Optimize the order for cutting vinyl overlay objects

Hello

I'm looking for a script to optimize the cutting speed of vinyl.

The script must be similar to the following, but it will sort the objects selected by the position on the origin of the page and not the height of the point of origin of the page, as it does now

Arranging stacking order of top-down script

David John Entwistle

var thisDoc = activeDocument;

get selected objects

var selObj = thisDoc.selection;

count selected objects

var selObjCount = selObj.length;

Sort the selected objects by their height at the origin of the page

var byProperty = {function (prop)}

return function(a,b) {}

If (typeof a [prop] == 'number') {}

return (a [prop] - b [prop]);

} else {}

Return ((un [prop] < b[prop])?-1: ((un [prop] > b[prop])? 1: 0));

}

};

var symbolsSorted = selObj.sort (byProperty ("top"));

for each object in turn in the orderly selection, BringToFront

for (i = selObjCount; I > 0; i--) {}

var currObj = symbolsSorted [i-1];

currObj.zOrder (ZOrderMethod.BRINGTOFRONT);

}

Redraw();

Alert ("selected objects sorted =" + selObjCount);

Any help is welcome

Panagiotis

OK its end and is not exactly what you want.

There are probably better ways to do this.

Measure the distance from the top right of the page at the top right of the pathitems

then sorts them accordingly.

var doc = app.activeDocument;
var item = doc.pathItems;
var newLayer = doc.layers.add();
newLayer.name = "New Layer";

var newL = doc.layers['New Layer'];
var oldL = doc.layers['Layer 1'];

var list = new Array();
for(var i = 0; i < item.length; i++)
{
    list.push(dist(item[i].geometricBounds[0]/2.834645,item[i].geometricBounds[1]/2.834645).toFixed(3));
    item[i].name = list[i];
}
list.sort(sort);
list.reverse();
for(var j = 0 ; j <  list.length; j++)
{
    for(var k = 0; k < oldL.pathItems.length; k++)
    {
        if(oldL.pathItems[k].name == list[j])
        {
            oldL.pathItems[k].move(newL, ElementPlacement.INSIDE);
        }
    }
}
function sort(A,B){return (A - B);}
function dist(A,B){return (Math.sqrt(A*A+B*B));}

Tags: Illustrator

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