Number of SQL executions

Similar Questions

• SQL execution time

  Hello

  I was wondering if anyone could advise on the best way to capture the following in an 11g database.

  Say that we have;

  -a piece of SQL execution by up to 50 times per minute.

  -unique execution times vary.

  Aside from dba_hist_sqlstat and generate a sort of average over a period of 30 min.

  What would be the best way to get the execution time of this piece of SQL in real-time.

  say I want the individual execution time of this last of 100 executions.

  Any help would be appreciated

  Thank you

  Draw the session (with events of waiting if you want) that executes SQL and tkprof the trc file.

  ORACLE-BASE - Oracle Trace and TKPROF

  Oracle related things: basic SQL statement diagnostic performance - HOW TO, step-by-step instructions

• How to increase the historical number of Sqls stored in SQL

  Hello
  
  Is it possible to increase the number of SQLs stored in history of the SQL SQL Developer?
  
  Thank you

  Hello

  Use the tools - preferences - data - sheet - SQL history limit.
  Change its value to what you want.
  Note: the greater value, as you put it, the SQL Dev more will maintain the size of the history.

  Kind regards

  Buntoro

• Get the SQL execution plan that is currently running in 9i

  Hello
  
  Apologies for the magnitude of this issue, but I was wondering if someone could help me to the more accurate/efficient way to get a piece of running Oracle 9i SQL execution plan.
  
  in 10g and 11g of course dbms_xplan.display_cursor (sql_id) can be used.
  
  How can this be achieved in 9i, currently I am just get the SQL_TEXT and then executing a plan to explain ("EXPLAIN PLAN for.") - I think that this is not neccesserally the same plan to explain that will be used for the sql code that runs if
  
  Any help would be appreciated.
  
  Thank you

  The plan exists after analysis difficult.
  Statistics of actual execution will require a completed.
  That is why sql followed in real time is so great in 11g.
  In 9i, difficult.

• v$ SQL.elapased_time > 0 and v$ sql.executions = 0-> does this mean?

  Hello. all.
  
  that means in the dictionary of v$ sql (10.2.0.4)
  
  v$ SQL.elapased_time > 0
  v$ SQL.executions = 0
  
  Best regards.

  The statement has been analyzed (or it would not have been in v$ sql), but it was never executed.

  Some drivers ODBC and other front end tools seem to require additional analysis.
  You do not provide any other context (as affected for example instruction) a more precise answer is difficult to predict.

  -------
  Sybrand Bakker
  Senior Oracle DBA

• How many days old, we can see SQL executions OEM 11 g

  one of my technical guys asked me to back sql session 5 days old information how many days we can see SQL executions OEM 11 g... ?

  Metric historical information will be saved for a year by default.

  Check http://download.oracle.com/docs/cd/E11857_01/em.111/e16790/repository.htm#i1030660

  Executing SQL statements may be analyzed snapshots AWR using ADDM.
  You can keep the instant CWA as long as you want.
  Bare in mind that this will occupy space in database.

  From the homepage of the database select the Server tab and select the automatic workload repository link to set the snapshot retention

  Concerning
  Rob
  http://oemgc.WordPress.com

• How to convert the number to SQL?

  How can I convert the number in SQL?
  The problem is that I use .NET and the Oraclenumber seems to be too big.
  
  Number of database - what I get when I select
  -----------'12'--------------------------------------'12'
  -12, 1-12, 10' <-this 0 should not be there
  -----------'12,12'-----------------------------------'12,12'
  -12, 123'---12, 1230' <-this 0 should not be there
  -----------'12,1234'-------------------------------- '12,1234'
  
  
  I don't know why this happens?
  
  Now, I tried to select with to_char (COLUMN1), but when I have values like "' 0,15 ' in the base, I get in select ', 15' when I convert with to_char?"
  
  Anyone know a solution?
  
