Performance problem: select *.

Similar Questions

• Performance problem when a direct IO option is selected

  Hello Experts,
  
  One of my clients has a performance problem when a direct IO option is selected. Reports that there was increase in the memory usage of storage Direct to e/s is selected compared to the option of buffering of i/o.
  
  There are two applications on the server of type OSB. When using IO buffer warnings, has experienced a high level of read and write I / O direct i/o reduced the read and write I / O, but greatly increases the memory usage.
  
  Other information-
  
  (a) Details of the environment
  
  HSS - 9.3.1.0.45, AA - 9.3.1.0.0.135, Essbase - 9.3.1.2.00 (64-bit)
  OS: Microsoft Windows x 64 (64-bit) 2003 R2
  
  (b) what is the use of memory when it is buffered for i/o and direct i/o is used? What running of calculations, restructuring of the database and the database queries? These processes take a lot of time for execution?
  
  Application 1: 700 MB buffered, 5 GB live
  Application 2: Buffering 600 MB to 1.5 GB, 2 GB Direct
  Calculation time can increase from 15 minutes to 4 hours. Even with the restructuring.
  
  
  (c) what is the current database cache; Cache data files and cache Index values?
  
  Application 1: Buffering (index 80 MB, 400 MB of data), Direct (Index 120Mo;) 4 GB data file, given 480 MB).
  Application 2: Buffering (index 100MB, 300 MB of data), Direct (Index of 700 MB, 1.5 GB, 300 MB of data from data file)
  
  
  (d) what is the total size of the files ess0000x.pag and ess0000x.ind files?
  
  Application 1: Page 20 GB, 1.7 GB of the Index file.
  Application 2: Page 3 GB, index of 700 MB.
  
  Any suggestions on how to improve performance when direct i/o is enabled? All performance records in above scenario would be a great help.
  
  Thanks in advance.
  
  
  
  Kind regards
  Sudhir

  This post understanding buffered of e/s and e/s direct may be of some use to you.

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• WRT54GS - wireless performance problem

  Dear someone

  I am currently having performance problems with my WRT54GSv1.1

  Just received my new internet connection to 30Mbit. Unfortunately, I am not able to download at that speed. If I connect via one of the linksys router's ethernet ports, I'm a happy person, but using the wireless makes me a little less happy.

  Wireless: 15Mbit/s

  Through the cable: 27Mbit/s

  Network information:

  The distance between the router and the computer laptop 3-4 meters

  Linksys WRT54GSv1.1 - Firmware Version: v4.71.4

  Network wireless - g only mode

  TV - 6 (because all the surrounding neighbor use 10-11, I noticed using Cain Abel & wireless discovered 4.9.29)

  Security: WPA2-Personal (TKIP + AES)

  All other settings are default (just reset to the factory settings).

  Laptop:

  Windows Vista Business SP1 32-bit

  Intel PRO/Wireless 3945ABG (installed the latest drivers from the website of intel, default settings)

  When you check the diagnostic of Intel tools, it tells me the link is 54 megabits and pushes meter packages of 54 megabits, while all lower speeds remain the same.

  More diagnostic information:

  Percent missed beacons: 0

  Percent transmit errors: 18

  Current Tx power: ~ 32 mW (100%)

  Supported power levels: 1.0 mW - 32.0 mW.

  Hope someone can help me here.

  Thanks in advance!

  Kind regards

  Ski Klesman

  Although wireless g "connects" to 54 Mbit/s, the maximum possible wireless "data rate" (in ideal laboratory conditions) is only about 20 to 25 Mbit/s.  Unfortunately, the phrase "in ideal laboratory conditions" generally excludes home intrusion!

  The aerial transmission for wireless connections is higher than for wired connections.   Thus, most individuals find that their Wi - Fi connection works at 50% to 70% of their speed of wired (LAN).  Your wired LAN being 27 Mbps connection speed, your 15 Mbps wireless speed is within normal limits.

  You might be able to tweak a bit more speed from your wireless network by optimizing all your wireless settings.  Here are a few suggestions:

  I guess you want actually to WPA2 encryption.  If so, set to AES only.   When you set the router to TKIP and AES, you actually tell the router to accept a WPA or WPA2 connection.

  Also, give your network a unique SSID. Do not use "linksys". If you use "linksys", you can try to connect the router to your neighbor. Also set 'SSID Broadcast' to 'active '. This will help your computer to find and lock on the signal from your router.

