Testing options SQL> SQL> SQL> SQL> SQL> SQL> select 12 "col1" from dual; col1 ---------- 12 SQL> select 'abcd' "col2" from dual; col2 ---- abcd SQL> select; select * ERROR at line 1: ORA-00936: missing expression Disconnected from Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production With the Partitioning, Real Application Clusters, Automatic Storage Management, OLAP, Data Mining and Real Application Testing options
Thank you
Srinivas - y.
- echo setting
- Set feedback off;
use
Set of feedback on
-
number of rows fetch are not even
Hi all
I'm new to sql/plsql
Oracle version 11R2
RHL 5.0 OS
I'm deleting all rows in the parent table as well as children tables based on some criteria to date.
the parent BE_STATUS table contains a column OOC_DT. based on the OOC_DT I get BE_STATUSin the parent Table rows.
other children tables DOES NOT have OOCDT column but meet BENo. and BEDT WHO are also in PARENT TABLE BESTATUS.
So I get all the be_no, * be_dt * of BE_STATUS based on the OOC_DT column as below
and I create a temporary table based on the above query asselect distinct(count(*)) from be_status where ooc_dt between '31-mar-10' AND '24-dec-10'; (COUNT(*)) ---------- 65074
and then I count the number of rows in the temporary tablecreate table temp as select be_no, be_dt from be_status where ooc_dt between '31-mar-10' AND '24-dec-10'; table created.
so there are around 51 children tables that have the BE_NO AND BE_DTcolumn.select distinct(count(*)) from temp; (COUNT(*)) ---------- 65074
If the total number of lines in the temp must be equal to the total of all the lines in each column according to the above criteria.
It's
so, as you can see the TEMP TABLE contains only * 65074 *. Therefore the sum of the numbers of all of the above tables should be * 65074 * but only item_det containsselect distinct(count(*)) from be_penal where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 64 select distinct(count(*)) from be_fine where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 62 select distinct(count(*)) from be_cash_lic where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 23 select distinct(count(*)) from c_cl_be where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 2 select distinct(count(*)) from chex where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 0 select distinct(count(*)) from amend_q where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 0 select distinct(count(*)) from be_perm where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 889 select distinct(count(*)) from exam_instr where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 690 select distinct(count(*)) from c_rms_mesg where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 64982 select distinct(count(*)) from item_duty_fg where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 398129 select distinct(count(*)) from a_item_det where (be_no,be_dt) in (select be_no,be_dt from temp); (COUNT(*)) ---------- 31453 select distinct(count(*)) from item_det where (be_no,be_dt) in (select be_no,be_dt FROM temp); (COUNT(*)) ---------- 622271
* 622271 * lines.
I have made a mistake in counting the records individually?
waiting for your helpful answer
Thanks and greetingsNot quite sure, I followed your question, but a glaring fault in your codes...
between '31-mar-10' AND '24-dec-10';
dates should be treated as dates, not the chains and left us 2 years of numbers of programming standards waaay back in the 90's when everyone fixed these issues in the context of the challenges of the Millennium bug.
between to_date('31-mar-2010','DD-MON-YYYY') AND to_date('24-dec-2010','DD-MON-YYYY');
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