Order this bomb at the end of the month!

Similar Questions

• It should be at this time of the month again!

  It seems that every time that a major upgrade I happen to have computer problems with my home network.  Here is what is happening for the month of June...  I connect to my Tablet and needed to find a magazine article that was stored in a shared in my Vist32 (ultimate) desktop directory.  And low and behold I can't access my network drive which worked for about three weeks, since the implementation of maped.

  Now would someone please understand what was fucking time Jules Destrooper and say it would be how to fix!

  Thank you again...

  Greg

  Hi Gregory,

  Please visit the link below and download the Link Layer Topology Discovery () on your tablet PC XP LLTD Responder install it, then restart the computer and try to access the files on the Vista Machine.

  Please visit the link below to download the Link Layer Topology Discovery () LLTD Responder:

  http://www.Microsoft.com/downloads/details.aspx?FamilyId=4F01A31D-EE46-481e-BA11-37F485FA34EA&displaylang=en

  Hope the above steps will help you to solve the problem.

  Please answer if the problem is resolved.

• How to set the filter criteria for the month and the year to aid in the timestamp input field?

  Hello

  I use jdev 11.1.2.3.

  I have a problem with the generation of reports, I have a report table that is in the form of VO (query based) and I want to search this table in the month and year of the basic

  but in this table (query) This timestamp field of having value based on... How to do a search with the name of the month and year only... Here I totally use vo base query to generate a

  reports... Anyone can guide me.

  Thank you.

  I want to create a drop-down list for month + year as an executable parameters with bind variable no matter what idea this subject, my attribute here is TimestampFormat.

  Then add to your sql query something like:

  WHERE extract (your_timestamp_column MONTHS) =: monthBindVar

  OR an extract (YEAR your_timestamp_column) =: yearBindVar

  and add monthBindVar and yearBindVar as a bind variable to your view object.

  Then you can use it as a ExecuteWithParams operation (or manually set these bind variables and execute the query)

  Dario

• Elgato EyeTV - I copied my recordings on another external hard drive, assigned to this disk as the location of the Archive, restarted the computer, but the location of unpublished/are not recognized. (End of 2006 Intel iMac / OSX 10.7.5 Lion)

  Elgato EyeTV - I copied my recordings on another external hard drive, assigned to this disk as the location of the Archive, restarted the computer, but the location of unpublished/are not recognized. (End of 2006 Intel iMac / OSX 10.7.5 Lion)

  What do you mean by "assigned to this disk as the location of the Archive" is this something to do with the software you use?

  The drive is formatted for Mac?  Menu go to menu, click Finder go > utilities > disk utility > click on external drives partition - format it sets out Mac OS X extended.   Otherwise, to save the files on the disk and ease than Mac OS

  

• Had to reformat my hard drive, now when I try to reinstall Windows XP I get a blue screen with this code at the end 0x0000007b.

  has had to reformat my hard drive now when he star0x0000007b (0x78d663c, 0xc0000034, 0x00000000, 0x00000000)

  has had to reformat my hard drive, now when I try to reinstall windows xp, I get a blue screen with this code at the end 0x0000007b (0x78d663c, 0xc0000034, 0x00000000, 0x00000000) how to solve this problem

  Hello

  I saw the 0x0000007B BSOD caused by trying to install XP on a disk hard while the BIOS is designating the reader as AHCI instead of IDE. XP has no native AHCI drivers, resulting in a stop 7B. Unless the PC had originally Vista or Win 7, but it might be useful to check that it is not likely.

  If the BIOS is set to AHCI, you could do one of three things (depending on whether your PC has a floppy drive)...

  1 find the Setup F6 disk on AHCI support at installation time (start with the manufacturer's website if you do not already have such a thing). Watch the very hit F6 prompt early in the installation process.

  2. change the setting in BIOS on IDE / ATA

  3. create a new "slipstreaming" installation disc drivers AHCI in the existing installation disc, see http://www.nliteos.com/index.html

  After the back if your BIOS is IDE / ATA

  Tricky

• I want to use InDesign, but for this month only! so if I pay for the "monthly plan" means that I pay for this month then the plan InDesign will end?