  Bad wireless connections are often caused by interference from other 2.4 GHz devices. This includes cordless phones, baby monitor wireless, microwave ovens, wireless mice and keyboards, wireless speakers and wireless network from your neighbor. In rare cases, Bluetooth devices can interfere. Even some 5 + GHz phones also use the 2.4 Ghz band. disconnect these devices and see if that solves your problem.

  In your router, try another channel. There are 11 channels in the band of 2.4 GHz channel 1, 6 or 11 generally works better. Discover your neighbors and see what channel they use. Because the channels overlap, try to stay at least + 5 or - 5 channels of your more powerful neighbors. For example, if you have a powerful neighbour on channel 9, try any channel 1 to 4.

  Also, try putting the router about 4 to 6 feet above the ground in an open area. Do not place behind your screen or other computer equipment or speakers. The antenna must be vertical.

  In addition, in the computer, go to your wireless software and go to 'Favorite networks' (sometimes called 'Profiles'). There are probably a few listed networks. Remove any network called "linksys". Also remove any network that you don't recognize or that you no longer use. If your current network is not listed, enter its information (SSID, encryption (if any) and key (if any)). Select your current network and make your network by default, then set it to auto login. You may need to go to 'settings' to do this, or you may need to right click on your network and select 'Properties' or 'settings '.

  If you continue to have problems, try the following:

  For wireless g routers, try setting the "baud rate" at 54 Mbps.

  If you still have problems, download and install the latest firmware for your router. After an update of the firmware, you must reset the default router, and then configure the router again from scratch. If you have saved a router configuration file, DO NOT use it.

  I hope this helps.

• 4.2 APEX performance problem

  Hi all

  We are facing the problem of performance when we are by selecting one of the underside of responsibility that rests in the Organization as if we select APEX_01 Reporting ALL then in this case, we can see all the organization such as ETL, BRN, CHICKEN ect in home page, but I am facing performance problem when it forms that select area of responsibility to the home page. Please indicate how to check this page's performance in the APEX and also advise how to solve this problem.

  

  LnTInfotech wrote:

  so you want to say below takes more time and we need to address this request?

  15.34901

  224.01663

  ... Run the statement: SELECT DISTINCT papf.full_name a, papf.full_name b OF po_agents pa per_all_people_f women's wear org_organization_definitions org WHERE 1 = 1 AND papf.person_id = pa.agent_id AND org.organization_CODE = NVL(:P1_WARE_HOUSE,org.organization_CODE) AND TRUNC (SYSDATE) BETWEEN papf.effective_start_date AND papf.effective_end_date AND EXISTS SELECT (SEPARATE 1 OF po_headers_all poh WHERE poh.agent_id = pa.agent_id AND poh.org_id = org.operating_unit)

  This request seems to be missing a join. An obligation to use DISTINCT in application code usually indicates that there is something seriously wrong with the data model or query...

• Performance problem - oracle 10.2.0.4

  HI Experts,

  Today I met a performance problem. I pulled a simple query to get the number of records in a table existed in the databases of PROD and QA. The two databases are the same settings at parameter level. But when I launch the application, Prod database takes 10 minutes to get the result. Not sure why prod base it takes a lot of time.

  Additional information:

  ---------------------

  The number of lines is almost the same on the two databases

  OPERATING SYSTEM: IBM AIX

  Oracle: 10.2.0.4

  QA Database - explain plan

  ==========================

  06:40:49 SQL > select count (*) in the Siebel.s_prod_baseline;

  COUNT (*)

  ----------

  42146408

  Elapsed time: 00:00:45.35 == > just 45 seconds

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------

  Hash value of plan: 645963650

  -------------------------------------------------------------------------------

  | ID | Operation | Name               | Lines | Cost (% CPU). Time |

  -------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                    |     1.  1165 (1) | 00:00:14 |

  |   1.  GLOBAL TRI |                    |     1.            |          |

  |   2.   INDEX SCAN FULL | S_PROD_BASELINE_P1 |    42 M |  1165 (1) | 00:00:14 |

  -------------------------------------------------------------------------------

  Database of PROD explain plan

  ======================

  06:42:59 SQL > select count (*) in the Siebel.s_prod_baseline;

  COUNT (*)

  ----------

  42730261

  Elapsed time: 00:10:13.43 == > took more than 10 minutes

  PLAN_TABLE_OUTPUT

  --------------------------------------------------------------------------------

  Hash value of plan: 645963650

  -------------------------------------------------------------------------------

  | ID | Operation | Name               | Lines | Cost (% CPU). Time |

  -------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |                    |     1.  4160 (1) | 00:00:50 |

  |   1.  GLOBAL TRI |                    |     1.            |          |

  |   2.   INDEX SCAN FULL | S_PROD_BASELINE_P1 |    42 M |  4160 (1) | 00:00:50 |

  -------------------------------------------------------------------------------

  Could if it you please let me know why oracle it takes a lot of time prod database?

