On the date ranges in search of oracle forms

I use service number, name, type person and date as search criteria in the custom form ranges.
When I enter the employee number, press the search button, I get the exact info in the block of result.
Result block contains
name of the employee, personid, emp numbed, org, start_date.
Similarly when I enter the employee number, dept, I get the correct values.
My question is, when I enter the date range. IAM unable to filter the data.
When I enter START_DATE between nvl(:BLOCKNAME.) Start_date, 1 January 1901 ') and nvl(:BLOCKNAME.) End_date, 31-DEC-4712') where block clause in the result. I had data for the range of dates also.

If I give condition in where clause results take so long when I search with the name of the employee, number, dept, person type.

If I have a query with the date, the persormance is good.

Think you know everything, how it prevents START_DATE between nvl(:BLOCKNAME.) Start_date, 1 January 1901 ') and nvl(:BLOCKNAME.) End_date, 31-DEC-4712') when look us with the employee's name, number, dept, person type.

So leave the WHERE clause of your empty block and put something like the following in your search button:

IF    :BLOCK.START_DATE IS NOT NULL
   OR :BLOCK.END_DATE IS NOT NULL THEN
  SET_BLOCK_PROPERTY('YOURBLOCK', ONETIME_WHERE, 'START_DATE between nvl(:BLOCKNAME.START_DATE,TO_DATE(''01-JAN-1901'', ''DD-MON-YYYY'')) and nvl(:BLOCKNAME.END_DATE,TO_DATE(''31-DEC-4712'', ''DD-MON-YYYY''))');
END IF;

Tags: Oracle Development

Similar Questions

  • SUM (case use this structure to get average values on the date range

    I use:

    Oracle SQL Developer (3.0.04) build hand - 04.34 Oracle Database 11 g Enterprise Edition 11.2.0.1.0 - 64 bit Production

    How do we use the function sum with a structure of matter inside.

    so I gave that looks like have an ID, date and value. I'm looking to get the day 7 medium for the date range of 04/01/2013 to 20/04/2013
    with t as (
select 1 ID_Key,to_date('4/1/2013','mm-dd-yyyy') date_val, 10 Value_num from dual union all
select 1 ID_key,to_date('4/2/2013','mm-dd-yyyy'), 15 from dual union all
select 1 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 20 from dual union all
select 1 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/8/2013','mm-dd-yyyy'), 12 from dual union all
select 1 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 8 from dual union all
select 1 ID_key,to_date('4/10/2013','mm-dd-yyyy'), 6 from dual union all
select 1 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 10 from dual union all
select 1 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/14/2013','mm-dd-yyyy'), 0 from dual union all
select 1 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 10 from dual union all
select 1 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 5 from dual union all
select 1 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 2 from dual union all
select 1 ID_key,to_date('4/20/2013','mm-dd-yyyy'), 3 from dual union all
select 2 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 12 from dual union all
select 2 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 15 from dual union all
select 2 ID_key,to_date('4/6/2013','mm-dd-yyyy'), 5 from dual union all
select 2 ID_key,to_date('4/7/2013','mm-dd-yyyy'), 7 from dual union all
select 2 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 10 from dual union all
select 2 ID_key,to_date('4/11/2013','mm-dd-yyyy'), 5 from dual union all
select 2 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 6 from dual union all
select 2 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 8 from dual union all
select 2 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 0 from dual union all
select 2 ID_key,to_date('4/18/2013','mm-dd-yyyy'), 10 from dual union all
select 2 ID_key,to_date('4/19/2013','mm-dd-yyyy'), 5 from dual
)
    * Please let me know if the table does not load.

    I would get the average of 7 days, as long as there is date for the rank of enough previous dates, is it not, then it returns a null value.