  I want to use InDesign, but for this month only! so if I pay for the "monthly plan" means that I pay for this month then the plan InDesign will end?

  Hello

  Please go through the Adobe - General conditions of subscription as well.

  Alternatively, you can contact customer service

  Hope that helps!

  Kind regards

  Sheena

• I installed Photoshop CC2014 to CC2015 which is a single 30 day trial (?) and my CC2014 is not accessible now, why? Does this mean that I have TO pay for this upgrade at the end of 30-day track? I can't go back to CC2014?

  I installed Photoshop CC2014 to CC2015 which is a single 30 day trial (?) and my CC2014 is not accessible now (it displays an exclamation mark) why? Does this mean that I have TO pay for this upgrade at the end of 30-day track? I can't go back / stick with CC2014?

  There is a problem with your account if it does not show that your subscription is current.

  Contact adobe support by clicking on this link then "still need help" as soon as it appears, http://helpx.adobe.com/x-productkb/global/service-ccm.html

• I'll try to find the right program for my project, I just invented it a design with the United States Patent Office and I need my logo in order to obtain a trade-mark. Two things I have to add this logo on the product I have on my computer and I need to b

  I need a program that allows me to design my Logo, also the product that I invented, I need to be able to put the logo on what I have in my computer. The logo is the overlap of 2 letters which I have on my computer and the word of this logo at the back of my product. I don't know what program would help me to do so. I was thinking about the color of cs6 Adobe illustrator, but not sure.

  Hi Chicky,

  Looking at your statement, Illustrator should be the best program to work with, if you need to be a vector art, otherwise you can use Photoshop as well. Please see the links below for some basics of Illustrator:

  Tutorials Illustrator CC | Learn how to use Illustrator CC

  Illustrator tutorials | Lynda.com

  How to design a crest logo | Adobe Illustrator CC tutorials

  Kind regards

  OM

• Control the order of execution of the init/release

  I have a small program that I write in LabView.  It has an API (one set of screws to wrapping the functions of the DLL to control a device).

  Other such programs in the Gayshop make liberal use of the structures of the sequence.  I understand that the sequence into LabVIEW structures are not usually recommended.  I am writing my program with the best style of LabVIEW (as far as I understand - I'm still a relative novice in LabVIEW).

  I found that I could wire together the error / mistake Terminal to create a data flow to control the order of execution and it works beautifully.

  However, there are some cases where it is not enough.

  Here is an example.  I hope that the answer to this will answer my other questions.  If this is not the case, perhaps that I'll post more.

  One of the first live I call is an Init function.  One of the last screw is the release function.

  The release function must be called at the end, after the rest of the program executed (in this case, it is after the user requests the stop).  It should be naturally at the end (or almost) of the error string in / out connections error (as it is currently).

  However, the error it receives, which will determine whether or not he will run, should be the output of Init.  Release should work even if something else has failed.

  I enclose a photo showing the problem, with most of the code snipped out (as exactly what is happening in the middle is not relevant).

  What is the elegant way to handle this in LabVIEW.  Is it really a deal for a structure of the sequence, or is there a way more pleasant or better?  How would you recommend handling?

  Thank you very much.

  BP

  I agree with what pincpanter said, more you will need to use the status of the function 'Init '.

  Note that you can ignore the error and make the merger within the Vi version if you wish.

  Steve

  

• Follow this procedure when the Sansa Connect recovery tool does not work!

  Hey people;

  This thread is just to consolidate the info from a lot a longer wire, earlier.

  Currently, the Sansa Connect recovery tool may or may not work for you.  You can see an error like 'failed to connect to the Internet' or "cannot retrieve the device, SanDisk contact technical support for assistance."  If Yes, it's probably because the recovery tool is unable to download the firmware images he needs zing.net.  SanDisk has not (yet) recognized this problem.  The strange thing is that * sometimes * recovery tool works, if you already have images of the firmware on the drive... but usually it doesn't.