  Thank you..

  > There was another option to check why prod database behaves differently?

  Yes.  The trace file, TRACE the request and review (or the tkprof).

  Hemant K Collette

• [ORACLE 10.2.0.5] performance problem with high enq: TX - line lock contention waiting

  Hello

  I have a performance problem involving high line response to locking conflicts that I can't wait.

  The application updates the specific table about 1200 times for my AWR report representing 2 hours.

  This update represents 98% of the db_time and wait to enq: TX - line lock conflict is:

  -83 796 waiting

  -245 441 seconds

  The application updates a row both an unprecedented SELECT UPDATES. This is the query:

  Update my_table set creationtime =: 1, modificationdate =: version 2, =: creationuserid 3, =: fortesting 4, =: 5, modificationuserid =: participation_uuid 6, =: actimenucontact 7, =: allegroid 8, =: campaign_uuid 9, =: desjardinsemployeetype 10, =: effectiveparticipationtype 11, =: family_uuid 12, =: fetchpasseport 13, =: 14, healthratingfilldate =: hoursofsleeptimecommitment 15, =: igaid 16, =: initialsubscriptiontype 17, =: minutesofsleeptimecommitment 18, =: goal 19, =: partner_uuid 20, =: 21, promotionalemails =: 22, readrules =: sccsubscriptionprovenance 23, =: = subscriptionprovenance 24,: 25, supportemails =: where the 26 uuid = : 27 and = version: 28

  Clause where is filtering on uuid which is the primary key of my_table.

  The uuid is a specific user and two users would not update the same row, what could be the reason for this wait event?

  Thank you

  Why guess when you know.

  Watch ASH data for these events to the queue.

  He'll tell you sql id as well.

• question about a view that I have created to solve performance problems

  Dear alll;
  
  I have an interesting problem. I created a view to help solve some performance problems, I've had with my query
  
  See below
  

  create or replace view view_test as 
  
  Select trunc(c.close_date, 'YYYY-MM-DD') as close_date, t.names
  from tbl_component c, tbl_joborder t
  where c.t_id = t.p_id
  and c.type = 'C'
  group by trunc(c.close_date, 'YYYY-MM-DD'), t.names
  ;

  and I tried test the view using the following syntax and I get the following errors
  

  select k.close_date, k.names from view_test k
  where k.names = 'Kay'
  and k.close_date between to_date('2010-01-01', 'YYYY-MM-DD') and to_date('2010-12-31', 'YYYY-MM-DD')

  However, I get the below error messages
  

  ora-o1898: too many precision specifiers

  I Googled it and tried a lot of things online but I can't solve the problem unfortunately, and I don't know why.
  
  
  
  

  What you trying to accomplish with TRUNC:

  SQL> select trunc(sysdate, 'YYYY-MM-DD') from dual;
  select trunc(sysdate, 'YYYY-MM-DD') from dual
                        *
  ERROR at line 1:
  ORA-01898: too many precision specifiers
  

  I think you meant simply TRUNC (c.close_date)

• Performance problem in production; Please help me out

  Hi all,
  
  I'd really appreciate if someone can help me with this.
  
  Every night, the server's SWAP, Sysadmin add more space disk swap every night and for the last 4 days.
  I run ADDM report from 22:00 to 04:00 (when the server is running out of memory)
  I had the problem of performance of this query:
  

  RECOMMENDATION 4: SQL Tuning, 4.9% benefit (1329 seconds)
        ACTION: Investigate the SQL statement with SQL_ID "b7f61g3831mkx" for 
           possible performance improvements.
           RELEVANT OBJECT: SQL statement with SQL_ID b7f61g3831mkx and 
           PLAN_HASH 881601692

  I can't find what the problem is and why it is a source of performance problem, could you help me please

  *WORKLOAD REPOSITORY SQL Report*
  
  Snapshot Period Summary
  
  DB Name         DB Id      Instance     Inst Num Release     RAC Host        
  ------------ ----------- ------------ -------- ----------- --- ------------
  ****       1490223503 ****             1 10.2.0.1.0  NO  ****
  