    the results should look like this
    ID_Key      date_val     Value_num     7Day_Avg     7Day_Avg2
1     4/1/2013     10          null          null
1     4/2/2013     15          null          null
1     4/3/2013     20          null          null
1     4/5/2013     0          null          null
1     4/8/2013     12          6.71          11.75
1     4/9/2013     8          5.71          10.00
1     4/10/2013     6          3.71          6.50
1     4/12/2013     10          5.14          9.00
1     4/13/2013     0          5.14          7.20
1     4/14/2013     0          5.14          6.00
1     4/15/2013     10          4.86          5.67
1     4/16/2013     5          4.42          5.17
1     4/17/2013     2          3.85          4.50
1     4/20/2013     3          2.86          4.00
2     4/3/2013     12          null          null
2     4/5/2013     15          null          null
2     4/6/2013     5          null          null
2     4/7/2013     7          5.57          9.75
2     4/9/2013     10          7.00          9.80
2     4/11/2013     5          6.00          8.40
2     4/12/2013     0          3.86          5.40
2     4/13/2013     0          3.14          4.40
2     4/15/2013     6          3.00          4.20
2     4/16/2013     8          2.71          3.80
2     4/17/2013     0          2.71          3.17
2     4/18/2013     10          3.43          4.00
2     4/19/2013     5          4.14          4.83
    As you can see, there are gaps in the dates, the value is then processed by zeros for the 7Day_Avg and then ignored for the 7Day_Avg2 (not counted in the number of days on average do to no valu_num line)
    I tried something like this at first, but becomes "missing keyword" error
    select
t.*/,
sum(
      case 
        when date_val between :day2 - 6 and :day2
        then value_num between date_val - 6 and date_val
        else null
        end
        )
        as 7Day_avg

form t
    Should I have the structure outside the sum function?

    Any thoughts?

    Published by: 1004407 on June 7, 2013 11:06

    Hello

    If you want to calculate the average of the last 7 days, including the current day, then then RANGE should be 6 PRIOR, not 7.

    Try this:

    WITH got_min_date_val AS

    (

    SELECT id_key, date_val, value_num

    MIN (date_val) compared to (AS min_date_val)

    T

    WHERE the date_val BETWEEN TO_DATE (April 1, 2013 ', "dd-mm-yyyy")

    AND TO_DATE (April 20, 2013 ', "dd-mm-yyyy")

    )

    SELECT id_key, date_val, value_num

    CASE

    WHEN date_val > = min_date_val + 6

    THEN SUM (value_num) OVER (PARTITION BY id_key

    ORDER BY date_val

    PRIOR TO TIER 6

    )

    / 7

    END AS avg_7_day

    CASE

    WHEN date_val > = min_date_val + 6

    THEN AVG (value_num) OVER (PARTITION BY id_key

    ORDER BY date_val

    PRIOR TO TIER 6

    )

    END AS avg_7_day_2

    OF got_min_date_val

    ORDER BY id_key

    date_val

    ;

    Output:

    ID_KEY DATE_VAL VALUE_NUM AVG_7_DAY AVG_7_DAY_2

    ---------- --------- ---------- ---------- ------------

    1 1 APRIL 13 10

    1 2 APRIL 13 15

    1 APRIL 3, 13 20

    1 5 APRIL 13 0

    1 APRIL 8, 13 12 6.71 11.75

    1 APRIL 9, 13 8 5.71 10.00

    1 APRIL 10 13 6 3.71 6.50

    1 12 APRIL 13 10 5.14 9,00

    1 13 APRIL 13 0 5,14 7.20

    1 14 APRIL 13 0 5,14 6.00

    1 15 APRIL 13 10 4.86 5.67

    1 16 APRIL 13 5 4.43 5.17

    1 APRIL 17, 13 2 3.86 4.50

    1 APRIL 20, 13 3 2.86 4.00

    2 APRIL 3, 13 12

    2 5 APRIL 13 15

    2 6 APRIL 13 5

    2 7 APRIL 13 7 5.57 9.75

    2 9 APRIL 13 10 7,00 9.80

    2 11 APRIL 13 5 6.00 8.40

    2 12 APRIL 13 0 3.86 5.40

    2 13 APRIL 13 0 3.14 4.40

    2 15 APRIL 13 6 3.00 4.20

    2 16 APRIL 13 8 2.71 3.80

    2 17 APRIL 13 0 2.71 3.17

    2 18 APRIL 13 10 3.43 4.00

    2 APRIL 19, 13 5 4.14 4,83

    Post edited by: FrankKulash

    Sorry; I wanted to respond to OP, not Greg

  • Get number of records in the date range - IDE: PLSQL Developer

    I want to count the number of records of members who register within a date range specified, based on effective and expiration dates and their "elg_code". I posted the SQL code for some examples of data. What I would like to see returned is in three columns of the counties where the eff_date date_exp members fall within the date range specified by the SQL and have an Elg_code of ' ' (space).

