Get number of records in the date range - IDE: PLSQL Developer
I want to count the number of records of members who register within a date range specified, based on effective and expiration dates and their "elg_code". I posted the SQL code for some examples of data. What I would like to see returned is in three columns of the counties where the eff_date date_exp members fall within the date range specified by the SQL and have an Elg_code of ' ' (space).So what I would like is all members with elg_code ' ' where he eff_dt and exp_dt range is April 2012, 2012 MAY & JUN 2012. Thus, according to data from the sample I posted, Mark, where his elg_code record is ' ', his eff_dt is 01/01/2011 and April 2012 (30/04/2012) is his exp_dt. Range of the brand statement may 2012, but not MAY or JUNE of 2012. Marty would tally for the APR and MAY because his eff_dt is before MAY 2012 and his exp to MAY 2012. etc...
According to the data below, the results should resemble:
APR MAY JUN
4-3-2
APR should have FRANK, MARK, MARTY, MARY.
MAY should have FRANK, MARTY, MARY
JUN should have FRANK and MARIE
NOAM and JOHN should not appear as his records with elg_code ' ' have no documents eff_dt and exp_dt which are April-June 2012.
So what I tried without success as it appears that I have a kind of Cartesian question (?), is:
Select count (m1.mbr_name) APR,
Count (m2.mbr_name) MAY,
Count (m3.mbr_name) JUN
mbr2 M1,
mbr2 m2,
mbr2 m3
"where m1.eff_dt < ' 01 - may - 2012"
"and m1.exp_dt > ' 01-Apr-2012.
and m1.elg_code = ' '
"and m2.eff_dt < 1 June 2012"
"and m2.exp_dt > ' 01 - may - 2012"
and m2.elg_code = ' '
"and m3.eff_dt < 1 July 2012"
"and m3.exp_dt > 1 June 2012"
and m3.elg_code = ' '
Here's the DML
Thanks for any help!
create table mbr2 (mbr_name varchar (10), varchar (1) grpid eff_dt date, date of exp_dt elg_code varchar (1))
Commit
insert into mbr2 values ('BRAND', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (April 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('BRAND', 'A', to_date (May 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')
insert into mbr2 values ('MARTY', 'A', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (May 31, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('MARTY', 'A', to_date (June 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), 'C')
insert into mbr2 values ('FRANK', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('FRANK', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')
insert into mbr2 values ('MARY', 'B', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (June 30, 2012 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('MARY', 'B', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY ""), 'C')
insert into mbr2 values ('JOHN', 'C', to_date (January 1, 2011 ',' DD-MM-YYYY '), to_date (July 1, 2011 ',' DD-MM-YYYY '), ' ')
insert into mbr2 values ('JOHN', 'C', to_date (July 1, 2011 ',' DD-MM-YYYY '), to_date (1 January 2012 ',' DD-MM-YYYY ""), 'C')
insert into mbr2 values ("NOAM" 'd', to_date (July 1, 2012 ',' DD-MM-YYYY '), to_date (31 December 2013 ',' DD-MM-YYYY '), ' ' ")
Commit
This gives you a report for the current month and the two front. Column header must be adjusted ;-)
select
count(
case
when
eff_dt < add_months(trunc(sysdate,'MM'), -1)
and
exp_dt >= add_months(trunc(sysdate,'MM'), -2)
then 1
end) April
, count(
case
when
eff_dt < add_months(trunc(sysdate,'MM'), 0)
and
exp_dt >= add_months(trunc(sysdate,'MM'), -1)
then 1
end) May
, count(
case
when
eff_dt < add_months(trunc(sysdate,'MM'), 1)
and
exp_dt >= add_months(trunc(sysdate,'MM'), 0)
then 1
end) June
from mbr2
where
elg_code = ' '
and
eff_dt < add_months(trunc(sysdate,'MM'), 1)
and
exp_dt >= add_months(trunc(sysdate,'MM'), -2)
APRIL MAY JUNE
4 3 2
Tags: Database
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Find records in the date range
Hello
I have the following data