  Kind regards
  Simon
  
  Edited by: user3654758 the 30.09.2010 02:02

  with mytable as
  (select 12 n of all the double union)
  Select 12.1 in union double all the
  Select 12.12 in union double all the
  Select 12.123 in all the double union
  Select double 12.1234)
  Select case when trunc (n) = n then
  TO_CHAR (n, 'FM9999999999999999999')
  on the other
  TO_CHAR (n, 'FM9999999999999999999D9999999')
  end
  FROM MyTable;

  Edited by: hartmutm the 30.09.2010 02:21

  I changed it a bit, because you have a problem with the separator decimal escape in the previous code.

• Top of page SQL executions on particular schema

  Hello
  
  Operating system: Sun solaris
  Oracle10g
  
  How to find the "Top Sql execution" on my diagram. While I find RowsProcessed rows by Exec, Cpu by Exec, id Sql, sql module, sql and complete sql statement text.
  
  Thanks in advance
  KSG

  Hello

  You can query V$ SQL or DBA_HIST_SQLSTAT and use the PARSING_SCHEMA_NAME column to limit the results to the SQLs executed by a specific schema.

  Concerning
  Maurice

• PL/SQL execution error Question

  Hi Experts,
  It's the SQL procedure I remove a set number of order that are closed
  
  CREATE OR REPLACE PROCEDURE closed_test1 (varchar tabname, v_rowcount_int certain NUMBER)
  is
  v_sql varchar2 (4000);
  Start
  v_sql: =' delete ' | tabname |' College where exists (select order_nbr from the cl closed_order where fac.internal_order_id = cl.order_nbr)';
  immediately run v_sql;
  v_rowcount_int: = number of lines sql %;
  dbms_output.put_line (v_rowcount_int |) ("' deleted rows");
  commit;
  end;
  /
  
  I use an ETL tool to display the number of deleted rows, so I had to create an output parameter and awarded for the number of rows sql %
  
  When I run
  
  Declare
  number of v_rowndel;
  exec closed_test1 ('COST_TRANS_TABLE', v_rowndel);
  
  I get this error message
  ERROR at line 3:
  ORA-06550: line 3, column 57:
  PLS-00103: encountered the symbol "end-of-file" when awaits an of the
  Next:
  := ; not null default characters
  
  I don't understand what the problem is! Is it because I don't have an exit statement, but the sql statement is interlooped
  
  Any help is apprct in advance
  
  Thank you
  AJ

  It's the way you need to call the procedure.

  DECLARE
    v_rowndel   NUMBER;
  BEGIN
    closed_test1 ( 'COST_TRANS_TABLE', v_rowndel);
    DBMS_OUTPUT.PUT_LINE ('v_rowndel = ' || v_rowndel);
  END;
  

  If you use a tool, then turn on dbms_output.
  If execution of sqlplus and then SET SERVEROUPUT on.

  G.

• the formatting of char to number in sql loader control file

  I tried to load a huge csv Excel file into oracle with sql loader database. But a column contains numbers of year as '2014', ' 2015 ". In the control file, I have defined as:

  column_name decimal (38) external "TO_NUMBER (: column_name, ' 9999').

  It awlays say: ORA-01722 invalid number format. I changed the format of different number. All this has not worked. Please help me on this.

  1. the data of table column type is number (38.0)

  2. data csv file looks like this: color is the number of year.

  04/03/15, D_2-15, 10953562, 11116, 27144, 03/03/15,2015

  04/03/15, P_1-58, 1143088, 5262, 12994, 03/03/15,2015

  04/03/15, Q_1-31_Distinct_WWE, 7576633, 22352, 52975, 03/03/15,2015

  Thanks in advance.

  We can not help you unless you provide a sample of documents failed. The sample you provided loads without any problems:

  SQL > CREATE TABLE MY_TABLE)
  2 COLONNE_1 DATE,
  3 COLUMN_2 VARCHAR2 (255 BYTE).
  COLUMN_3 VARCHAR2 (255 BYTE) 4.
  COLUMN_4 VARCHAR2 (255 BYTE) 5.
  6 COLUMN_5 VARCHAR2 (255 BYTE).
  7 COLONNE_6 DATE,
  8 BUSINESS_YR NUMBER(*,0)
  9                      )
  10.