    So what I would like is all members with elg_code ' ' where he eff_dt and exp_dt range is April 2012, 2012 MAY & JUN 2012. Thus, according to data from the sample I posted, Mark, where his elg_code record is ' ', his eff_dt is 01/01/2011 and April 2012 (30/04/2012) is his exp_dt. Range of the brand statement may 2012, but not MAY or JUNE of 2012. Marty would tally for the APR and MAY because his eff_dt is before MAY 2012 and his exp to MAY 2012. etc...

    According to the data below, the results should resemble:

    APR MAY JUN
    4-3-2

    APR should have FRANK, MARK, MARTY, MARY.
    MAY should have FRANK, MARTY, MARY
    JUN should have FRANK and MARIE

    NOAM and JOHN should not appear as his records with elg_code ' ' have no documents eff_dt and exp_dt which are April-June 2012.

    So what I tried without success as it appears that I have a kind of Cartesian question (?), is:

    Select count (m1.mbr_name) APR,
    Count (m2.mbr_name) MAY,
    Count (m3.mbr_name) JUN
    mbr2 M1,
    mbr2 m2,
    mbr2 m3
    "where m1.eff_dt < ' 01 - may - 2012"
    "and m1.exp_dt > ' 01-Apr-2012.
    and m1.elg_code = ' '
    "and m2.eff_dt < 1 June 2012"
    "and m2.exp_dt > ' 01 - may - 2012"
    and m2.elg_code = ' '
    "and m3.eff_dt < 1 July 2012"
    "and m3.exp_dt > 1 June 2012"
    and m3.elg_code = ' '


    Here's the DML

    Thanks for any help!


    create table mbr2 (mbr_name varchar (10), varchar (1) grpid eff_dt date, date of exp_dt elg_code varchar (1))
    Commit

    insert into mbr2 values ('BRAND', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (April 30, 2012 ',' DD-MM-YYYY '), ' ')
    insert into mbr2 values ('BRAND', 'A', to_date (May 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')

    insert into mbr2 values ('MARTY', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (May 31, 2012 ',' DD-MM-YYYY '), ' ')
    insert into mbr2 values ('MARTY', 'A', to_date (June 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')

    insert into mbr2 values ('FRANK', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
    insert into mbr2 values ('FRANK', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')

    insert into mbr2 values ('MARY', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
    insert into mbr2 values ('MARY', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')

    insert into mbr2 values ('JOHN', 'C', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (July 1, 2011 ',' DD-MM-YYYY '), ' ')
    insert into mbr2 values ('JOHN', 'C', to_date (July 1, 2011 ',' DD-MM-YYYY '), to_date (1 January 2012 ',' DD-MM-YYYY ""), 'C')

    insert into mbr2 values ("NOAM" 'd', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), ' ' ")

    Commit

    This gives you a report for the current month and the two front. Column header must be adjusted ;-)

    select
  count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), -1)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), -2)
  then 1
  end) April
, count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), 0)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), -1)
  then 1
  end) May
, count(
  case
  when
    eff_dt < add_months(trunc(sysdate,'MM'), 1)
    and
    exp_dt >= add_months(trunc(sysdate,'MM'), 0)
  then 1
  end) June
from mbr2
where
elg_code = ' '
and
eff_dt < add_months(trunc(sysdate,'MM'), 1)
and
exp_dt >= add_months(trunc(sysdate,'MM'), -2)

APRIL     MAY     JUNE
4     3     2

  • Search in Oracle forms

    Dear professionals,
    How to perform a search in oracle forms using the toolbar: (press enter query key + press run key) using the following criteria:
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    2. how to find NULL values in date and no items date (IS NULL does not work)

    It is not the problem of dynamically set these criteria: set_block_property ('block_name', default_where,'date_item IS NULL "") OR set_block_property ('block_name', default_where,'date_item < ' 01.02.2011 ").

    There is a useful link to get advice from oracle forms research?

    THX in advance,
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    Published by: adnanBIH on February 8, 2011 11:18

    You can do this by using

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-- or

#IS NOT NULL

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    Another way may be to use replace colon (:) in all areas and it will appear in a search window where you can type your condition (so you can put the like condition - YourColumn IS NOT NULL, etc) and it will be increased to current blocks where clause.)

    I hope that helps!

  • AMOUNT of Oracle with the date range

    Hello community,

    I'm having a problem with the addition of a field with a date range. It comes to my table

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    Hello

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    OR TO_NUMBER (SUBSTR (PERIOD, 1, 4)) = 0

    /

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    SY.

