"Physics read total multi block applications ' wrong?

Similar Questions

• more physical reads the blocks (in this partition)

  Hi all
  
  I have the partitioned table hash on an indexed column 'id', which is non-unique and a part of my primary key. Inside each partition, lines with the same id are located close to each other which is done by dbms_redefinition reorg using orderby_cols. The intention is to reduce the amount of physical reads as there are no requests that don't filter on the column id.
  
  However, what I see is a large number of physical reads. The first partition has roughly 80K lines, a length of 347, block size of 8K and compression mean line... resulting in 821 blocks. And when (after flushing cache in the memory buffer and shared pool) submit a query that filters on 'id' only and results is 106 selected lines, I see to roughly 1400 physical reads.
  
  --------------------------------------------------------------------------------------------------------------------------------
  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |
  --------------------------------------------------------------------------------------------------------------------------------
  | 0 | SELECT STATEMENT | 106. 36782 | 3 (0) | 00:00:01 |
  | 1. SIMPLE HASH PARTITION | 106. 36782 | 3 (0) | 00:00:01 | 1. 1.
  | 2. TABLE ACCESS BY LOCAL INDEX ROWID | XXX MOVIES | 106. 36782 | 3 (0) | 00:00:01 | 1. 1.
  |* 3 | INDEX RANGE SCAN | XXXXX | 1 | | 1 (0) | 00:00:01 | 1. 1.
  --------------------------------------------------------------------------------------------------------------------------------
  
  Information of predicates (identified by the operation identity card):
  ---------------------------------------------------
  
  3 - access ("ID" = 49743)
  
  
  Statistics
  ----------------------------------------------------------
  22243 recursive calls
  0 db block Gets
  66651 compatible Gets
  physical reads 1404
  0 redo size
  10933 bytes sent via SQL * Net to client
  299 bytes received via SQL * Net from client
  9 SQL * Net back and forth to and from the client
  150 sorts (memory)
  0 sorts (disk)
  106 lines processed
  
  
  I expect to see around 10-15 physical reads. And I don't understand how it can be 1400 physical reads with only 821 blocks in this partition. Can someone explain this behavior to me?
  
  Thanks in advance,
  Dirk

  DRabbit wrote:
  However, what I see is a large number of physical reads. The first partition has roughly 80K lines, a length of 347, block size of 8K and compression mean line... resulting in 821 blocks. And when (after flushing cache in the memory buffer and shared pool) submit a query that filters on 'id' only and results is 106 selected lines, I see to roughly 1400 physical reads.

  --------------------------------------------------------------------------------------------------------------------------------
  | Id  | Operation                          | Name  | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
  --------------------------------------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT                   |       |   106 | 36782 |     3   (0)| 00:00:01 |       |       |
  |   1 |  PARTITION HASH SINGLE             |       |   106 | 36782 |     3   (0)| 00:00:01 |     1 |     1 |
  |   2 |   TABLE ACCESS BY LOCAL INDEX ROWID| XXX   |   106 | 36782 |     3   (0)| 00:00:01 |     1 |     1 |
  |*  3 |    INDEX RANGE SCAN                | XXXXX |     1 |       |     1   (0)| 00:00:01 |     1 |     1 |
  --------------------------------------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
  3 - access("ID"=49743)
  
  Statistiken
  ----------------------------------------------------------
  22243  recursive calls
  0  db block gets
  66651  consistent gets
  1404  physical reads
  0  redo size
  10933  bytes sent via SQL*Net to client
  299  bytes received via SQL*Net from client
  9  SQL*Net roundtrips to/from client
  150  sorts (memory)
  0  sorts (disk)
  106  rows processed
  

  For me, the most important statistic is recursive calls. Even for a partitioned table with (for example) a few thousands of partitions, this seems very high for a simple analysis and perform call that eventually access a single partition known by index.

  Test strategies - rerun the query immediately to see if you get similar results, run the query again ONLY after a buffer_cache (not shared_pool) hunt.
  It is possible that more work on optimization, or calls to (for example) a pl/sql function embedded. The behavior of the repeated executions can give you a clue on this subject.
  (And if none of these options can help, then activation trace and check the trace file should help).

  Concerning
  Jonathan Lewis

• The Oracle trace: number of physical reads of the signifier of disk buffer

  Hi all

  
  Since yesterday, I was under the impression that, in a trace file Oracle, the "number of physical buffer of disk reads" should be reflected in the wait events section.

