Oracle Date of 12 month display function.

Hi I have an annual amount of the contract from 78,00 dollars with subscription start date and end date of subscription. I wish to have a column added to my SQL with the annual contract at a monthly view called instalment_date starting beginning 01 12, 2015 for the next 12 months

This my sql

select to_date('01-dec-2015','dd-mon-yyyy') subscription_start_date , 
    to_date ('30-nov-2016','dd-mon-yyyy') as subscription_end_date, 78.00 contract_amount   
from dual;

This is the result I'm looking for.

INSTALMENT_DATE	CONTRACT_AMOUNT
12/01/2015	6.5
01/01/2016	6.5
02/01/2016	6.5
03/01/2016	6.5
04/01/2016	6.5
05/01/2016	6.5
06/01/2016	6.5
07/01/2016	6.5
08/01/2016	6.5
09/01/2016	6.5
10/01/2016	6.5
11/01/2016	6.5

Hello

Something like:

WITH the settings THAT

(

SELECT TO_DATE ('01-dec-2015', 'dd-mon-yyyy') AS subscription_start_date

, TO_DATE (November 30, 2016 ', 'dd-mon-yyyy') AS subscription_end_date

78.00 AS contract_amount

OF the double

)

got_num_months AS

(

SELECT subscription_start_date

TOWER (MONTHS_BETWEEN (subscription_end_date

subscription_start_date

)

) AS num_months

contract_amount

OF parameters

)

SELECT ADD_MONTHS (subscription_start_date

, LEVEL - 1

) AS installment_date

, contract_amount / num_months AS monthly_amount

OF got_num_months

CONNECT BY LEVEL<=>

;

Output:

EPISODE MONTHLY_AMOUNT

----------- --------------

01 dec-2015 6.5

1 January 2016 6.5

February 1, 2016 6.5

01 mar-2016 6.5

01-apr-2016 6.5

01 may-2016 6.5

June 1, 2016 6.5

July 1, 2016 6.5

August 1, 2016 6.5

01 sep-2016 6.5

October 1, 2016 6.5

November 1, 2016 6.5

It is not assumed that the contract is exactly twelve months; It could be any number, the actual number of months between subscription_start_date and subscription_end_date. If you know that it will be always exactly 12 months, then this can be simplified, and there is no need to subscription_end_date.

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---------

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AND to avoid hard-coding, you can also modify your query in the form:

select
max(case  when rownum=1 then last_day(to_date(to_char(rownum),'MM')) end) as Jan_month,
max(case  when rownum=2 then last_day(to_date(to_char(rownum),'MM')) end) as Feb_month,
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max(case  when rownum=6 then last_day(to_date(to_char(rownum),'MM')) end) as jun_month,
max(case  when rownum=7 then last_day(to_date(to_char(rownum),'MM')) end) as jul_month,
max(case  when rownum=8 then last_day(to_date(to_char(rownum),'MM')) end) as aug_month,
max(case  when rownum=9 then last_day(to_date(to_char(rownum),'MM')) end) as sep_month,
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max(case  when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month
from dual connect by level <= 12 order by rownum;

Easy way: (without login)

SELECT LAST_DAY (TO_DATE (ROWNUM, 'MM')) AS Jan_month,
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       LAST_DAY (TO_DATE (ROWNUM + 2, 'MM')) AS Mar_month,
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See you soon,.

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