  So here's what you do (with thanks to Larlos for providing the firmware images and order lines to their installation).  This assumes that you're 'stuck' to the "necessary recovery" post on your connection.  If not and you are in the regular menu of Sansa Connect, first follow steps 2 and 3 in this paper: http://mp3support.sandisk.com/tools/connect-recovery-instructions.pdf, do the following:

  (1) download the zip file containing the images of the http://www.megaupload.com/?d=UNLDGZ1N firmware

  (2) search for the following files in the zip file, and then copy them into the directory of your drive "C:\Program Updater Connect Device Recovery\cmdline":

  • everest_initrd_ext_prod_1.1.1.50239.SRR.e
  • everest_vmlinux_ext_prod_1.1.1.50239.SRR.e
  • yeverest_zap_ota_rel_1.1.2.65799.tar.gz.e
  • yeverest_zap_ota_rel_ext_prod_1.1.2.65799.SIG

  (3) in the same directory, create a file named recovery.bat that contains the following three lines:

  zsi_fw.exe w everest_vmlinux_ext_prod_1.1.1.50239.srr.e everest_initrd_ext_prod_1.1.1.50239.srr.e

  zaprecover.exe t 600000 f yeverest_zap_ota_rel_1.1.2.65799.tar.gz.e yeverest_zap_ota_rel_ext_prod_1.1.2.65799.sig

  pause

  (4) connect your Sansa Connect USB.

  (5) run the recovery.bat file (double-click it in Windows Explorer, or run from a DOS command prompt).  The line of 'pause' is there only so you can see the results of running if you run it from Windows Explorer.  Expect the recovery to the end; at the end of that your connection will restart.  If Windows displays the hardware wizard detected during this process, simply cancel the wizard.

  whturner wrote:

  Thanks for the help - it updated my white box to connect to the WiFi and after registration on Yahoo (without choosing any service, just updated my old email and user ID) I now INet radio with a number of stations that work fine on my home wireless network. To do this, DND to explore and syncs with WMP OK. A few quirks that I wonder about.        (1) after the firmware update, my ZAP showed that 1.2.0.58335r and OS = 1.2.0.58835 - NOW (the next day), it changed to ZAP = 1.1.2.65799r and 1.1.1.50239 = OS. Every thing seems to work even though; I have a firmware download while I was playing with the INet radio?     2) there is also a new menu item "Server Zing" that lists the name of the module, the version, and the primary and secondary server. Is this normal?  (3) what Yahoo service I - I see a small Y! symbol at the top right of the screen.                                                                                                                                               Thank you very much and congratulations Warren

  (1) no; you see the version numbers are associated with the files of the firmware (names starting with "everest" and "yeverest" files) that you have either downloaded when you ran the recovery tool, or download in megaupload.com zip file.

  (2) Yes, it's normal.  Zing is the company that allows you to manage authentication of audio stream and firmware for the connection.

  (3) the Y! symbol indicates just that when you use the Internet Radio feature, you are streaming audio of Yahoo (in fact, now owned by CBS Radio).  There is also a function of Flickr photos, which is associated with Yahoo.

• I want to find the string "EMP1" procedures have this chain of the package

  Hi team,

  I have a package, the package, it has 70 technical acts, I want to find the string "EMP1" what procedures to have this channel under this package.
  If I use dba_source its name from package edition only. not to say about wise procedures in this package.
  can you please help here to find procedure under the package names because I analysis for all of the schema.

  Thanks in advance.

  Thanks and greetings
  Vincent

  Hello

  You can use the pl/sql program to do this by giving the name of the package as an input. It won't like your exact expectations. But of course, it will help you.
  

  
  

  
  

  DECLARE

  CURSOR c1 IS

  SELECT *.

  From all_source b

  WHERE upper (b.text) like '% EMP1% '.

  AND b.name = & nom_package

  ONLINE ORDERING;

  CURSOR c2 (ln_line NUMBER) IS

  SELECT *.

  From all_source one

  WHERE b.SID = & nom_package

  AND (UPPER (a.TEXT) LIKE '% FUNCTION %') OR UPPER (a.TEXT) LIKE '% PROCEDURE % '.