What is the best way to find all records in April 1, 2012 and April 30, 2012?with t as ( select 1234 prod_id, to_date('01-Jan-2008', 'dd-MON-yyyy') start_date, to_date('01-May-2012', 'dd-MON-yyyy') end_date from dual union select 4567 prod_id, to_date('01-Aug-2007', 'dd-MON-yyyy') start_date, to_date('01-Apr-2012', 'dd-MON-yyyy') end_date from dual union select 8910 prod_id, to_date('01-Jul-2006', 'dd-MON-yyyy') start_date, to_date('01-Mar-2012', 'dd-MON-yyyy') end_date from dual ) SELECT * FROM t
ConcerningAssuming that you are looking for cumulation ranges
SELECT * FROM t WHERE start_date BETWEEN date '2012-04-01' and date '2012-04-30' OR end_date BETWEEN date '2012-04-01' and date '2012-04-30' OR ( start_date < date '2012-04-01' AND end_date > date '2012-04-30' )who produces the two lines expected
SQL> with t as ( 2 select 1234 prod_id, to_date('01-Jan-2008', 'dd-MON-yyyy') start_date, to_date('01-May-2012', 'dd-MON-yyyy') end_date 3 from dual union 4 select 4567 prod_id, to_date('01-Aug-2007', 'dd-MON-yyyy') start_date, to_date('01-Apr-2012', 'dd-MON-yyyy') end_date 5 from dual union 6 select 8910 prod_id, to_date('01-Jul-2006', 'dd-MON-yyyy') start_date, to_date('01-Mar-2012', 'dd-MON-yyyy') end_date 7 from dual 8 ) 9 SELECT * 10 FROM t 11 WHERE start_date BETWEEN date '2012-04-01' and date '2012-04-30' 12 OR end_date BETWEEN date '2012-04-01' and date '2012-04-30' 13 OR ( start_date < date '2012-04-01' 14 AND end_date > date '2012-04-30' ); PROD_ID START_DAT END_DATE ---------- --------- --------- 1234 01-JAN-08 01-MAY-12 4567 01-AUG-07 01-APR-12Justin
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SUM (case use this structure to get average values on the date range
I use:
Oracle SQL Developer (3.0.04) build hand - 04.34 Oracle Database 11 g Enterprise Edition 11.2.0.1.0 - 64 bit Production
How do we use the function sum with a structure of matter inside.
so I gave that looks like have an ID, date and value. I'm looking to get the day 7 medium for the date range of 04/01/2013 to 20/04/2013
* Please let me know if the table does not load.with t as ( select 1 ID_Key,to_date('4/1/2013','mm-dd-yyyy') date_val, 10 Value_num from dual union all select 1 ID_key,to_date('4/2/2013','mm-dd-yyyy'), 15 from dual union all select 1 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 20 from dual union all select 1 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/8/2013','mm-dd-yyyy'), 12 from dual union all select 1 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 8 from dual union all select 1 ID_key,to_date('4/10/2013','mm-dd-yyyy'), 6 from dual union all select 1 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 10 from dual union all select 1 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/14/2013','mm-dd-yyyy'), 0 from dual union all select 1 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 10 from dual union all select 1 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 5 from dual union all select 1 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 2 from dual union all select 1 ID_key,to_date('4/20/2013','mm-dd-yyyy'), 3 from dual union all select 2 ID_key,to_date('4/3/2013','mm-dd-yyyy'), 12 from dual union all select 2 ID_key,to_date('4/5/2013','mm-dd-yyyy'), 15 from dual union all select 2 ID_key,to_date('4/6/2013','mm-dd-yyyy'), 5 from dual union all select 2 ID_key,to_date('4/7/2013','mm-dd-yyyy'), 7 from dual union all select 2 ID_key,to_date('4/9/2013','mm-dd-yyyy'), 10 from dual union all select 2 ID_key,to_date('4/11/2013','mm-dd-yyyy'), 5 from dual union all select 2 ID_key,to_date('4/12/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/13/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/15/2013','mm-dd-yyyy'), 6 from dual union all select 2 ID_key,to_date('4/16/2013','mm-dd-yyyy'), 8 from dual union all select 2 ID_key,to_date('4/17/2013','mm-dd-yyyy'), 0 from dual union all select 2 ID_key,to_date('4/18/2013','mm-dd-yyyy'), 10 from dual union all select 2 ID_key,to_date('4/19/2013','mm-dd-yyyy'), 5 from dual )
I would get the average of 7 days, as long as there is date for the rank of enough previous dates, is it not, then it returns a null value.