  Table created.

  SQL > home
  Microsoft Windows [Version 6.1.7600]
  Copyright (c) 2009 Microsoft Corporation.  All rights reserved.

  C:\app\xxx\product\11.2.0\dbhome_2\BIN>type c:\temp\xx.ctl
  DOWNLOAD THE DATA
  CHARACTERSET US7ASCII

  INFILE *.
  TRUNCATE
  IN THE TABLE MY_TABLE
  FIELDS ENDED BY ',' POSSIBLY FRAMED BY "" "
  TRAILING NULLCOLS
  (
  COLONNE_1 DATE "MM-DD-AA.
  COLUMN_2 CHAR (255),
  COLUMN_3 CHAR (255),
  COLUMN_4 CHAR (255) NULLIF COLUMN_4 = BLANKS,
  COLUMN_5 CHAR (255) NULLIF COLUMN_5 = BLANKS,
  COLONNE_6 DATE "MM-DD-YY."
  BUSINESS_YR EXTERNAL INTEGER (38)
  )
  BEGINDATA
  03/20/15,1P-11,1111.22,,,03/22/15, 2014
  21/03/15, M_XXX-4, 5607817, 0, 0, 03-9/22/15, 2014
  22/03/15, M_DDD-2, 54990, 0, 0, 03-8/22/15, 2014
  23/03/15, R_1-46, 5297481, 24, 24, 03/22/15, 2014
  16/03/15, X_1 - 48 a, 8547274, 13474, 13474, 15/03/15, 2015
  03/17/15,1T-15-dental,2118.12,,,03/15/15, 2015
  18/03/15, 1 S - 1S, 555, 15/03/15, 2015
  19/03/15, P_NNN-7, 7455342, 10941, 10941, 03/15/15, 2015
  C:\app\xxx\product\11.2.0\dbhome_2\BIN>sqlldr control=c:\temp\xx.ctl log=c:\temp\xx.log
  Username:Scott
  Password:

  SQL * Loader: release 11.2.0.3.0 - Production on Sun Apr 5 06:28:06 2015

  Copyright (c) 1982, 2011, Oracle and/or its affiliates.  All rights reserved.

  Commit the point reached - the number of logical records 7
  Commit the point reached - the number of logical records 8

  C:\app\xxx\product\11.2.0\dbhome_2\BIN>exit

  SQL > column column_2 format a15
  SQL > column column_3 format a10
  SQL > column column_4 format a8
  SQL > column column_5 format a8
  SQL > select * from my_table
  2.

  COLUMN_1, COLUMN_2, COLUMN_3, COLUMN_4 COLUMN_5 COLONNE_6 BUSINESS_YR
  --------- --------------- ---------- -------- -------- --------- -----------
  MARCH 20, 15 1 P - 11 1111.22 2014 22 MARCH 15
  21 MARCH 15 M_XXX-9-4 5607817 0 0 22 MARCH 15 2014
  22 MARCH 15 M_DDD-8-2 54990 0 0 22 MARCH 15 2014
  23 MARCH 15 R_1-46 5297481 24 24 22 MARCH 15 2014
  16 March 15 X_1-48 has 8547274 13474 13474 15 March 15 2015
  March 17, 15 1 t 15-dental 2118.12 15 March 15 2015
  1 S - 1 S 18 MARCH 15 555 2015 15 MARCH 15
  MARCH 19, 15 P_NNN-7 7455342 10941 10941 15 MARCH 15 2015

  SY.

• SQL execution 11.2.0.1 to 11.2.0.4

  Hi all

  I have a problem of my version of the 11.2.0.1 to 11.2.0.4 database migration, save you resources are the same, but when to perform a select Oracle consumes 100% of CPU and not respond to the request.

  Is there a function or something that could have an impact on?

  Thank you very much.