  AND a.line<=>

  ORDER BY desc line;

  lv_source all_source % rowtype;

  BEGIN

  I'm in c1 LOOP

  --

  OPEN c2 (i.line);

  Get INTO lv_source c2;

  dbms_output.put_line (' procedure ' | lv_source.) Line: ' text: ' | lv_source. (Text);

  CLOSE C2;

  --

  END LOOP;

  END;

  /

  
  

  
  

  
  

  Concerning

  Patrick Reddy.K
  

• Breaking a year in coming weeks of beginning and end Dates (parameters) and first and last day of the month

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  SELECT first_thursday + (7 * (LEVEL - 1))   AS week_start_date,
                   first_thursday + (7 * LEVEL) - 1    AS  week_end_date
  FROM
  (
    SELECT TRUNC(p_from_date + 4, 'IW') - 4   AS first_thursday, -- Week should start the pre ceeding THURSDAY based on the Start Date
                    TRUNC( p_to_date + 4,  'IW') - 5     AS last_wednesday
    FROM
    (
      SELECT to_date('01-JAN-2013') AS p_from_date,
                      NVL(to_date('31-DEC-2013'), SYSDATE) AS p_to_date
      FROM     dual
    ) parms
  ) end_points
  CONNECT BY LEVEL <= ( last_wednesday + 1 - first_thursday)/7;
  

  Currently, this is the result I get (I'm only including the months of January and December here).

  Week_Start_Date     Week_End_Date
  27-DEC-12                02-JAN-13
  03-JAN-13                 09-JAN-13
  10-JAN-13                 16-JAN-13
  17-JAN-13                 23-JAN-13
  24-JAN-13                 30-JAN-13
  31-JAN-13                 06-FEB-13
  

  December:

  28-NOV-13               04-DEC-13
  05-DEC-13              11-DEC-13
  12-DEC-13              18-DEC-13
  19-DEC-13              25-DEC-13
  

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  01-JAN-13              02-JAN-13
  03-JAN-13              09-JAN-13
  10-JAN-13             16-JAN-13
  17-JAN-13             23-JAN-13
  24-JAN-13             30-JAN-13
  31-JAN-13             31-JAN-13
  

  February:

  01-FEB-13    06-FEB-13
  07-FEB-13    13-FEB-13
  14-FEB-13    20-FEB-13
  21-FEB-13    27-FEB-13
  28-FEB-13    28-FEB-13
  

  November:

  31-OCT-13    06-NOV-13
  07-NOV-13    13-NOV-13
  14-NOV-13    20-NOV-13
  21-NOV-13    27-NOV-13
  28-NOV-13    04-DEC-13
  

  December:

  01-DEC-13           04-DEC-13
  05-DEC-13           11-DEC-13
  12-DEC-13          18-DEC-13
  19-DEC-13          25-DEC-13
  26-DEC-13          31-DEC-13
  

  Hello

  Roxyrollers wrote:

  Hello people:

  I have currently a query that picks up all the weeks between a date range where my week starts on Thursday and ends on Wednesday. The following query works fine except that I need the week of beginning and end, from beginning and end Dates of months and the beginning and the Dates of end of the values of the settings, I'm passing. In this case, I chose January 1, 2013 to 31 December 2013.

  Any help or pointers would be great!

  Thank you!

  Problem: I am picking up days of December 2012 as the first week began on December 27, 2012. In addition, in December, I'm pretty much lost last week as well (26 December - 31 December).

  The request in hand:

  1. First_thursday SELECT + (7 * (LEVEL - 1)) AS week_start_date,
  2. first_thursday + (7 * LEVEL)-1 AS week_end_date
  3. Of
  4. (
  5. SELECT TRUNC (p_from_date + 4, 'IW') - 4 AS first_thursday,-week should start to perform the pre-mounted THURSDAY based on the Start Date
  6. TRUNC (p_to_date + 4, 'IW') - 5 AS last_wednesday
  7. Of
  8. (
  9. SELECT to_date('01-JAN-2013') AS p_from_date,
  10. NVL (to_date('31-Dec-2013'), SYSDATE) AS p_to_date
  11. OF the double
  12. ) parms
  13. ) end_points
  14. CONNECT BY LEVEL<= (="" last_wednesday="" +="" 1="" -="">

  Currently, this is the result I get (I'm only including the months of January and December here).

