Number of the page in publisher bi

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• Number of the page to start from another field

  Hi all

  I have a RTF model that shows a few bills. I have the invoice number and the page number that appear correctly. So if my report back 5 invoices I want for each bill page from 1 number. Currently, he does not like that.

  Now as a result:

  Invoice: has

  Page NUM:1

  Line: 1

  Invoice: has

  Page number: 2

  Line 2

  Invoice: B

  Page NUM:3

  Line 1

  Can begin it of Bill B by Page number 1 instead of 3?

  Kind regards

  Stoyanov

  Thank you for using for-each@section:G_INVOICE, instead of just for each.

  This will reset the page numbers for each invoice.

  Replace G_INVOICE with your actual bill group name.

• Number of the page of search results

  Hello

  Can anyone help me please with a problem that has me pulling my hair right now. I googled extensively and had no joy. My Indesign Scripting experience is pretty weak, but I spend a lot of time in VBA and PHP then coding and objects are not foreign to me.

  I'm modyfing the existing (and excellent) script to cover my needs. I need to find each instance of a paragraph style, then use the page number and the text to build a content page later. The original script achieved via an index, but it is not convinient for me in this case that I need to first make a change more.

  I successfully converted the original script to search all text that has a special paragraph on her style. I'm so succsefully entering the text. I just can't do, is to enter the number of the search result page. I understand that I probably need to look at the parent page of tags, but I don't see how. If there is no help, the paragraph style is likely to be nested within two or three tags embedded in a text box.

  Any help would be greatly appreciated.

  JavaScript document

  /*

  Based on the "marking of the character style index words" of Josha Hubbers who was based on the "Marking of the color index words" script by Thomas Silkjær

  http://indesigning.net/

  */

  var result_words_found = 0;

  var curr_document = 0;

  var my_document = app.documents.item (curr_document);

  Create a list of samples

  var list_of_paraStyles = my_document.paragraphStyles.everyItem () .name;

  var list_of_paraStyles is my_document.paragraphStyleGroups.item("Book").paragraphStyles.everyItem () .name;.

  var list_of_paraStyles is my_document. ParagraphStyleGroup.allParagraphStyles)

  var yesNoDialog = ['Yes', 'No'];

  That the dialog box to select the style of char at index

  var paraStyle_dialog = app.dialogs.add ({name: "Generate index of paragraph style"});

  {with (paraStyle_dialog.dialogColumns.Add ())}

  {with (borderPanels.Add ())}

  {with (dialogRows.Add ())}

  {with (dialogColumns.Add ())}

  staticTexts.add ({staticLabel: "choose the style of paragraph :"});})

  }

  {with (dialogColumns.Add ())}

  var selected_paraStyle = dropdowns.add ({stringList:list_of_paraStyles, selectedIndex:0});})

  }

  }

  {with (dialogRows.Add ())}

  {with (dialogColumns.Add ())}

  staticTexts.add ({staticLabel: "search all documents opened :"});})

  }

  {with (dialogColumns.Add ())}

  var selected_search_span = dropdowns.add ({stringList:yesNoDialog, selectedIndex:1});})

  }

  }

  }

  }

  catch the Cancel button

  var doSearch = paraStyle_dialog.show ();

  If selected_search_span.selectedIndex == 0 then search for 'all documents '.

  other searches only active document.

  an active document is element 0 of the array app.documents.item

  If {(doSearch)

  Set the options to search text to find all words with the selected character style

  app.findChangeTextOptions.caseSensitive = false;

  app.findChangeTextOptions.wholeWord = false;

  app.findChangeTextOptions.includeFootnotes = false;

  app.findChangeTextOptions.includeHiddenLayers = false;

  app.findChangeTextOptions.includeLockedLayersForFind = false;

  app.findChangeTextOptions.includeLockedStoriesForFind = false;

  app.findChangeTextOptions.includeMasterPages = false;

  app.findTextPreferences = NothingEnum.nothing;

  app.findTextPreferences.appliedParagraphStyle = my_document.paragraphStyleGroups.item("Book").paragraphStyles.item (selected_paraStyle.sel ectedIndex);

  Browse open documents to index all the...

  {}

  my_document = app.documents.item (curr_document);

  Search in the document

  var found_words = my_document.findText ();

  Make index

  var my_contents

  check if words are found

  If (found_words.length > 0) {}

  To loop through the paragraphs, create a list of words and mark them as index words

  myCounter = found_words.length - 1;

  {}

  var found_word = found_words [myCounter];

  var my_topic_name = found_word.contents;

  check if the subject is not empty

  If (my_topic_name.length > 1) {}

  items have been found

  result_words_found += 1;

  / / Need to retrieve the page number as a variable here.

  Create the page reference

  my_topic.pageReferences.Add (found_word);

  }

  -myCounter;

  } While (myCounter > = 0);

  }

  remove unused topics from the index, just for cleaning

  break if a single active document is extended search

  If (selected_search_span.selectedIndex == 1) {}

  break;

  }

  curr_document += 1;

  } While (curr_document < app.documents.count ());

  display the dialog result...