  Thank you to all the world and we have seen how you run THAT SQL is apparently the execution plan that is oracle doing was choose better execution plans, but this affects the performance of the database, try to modify the hidden parameter "_optimizer_use_feedback"a false and started to behave better basis. "

  SQL > alter system set "_enable_shared_pool_durations" = false scope = spfile;

  Thank you very much

• Trace SQL execution plan

  Hello

  I need to get the execution plan for a particular SQL, but I don't have it. Application it issues for a second or two and then his party so I think that the definition of a trace on specific user. Is it possible to get the execution plan of the query like this? Thank you!

  Find the sql code, you are interested in v$ sql using the sql_text column and get the SQL_ID and CHILD_NUMBER. Entry of these two values for the query to get the execution below plan.

  Select * from table

  (dbms_xplan.display_cursor ('> ',>, 'ALLSTATS'));

• SQL execution order

  Hi friends,

  Reference post https://community.oracle.com/thread/3520158

  If the order of processing of a SQL statement is

  OF-> WHERE-> GROUP-> GET-> SELECT-> ORDER BY

  So why do I get errors in a different order:

  See for more information.

  (A). all fields are false. FROM a known first.

  SQL > SELECT EAEED

  2 FROM DEEP FISHING

  3. WHERE MODOU > 3

  GROUP 4 BY EDDEW

  5 HAVE EDEW = 5

  6 ORDER BY ERA;

  DEEP FISHING

  *

  ERROR on line 2:

  ORA-00942: table or view does not exist

  (B) correction OF the identifier clause.   [ORDER BY has been checked before WHERE]

  SQL > SELECT EAEED

  2 FROM EMP

  3. WHERE MODOU > 3

  GROUP 4 BY EDDEW

  5 HAVE EDEW = 5

  6 ORDER BY ERA;

  ORDER BY ERA

  *

  ERROR on line 6:

  ORA-00904: "ERA": invalid identifier

  (C) correction ORDERBY clause.  [HAVING been checked before GROUP BY]

  SQL > SELECT EAEED

  2 FROM EMP

  3. WHERE MODOU > 3

  GROUP 4 BY EDDEW

  5 HAVE EDEW = 5

  6 ORDER BY ENAME;

  AFTER YOU HAVE EDEW = 5

  *

  ERROR on line 5:

  ORA-00904: "EDEW": invalid identifier

  (D). WITH withdrawal clause.

  SELECT EAEED

  FROM EMP

  WHERE MODOU > 3

  EDDEW GROUP

  -HAVE EDEW = 5

  ORDER BY ENAME;

  (E) correction Group by

  SQL > SELECT EAEED

  2 FROM EMP

  3. WHERE MODOU > 3

  GROUP 4 BY EMPNO

  5 WITH EDEW = 5

  6 ORDER BY ENAME;

  WHERE MODOU > 3

  *

  ERROR at line 3:

  ORA-00904: "MODOU": invalid identifier

  (F) fixed WHERE

  SQL > SELECT EAEED

  2 FROM EMP

  3. WHERE deptno <>10

  GROUP 4 BY EMPNO

  5 WITH EDEW = 5

  6 ORDER BY ENAME;

  SELECT EAEED

  *

  ERROR on line 1:

  ORA-00904: "EAEED": invalid identifier

  (G). SELECT correction

  SELECT EMPNO

  FROM EMP

  WHERE deptno <>10

  GROUP BY EMPNO

  VIEW count (*) > 1

  ORDER BY Empno;

  EMPNO

  ----------

  7369

  7499

  7521

  7566

  7654

  7698

  7788

  7844

  7876

  7900

  7902

  11 selected lines.

  This means SQL executed in different order, or there is some reason to get error in that order?

  Hello

  Kimmy says:

  HI Frank and Baris,

  Is that means there is a defined order for execution of SQL to oracle but compiling the SQL statement has no order defined by the (FROM, WHERE, GROUP BY) clauses and compilation may give error in any order, and which will compile all first does matter?