the results should look like this
As you can see, there are gaps in the dates, the value is then processed by zeros for the 7Day_Avg and then ignored for the 7Day_Avg2 (not counted in the number of days on average do to no valu_num line)ID_Key date_val Value_num 7Day_Avg 7Day_Avg2 1 4/1/2013 10 null null 1 4/2/2013 15 null null 1 4/3/2013 20 null null 1 4/5/2013 0 null null 1 4/8/2013 12 6.71 11.75 1 4/9/2013 8 5.71 10.00 1 4/10/2013 6 3.71 6.50 1 4/12/2013 10 5.14 9.00 1 4/13/2013 0 5.14 7.20 1 4/14/2013 0 5.14 6.00 1 4/15/2013 10 4.86 5.67 1 4/16/2013 5 4.42 5.17 1 4/17/2013 2 3.85 4.50 1 4/20/2013 3 2.86 4.00 2 4/3/2013 12 null null 2 4/5/2013 15 null null 2 4/6/2013 5 null null 2 4/7/2013 7 5.57 9.75 2 4/9/2013 10 7.00 9.80 2 4/11/2013 5 6.00 8.40 2 4/12/2013 0 3.86 5.40 2 4/13/2013 0 3.14 4.40 2 4/15/2013 6 3.00 4.20 2 4/16/2013 8 2.71 3.80 2 4/17/2013 0 2.71 3.17 2 4/18/2013 10 3.43 4.00 2 4/19/2013 5 4.14 4.83
I tried something like this at first, but becomes "missing keyword" error
Should I have the structure outside the sum function?select t.*/, sum( case when date_val between :day2 - 6 and :day2 then value_num between date_val - 6 and date_val else null end ) as 7Day_avg form t
Any thoughts?
Published by: 1004407 on June 7, 2013 11:06Hello
If you want to calculate the average of the last 7 days, including the current day, then then RANGE should be 6 PRIOR, not 7.
Try this:
WITH got_min_date_val AS
(
SELECT id_key, date_val, value_num
MIN (date_val) compared to (AS min_date_val)
T
WHERE the date_val BETWEEN TO_DATE (April 1, 2013 ', "dd-mm-yyyy")
AND TO_DATE (April 20, 2013 ', "dd-mm-yyyy")
)
SELECT id_key, date_val, value_num
CASE
WHEN date_val > = min_date_val + 6
THEN SUM (value_num) OVER (PARTITION BY id_key
ORDER BY date_val
PRIOR TO TIER 6
)
/ 7
END AS avg_7_day
CASE
WHEN date_val > = min_date_val + 6
THEN AVG (value_num) OVER (PARTITION BY id_key
ORDER BY date_val
PRIOR TO TIER 6
)
END AS avg_7_day_2
OF got_min_date_val
ORDER BY id_key
date_val
;
Output:
ID_KEY DATE_VAL VALUE_NUM AVG_7_DAY AVG_7_DAY_2
---------- --------- ---------- ---------- ------------
1 1 APRIL 13 10
1 2 APRIL 13 15
1 APRIL 3, 13 20
1 5 APRIL 13 0
1 APRIL 8, 13 12 6.71 11.75
1 APRIL 9, 13 8 5.71 10.00
1 APRIL 10 13 6 3.71 6.50
1 12 APRIL 13 10 5.14 9,00
1 13 APRIL 13 0 5,14 7.20
1 14 APRIL 13 0 5,14 6.00
1 15 APRIL 13 10 4.86 5.67
1 16 APRIL 13 5 4.43 5.17
1 APRIL 17, 13 2 3.86 4.50
1 APRIL 20, 13 3 2.86 4.00
2 APRIL 3, 13 12
2 5 APRIL 13 15
2 6 APRIL 13 5
2 7 APRIL 13 7 5.57 9.75
2 9 APRIL 13 10 7,00 9.80
2 11 APRIL 13 5 6.00 8.40
2 12 APRIL 13 0 3.86 5.40
2 13 APRIL 13 0 3.14 4.40
2 15 APRIL 13 6 3.00 4.20
2 16 APRIL 13 8 2.71 3.80
2 17 APRIL 13 0 2.71 3.17
2 18 APRIL 13 10 3.43 4.00
2 APRIL 19, 13 5 4.14 4,83
Post edited by: FrankKulash
Sorry; I wanted to respond to OP, not Greg
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Get the number of months between the dates.
Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?876056 wrote:
Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?I don't see how you get 8.4 months. The counted months are February, March, April, may, June, July, August and, as of today, 9 and change the days of September. Unless I forgot the lessons of counting, I learned in kndergarten is 7 full months and a bit.
Maybe you want something like:
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create table table_1 (product_id varchar2(25), region_id number, event_id number event_date date, event_status number(1)) /
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------------------------- ---------- -------- --------- ------------
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------------------------- ---------- -------------- --------------
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No this isn't a recursive with clause, perhaps the UNION ALL you got confused. She will work with 10g.
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on the other
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Similarly for > =.
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Please find below the screen for reference.
Kind regards
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Hello
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See you soon,.
Pedro
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Here is the sample sql for sample table and data.
Create table student (dept_id number(10), first_name varchar2(10),last_name varchar2(10),join_date date,years_attended number(10));
insert into student values (1,'Ann','Coleman',to_date('3/7/1917','MM/DD/YYYY'),4);
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Hello
Thanks for posting CREATE TABLE and INSERT statement. This really helps.
Here's a solution. I also added a name that seems logical. In which case you can delete:
Select dept_id, first_name, last_name
, max (years_attended) Dungeon years_attended (last dense_rank order by join_date)
the student
Group of dept_id, first_name, last_name;
DEPT_ID FIRST_NAME LAST_NAME YEARS_ATTENDED
---------- ---------- ---------- --------------
1 Ann Coleman 4
Rock 2 star 6
3 Jack Smith 4
Kind regards.
Alberto
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The number of records by empno varies and can be from 1 to n. I want the output like below:empno startdt enddt 12 15/12/2009 28/12/2009 12 10/01/2010 25/03/2010 12 30/03/2010 18/04/2010 34 05/02/2010 20/02/2010 34 01/03/2010 15/03/2010 86 11/11/2009 29/07/2010 . . .
I tried searching the forum but could not find a relevant answer. Any help is appreciated.empno startdt enddt 12 15/12/2009 28/12/2009 12 10/01/2010 31/01/2010 12 01/02/2010 28/02/2010 12 01/03/2010 25/03/2010 12 30/03/2010 31/03/2010 12 01/04/2010 18/04/2010 34 05/02/2010 20/02/2010 34 01/03/2010 15/03/2010 86 11/11/2009 30/11/2009 86 01/12/2009 31/12/2009 86 01/01/2010 31/01/2010 86 01/02/2010 26/02/2010 . . .
UMESHHello
umesh19 wrote:
Hello!I use oracle 10g Standard Edition. I have following the set of records in a table T1 maintain periods of leave in it.
What version (e.g. 10.2.0.3.0)? The version is more important in you giving a good response than that of the edition.
The solution below works in Oracle 9 (and), but could be modified to work in Oracle 8.1.empno startdt enddt 12 15/12/2009 28/12/2009 12 10/01/2010 25/03/2010 12 30/03/2010 18/04/2010 34 05/02/2010 20/02/2010 34 01/03/2010 15/03/2010 86 11/11/2009 29/07/2010 . . .Always post your sample data in a form that people can use to recreate the problem and test their ideas.
