retrieve the last date of the month

Hello

I give myself a date. I want to find the last date of the month containing the given date.

Is there any built-in why?

Thanks in advance.

DateTimeUtilities.getNumberOfDaysInMonth (cal.get (Calendar.MONTH), cal.get (Calendar.YEAR));

Tags: BlackBerry Developers

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    Yes, you are right. Jean SQL for the last day of the month, if the "last day of the previous month" ends on June 30, that "adding a month" will result in the 30th of the following month. But if the next month has 31 days, you don't miss this day here.

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  • to get the last date of every month between year 2000 to 2100

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    You must use the LAST_DAY() function:

    WITH months AS
(
     SELECT      TO_DATE('01/01/2000','MM/DD/YYYY') AS dt1
     ,     TO_DATE('12/31/2100','MM/DD/YYYY') AS dt2
     FROM     DUAL
)
SELECT LAST_DAY(ADD_MONTHS(dt1,level-1)) LST_DAY_MONTHS
FROM     months
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    Sample of results (too many to display):

    LST_DAY_MONTHS
-------------------
01/31/2000 00:00:00
02/29/2000 00:00:00
03/31/2000 00:00:00
04/30/2000 00:00:00
05/31/2000 00:00:00
06/30/2000 00:00:00
07/31/2000 00:00:00
08/31/2000 00:00:00
09/30/2000 00:00:00
10/31/2000 00:00:00
11/30/2000 00:00:00
12/31/2000 00:00:00
01/31/2001 00:00:00
02/28/2001 00:00:00
03/31/2001 00:00:00
04/30/2001 00:00:00
05/31/2001 00:00:00
06/30/2001 00:00:00
07/31/2001 00:00:00
08/31/2001 00:00:00
09/30/2001 00:00:00
10/31/2001 00:00:00
11/30/2001 00:00:00
12/31/2001 00:00:00
01/31/2002 00:00:00
02/28/2002 00:00:00
03/31/2002 00:00:00

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  • Breaking a year in coming weeks of beginning and end Dates (parameters) and first and last day of the month

    Hello people:

    I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

    Any help or pointers would be great!

    Thank you!

    Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

    The request in hand:

    SELECT first_thursday + (7 * (LEVEL - 1))   AS week_start_date,
                 first_thursday + (7 * LEVEL) - 1    AS  week_end_date
FROM
(
  SELECT TRUNC(p_from_date + 4, 'IW') - 4   AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date
                  TRUNC( p_to_date + 4,  'IW') - 5     AS last_wednesday
  FROM
  (
    SELECT to_date('01-JAN-2013') AS p_from_date,
                    NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date
    FROM     dual
  ) parms
) end_points
CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;

    Currently, this is the result I get (I'm only including the months of January and December here).

    Week_Start_Date     Week_End_Date
27-DEC-12                02-JAN-13
03-JAN-13                 09-JAN-13
10-JAN-13                 16-JAN-13
17-JAN-13                 23-JAN-13
24-JAN-13                 30-JAN-13
31-JAN-13                 06-FEB-13

    December:

    28-NOV-13               04-DEC-13
05-DEC-13              11-DEC-13
12-DEC-13              18-DEC-13
19-DEC-13              25-DEC-13

    What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

    January:

    01-JAN-13              02-JAN-13
03-JAN-13              09-JAN-13
10-JAN-13             16-JAN-13
17-JAN-13             23-JAN-13
24-JAN-13             30-JAN-13
31-JAN-13             31-JAN-13

    February:

    01-FEB-13    06-FEB-13
07-FEB-13    13-FEB-13
14-FEB-13    20-FEB-13
21-FEB-13    27-FEB-13
28-FEB-13    28-FEB-13

    November:

    31-OCT-13    06-NOV-13
07-NOV-13    13-NOV-13
14-NOV-13    20-NOV-13
21-NOV-13    27-NOV-13
28-NOV-13    04-DEC-13

    December:

    01-DEC-13           04-DEC-13
05-DEC-13           11-DEC-13
12-DEC-13          18-DEC-13
19-DEC-13          25-DEC-13
26-DEC-13          31-DEC-13

    Hello

    Roxyrollers wrote:

    Hello people:

    I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

    Any help or pointers would be great!

    Thank you!

    Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

    The request in hand:

    1. First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
    2. first_thursday + (7 * LEVEL)-1 AS week_end_date
    3. Of
    4. (
    5. SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
    6. TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
    7. Of
    8. (
    9. SELECT to_date('01-JAN-2013') AS p_from_date,
    10. NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
    11. OF the double
    12. ) parms
    13. ) end_points
    14. CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">

    Currently, this is the result I get (I'm only including the months of January and December here).

    1. Week_Start_Date Week_End_Date
    2. DECEMBER 27, 12 2 JANUARY 13
    3. JANUARY 3, 13 JANUARY 9, 13
    4. 10 JANUARY 13 JANUARY 16, 13
    5. 17 JANUARY 13 23 JANUARY 13
    6. 24 JANUARY 13 30 JANUARY 13
    7. 31 JANUARY 13 FEBRUARY 6, 13

    December:

    1. NOVEMBER 28, 13 4 DECEMBER 13
    2. 5 DECEMBER 13 DECEMBER 11, 13
    3. 12 DECEMBER 13 18 DECEMBER 13
    4. 19 DECEMBER 13 DECEMBER 25, 13

    What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

    January:

    1. JANUARY 1, 13 2 JANUARY 13
    2. JANUARY 3, 13 JANUARY 9, 13
    3. 10 JANUARY 13 JANUARY 16, 13
    4. 17 JANUARY 13 23 JANUARY 13
    5. 24 JANUARY 13 30 JANUARY 13
    6. 31 JANUARY 13 JANUARY 31, 13

    February:

    1. 1ST FEBRUARY 13 FEBRUARY 6, 13
    2. 7 FEBRUARY 13 FEBRUARY 13, 13
    3. 14 FEBRUARY 13 FEBRUARY 20, 13
    4. 21 FEBRUARY 13 FEBRUARY 27, 13
    5. 28 FEBRUARY 13 FEBRUARY 28, 13

    November:

    1. 31 OCTOBER 13 NOVEMBER 6, 13
    2. 7 NOVEMBER 13 NOVEMBER 13, 13
    3. 14 NOVEMBER 13 NOVEMBER 20, 13
    4. 21 NOVEMBER 13 NOVEMBER 27, 13
    5. NOVEMBER 28, 13 4 DECEMBER 13

    December:

    1. 1ST DECEMBER 13 DECEMBER 4, 13
    2. 5 DECEMBER 13 DECEMBER 11, 13
    3. 12 DECEMBER 13 18 DECEMBER 13
    4. 19 DECEMBER 13 DECEMBER 25, 13
    5. 26 DECEMBER 13 DECEMBER 31, 13

    Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less?  (For example, February 28 is a 'week' alone.)

    The following works for the other months:

    WITH all_days AS

    (

    SELECT DATE "2013-01-01' + LEVEL - AS a_date 1

    OF the double

    CONNECT BY LEVEL<=>

    )

    SELECT DISTINCT

    More GRAND (TRUNC (a_date + 4, 'IW') - 4)

    , TRUNC (a_date, 'MONTH')

    ) AS week_begin

    , The LEAST (TRUNC (a_date + 4, 'IW') + 2

    TRUNC (LAST_DAY (a_date))

    ), Week_end

    Of all_days

    ORDER BY week_begin

    ;

    Output:

    WEEK_BEGIN WEEK_END

    ----------- -----------

    January 1, 2013 January 2, 2013

    January 3, 2013 January 9, 2013

    January 10, 2013 January 16, 2013

    January 17, 2013 January 23, 2013

    January 24, 2013 January 30, 2013

    January 31, 2013 January 31, 2013

    February 1, 2013 February 6, 2013

    February 7, 2013 February 13, 2013

    February 14, 2013 February 20, 2013

    February 21, 2013 February 27, 2013

    February 28, 2013 February 28, 2013

    ...

    November 1, 2013 November 6, 2013

    November 7, 2013 November 13, 2013

    November 14, 2013 November 20, 2013

    November 21, 2013 November 27, 2013

    November 28, 2013 November 30, 2013

    December 1, 2013 December 4, 2013

    December 5, 2013 December 11, 2013

    December 12, 2013 December 18, 2013

    December 19, 2013 December 25, 2013

    26 December 2013 31 December 2013

  • Get the date of each month in the last year

    Hi all

    I need to find the last date of the month for the year.

    Example:

    I used to spend the date or such year 2012 or 01-01-2012(DD-MM-YYYY)

    SQL query should return the last date of the month as

    31/01/2012

    28/02/2012

    31/03/2012

    30/04/2012

    .

    .

    .