  Kind regards

  The system can choose to compile an SQL statement in any order.  I have never seen a case where this order is significant to anyone.  (I don't know what is important to you.)

  If your code has compile errors, you will get only 1 error message, and the message can be caused by any line of your code.  If your SQL statement has 10 lines, and you get an error message referring to line 5, there may be other errors as well.  If there is another error, could be on lines 1-4, or it could be on lines 6-10, it could be elsewhere on line 5.

  There is a relationship between the clauses in your code and the order in which the code is run.  For example, the compiled code corresponding to a condition of a FROM clause join will probably run before the compiled code corresponding to the ORDER byclause of this request.  The rules specifying the 'order' can be useful, but should not be taken too literally.

• Timestamp in PL/SQL execution

  Hi all
  
  Oracle 11 g 2
  Developer SQL 3.2.09
  
  We have a procedure stored in a package that returns a refcursor. One of the columns (for example, XYZ) is timestamp with local time zone. When I right-click on the package and select run I get the window run PL/SQL where I enter the input parameters and perform the procedure. The result is displayed in the tab "output Variables. When I select the refcursor I can see data from all columns except XYZ. It displays oracle.sql.TIMESTAMPLTZ@XXXXXX (where XXXXXX is a hexadecimal number).
  
  If I take the XYZ timestamp with time zone column then I get oracle.sql.TIMESTAMPTZ@XXXXXX
  
  If I have to cast to timestamp just so I can see the data.
  
  Without the casting, data are available for our other applications. For some reason any SQL Developer is not able to view it.
  
  I added couple of execute immediate instructions to set the time zone and timestamp format. Still no use.
  
  Does anyone know of a fix for this?
  
  Thank you
  Barro

  It is a bug. It has been reproduced in-house and fixed for our next release.

  I reproduced with this test scenario

  create or replace
  FUNCTION SYSREF_TIMESTAMP
  RETURN sys_refcursor
  IS
  l_curvar sys_refcursor;
  BEGIN
  L_curvar OPEN FOR "SELECT Systimestamp from dual;

  RETURN l_curvar;
  END SYSREF_TIMESTAMP;

  Run, it appears in the output for the ref cursor
  oracle.sql.TIMESTAMPTZ@7449369e

  Published by: Jeff Smith SQLDev PM on November 28, 2012 22:47

• Increase in the number of SQL

  I want a query that increments a count by one after each number of documents...
  example,
  After that 3 rows, it increases a 1 meter
  Counter value
  1A
  2A
  1 c
  d 2
  2 e
  $0
  3 d
  3 rd
  3 f

  NTILE (3) separate all lines into three size groups equal (as close as possible) while the OP asked to divide all the lines in groups where each group has 3 rows. Everything you need for this is ROWNUM. See the difference:

  SQL> select ename,NTILE(3) OVER(ORDER BY ename) from emp;
  
  ENAME      NTILE(3)OVER(ORDERBYENAME)
  ---------- --------------------------
  ADAMS                               1
  ALLEN                               1
  BLAKE                               1
  CLARK                               1
  FORD                                1
  JAMES                               2
  JONES                               2
  KING                                2
  MARTIN                              2
  MILLER                              2
  SCOTT                               3
  
  ENAME      NTILE(3)OVER(ORDERBYENAME)
  ---------- --------------------------
  SMITH                               3
  TURNER                              3
  WARD                                3
  
  14 rows selected.
  
  SQL> select ename,ceil(rownum / 3) from emp;
  
  ENAME      CEIL(ROWNUM/3)
  ---------- --------------
  MILLER                  1
  CLARK                   1
  KING                    1
  ADAMS                   2
  SMITH                   2
  JONES                   2
  FORD                    3
  SCOTT                   3
  JAMES                   3
  MARTIN                  4
  WARD                    4
  
  ENAME      CEIL(ROWNUM/3)
  ---------- --------------
  ALLEN                   4
  BLAKE                   5
  TURNER                  5
  
  14 rows selected.
  
  SQL> 
  

  SY.