  If (result_words_found == 0) {}

  Nothing found alert

  Alert ("nothing has been found, try again...");

  } else {}

  Alert ("made of indexing! \n"+ result_words_found +" items found.\n\nNow choose \"Generate index\"in the Panel Index to update your index.")" ;

  }

  }

  The number of the page on which there is a text is the name of the parent of the text of the parent text block page (if you know what I mean):

  var found_words = my_document.findText ();

  $.writeln (found_words [0] .parentTextFrames [0].parentPage.name);

  Is CS5 and later versions. In CS4, it's a little different, I forgot the details.

  Peter

• Number of the page OK in preview, empty on server

  I have a XDP template which is merged with XML data on the server to produce a flat PDF. Several pages are sometimes produced. On the form is good, including totals totals except the page number and page. The current page and number of pages are always empty. In the designer of the preview always look great. How this can be solved? Thank you

  The only change I made to fix that changes the Runt "Client and server" property for the script where page numbers are calculated.

  Voucher.Master1.PageArea1.FixedPortion.zPage.zPageNumber::ready:layout - (JavaScript, both)

  this.rawValue = xfa.layout.page (this)

  Voucher.Master1.PageArea1.FixedPortion.zPage.zPageNumberCount::ready:layout - (JavaScript, both)

  this.rawValue = xfa.layout.pageCount)

  Thank you

  Srini

• Number of the page links?

  I have a series of 3 pages to display in the order, page 1, page 2, page 3.  Is it possible to have a button that following the links to the next page in the order using the same code on each page?  Did since then?  I can't imagine a better way to specify it.

  Hello

  If these pages are generated dynamically the write you a little code that will check the name of the current page and use it will generate the link to the next page. But if all this is static HTML pages then you will need to manually give the respective next page link in a tag href of the next button.

  Hope this helps,

  See you soon,.

  [Advertising link removed by Moderator]

• HP Photosmart C6180: analyzing the number and the number of the Page fault

  I am totally computer illiterate, so please forgive me if I ask you something which is 100 times or if I have no sense.

  I am receving the message 'no. Scan Options '. I'm trying to use printing HP and the Scarn Dr. 4.6. He says that my system needs an update to resolve this issue. When I click on update, I gives me this message: the service or the information requested is not available at this time.
  Please try again later.

  (Error: system-websrv_unavail)

  How to fix this?

  My computer is model a6683w if it matters. Thanks in advance.

  Hi Ryleighsmom,

  Do you appreciate the steps by train even once, so again, it does not solve the issue, I would like to as you try the following steps:

  • Uninstall the software. Uninstalling the printer software.
  • Clean boot the computer. How to perform a boot in Windows.
  • Disable all antivirus programs. Disable the anti-virus software.
  • Disable all firewall programs. Turn Windows Firewall on or off.
  • Create a new user account. Management of accounts of users and connections (Windows vista).
  • Reinstall using the full feature software and drivers. HP Photosmart C5100 C6100 and C7100 full feature all-in-one software and drivers.

  I hope this works for you and please keep me updated!

• How to access the page of a page number?

  I spent hours on the site of jongware, try to understand this. Can someone give a help?

  It depends on what you mean by page number. There are 2 options: (a) the physical number of the page, the first page of count 0; (b) the name of the page (page xii, etc.).

  To get the physical number of the page, taking into account my page as a Page object:

  myPage.documentOffset

  To get the name of the page:

  myPage.name

• How to retrieve the page number of a page

  Hello

  I need to retrieve page which have been implemented with InDesign pages numbers. However, these page numbers are generated automatically based on markers (formula) created by using a master page. (Insert special characters-> markers).

  When I try to retrieve items from the page on a page, I'm not able to obtain the page number. If I try to get the pageitem corresponding to the page number of the page master, I retrieve the marker but not the page number that is on my page.

  I wonder if there is any way I can retrieve the page on a given page number using the SDK

  Thank you very much

  Sam

  Hello

  Have you tried GetPageString of IPageList?

  Concerning
  Bartek

• [JS] [CS3] Get the Page number

  Hello.

  I need to find the number of the page containing a frame.

  Normally, I would use "myFrame.parent.name" to find the page number. However, I can't use this method on a line chart.  What I'm getting back is the story, which has no page number.  I've used in various ways, such as:

  myFrame.parent.insertionPoints [0] .parent

  but nothing returns the page number.  I looked at all the properties of the frame and impossible to find a property, I can handle to extract the page number.
  Is this possible? Should I give up now?
  See you soon
  Roy

  Use the code below,

  myFrame.parent.insertionPoints [0]. parentTextFrames [0]. parent.name

  Kind regards

  Imagine.

• Is it possible to see the pages that an image is used on through the use of page indicator?

  I create a book 5 Lightroom and really like that it shows me the number of times that that a photo was used in the book.  Is there a way to see where it is used?