  Yesterday we add this trace file (Oracle 11 g 2):

  call the query of disc elapsed to cpu count current lines

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  Parse        1      0.00       0.00          0          0          0           0

  Run 1 0.04 0.02 0 87 0 0

  Get 9 1.96 7.81 65957 174756 0 873

  ------- ------  -------- ---------- ---------- ---------- ----------  ----------

  total 11 2.01 7.84 65957 174843 0 873

  Elapsed time are waiting on the following events:

  Event waited on times max wait for the Total WHEREAS

  ----------------------------------------   Waited  ----------  ------------

  SQL * Net message to client 9 0.00 0.00

  reliable message 1 0.00 0.00

  ENQ: KO - checkpoint fast object 1 0.00 0.00

  direct path read 5074 0.05 5,88

  SQL * Net more data to the customer 5 0.00 0.00

  SQL * Net client message 9 0.01 0.00

  ********************************************************************************

  We can see that the 65957 physical disk reads resulted only 5074 direct path read. Normally, the number of physical reads from disk is more directly reflected in the wait events section.

  Is this normal? Why is that? Maybe because these discs are on a San have a cache?

  Best regards.

  Carl

  direct path read is an operation of e/s diluvium, is not just to read 1 block

• question about physical reads

  RMAN I/o is taken into account in the stat of physical reads ?
  
  I mean, it's blocks read from disk by RMAN to backup the database is represented in physical reads statistics?
  
  One of our databases has a value for the IO requests total physical reading greater than physical reads , so I guess that the missing physical reads are RMAN.
  
  Thanks in advance

  blocks read from disk by RMAN to back up the database represented by physical reads statistics?

  Yes, I do. It is something that can be tested by looking at the session for the RMAN sessions statistics.

  Hemant K Collette

• How to check the instance datafile I/O? solve the high physical reads/writes?

  Method-1
  identify 'hot spots' or I/O contention
  Select NAME,
  "Physical reads," PHYRDS
  round ((PHYRDS/PD.)) (PHYS_READS) * 100, 2) «Read %»,
  PHYWRTS "physical Scriptures."
  Round (PHYWRTS * 100/PD.) PHYS_WRTS, 2) "% of writing."
  FS. PHYBLKRD + FS. PHYBLKWRT "Total block I / O of.
  de)
  Select sum (PHYRDS) PHYS_READS,
  Sum (PHYWRTS) PHYS_WRTS
  v $ filestat
  ) pd,.
  v$ datafile df,.
  v$ filestat fs
  where df. FILE # = fs. FILE NO.
  ranking by fs. PHYBLKRD + fs. PHYBLKWRT / / desc
  
  
  Another method-
  On Oracle10g, CWA also provides the dba_hist_filestatxs table to track the disk i/o:
  
  break on begin_interval_time jump 2
  
  column phyrds 999 999 999 format
  column begin_interval_time format a25
  
  Select
  begin_interval_time,
  file name,
  phyrds
  Of
  dba_hist_filestatxs
  natural join
  dba_hist_snapshot;
  
  It is - method that you use to check for errors in data I/O file? AND how to solve high physical reads and writes?

  Ankit Ashok Aggarwal wrote:
  AWR project stat e/s in terms of segments, query and etc.
  Here, my concern is what should be the value of ideal threashold for a DBA to act on the high physical reads/writes?
  and how he can fix this problem if it affects database performance?

  I don't think that there is any possibility to mention that the amount of an e/s is going to be good or bad for a database in general. The reason is that it is not quantifiable. For example, in a store, maybe one day that no one gets and another day, there is no place to stand (because there was a sale announced by the store). So now, how do you say that it was not necessary? Rather than search for best practice values, it is best that you keep track of the normal functioning of your db and when you see a special summit in the values of events scattered user IO as DB file read, DB file parallel read etc and when this happens, you should check back the work you are doing and see if that can be refined somehow.

  Aman...

• Why the adobe reader software is blocking all access to pdf files

  software Adobe reader doesn't block my access to pdf files.  Says I have to sign the contract of use I did.  How can I get on it?

  If you are on Mac and installed the Adobe Reader software to the deafult location.

  Try this:

  1. Quit Safari

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  3. run "Adobe Reader"

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  5. open a PDF file in Safari.

• physical reads...

  Hello
  I want to gather statistics on special applications and want to know how many physical reads this query do?
  How can I get that... Statistics v$ sysstat gives a long list...
  
  Thank you... at all

  Here are the different options that you can use with AUTOTRACE:

  SET OFF AUTOTRACE - cut the AUTOTRACE
  SET AUTOTRACE WE EXPLAIN - show that the optimizer execution path
  SET AUTOTRACE ON STATISTICS - display only the execution statistics
  SET AUTOTRACE ON - show both the optimizer execution path
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  SET AUTOTRACE TRACEONLY - like SET AUTOTRACE ON, but remove output

• How to find the sum of an element of the record multi block?

  Hello
  
  Hi I have form have a multi block record and sing record block. Multi block record for an element, namely Excise_value. I want to find the sum of total Excise_Value of the entire tape. How to get there.
  
  Please guide me in this regard.
  
  PS: I want to use the Formula property / summary forms
  
  Thank you
  
  Iqbal

  For your unique record block, set the property of simple recording/precalculate summaries on YES.
  And in BlockA, set the property of all the query to YES.