                Snap Id      Snap Time      Sessions Curs/Sess
              --------- ------------------- -------- ---------
  Begin Snap:      9972 21-Apr-10 23:00:39       106       3.6
    End Snap:      9978 22-Apr-10 05:01:04       102       3.4
     Elapsed:              360.41 (mins)
     DB Time:              451.44 (mins)
  
  SQL Summary                         DB/Inst: ****/****  Snaps: 9972-9978
  
                  Elapsed 
     SQL Id      Time (ms)
  ------------- ----------
  b7f61g3831mkx  1,329,143
  Module: DBMS_SCHEDULER
   GATHER_STATS_JOB
  select /*+ no_parallel(t) no_parallel_index(t) dbms_stats cursor_sharing_exact u
  se_weak_name_resl dynamic_sampling(0) no_monitoring */ count(*),count("P_PRODUCT
  _ID"),count(distinct "P_PRODUCT_ID"),count("NAME"),count(distinct "NAME"),count(
  "DESCRIPTION"),count(distinct "DESCRIPTION"),count("UPC"),count(distinct "UPC"),
  
            -------------------------------------------------------------       
  
  SQL ID: b7f61g3831mkx               DB/Inst: ***/***  Snaps: 9972-9978
  -> 1st Capture and Last Capture Snap IDs
     refer to Snapshot IDs witin the snapshot range
  -> select /*+ no_parallel(t) no_parallel_index(t) dbms_stats cursor_shari...
  
      Plan Hash           Total Elapsed                 1st Capture   Last Capture
  #   Value                    Time(ms)    Executions       Snap ID        Snap ID
  --- ---------------- ---------------- ------------- ------------- --------------
  1   881601692               1,329,143             1          9973           9974
            -------------------------------------------------------------       
  
  
  Plan 1(PHV: 881601692)
  ---------------------- 
  
  Plan Statistics                     DB/Inst: ***/***  Snaps: 9972-9978
  -> % Total DB Time is the Elapsed Time of the SQL statement divided 
     into the Total Database Time multiplied by 100
  
  Stat Name                                Statement   Per Execution % Snap 
  ---------------------------------------- ---------- -------------- -------
  Elapsed Time (ms)                         1,329,143    1,329,142.7     4.9
  CPU Time (ms)                                26,521       26,521.3     0.7
  Executions                                        1            N/A     N/A
  Buffer Gets                                 551,644      551,644.0     1.3
  Disk Reads                                  235,239      235,239.0     1.5
  Parse Calls                                       1            1.0     0.0
  Rows                                              1            1.0     N/A
  User I/O Wait Time (ms)                     233,212            N/A     N/A
  Cluster Wait Time (ms)                            0            N/A     N/A
  Application Wait Time (ms)                        0            N/A     N/A
  Concurrency Wait Time (ms)                        0            N/A     N/A
  Invalidations                                     0            N/A     N/A
  Version Count                                     2            N/A     N/A
  Sharable Mem(KB)                                 71            N/A     N/A
            -------------------------------------------------------------       
  
  Execution Plan
  ---------------------------------------------------------------------------------------------------
  | Id  | Operation               | Name    | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
  ---------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT        |         |       |       | 24350 (100)|          |       |       |
  |   1 |  SORT GROUP BY          |         |     1 |   731 |            |          |       |       |
  |   2 |   PARTITION RANGE SINGLE|         |  8892 |  6347K| 24350   (1)| 00:04:53 |   KEY |   KEY |
  |   3 |    PARTITION LIST ALL   |         |  8892 |  6347K| 24350   (1)| 00:04:53 |     1 |     5 |
  |   4 |     TABLE ACCESS SAMPLE | PRODUCT |  8892 |  6347K| 24350   (1)| 00:04:53 |   KEY |   KEY |
  ---------------------------------------------------------------------------------------------------
   
  
  