For example:CREATE TABLE table_x ( empno NUMBER (4) , startdt DATE , enddt DATE ); INSERT INTO table_x (empno, startdt, enddt) VALUES (12, TO_DATE ('15/12/2009', 'DD/MM/YYYY'), TO_DATE ('28/12/2009', 'DD/MM/YYYY')); INSERT INTO table_x (empno, startdt, enddt) VALUES (12, TO_DATE ('10/01/2010', 'DD/MM/YYYY'), TO_DATE ('25/03/2010', 'DD/MM/YYYY')); INSERT INTO table_x (empno, startdt, enddt) VALUES (12, TO_DATE ('30/03/2010', 'DD/MM/YYYY'), TO_DATE ('18/04/2010', 'DD/MM/YYYY')); INSERT INTO table_x (empno, startdt, enddt) VALUES (34, TO_DATE ('05/02/2009', 'DD/MM/YYYY'), TO_DATE ('20/02/2010', 'DD/MM/YYYY')); INSERT INTO table_x (empno, startdt, enddt) VALUES (34, TO_DATE ('01/03/2010', 'DD/MM/YYYY'), TO_DATE ('15/03/2010', 'DD/MM/YYYY')); INSERT INTO table_x (empno, startdt, enddt) VALUES (86, TO_DATE ('11/11/2009', 'DD/MM/YYYY'), TO_DATE ('29/07/2010', 'DD/MM/YYYY')); COMMIT;The number of records by empno varies and can be from 1 to n. I want the output like below:
empno startdt enddt 12 15/12/2009 28/12/2009 12 10/01/2010 31/01/2010 12 01/02/2010 28/02/2010 12 01/03/2010 25/03/2010 12 30/03/2010 31/03/2010 12 01/04/2010 18/04/2010 34 05/02/2010 20/02/2010 34 01/03/2010 15/03/2010 86 11/11/2009 30/11/2009 86 01/12/2009 31/12/2009 86 01/01/2010 31/01/2010 86 01/02/2010 26/02/2010 . . .Explain how you get the desired results based on data you've posted.
I tried searching the forum but could not find a relevant answer. Any help is appreciated.
What you're looking for? Which could give us some clues as to what you want.
What have you tried yourself?If you would like each input line to split into one or more production lines, each for a single calendar month, then follow these steps:
WITH all_months AS ( SELECT ADD_MONTHS (firstdt, LEVEL - 1) AS startdt , ADD_MONTHS (firstdt, LEVEL ) - 1 AS enddt FROM ( SELECT TRUNC ( MIN (startdt) , 'MONTH' ) AS firstdt , MAX (enddt) AS lastdt FROM table_x ) CONNECT BY LEVEL <= CEIL ( MONTHS_BETWEEN ( lastdt , firstdt ) ) ) SELECT empno , GREATEST (t.startdt, m.startdt) AS startdt , LEAST (t.enddt, m.enddt ) AS enddt FROM table_x t JOIN all_months m ON t.startdt <= m.enddt AND m.startdt <= t.enddt ORDER BY empno , startdt ; -
Difference in the number of records for the same date - 11 GR 2
Guy - 11 GR on Windows2005 2, 64-bit.
BILLING_RECORD_KPN_ESP - is a monthly partitioned table.
BILLING_RECORD_IDX #DATE - is a local index on "charge_date" in the table above.
SQL > select / * + index (BILLING_RECORD_KPN_ESP BILLING_RECORD_IDX #DATE) * /.
2 (trunc (CHARGE_DATE)) CHARGE_DATE;
3 count (1) Record_count
4. IN "RATOR_CDR". "" BILLING_RECORD_KPN_ESP ".
where the 5 CHARGE_DATE = January 20, 2013.
Group 6 by trunc (CHARGE_DATE)
5 m
CHARGE_DATE RECORD_COUNT
------------------ ------------
2401 20 January 13-> > some records here.
-> > Here I can see only '2041' records for Jan/20. But in the query below, it shows "192610" for the same date.
Why is this difference in the number of records?
SQL > select / * + index (BILLING_RECORD_KPN_ESP BILLING_RECORD_IDX #DATE) * /.