    .

    .

    12/31/2012

    For more top the requirement that I wrote the SQL code following

    select rownum as row_count,
case when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Jan_month,
case when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Feb_month,
case when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as mar_month,
case when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as apr_month,
case when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as may_month,
case when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jun_month,
case when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jul_month,
case when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as aug_month,
case when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as sep_month,
case when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as oct_month,
case when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as nov_month,
case when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as dec_month


from dual connect by level <= 12 order by rownum;

    Result

    Jan_MonthFeb_MonthMar_MonthApr_Monthmay_monthjun_monthjul_monthaug_monthsep_monthoct_monthnov_monthdec_month
    131/01/2014
    228/02/2014
    331/03/2014
    430/04/2014
    531/05/2014
    630/06/2014
    731/07/2014
    831/08/2014
    930/09/2014
    1031/10/2014
    1130/11/2014
    1212/31/2012

    Except the result:

    am result except as single line such as

    Jan_MonthFeb_MonthMar_MonthApr_Monthmay_monthjun_monthjul_monthaug_monthsep_monthoct_monthnov_monthdec_month
    31/01/201228/02/201231/03/201230/04/201231/05/201230/06/201231/07/201231/08/201230/09/201210/31/201230/11/201212/31/2012

    Kindly give me suggestion to archive more high result.

    Thanks and greetings

    Saami

    I agree with Marcus Pivot is the way to go on this subject... But on the other hand you almost solved yourself... it was just a max function for your results:

    ---------

    select
max(case  when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Jan_month,
max(case  when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Feb_month,
max(case  when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as mar_month,
max(case  when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as apr_month,
max(case  when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as may_month,
max(case  when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jun_month,
max(case  when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jul_month,
max(case  when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as aug_month,
max(case  when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as sep_month,
max(case  when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as oct_month,
max(case  when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as nov_month,
max(case  when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as dec_month
from dual connect by level <= 12 order by rownum;

    AND to avoid hard-coding, you can also modify your query in the form:

    select
max(case  when rownum=1 then last_day(to_date(to_char(rownum),'MM')) end) as Jan_month,
max(case  when rownum=2 then last_day(to_date(to_char(rownum),'MM')) end) as Feb_month,
max(case  when rownum=3 then last_day(to_date(to_char(rownum),'MM')) end) as mar_month,
max(case  when rownum=4 then last_day(to_date(to_char(rownum),'MM')) end) as apr_month,
max(case  when rownum=5 then last_day(to_date(to_char(rownum),'MM')) end) as may_month,
max(case  when rownum=6 then last_day(to_date(to_char(rownum),'MM')) end) as jun_month,
max(case  when rownum=7 then last_day(to_date(to_char(rownum),'MM')) end) as jul_month,
max(case  when rownum=8 then last_day(to_date(to_char(rownum),'MM')) end) as aug_month,
max(case  when rownum=9 then last_day(to_date(to_char(rownum),'MM')) end) as sep_month,
max(case  when rownum=10 then last_day(to_date(to_char(rownum),'MM')) end) as oct_month,
max(case  when rownum=11 then last_day(to_date(to_char(rownum),'MM')) end) as nov_month,
max(case  when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month
from dual connect by level <= 12 order by rownum;

    Easy way: (without login)

    SELECT LAST_DAY (TO_DATE (ROWNUM, 'MM')) AS Jan_month,
       LAST_DAY (TO_DATE (ROWNUM + 1, 'MM')) AS Feb_month,
       LAST_DAY (TO_DATE (ROWNUM + 2, 'MM')) AS Mar_month,
       LAST_DAY (TO_DATE (ROWNUM + 3, 'MM')) AS Apr_month,
       LAST_DAY (TO_DATE (ROWNUM + 4, 'MM')) AS May_month,
       LAST_DAY (TO_DATE (ROWNUM + 5, 'MM')) AS Jun_month,
       LAST_DAY (TO_DATE (ROWNUM + 6, 'MM')) AS Jul_month,
       LAST_DAY (TO_DATE (ROWNUM + 7, 'MM')) AS Aug_month,
       LAST_DAY (TO_DATE (ROWNUM + 8, 'MM')) AS Sep_month,
       LAST_DAY (TO_DATE (ROWNUM + 9, 'MM')) AS Oct_month,
       LAST_DAY (TO_DATE (ROWNUM + 10, 'MM')) AS Nov_month,
       LAST_DAY (TO_DATE (ROWNUM + 11, 'MM')) AS Dec_month
  FROM DUAL

    See you soon,.