  1. Week_Start_Date Week_End_Date
  2. DECEMBER 27, 12 2 JANUARY 13
  3. JANUARY 3, 13 JANUARY 9, 13
  4. 10 JANUARY 13 JANUARY 16, 13
  5. 17 JANUARY 13 23 JANUARY 13
  6. 24 JANUARY 13 30 JANUARY 13
  7. 31 JANUARY 13 FEBRUARY 6, 13

  December:

  1. NOVEMBER 28, 13 4 DECEMBER 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13

  What I would really like is based on start and end Dates, as well as the first and the last day of the month is similarly try nicely. I have provided and then gently break at the end of the month:

  January:

  1. JANUARY 1, 13 2 JANUARY 13
  2. JANUARY 3, 13 JANUARY 9, 13
  3. 10 JANUARY 13 JANUARY 16, 13
  4. 17 JANUARY 13 23 JANUARY 13
  5. 24 JANUARY 13 30 JANUARY 13
  6. 31 JANUARY 13 JANUARY 31, 13

  February:

  1. 1ST FEBRUARY 13 FEBRUARY 6, 13
  2. 7 FEBRUARY 13 FEBRUARY 13, 13
  3. 14 FEBRUARY 13 FEBRUARY 20, 13
  4. 21 FEBRUARY 13 FEBRUARY 27, 13
  5. 28 FEBRUARY 13 FEBRUARY 28, 13

  November:

  1. 31 OCTOBER 13 NOVEMBER 6, 13
  2. 7 NOVEMBER 13 NOVEMBER 13, 13
  3. 14 NOVEMBER 13 NOVEMBER 20, 13
  4. 21 NOVEMBER 13 NOVEMBER 27, 13
  5. NOVEMBER 28, 13 4 DECEMBER 13

  December:

  1. 1ST DECEMBER 13 DECEMBER 4, 13
  2. 5 DECEMBER 13 DECEMBER 11, 13
  3. 12 DECEMBER 13 18 DECEMBER 13
  4. 19 DECEMBER 13 DECEMBER 25, 13
  5. 26 DECEMBER 13 DECEMBER 31, 13

  Why the "weeks" in November, have all 7 days, while the "weeks" in the first or the last week in the other month usually have less?  (For example, February 28 is a 'week' alone.)

  The following works for the other months:

  WITH all_days AS

  (

  SELECT DATE "2013-01-01' + LEVEL - AS a_date 1

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT DISTINCT

  More GRAND (TRUNC (a_date + 4, 'IW') - 4)

  , TRUNC (a_date, 'MONTH')

  ) AS week_begin

  , The LEAST (TRUNC (a_date + 4, 'IW') + 2

  TRUNC (LAST_DAY (a_date))

  ), Week_end

  Of all_days

  ORDER BY week_begin

  ;

  Output:

  WEEK_BEGIN WEEK_END

  ----------- -----------

  January 1, 2013 January 2, 2013

  January 3, 2013 January 9, 2013

  January 10, 2013 January 16, 2013

  January 17, 2013 January 23, 2013

  January 24, 2013 January 30, 2013

  January 31, 2013 January 31, 2013

  February 1, 2013 February 6, 2013

  February 7, 2013 February 13, 2013

  February 14, 2013 February 20, 2013

  February 21, 2013 February 27, 2013

  February 28, 2013 February 28, 2013

  ...

  November 1, 2013 November 6, 2013

  November 7, 2013 November 13, 2013

  November 14, 2013 November 20, 2013

  November 21, 2013 November 27, 2013

  November 28, 2013 November 30, 2013

  December 1, 2013 December 4, 2013

  December 5, 2013 December 11, 2013

  December 12, 2013 December 18, 2013

  December 19, 2013 December 25, 2013

  26 December 2013 31 December 2013

• order by pulling on the cost of the query by 4 times

  I have the following query:

  Select company_id, company_name, total_depts,

  TO_CHAR (case when total_depts = 0 then 0 otherwise (accnt_count/total_depts * 100) end, '990,99'). ' %' as accnt_count_percent.