  Full SQL Text
  
  SQL ID       SQL Text                                                         
  ------------ -----------------------------------------------------------------
  b7f61g3831mk select /*+ no_parallel(t) no_parallel_index(t) dbms_stats cursor_
               _sharing_exact use_weak_name_resl dynamic_sampling(0) no_monitori
               ng */ count(*), count("P_PRODUCT_ID"), count(distinct "P_PRODUCT_
               ID"), count("NAME"), count(distinct "NAME"), count("DESCRIPTION")
               , count(distinct "DESCRIPTION"), count("UPC"), count(distinct "UP
               C"), count("ADV_PRODUCT_URL"), count(distinct "ADV_PRODUCT_URL"),
                count("IMAGE_URL"), count(distinct "IMAGE_URL"), count("SHIPPING
               _COST"), count(distinct "SHIPPING_COST"), sum(sys_op_opnsize("SHI
               PPING_COST")), substrb(dump(min("SHIPPING_COST"), 16, 0, 32), 1, 
               120), substrb(dump(max("SHIPPING_COST"), 16, 0, 32), 1, 120), cou
               nt("SHIPPING_INFO"), count(distinct "SHIPPING_INFO"), sum(sys_op_
               opnsize("SHIPPING_INFO")), substrb(dump(min(substrb("SHIPPING_INF
               O", 1, 32)), 16, 0, 32), 1, 120), substrb(dump(max(substrb("SHIPP
               ING_INFO", 1, 32)), 16, 0, 32), 1, 120), count("P_STATUS"), count
               (distinct "P_STATUS"), sum(sys_op_opnsize("P_STATUS")), substrb(d
               ump(min(substrb("P_STATUS", 1, 32)), 16, 0, 32), 1, 120), substrb
               (dump(max(substrb("P_STATUS", 1, 32)), 16, 0, 32), 1, 120), count
               ("EXTRA_INFO1"), count(distinct "EXTRA_INFO1"), sum(sys_op_opnsiz
               e("EXTRA_INFO1")), substrb(dump(min(substrb("EXTRA_INFO1", 1, 32)
               ), 16, 0, 32), 1, 120), substrb(dump(max(substrb("EXTRA_INFO1", 1
               , 32)), 16, 0, 32), 1, 120), count("EXTRA_INFO2"), count(distinct
                "EXTRA_INFO2"), sum(sys_op_opnsize("EXTRA_INFO2")), substrb(dump
               (min(substrb("EXTRA_INFO2", 1, 32)), 16, 0, 32), 1, 120), substrb
               (dump(max(substrb("EXTRA_INFO2", 1, 32)), 16, 0, 32), 1, 120), co
               unt("ANALISIS_DATE"), count(distinct "ANALISIS_DATE"), substrb(du
               mp(min("ANALISIS_DATE"), 16, 0, 32), 1, 120), substrb(dump(max("A
               NALISIS_DATE"), 16, 0, 32), 1, 120), count("OLD_STATUS"), count(d
               istinct "OLD_STATUS"), sum(sys_op_opnsize("OLD_STATUS")), substrb
               (dump(min("OLD_STATUS"), 16, 0, 32), 1, 120), substrb(dump(max("O
               LD_STATUS"), 16, 0, 32), 1, 120) from "PARTNER_PRODUCTS"."PRODUCT
               " sample ( 12.5975349658) t where TBL$OR$IDX$PART$NUM("PARTNER_PR
               ODUCTS"."PRODUCT", 0, 4, 0, "ROWID") = :objn
               

  Dear friend,

  Why do you think you have problems with shared pool? In the ASH report you are provided, there was just 2.5 medium active sessions and 170 requests during this period, he is very low with swimming pool shared, problems
  you have some queries that use literals, it will be better to replace literals with bind variable if possible, or you can set the init cursor_sharing parameter to force or similar, this is the dynamic parameter.
  But it is not so dramatic problem in your case!

  From ASHES of your report, we can see that top wait events is "CPU + wait for CPU", "RMAN backup & recovery i/o" and "log file sync" and 65% of your database of waiting time. And even in the background waiting events.
  If I understand well report, you have two members in your redo log groups, you have problems with log IO writer speed, check the distribution of files on the disc, newspaper editor is slow causing it to wait for the other sessions. High
  processor can be related to rman compression. Best service can we sea GATHER_STATS_JOB consumes 16% of activity 33% consumes rman and only 21% your applications and also there is something running
  SQL * more under the sys (?) account. There is from the top of the sql page, this is the sql in your application, if I understand correctly, 'scattered db reading file' event indicates that full scans have a place, is it normal that your application? If Yes, then try using
  running in parallel, as we can see in the section "Sessions running PQs Top" your report there is no running in parallel, but as I understand it there are 8 processors, try to use parallel executions or avoid full scans. But consider that
  When you do full scans in parallel PGA memory not used CMS, then decrees setting pga_aggregate_target SGA and increase respectively.

  Is there another application or a program running on the server except oracle?
  Is the performance degradation was strong, I mean yesterday, everything was ok, but today all the evil, or it was good?