  Click on the mouse exactly on the indicator 'Number' and the pages will go to the yellow-culminating point where this image was used. (be in multi-page view CTRL + E)

  

• How can I add two pages just before page 7 of the book, which will change all the page numbers that follow?

  Hello

  I'm close to finishing a book of 257 pages.  All pages are numbered automatically down, and I spent a few weeks carefully constructed an Index at the end of the book that has all the right page numbers listed for everything.  So whatever I do, I can't change my page numbers.

  But at this late stage, I would like to add a few epigraphs (quotations) in four or five places (I just got this idea today, I'm afraid).

  Is it possible to add a few pages here and there (I will add two pages at a time, I know, or he'll hit all the pages that follow, half of them designed to be left, and half designed to be on the right - off) that are not numbered, and that will not affect the numbering of the following pages?

  Kind regards

  Malcolm

  It is not Automatic way. If you are ready to have unnumbered pages which are not included in the number of pages, you can, for each page the inserted value

  (1) select the first page after the pages will be added

  (2) in the menu pages palette, use the Options Section and number and the page number of started with the value what it is already. In this way, adding pages will not affect the numbering.

  (3) in order to avoid conflicts with the new pages page number, set their numbering on something else as 1,2,3. (as i, ii, iii, for example)

  For later use, you can configure your index with the indexing of InDesign tools, if a false problem, as you would have been able to add the pages and then re - automatically generate a correct index.

• How can I change the order of the pages of work plans in Illustrator CS6?

  How can I change the order of pages / print order of artboards in Illustrator CS6? I know that it was negligence in this regard griped in previous versions, once work plans have been introduced, but surely, it's been fixed now. It is only fair that I can't understand how do. It is not intuitive by any means.

  Open the Panel work plans (in the window menu) and drag work here plans to change the order. When the work plan tool is the current tool, selection of a plan of work in the work plans Panel will highlight the workplan in the workspace.  The first column in the work plans Panel indicates a number representing the page / print order. The second column is the name given by the Illustrator which you can change in the Control Panel, while the artboard tool is selected.

• "Sign in" moving text from the top of the page to the bottom?

  Hello
  
  I use a grey theme #17 in my application. Above all my
  I have the Logo of the company on the upper left side and a page Navigation bar
  at the top right. But the model puts the connection of users (for example, JSMITH)
  just to the right of the Logo of the company and it seems weird here. Can someone
  explain how I set the login of the user posted on the lower left of the screen?
  I don't have an understanding of how to Edit Templates and themes. Thank you
  for any help.
  
  Carol
  
  Currently:
  
  [Logos] JSMITH HOME | LINKS | ADMIN | HELP | LOGOUT
  
  
  I like it:
  
  [Logos] HOME PAGE | LINKS | ADMIN | HELP | LOGOUT
  
  Parts of the page
  JSMITH
  
  Published by: Carol_new_to_APEX on April 2, 2010 10:08

  Go to the components section of your application shared.
  Click models
  Find your default page template (there will be a check mark next to her).
  Click on the name of the model.
  I think that the parts you are looking for are: #NAVIGATION_BAR # and & APP_USER.

  HTH,
  John

• OPA BI Publisher - can show features in this form instead of to the bottom of the page?

  I want to show a list of left right through a form rather than one after the other to the bottom of the page of the entity data.  For example, I have an entity called "Code HW", each instance of the entity has a number of different code entered by the user.

  HW Code1: P001

  Code2 HW: F007

  Code 3 HW: U112

  Code 4 HW: H104

  etc.

  I would like that they print across the page rather than down and then move to the next line and continue until all are printed.  The number of codes, that a user can enter is unknown.  For example

   

  P001	F007	U112
  H104	etc.

  Is there a way to do this?
  

  Thank you!  It worked very well - just a tweak was to be taken to make it work.  In the first column of the table I had to add the around the child_name_value at the end (see below in bold italic).

  child_name_value	child_name_value	child_name_value
  <>child_name_value? >

  Now another question - the customer wants the values sorted in alphabetical order from left to right as they print in the table - I played a little to put a sort command in the table after and before the XML I the first column, but who doesn't have the desired effect.  Is it possible to use the sort command in the table above?

  If this isn't the case, I'll try the OPA sort t instances before sending it to BI Publisher.

  Thank you

• Display the page number and the total number of pages in a single domain. Is this possible?

  I would like to than my report to view the number of page in the format "< page number > of < total page >", as "2 of the 6". Rather than create 2 fields to display the page number and the total number of pages and 1 label to display the word 'from' in the Middle, can I combine all of this into one? If so, how?
  
  Note: I woud wants to use "physical page number" as "total physical pages" and page number as the total number of pages.
  
  Published by: 1008305 on June 6, 2013 19:31

  Hello

  It is not possible to write in a.

  Even I try for the same, but didn't find any solution.

  We ave only two options to display the page number;

  1.) reports under construction Page number option: string will be: page & to &

  2.), we can take 2 text field that displays the page number and the total number of pages with 'from' lable inside the two text fields.

  IF any new you will come to know then.

  Thank you

  SHAH HARD