  TO_CHAR (case when total_depts = 0 then 0 otherwise (lib_count/total_depts * 100) end, '990,99'). ' %' as lib_count_percent.

  TO_CHAR (case when total_depts = 0 then 0 otherwise (house_count/total_depts * 100) end, '990,99'). ' %' as house_count_percent.

  TO_CHAR (case when total_depts = 0 then 0 otherwise (fin_count/total_depts * 100) end, '990,99'). ' %' as fin_count_percent.

  "to_char (case when total_depts = 0 then 0 otherwise (total_depts - (accnt_count + lib_count + house_count + fin_count)) / total_depts * 100 end, ' 990.99' ') | ' %' as total_success

  , total_deptments, less, More, version_id_count as total_users

  Of

  (

  Select dpt_inst.company_id as company_id,

  dpt_inst.company_name as company_name,

  Count (*) as total_depts,

  sum (case when (upper (err.problem) = upper ('accnt_count')) then 1 else 0 end) as accnt_count,

  sum (case when (upper (err.problem) = upper ('lib_count')) then 1 else 0 end) as lib_count,

  sum (case when (upper (err.problem) = upper ('fin_count')) then 1 else 0 end) as fin_count,

  sum (case when (upper (err.problem) = upper ('house_count')) then 1 else 0 end) as house_count

  of education.dept_and_inst_view dpt_inst

  Err education.dept_error left join

  On dpt_inst.dept_code = err.code

  where dpt_inst.part_id in ('A', 'L', ')

  and dpt_inst.company_id not in ('L100901', 'L20009')

  Dpt_inst.company_id group, dpt_inst.company_name

  ) inst_dept_q

  inner join

  (

  Select company_id, count of total_deptments (*)

  of education.departments ed_acc

  Join internal cv.cv_customers cv_usr

  On ed_acc.cust_id = cv_usr.id

  join in-house cv.customer_enrollment cvce

  On cv_usr.subs_id = cvce.subs_id

  where ed_acc.status = 'important'

  and company_id not in ('L100901', 'L20009')

  Company_id group

  ) dept_customers_q on inst_dept_q.company_id = dept_customers_q.company_id

  inner join

  (

  Select

  COMPANY_ID,

  sum (case when version_id = 1 then 1 else 0 end) as less.

  sum (case when version_id = 2 then 1 else 0 end) as More.

  Count (*) version_id_count

  de)

  Select distinct (cvce.subs_id), ed_acc.company_id, cvce.version_id

  of education.departments ed_acc

  Join internal cv.cv_customers cv_usr

  On ed_acc.cust_id = cv_usr.id

  join in-house cv.customer_enrollment cvce

  On cv_usr.subs_id = cvce.subs_id

  If not ed_acc.company_id ("L100901", "L20009")

  and ed_acc.status = 'important'

  ) company_id group

  ) inst_cust_cnt_q on dept_customers_q.company_id = inst_cust_cnt_q.company_id

  order by 3 desc

  The Decree of this query is the price increase by 4 times.

  I wan to see the Plan to explain SQL Developer but when I paste in this window it is all unreadable (undergoes the hanging indent). How to put the plan to explain it?

  The problem with sorting, is that it is based on the COUNT (*) FUNCTION total_depts. Since it is an aggregate, value

  You can't have an index based on this value. Therefore, the cost will be higher for sorting on this column. You can

  move the first part of the clause to a with clause that could help. It's certainly worth a try.

  You should also allow each part of the query make each less expensive part, so all of the query will be cheaper to run.