  Check the reasons for the slow newspaper writer, it can greatly affect performance.
  Also of 90% of the performance problems generally because of the poor sql, poor execution plans.
  Also if you use automatic memory management, tap Settings, but you must know that in this case the settings will identify the minimum values, this is why define them to lower values in oracle can manage
  entirely.
  Don't increase your SGA at this stage, get the awr report, use @$ORACLE_HOME/rdbms/admin/awrrpt.sql, check your cover shot.

  BUT first, you must change your backup strategy, look at my first post, after that check performance again, before you do that it will be very difficult to help you.

  Good luck

• SEM_MATCH queries performance problems

  Hello
  
  We run into performance problems when you use queries SEM_MATCH.
  
  We have a model for data (ABox) containing a triple 12 000 000.
  We have a model for the plan (TBox) containing 800 triple.
  We ran an implication of "OWLprime" and built the model and entailment index with the SEM_APIS commands.
  
  The number of triplets after the execution of entailment was 35.000.000 triples.
  
  We use the following hardware configuration:
  OS: Windows Server 2008
  CPU: Intel CPU Xeon X 5460 @3.15 GHz (2 CPUs).
  64-bit operating system.
  Memory: 32 GB
  
  The results below, it seems that whenever we execute a query against the index of inference, execution time increases significantly.
  
  Here are the results:
  
  
  1. single template query using index of inference:
  SELECT
  
  x
  TABLE)
  SEM_MATCH (' (? x < http://www.we.com/weo.owl#has_symptom > < http://www.we.com/weo.owl #allergyA >)',)
  SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  
  SDO_RDF_RULEBASES ('OWLPrime'), NULL, NULL, NULL)
  +);+
  Execution time: 0.02 seconds
  
  2.
  a.Double query model using index of inference:
  SELECT
  
  x, y
  TABLE)
  SEM_MATCH (' (? x < http://www.we.com/weo.owl#has_symptom > < http://www.we.com/weo.owl #allergyA >))
  
  +(?x RDF:type <http://www.We.com/WEO.Owl#patient>) +.
  
  + (? x < http://www.we.com/weo.owl#id >? y)', +.
  SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  
  SDO_RDF_RULEBASES ('OWLPrime'), NULL, NULL, NULL)
  +);+
  Run time: 127 seconds
  
  b. double model query without indication of inference:
  SELECT
  
  x, y
  TABLE)
  SEM_MATCH (' (? x < http://www.we.com/weo.owl#has_symptom > < http://www.we.com/weo.owl #allergyA >))
  
  +(?x RDF:type <http://www.We.com/WEO.Owl#patient>) +.
  
  + (? x < http://www.we.com/weo.owl#id >? y)', +.
  SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  
  NULL, NULL, NULL, NULL)
  +);+
  Execution time: 2.5 seconds
  
  
  3.
  a. triple query model using index of inference:
  SELECT
  x, y, z
  TABLE)
  SEM_MATCH (' (? x < http://www.we.com/weo.owl#has_symptom > < http://www.we.com/weo.owl #allergyA >))
  (? x rdf:type < http://www.we.com/weo.owl#patient >)
  (? x < http://www.we.com/weo.owl#id >? y)
  (? x < http://www.we.com/weo.owl#gender >? z)',
  SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  SDO_RDF_RULEBASES ('OWLPrime'), NULL, NULL, NULL)
  );
  
  Running time: 146 seconds
  b. triple query model without using the index of inference:
  SELECT
  x, y, z
  TABLE)
  SEM_MATCH (' (? x < http://www.we.com/weo.owl#has_symptom > < http://www.we.com/weo.owl #allergyA >))
  (? x rdf:type < http://www.we.com/weo.owl#patient >)
  (? x < http://www.we.com/weo.owl#id >? y)
  (? x < http://www.we.com/weo.owl#gender >? z)',
  SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  NULL, NULL, NULL, NULL)
  );
  
  Execution time: 9 seconds
  
  Thank you
  
  Doron

  If you use 11.1.0.7.0 and you have installed the 7600122 hotfix, please use:
  -Brace for the SEM_MATCH query syntax
  -Virtual model (using SEM_Models ('TOM_ONTOLOGY', 'TOM_ONTOLOGY_TA'),
  SDO_RDF_RULEBASES ('OWLPrime'))
  -ALLOW_DUP = T (as part of the parameter options of SEM_MATCH)

  For more details, please see
  http://download.Oracle.com/docs/CD/B28359_01/AppDev.111/b28397/sdo_rdf_newfeat.htm

• On query performance problem. Need help.