  -Clément

• Can we read/write in native application of contact?

  Is it possible to read/write the native application of contact using the android runtime? The api says it succeeds, and if I dump the db slider in a newspaper, it shows the recording, but the native application of contact does not show recording.

  If I make a new record using the native application of contact and then launch the android application and empty the db again, it does not show the contact, I added, which makes me think that they are separated.

  Is it possible to read/write in the native application of contact? The Simulator says it of an Alpha, is this something that will work on a real device of BB 10?

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• Reading total failure first Pro CC 2015.4

  I'm on Premiere Pro 2015.4 CC, and tonight my reading the script completely ceased to operate. I am quite at a loss to know what to do.

  I'm on a Mac, OS X 10.10.5

  Processor 3.5 GHz 6-Core Intel Xeon E5

  16 GB 1866 MHz DDR3 ECC memory

  Graphics AMD over-pants D500 3072 MB

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• to get the total value as application even if item_number is added

  Hi all
  
  I have the following query with me
  

  SELECT   SUM (  (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
                  )
                - (  NVL (f.calc_cement_sk, f.calc_amount)
                   * NVL (f.item_price, 0)
                   * (NVL (f.dis_per, 0) / 100)
                  )
               ) total,
           h.slurry_type, h.stage_id, h.slurry_vol_actual
      FROM xxnp_opn_joblog_est_002 f,
           xxnp_opn_joblog_001 j,
           xxnp_opn_joblog_slurry_003 h,
           qp_secu_list_headers_v qw
     WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
       AND f.opn_joblog_001_id = j.opn_joblog_001_id
       AND j.contract = qw.NAME
       AND h.opn_joblog_001_id = j.opn_joblog_001_id
       AND h.opn_joblog_007_id = f.opn_joblog_007_id
       AND h.opn_joblog_006_id = f.opn_joblog_006_id
  GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual

  the result I get is
  
  
  SLURRY_TYPE TOTAL STAGE_ID SLURRY_VOL_ACTUAL
  9,562.59 lead 1 490
  2,184.84 1 80 tail
  1,091.73 reload 1 56
  3,431.64 tail 2 100

  when i add f.item_number to the above query as shown below
  
  SELECT   SUM (  (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
                  )
                - (  NVL (f.calc_cement_sk, f.calc_amount)
                   * NVL (f.item_price, 0)
                   * (NVL (f.dis_per, 0) / 100)
                  )
               ) total,f.item_number,
           h.slurry_type, h.stage_id, h.slurry_vol_actual
      FROM xxnp_opn_joblog_est_002 f,
           xxnp_opn_joblog_001 j,
           xxnp_opn_joblog_slurry_003 h,
           qp_secu_list_headers_v qw
     WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
       AND f.opn_joblog_001_id = j.opn_joblog_001_id
       AND j.contract = qw.NAME
       AND h.opn_joblog_001_id = j.opn_joblog_001_id
       AND h.opn_joblog_007_id = f.opn_joblog_007_id
       AND h.opn_joblog_006_id = f.opn_joblog_006_id
  GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual,f.item_number
  
  
  the field total gets split and gives value corresponding to each item_number
  
  i am giving the ouptut for stage 1

  ITEM_NUMBER TOTAL SLURRY_TYPE STAGE_ID SLURRY_VOL_ACTUAL
  5011.5 1020101001 lead 1 490
  1308.93 1020102002 lead 1 490
  127.215 1020111001 lead 1 490
  138.92 1020112001 lead 1 490
  686 1020113001 lead 1 490
  550,5 1020113002 lead 1 490
  1739.52 1020222010 lead 1 490
  1517.1 1020101001 1 80 tail
  379.5 1020102003 1 80 tail
  83.2 1020103001 1 80 tail
  166.53 1020104001 1 80 tail
  38.511 1020111001 1 80 tail
  1064,7 1020101001 reload 1 56
  27,027 1020111001 reload 1 56
  
  
  If we add up the values in the total field to the head, tail, charge that we get 9562.59,2184.84,1091.73 respectively
  
  kindly Guide
  to get the total value as application even if item_number is added
  thanking in advance

  Hello

  You can do this by enclosing it with another selection

  select
  total, slurry_type, stage_id, slurry_vol_actual,
  sum(total) over (partition by slurry_type, stage_id, slurry_vol_actual) from (
  your actual select
  )
  

  concerning

• How can I set Adobe Reader as my default application to open PDF files?

  I am a user of Mac with OS 10.5.8. The default application for PDF files found.

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  I am answering my own question. I learned that if you right-click while trying to open a PDF file, you will be asked which application you want to use to open the file. If you click read the information, instead of choosing an application, you get this great information box that gives you the ability to set Adobe Reader in your default application for PDF files. It lets you change all the pdf files, you already have the Adobe files. Yay.