    This can cause other errors, according to what is in this column.  A better way would be something like:

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    'TABLE' - avoid names which need quotation marks

    (Period WHERE the TRANSLATION)

    '012345678'

    '999999999'

    ) <> = "999999"

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    ;

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  • Conditional formatting depends on the date ranges

    Basically, I want to be able to enter a date in column A and a sum of money in the B column, depending on where the date in column A grave in a date range, I want the money in column B to copy to a corresponding column. Is this possible? The only questions I found on here deal in a conditional formatting with dates have to do with derivative.

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  • The smart Albums based on the date range cause app Crash Photos

    While I'm setting up a new Smart Album based on day of photos between 12/01/2015 and 31/12/2015 the Photos app closes with a crash. Cannot set the second date (the end date for this album). However, I can easily create a new Smart Album for next month (01/01/2016 and 01/31/2016). I create smart Albums, because the new Photos app does not like the old iPhoto does with my Photos from the photo gallery.

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  • To ignore the date ranges that overlap

    Hi guys,.

    I have the tables below

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    START_DATEEND_DATEID
    30-SEP-0513 OCTOBER 051
    12 OCTOBER 0514 NOVEMBER 052
    15 NOVEMBER 0515 DECEMBER 053

    T1

    DAT_COLIDAMOUNT
    11 OCTOBER 05110
    12 OCTOBER 05110
    16 NOVEMBER 05110

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    1130-SEP-0513 OCTOBER 0512 OCTOBER 05
    1315 NOVEMBER 0515 DECEMBER 0516 NOVEMBER 05

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    IDID_1START_DATEEND_DATEDAT_COL
    1130-SEP-0513 OCTOBER 0511 OCTOBER 05
    1130-SEP-0513 OCTOBER 0512 OCTOBER 05
    1212 OCTOBER 0514 NOVEMBER 0512 OCTOBER 05
    1315 NOVEMBER 0515 DECEMBER 0516 NOVEMBER 05

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    ("START_DATE" DATE,

    "END_DATE" DATE,

    'ID '.

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    Insert into periods (start_date, end_date, ID) values (to_date('12-OCT-05','DD-MON-RR'),to_date('14-NOV-05','DD-MON-RR'),2);

    Insert into periods (start_date, end_date, ID) values (to_date('15-NOV-05','DD-MON-RR'),to_date('15-DEC-05','DD-MON-RR'),3);

    Insert into T1 (DAT_COL, ID) values (to_date('11-OCT-05','DD-MON-RR'), 1);

    Insert into T1 (DAT_COL, ID) values (to_date('12-OCT-05','DD-MON-RR'), 1);

    Insert into T1 (DAT_COL, ID) values (to_date('16-NOV-05','DD-MON-RR'), 1);

    CREATE TABLE 'T1 '.

    (DATE OF THE 'DAT_COL',

    'ID '.

    );

    Hello

    If you really want to use something close to what you posted, then you can do it like this:

    WITH got_r_num AS

    (

    SELECT a.id

    b.id AS id_1

    b.start_date

    b.end_date

    a.dat_col

    , ROW_NUMBER () OVER (PARTITION BY a.id, a.dat_col)

    ORDER BY b.start_date, b.end_date

    ) AS r_num

    FROM one t1

    ,         (

    SELECT id, start_date, end_date

    Periods

    ) b

    WHERE a.dat_col BETWEEN b.start_date

    AND b.end_date

    GROUP BY a.id, b.end_date, a.dat_col, b.start_date and b.id

    )

    SELECT id, id_1, start_date, end_date, dat_col

    OF got_r_num

    WHERE r_num = 1

    ORDER BY start_date

    ;

    Note that the WITH clause, that's essentially what you posted in your first post (with the added r_num column) and the main request is essentially the same as in response #1.

    But why would you do something like that?  View online or GROUP BY allows all.  If you remove them, you get the #1 response solution.

  • Impossible to get Min, Max and median of the values in the date range values

    Hello

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    In the light of the median value on these values.

    Thanks in advance.