  It is essentially a performance problem. I hope someone can help me with that.
  
  Basically, I have four old masters (150000 records), (100000 records) Child1, Child2 (50 million records!), child 3 (10000 + records)
  (please forgive the alias).
  
  Each record in the master has now more than one matching record in each table child (one to many).
  Also there may be any record in any or all of the tables for a particular master record.
  
  Now, I need to get the maximum of last_updated_date for each master record in each table 3 child and then find the maximum of
  the three obtained last_active_dates from the 3 tables.
  for example: Master ID 100, to interrogate Child1 for all Master ID 100 records and get the max last_updated_date.
  Same for the other 2 tables and get the most out of these three values.
  (I also need to deal with cases where no trace may be found in a child table to a Master ID)
  
  Write a procedure that uses sliders that the value of each of the performance hits of child table
  evil. And that's, I need to know the last_updated_date for each master file (all 150000 of them). It will probably take days to do this.
  
  SELECT MAX (C1. LAST_UPDATED_DATE)
  MAX (C2. LAST_UPDATED_DATE)
  MAX (C3. LAST_UPDATED_DATE)
  OF CHILD1 C1
  CHILD2 C2
  CHILD3 C3
  WHERE C1. MASTER_ID = 100
  OR C2. MASTER_ID = 100
  OR C3. MASTER_ID = 100
  
  I tried the above, but I got an error in tablespace temp. I don't think that the application is good enough at all.
  (The GOLD clause is to take care of any records in a child table. If there is an AND, then the join and then select
  No, not even if there is no record in a child table, but valid values in the other 2 tables).
  
  Thank you very much.
  
  Published by: user773489 on December 16, 2008 11:49

  You want alias to this field then.

  SELECT MAX (C.LAST_UPDATED_DATE)
  FROM
  (select child1_master_id MASTER_ID, field2, field3,... field4 from CHILD1 UNION ALL
   select child2_master_id MASTER_ID, field2, field3,... field4 from CHILD2 UNION ALL
   select child3_master_id MASTER_ID, field2, field3,... field4 from CHILD3) C
  WHERE C.MASTER_ID = 100
  

  If do you something like that, and explicitly list the columns you want.

  Edit: for something like a specific query for a MASTER_ID...

  SELECT MAX (C.LAST_UPDATED_DATE)
  FROM
  (select child1_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD1 where child1_master_id = 100 UNION ALL
   select child2_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD2 where child2_master_id = 100 UNION ALL
   select child3_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD3 where child3_master_id = 100) C
  WHERE C.MASTER_ID = 100
  

  That should give you very good performance by raising a record. But a better idea, as indicated, would be to get it all at once with a sql:

  SELECT MASTER_ID, MAX(C.LAST_UPDATED_DATE)
  FROM
  (select child1_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD1 UNION ALL
   select child2_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD2 UNION ALL
   select child3_master_id MASTER_ID, LAST_UPDATED_DATE from CHILD3 ) C
  GROUP BY MASTER_ID
  

  This will give you the max for each MASTER_ID in a sql without a cursor.

  Published by: tk-7381344, December 16, 2008 12:12

• a defective battery in a tablet will cause performance problems of speed

  a defective battery in a tablet will cause a matter of output speed

  Hello

  Sometimes it can cause a performance problem, visit the following link to monitor how to take care of the battery:

  Taking care of your laptop battery

  http://Windows.Microsoft.com/en-us/Windows7/taking-care-of-your-laptop-battery

  In order to increase the performance of Windows XP please visit the link below:

  Windows XP performance

  http://TechNet.Microsoft.com/en-us/library/bb457057.aspx

  Reference: PC slow? Optimize your computer for peak performance

  http://www.Microsoft.com/athome/Setup/optimize.aspx

  Note: as long, the Tablet is connected to a power source it shouldn't affect the performance in itself. However, bad battery itself a performance problem.

• Oracle 9i Java component performance problems

  Hello

  I am reorganizing a java component inherited because of performance problems.

  
  A java stored procedure is used to trigger a shell script that runs a java component. The component connects to a series of remote directories via ftp, gets the files and load them using slq * charger.

  Is there a better way to do this? I saw a few articles talking using a FTP interface directly from PL - SQL jump the java component entirely. It would be preferable to the current solution its?

  Thanks in advance,
  Pedro
  

  I am reorganizing a java component inherited because of performance problems.

  The first step is to identify what are the problems of performance, where they occur, and what causes them.