  ORACLE-BASE - Clause: subquery factoring

• The end of the month selection

  Hi all
  
  We have a table say xyz with two columns month_cd and end_date where month is a code for each month and the end of the month is an end date of the regular calendar months and months where the end of the month is a day of weekend so for these months End_date is entered by a user in this table by another application. and we will have this information for al months in privious and current of the year
  
  for ex:
  
  Month_cd end_date
  201101 01/30/2011
  201102 03/04/2011
  201103 03/31/2011
  201104 04/30/2011
  201105 06/04/2011
  
  Now I have pick months based on the end_date, I mean everytime I run a query to select month_cd it must show date of cd for the month up to the endof month (maybe not a calendar end date)
  
  How can achieve us? Please help me.

  SQL and PL - SQL forum would be more appropriate for this type of question, and you should always mention the full version of Oracle you are using (for example, 10.2.0.4).

  Depending on the version of Oracle, there are several possible solutions. Here are a few that you can try:

  --sample data:
  with t as (
  select 201101 as month_cd, to_date('01/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201102 as month_cd, to_date('03/04/2011','mm/dd/yyyy') as end_date from dual union all
  select 201103 as month_cd, to_date('03/31/2011','mm/dd/yyyy') as end_date from dual union all
  select 201104 as month_cd, to_date('04/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201105 as month_cd, to_date('06/04/2011','mm/dd/yyyy') as end_date from dual
  )
  --end of sample data
  select max(month_cd) keep (dense_rank first order by case when end_date >= trunc(sysdate) then end_date end nulls last) as month_cd
  from t;
  

  --sample data:
  with t as (
  select 201101 as month_cd, to_date('01/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201102 as month_cd, to_date('03/04/2011','mm/dd/yyyy') as end_date from dual union all
  select 201103 as month_cd, to_date('03/31/2011','mm/dd/yyyy') as end_date from dual union all
  select 201104 as month_cd, to_date('04/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201105 as month_cd, to_date('06/04/2011','mm/dd/yyyy') as end_date from dual
  )
  --end of sample data
  select month_cd from (
  select month_cd, end_date, (lag(end_date,1,to_date('01/01/1900','mm/dd/yyyy')) over(order by end_date))+1 as begin_date
  from t
  )
  where trunc(sysdate) between begin_date and end_date
  ;
  

  or

  --sample data:
  with t as (
  select 201101 as month_cd, to_date('01/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201102 as month_cd, to_date('03/04/2011','mm/dd/yyyy') as end_date from dual union all
  select 201103 as month_cd, to_date('03/31/2011','mm/dd/yyyy') as end_date from dual union all
  select 201104 as month_cd, to_date('04/30/2011','mm/dd/yyyy') as end_date from dual union all
  select 201105 as month_cd, to_date('06/04/2011','mm/dd/yyyy') as end_date from dual
  )
  --end of sample data
  select month_cd
  from t
  where end_date=(
    select min(end_date)
    from t where end_date >= trunc(sysdate)
    )
  ;
  

  Kind regards
  Bob

• Order by the name of the month

  Hi all
  
  Is there a way to structure the report in order by month? I have a question for the chart as a sub-
  
  
  
  SELECT LINK NULL, month LABEL, SUM (TOT_VISITORS) VALUE OF RTV_VISTATS
  
  where financial_year =: P36_CHART_VALUE
  
  Group by month
  
  order by 1
  
  
  
  and it displays the result in alphabetical order as April, December, February, June, etc. But I want to display the name of the months January, February, March, April and so on.
  
  
  
  Can someone help me with this please?
  
  
  
  Thanks advanced
  
  
  
  Pascal M

  Hello

  Simply fill in the months missing "NOV" "MAR" IN "NOT IN ().

  order by to_date)
  -case when upper (substr (TRIM (MONTH), 1, 3)) NOT IN ("JAN", "Feb",..., "DEC") THEN
  ELSE 'JAN' substr (TRIM (MONTH), 1, 3) END
  (|' / 01/2008 ","month, dd, yyyy")

  Edited by: bobbydj 09 Sep, 2008 21:51

  /*
  Incidentally, if you could clean your month column first, then you can use my first example. After cleaning, you should consider adding a validation on month column in order to eliminate the months not valid (a perhaps check constraint).
  Also avoid using common words (e.g. month) of the reserve under the column names. :)
  */