    Requirement is as below:
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    AK 1 2 0 4 1 4 4 35 35 4 1 $25 $85 850 $1,200
    AL 0 0 2 27 10 17 35 2 2 35 0 $103 100-$1 500 750


    * "QUERY ' * '"

    WITH t AS
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    SELECT 'AL' State, 67 FROM DUAL VALUE
    UNION ALL
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    SELECT "AZ" State, 123 FROM DUAL VALUE
    UNION ALL
    SELECT "AZ" State, 123 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 23 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 120 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 456 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 11 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 24 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 34 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 87 DUAL FROM VALUE
    UNION ALL
    SELECT 'MY' State, 23 FROM DUAL VALUE
    UNION ALL
    SELECT 'MY' State, 234 DUAL FROM VALUE
    UNION ALL
    SELECT 'MY' State, 789 FROM DUAL VALUE
    UNION ALL
    SELECT "HD" State, VALUE FROM DUAL 54321).
    -End of test data
    AS T1
    (SELECT State,
    NVL (COUNT (DECODE (VALUE, 0, 0)), 0) '< 100 ',.
    NVL (COUNT (DECODE (VALUE, 1, 1)), 0) '100-199.
    NVL (COUNT (DECODE (VALUE, 2, 2)), 0) '200-299.
    NVL (COUNT (DECODE (VALUE, 3, 3)), 0) '300-399.
    NVL (COUNT (DECODE (VALUE, 4, 4)), 0) '400-499.
    NVL (COUNT (DECODE (VALUE, 5, 5)), 0) '500-599,'
    NVL (COUNT (DECODE (VALUE, 6, 6)), 0) '600-699.
    NVL (COUNT (DECODE (VALUE, 7, 7)), 0) '700-799.
    NVL (COUNT (DECODE (VALUE, 8, 8)), 0) '800-899.
    NVL (COUNT (DECODE (VALUE, 9, 9)), 0) '900-999. "
    NVL (COUNT (DECODE (VALUE, 10, 10)), 0) ' > = 1000.
    (SELECT STATE,
    CASE
    WHAT VALUE < 100 THEN 0
    WHAT A VALUE BETWEEN 100 AND 199 THEN 1
    WHAT VALUE BETWEEN 200 AND 299, THEN 2
    WHAT VALUE BETWEEN 300 AND 399 THEN 3
    WHAT VALUE BETWEEN 400 AND 499 THEN 4
    WHAT VALUE BETWEEN 500 AND 599 5 THEN
    WHAT VALUE BETWEEN 600 AND 699 6 THEN
    WHAT VALUE BETWEEN 700 AND 799 THEN 7
    WHAT VALUE BETWEEN 800 AND 899 8 THEN
    WHAT VALUE FROM 900 TO 999 9 THEN
    WHAT VALUE > = 10 THEN 1000
    END
    VALUE
    T)
    GROUP BY State)
    SELECTION STATE,
    "< 100."
    "100-199.
    "200 299",
    "300-399.
    "400-499.
    '500-599,'
    "600-699.
    "700-799.
    "800-899.
    "900-999."
    "> = 1000."
    '< 100 '.
    + "100-199.
    + "200-299.
    + '300-399.
    + '400-499.
    + "500-599.
    + '600-699.
    + "700-799.
    + "800-899.
    + '900-999 ".
    + ' > = 1000.
    in total,.
    less ("< 100",)
    "100-199.
    "200 299",
    "300-399.
    "400-499.
    '500-599,'
    "600-699.
    "700-799.
    "800-899.
    "900-999."
    ("> = 1000 ') min_val,.
    largest ("< 100",)
    "100-199.
    "200 299",
    "300-399.
    "400-499.
    '500-599,'
    "600-699.
    "700-799.
    "800-899.
    "900-999."
    ("> = 1000 ') max_val
    FROM t1
    /

    Why not keep it simple?

    WITH t AS
(SELECT 'AL' state, 12 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 67 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 23 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 12 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 12 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 78 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 34 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 4 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 12 VALUE FROM DUAL
UNION ALL
SELECT 'AL' state, 15 VALUE FROM DUAL
UNION ALL
SELECT 'AZ' state, 6 VALUE FROM DUAL
UNION ALL
SELECT 'AZ' state, 123 VALUE FROM DUAL
UNION ALL
SELECT 'AZ' state, 123 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 23 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 120 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 456 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 11 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 24 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 34 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 87 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 23 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 234 VALUE FROM DUAL
UNION ALL
SELECT 'MA' state, 789 VALUE FROM DUAL
UNION ALL
SELECT 'MH' state, 54321 VALUE FROM DUAL)
SELECT state
     , NVL( COUNT( case when VALUE < 100 then 0 end ), 0 ) "<100"
     , NVL( COUNT( case when VALUE between 100 and 199 then 0 end ), 0 ) "100-199"
     , NVL( COUNT( case when VALUE between 200 and 299 then 0 end ), 0 ) "200-299"
     , NVL( COUNT( case when VALUE between 300 and 399 then 0 end ), 0 ) "300-399"
     , NVL( COUNT( case when VALUE between 400 and 499 then 0 end ), 0 ) "400-499"
     , NVL( COUNT( case when VALUE between 500 and 599 then 0 end ), 0 ) "500-599"
     , NVL( COUNT( case when VALUE between 600 and 699 then 0 end ), 0 ) "600-699"
     , NVL( COUNT( case when VALUE between 700 and 799 then 0 end ), 0 ) "700-799"
     , NVL( COUNT( case when VALUE between 800 and 899 then 0 end ), 0 ) "800-899"
     , NVL( COUNT( case when VALUE between 900 and 999 then 0 end ), 0 ) "900-999"
     , NVL( COUNT( case when VALUE >= 1000 then 0 end ), 0 ) ">=100"
     , count( value ) "total"
     , min( VALUE ) "min"
     , max( VALUE ) "max"
     , avg( VALUE ) "avg"
     , median( value ) "median"
from t
group by state