  View details on

  1. WHAT you do

  2. HOW to

  3. WHAT results you get

  4 what ARE the results you expect to get.

• ViewObject range Paging performance problem

  Hi all

  I am facing a performance problem with the implementation of an obligation to programmatically add a number of extra where the parameters of the clause (using bind) variable in combination with range paging.

  My code looks like this

  ...
  
  ApplicationModule am = Configuration.createRootApplicationModule("services.DossierAM", "DossierAMLocal");
  ViewObject vo = am.findViewObject("DossierListView");
  
  // apply programmatic view criteria
  ViewCriteria vc = vo.createViewCriteria();
  ViewCriteriaRow vcr = vc.createViewCriteriaRow();
  vcr.setAttribute("Reference", "15/%");
  vc.addElement(vcr);
  vo.applyViewCriteria(vc, true);
  
  
  // enable range paging
  vo.setAccessMode(RowSet.RANGE_PAGING);
  vo.setIterMode(RowIterator.ITER_MODE_LAST_PAGE_PARTIAL);
  vo.setRangeSize(50);
  vo.scrollToRangePage(5); // Cause a java.sql.SQLException: Parameter IN or OUT missing for index.....debugging learned that the :vc_temp_1 bind variable is not filled
  // vo.scrollToRange(250); // Cause a java.sql.SQLException: Parameter IN or OUT missing for index.....debugging learned that the :vc_temp_1 bind variable is not filled
  
  ... 
    ...
  

  I found 2 solutions, but they both require an application of additional database that is, performance wise, is not acceptable.

  The first solution is to slip into an additional call to exectueQuery() before the call to function scrollToRangePage (int) or scrollToRange (int).

  The second solution is to use the method (int) setRangeStart instead of variants scrollToRange (Page). This method performs also 2 database calls.

  My question to you:

  Is there another way to satisfy the requirement of programming add a certain number of parameters of the additional where clause (using the variable binding) in combination with the pagination of the range without the need to perform queries of database 2?

  The code is tested with JDeveloper, 11.1.2.4.0, and 12.1.3.0.0 and behaves the same on both versions.

  Kind regards

  Steven.

  Have you tried to create truly VC with bind variable (rather than use binding implied var created by frame)?

  Something like: http://www.jobinesh.com/2010/10/creating-view-criteria-having-bind.html

  Dario

• Performance problems since the update of 2015.6

  Hello together,

  Since I updated lightroom yesterday to version 2015.6 the performance on my machine is incredible bad.

  My system:

  -MacBook Pro (retina, mid-2012)

  -2.3 GHz Intel Core i7

  -16 GB 1600 MHz DDR3

  -NVIDIA GeForce GT 650M 1024Mo

  -OS X El Capitan (10.11.5)

  Lightroom synchronizes actually 1400 photos, but even if I stop this process, LR uses CPU so I can't work in other programs like Photoshop (updated yesterday, too). I detected this performance problem as PS freezes when I used the Healing Brush tool.

  

  I don't know what's happening LR, but is not ideal for my workflow.

  Does anyone have an idea?

  If I close LR I can work in PS, even though the Healing Brush tool is slower than in the version before. But I can't always close and open LR.

  Thank you

  regards Denis

  There are already dozens of threads discussing the same question in this forum as well as in the official comments forum here: https://feedback.photoshop.com/photoshop_family/categories/photoshop_family_photoshop_ligh troom

  You can restore 6.5.1 if you wish. Here's how: How do I roll back to Lightroom 2015.1.1 or Lightroom 6.1.1? Lightroom Queen

  Just replace 6.1.1 with 6.5.1

• HP Pavilion 15-n005sg: performance problems and worsens

  Hello

  I bought this PC here is a year, has been a very good PC with good performance, but has been doing more and more slow to the month, for example, I used to run Diablo 3 on average - high specification with 60 fps constant with no performance problems, but that in the end, I can't still running at ultra low care without screen freezes and fps drops to 1-2 as well as the League of legends and other games.

  It takes more and more time for my pc to turn on, which was like 30 ~ 40 seconds not takes like 3 minutes.

  the performance gets really bad and should not happen on a pc of 1 year.

  What can I do?

  An update of the system may be your best course of action.

  Your data, files, etc. will be retained. Any Windows apps store is kept.

  Any program that came pre-installed is preserved.

  BUT all programs which are not in the above categories will have to be resettled; your games, printer, etc.

  Windows 8 system Refresh

  If you found my answer helpful please say thank you by clicking the s cursor Up icon. Thank you!