(trunc (CHARGE_DATE)) CHARGE_DATE,
2 count (1) Record_count
3. FOR "RATOR_CDR." "" BILLING_RECORD_KPN_ESP ".
"4 where CHARGE_DATE > 20 January 2013."
Group of 5 by trunc (CHARGE_DATE)
6 order by trunc (CHARGE_DATE)
5 m
CHARGE_DATE RECORD_COUNT
------------------ ------------
192610 20 January 13-> > more records here
JANUARY 21, 13 463067
JANUARY 22, 13 520041
23 JANUARY 13 451212
JANUARY 24, 13 463273
JANUARY 25, 13 403276
JANUARY 26, 13 112077
27 JANUARY 13 10478
28 JANUARY 13 39158
Thank you!Because in the second example you also select rows that have a nonzero component.
The first example selects only rows that are 00:00:00
(by the way, you should ask questions like this in the forum SQL)
-
Impossible to get Min, Max and median of the values in the date range values
Hello
I had a requirement as to show the data of each charge group of wise men as '< 100' ' 100-199 "" 200-299 "" 300-399 "400-499, 500-599 600-699 700-799 800-899 900-999 > = 1000 '"»
With the query be able to get the count between the beach and the total below. But impossible to get the Min and Max values for this range. For example if the County < 100 is 3 then in these 3, the lowest value is need to display in the min. Idem for Max column also.
In the light of the median value on these values.
Thanks in advance.
Requirement is as below:
State < 100 100-199, 200-299 300-399 400-499, 500-599 600-699 700-799 800-899 900-999 > = 1000 Min Total median Max
AK 1 2 0 4 1 4 4 35 35 4 1 $25 $85 850 $1,200
AL 0 0 2 27 10 17 35 2 2 35 0 $103 100-$1 500 750
* "QUERY ' * '"
WITH t AS
(SELECT 'AL' State, 12 DUAL FROM VALUE
UNION ALL
SELECT 'AL' State, 67 FROM DUAL VALUE
UNION ALL
SELECT 'AL' State, 23 FROM DUAL VALUE
UNION ALL
SELECT 'AL' State, 12 DUAL FROM VALUE
UNION ALL
SELECT 'AL' State, 12 DUAL FROM VALUE
UNION ALL
SELECT 'AL' State, 78 FROM DUAL VALUE
UNION ALL
SELECT 'AL' State, 34 FROM DUAL VALUE
UNION ALL
SELECT 'AL' State, 4 DUAL FROM VALUE
UNION ALL
SELECT 'AL' State, 12 DUAL FROM VALUE
UNION ALL
SELECT 'AL' State, 15 VALUE FROM DUAL
UNION ALL
SELECT "AZ" State, FROM DUAL VALUE 6
UNION ALL
SELECT "AZ" State, 123 FROM DUAL VALUE
UNION ALL
SELECT "AZ" State, 123 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 23 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 120 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 456 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 11 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 24 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 34 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 87 DUAL FROM VALUE
UNION ALL
SELECT 'MY' State, 23 FROM DUAL VALUE
UNION ALL
SELECT 'MY' State, 234 DUAL FROM VALUE
UNION ALL
SELECT 'MY' State, 789 FROM DUAL VALUE
UNION ALL
SELECT "HD" State, VALUE FROM DUAL 54321).
-End of test data
AS T1
(SELECT State,
NVL (COUNT (DECODE (VALUE, 0, 0)), 0) '< 100 ',.
NVL (COUNT (DECODE (VALUE, 1, 1)), 0) '100-199.
NVL (COUNT (DECODE (VALUE, 2, 2)), 0) '200-299.
NVL (COUNT (DECODE (VALUE, 3, 3)), 0) '300-399.
NVL (COUNT (DECODE (VALUE, 4, 4)), 0) '400-499.
NVL (COUNT (DECODE (VALUE, 5, 5)), 0) '500-599,'
NVL (COUNT (DECODE (VALUE, 6, 6)), 0) '600-699.