    Manik.

  • Extract the first and the last Date of the previous month

    This seems to be a delicate but again it is perhaps easy for some of you people.

    Here is how I find the previous month

    Any ideas on how to get the first and last date of the previous month?

    Thanks in advance.

    Hello!

    SQL>
SQL> select last_day(add_months(sysdate,-1)) from dual;

LAST_DAY
--------
28.02.10

SQL> select trunc(add_months(sysdate,-1),'MM') from dual

TRUNC(AD
--------
01.02.10

SQL>

    T

  • Select records based on the monthly anniversary date

    Hello

    I have a table with a field of date_added and I want to select records from monthly birthday of this field.

    for example. ID, Date_added
    1, DECEMBER 10, 2012
    2, 11 NOVEMBER 2012
    3, 10 MARCH 2012
    4, FEBRUARY 28, 2012
    5, 30 DECEMBER 2012

    So for January 10, 2013, I would like to return the documents 1 and 3 only

    I started watching the extract function, but this little falls down to the records at the end of the month. For example, on 28 February, I also include records where 29, 30 or 31 is the day of date_added. So, in the above table, I won't return documents 4 and 5, but retrieves only returns 4.

    Is there a simple function to make the request of birthday this month - have I missed something very obvious? Or I have to write a query to explicitly dates at the end of the month? So far I have not found a reasonable solution!

    I use 11g

    Thank you

    user11259857 wrote:
    Hi Al,.

    No I don't think that there is a flaw. For example, the 30 Jan is not the last day of the month, but is June 30. Thus, on 30 January I want only to interrogate all the dates falling on the 30th - 28 February, after already being interrogated on the 28 Jan. However, on 30 June, I would query the 30th of each month, as well as the 31 January, March, may, July, Aug, Oct, dec. February is a special case, being both shorter and a leap year

    Thank you

    Richard

    Hi Richard,

    so, we can assume that your needs are:

    If the day is the last day of that month, interview the day of the other months being > = day of the current month.

    That is to say:

    Jan-30 = query only 30 other months
    Jan-31 = query only 31 of the other months

    Feb-28 (non-leap years) = question 28, 29, 30 and 31 other months
    29 February (leap year) = query 29,30,31 to other months

    Mar-30 = query only 30 other months
    Apr-30 = query 30 and 31 other months

    This hypothesis is correct?

    If so, then something like this should work:

    WITH mydates(id, date_added) AS
(
   SELECT 1, TO_DATE('10-DEC-2012', 'DD-MON-YYYY') FROM DUAL UNION ALL
   SELECT 2, TO_DATE('11-NOV-2012', 'DD-MON-YYYY') FROM DUAL UNION ALL
   SELECT 3, TO_DATE('10-MAR-2012', 'DD-MON-YYYY') FROM DUAL UNION ALL
   SELECT 4, TO_DATE('28-FEB-2012', 'DD-MON-YYYY') FROM DUAL UNION ALL
   SELECT 5, TO_DATE('30-DEC-2012', 'DD-MON-YYYY') FROM DUAL
)
SELECT id, date_added
  FROM mydates
 WHERE (:input_date = LAST_DAY(:input_date) AND TO_CHAR(:input_date,'DD') <= TO_CHAR(date_added, 'DD'))
    OR TO_CHAR(:input_date,'DD') = TO_CHAR(date_added, 'DD');

with input_date = 28/02/2013

id   date_added
4    28/02/2012
5    30/12/2012

    Kind regards.
    Al

    Published by: Alberto Faenza on 10 January 2013 15:21
    Added example

  • Retrieve the time WITHOUT the current date

    Hi, I would like to retrieve only the current system time.

    If I use the System.currentTimeMillis (), I'll be able to retrieve the date and time and have long value of it since 1970. Is it possible to get the current time from the beginning of the day? Or at least format after I have recover time current time system?

    Maybe I can get the time current system in milliseconds, and then subtract the date in milliseconds of her current system? Are there more simpler way?

    Please help me! Thanks in advance!

    That's what I mean:

    long ldate = System.currentTimeMillis();
String date = new SimpleDateFormat("dd.MM.yyyy").format(new Date(ldate));

helpint = Integer.parseInt(date.substring(6));
calendar.set(Calendar.YEAR, helpint);
helpint = Integer.parseInt(date.substring(3, 5));
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