  • by selecting specific days of the week for the date range?

    I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
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    There is no duplicate of Date, it is counted for every day of the year.

    column 1: number of clients, count (customer_id)
    column 2: Date

    Need help with the best way to achieve this.

    Not sure if it is even possible to select a date in the name of the day?

    Basically, I want to select every Wednesday and Thursday of each week and compare the counts during the week, the week during
    week for the whole week see if charges go upwards or downwards, to get trends, thank you!

    Hello

    Kodiak_Seattle wrote:
    I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
    every week, since the beginning of the dates. Table is simple and has two columns. Each line is separate from a Date
    There is no duplicate of Date, it is counted for every day of the year.

    column 1: number of clients, count (customer_id)
    column 2: Date

    Need help with the best way to achieve this.

    Not sure if it is even possible to select a date in the name of the day?

    Sorry, we don't know what you want.

    To see if a date given (dt) is a Wednesday or Thursday, you can use:

    WHERE   TO_CHAR ( dt
          , 'DY'
          , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If necessary
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    I hope that answers your question.
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    Explain, using specific examples, how you get these results from these data.
    Always say what version of Oracle you are using (for example, 11.2.0.2.0).
    See the FAQ forum {message identifier: = 9360002}

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    Hello

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    Thank you
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  • Recover data to leave the date range Table

    Hi all

    We leave detail table for each employee contains information of beach to leave as follows.
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    How can this be achieved?

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    (2) absent from = May 16, 2012
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    (3) = 6 may 2012 absent
    Absent to = 30 may 2012

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    Hello

    The preliminary motion should be changed to the definitions of the new week.

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    WITH     got_weeks     AS
(
     SELECT     1 AS week_num, TRUNC (SYSDATE) AS from_dt, TRUNC (SYSDATE) + 6 AS to_dt          FROM dual     UNION ALL
     SELECT     2,               TRUNC (SYSDATE) + 7,        TRUNC (SYSDATE) + 13             FROM dual
)
SELECT       e.emp_id
,      SUM ( CASE
                WHEN w.week_num = 1
                    THEN 1 + LEAST    (w.to_dt,   e.leave_to_dt)
                    - GREATEST (w.from_dt, e.leave_from_dt)
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            END
          )          AS &week_1
,      SUM ( CASE
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             ELSE 0
            END
          )          AS &week_1
FROM              empleavedtls        e
LEFT OUTER JOIN       got_weeks        w  ON   w.from_dt     <= e.leave_to_dt
                       AND  w.to_dt     >= e.leave_from_dt
GROUP BY  e.emp_id
ORDER BY  e.emp_id
;

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    Hello

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  4  from a
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DT
-----------
05-FEB-2012
06-FEB-2012
07-FEB-2012
08-FEB-2012
09-FEB-2012
10-FEB-2012
11-FEB-2012
12-FEB-2012
13-FEB-2012
14-FEB-2012
15-FEB-2012

DT
-----------
16-FEB-2012
17-FEB-2012
18-FEB-2012
19-FEB-2012
20-FEB-2012
21-FEB-2012
22-FEB-2012
23-FEB-2012
24-FEB-2012
25-FEB-2012
26-FEB-2012

DT
-----------
27-FEB-2012
28-FEB-2012
29-FEB-2012
01-MAR-2012
02-MAR-2012

27 rows selected.

SQL>

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    Kind regards

    Brian Wheeldon

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