NVL (COUNT (DECODE (VALUE, 7, 7)), 0) '700-799.
NVL (COUNT (DECODE (VALUE, 8, 8)), 0) '800-899.
NVL (COUNT (DECODE (VALUE, 9, 9)), 0) '900-999. "
NVL (COUNT (DECODE (VALUE, 10, 10)), 0) ' > = 1000.
(SELECT STATE,
CASE
WHAT VALUE < 100 THEN 0
WHAT A VALUE BETWEEN 100 AND 199 THEN 1
WHAT VALUE BETWEEN 200 AND 299, THEN 2
WHAT VALUE BETWEEN 300 AND 399 THEN 3
WHAT VALUE BETWEEN 400 AND 499 THEN 4
WHAT VALUE BETWEEN 500 AND 599 5 THEN
WHAT VALUE BETWEEN 600 AND 699 6 THEN
WHAT VALUE BETWEEN 700 AND 799 THEN 7
WHAT VALUE BETWEEN 800 AND 899 8 THEN
WHAT VALUE FROM 900 TO 999 9 THEN
WHAT VALUE > = 10 THEN 1000
END
VALUE
T)
GROUP BY State)
SELECTION STATE,
"< 100."
"100-199.
"200 299",
"300-399.
"400-499.
'500-599,'
"600-699.
"700-799.
"800-899.
"900-999."
"> = 1000."
'< 100 '.
+ "100-199.
+ "200-299.
+ '300-399.
+ '400-499.
+ "500-599.
+ '600-699.
+ "700-799.
+ "800-899.
+ '900-999 ".
+ ' > = 1000.
in total,.
less ("< 100",)
"100-199.
"200 299",
"300-399.
"400-499.
'500-599,'
"600-699.
"700-799.
"800-899.
"900-999."
("> = 1000 ') min_val,.
largest ("< 100",)
"100-199.
"200 299",
"300-399.
"400-499.
'500-599,'
"600-699.
"700-799.
"800-899.
"900-999."
("> = 1000 ') max_val
FROM t1
/Why not keep it simple?
WITH t AS (SELECT 'AL' state, 12 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 67 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 23 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 12 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 12 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 78 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 34 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 4 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 12 VALUE FROM DUAL UNION ALL SELECT 'AL' state, 15 VALUE FROM DUAL UNION ALL SELECT 'AZ' state, 6 VALUE FROM DUAL UNION ALL SELECT 'AZ' state, 123 VALUE FROM DUAL UNION ALL SELECT 'AZ' state, 123 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 23 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 120 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 456 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 11 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 24 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 34 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 87 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 23 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 234 VALUE FROM DUAL UNION ALL SELECT 'MA' state, 789 VALUE FROM DUAL UNION ALL SELECT 'MH' state, 54321 VALUE FROM DUAL) SELECT state , NVL( COUNT( case when VALUE < 100 then 0 end ), 0 ) "<100" , NVL( COUNT( case when VALUE between 100 and 199 then 0 end ), 0 ) "100-199" , NVL( COUNT( case when VALUE between 200 and 299 then 0 end ), 0 ) "200-299" , NVL( COUNT( case when VALUE between 300 and 399 then 0 end ), 0 ) "300-399" , NVL( COUNT( case when VALUE between 400 and 499 then 0 end ), 0 ) "400-499" , NVL( COUNT( case when VALUE between 500 and 599 then 0 end ), 0 ) "500-599" , NVL( COUNT( case when VALUE between 600 and 699 then 0 end ), 0 ) "600-699" , NVL( COUNT( case when VALUE between 700 and 799 then 0 end ), 0 ) "700-799" , NVL( COUNT( case when VALUE between 800 and 899 then 0 end ), 0 ) "800-899" , NVL( COUNT( case when VALUE between 900 and 999 then 0 end ), 0 ) "900-999" , NVL( COUNT( case when VALUE >= 1000 then 0 end ), 0 ) ">=100" , count( value ) "total" , min( VALUE ) "min" , max( VALUE ) "max" , avg( VALUE ) "avg" , median( value ) "median" from t group by state
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