println method static of System.out?
In Lesson 1-5, the System.out::println is an example of a reference to a static method, (~ 5 min)
But it seems to me that println is a non-static method of PrintStream (PrintStream (Java Platform SE 8) (System.out is an instance of PrintStream))
I'm wrong or have I missed something?
You are right; println is not a static method, whereas System.out is a static variable, which may be where the confusion arises. I posted a similar request on this a few days ago. You can hear some hesitancy in the audio at that point, where I suspect an element of doubt has crept in Simon's mind as it has been described.
Another example would use something like the whole parseInt method, as I suggested to my request.
David
Tags: Java
Similar Questions
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All,
I am a newbie to CF/JAVA integration and inherited about 20 java applications that are called from a template CF. abounding in all the java code (in hundreds of places) it is System.out.println () statements. So far I have not been able to get this output to display on the web page.
CF Code:
< CFSET UploadName = UploadsDir & "-" & cffile.serverFile >
< CFSET ExceptionName = UploadsDir & "-" & ExPrefix & BaseName >
< cfobject type = 'java' name = "UploadObject" class = "UploadProgram" action = "crΘer" >
< cfset params = ArrayNew (1) >
< cfset params [1] = UploadName >
< cfset params [2] = ExceptionName >
#UploadObject.main (params) #.
Excerpt from Java:
System.out.println("");
System.out.println (recCount + "entry" records);
System.out.println (hdrCount + "header");
System.out.println ("good" account +);
System.out.println (errCount + "bad");
System.out.println (ignCount + "ignored");
System.out.println("");
System.out.Flush ();
Any help will be appreciated. Thank you!
I have it!
I finally understand how to redirect the output stream, then return the var. toString().
Java:
public static main (String [] args) String
throws the Exception
{
ByteArrayOutputStream outstream = new ByteArrayOutputStream();
PrintStream ps = new PrintStream (outstream);
System.setOut (ps);If (args.length< 1="">
{
System.out.println ("use: java InetLoad inet_sales_spreadsheet");
Return (outStream.ToString ());
}
inetLoad.run ();
Return (outStream.ToString ());
}CF:
#UploadObject.main (params) #.
Time for a beer.
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Strange problem of Debug with System.out.println
Hello
I have an interesting question that I have not been able to solve and I reach out for more help.
Earlier today my app stopped writing System.out.println messages in the console.
It is not a fact that I'm not running it in debug mode, because all debugging information is still there. I see that things get focus, etc.
But none of my system.out.println messages are written.
Even with System.out.println ("main entry method"); on the first line of the main method does not appear.
Is this a problem with the Simulator?
Restart the Simulator, restart eclipse and restarted my computer, I tried the Simulator, cleaning.
I use 8900 Blackberry Simulator.
Any help you offer is very appretiated!
Updated, I guess I was a bit premature in posting about me.
After rebooting my computer again, by disabling the Simulator a few times and restart Eclipse once again, its started to work again.
Strange strange question...
Well, ~ FIXED ~
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Hi all
I just want to know if there is no solution to see System.out.println.
I use neither Eclipse nor BlackBerry JDE for my development.
I have my jar, jad files. I convert my jar file using the CAP tool. The .cod files are generated.
I start the trainer. Now I have 2 windows: Windows Simulor and the output (see picture).
Then I load my .cod files. But I see not all System.out.println ("...") in the output windows.
How can I see these System.out.println ("...")?
Please help me.
Thank you all.
Thanks for your help.
I try your solution EventLogger.
But I have another problem:
My request is not a native application (it is a midlet in J2ME, not a UIApplication). Do you think that it will work with EventLogger?
How can I make a registry for EventLogger:
static boolean
register(long guid, String name)
Registers the name and the guid of the calling application.static boolean
register(long guid, String name, int viewerType)
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System.out.println)
I have a question.
I tend to use a lot of System.out.println () in my codes for debugging purposes.
Now, when we deploy our code in the case of Oracle applications, what happens to these System.out.println ()?Hi pradeep,.
System.out.println () does not store the output anywhere in the server.
But as Summit says that this unnecessary code lead to performance problems.There is only one output and one error in the JVM. Multiple threads calling these methods must be synchronized and will potentially block. Also in production (iAS 1,0.2.2.2), STD on is not to redirect to a file and is lost.
Prasanna-
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System.out.println () + Eclipse + Simulator
I expected that System.out.println () would be exit in the Blackberry Simulator output Console, but I don't get anything in this window. Y at - there a trick to getting the output here?
Thanks in advance,
You must attach the Simulator in debug mode. To do this simply right click on the project > Debug as > BlackBerry Simulator. That should fix the Simulator for the Eclipse JDE plugin and println (s) should now appear in the Console output for the Blackberry Simulator.
To connect a device in debug mode, right-click on the project > Debug as > BlackBerry device. It attach the unit to the Eclipse JDE plugin and as above, println (s) should appear in the Console output for the Blackberry Simulator.
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System.out.println () in the performance of blackberry
Hello everyone.
Can I print the messages during execution of an application from BlackBerry device? I would like to make something the link tipical System.out.println ("' you are in" ");
I don't want messages between class and then use add (ritchtext...), etc. I want just a feeling at this moment. It is possible that in blackberry?
Otherwise, there is another way to simulate something similar?
Thack you.
You can attach the debugger to the real blackberry as well.
We use a loggerservice making:
-DD
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the simplest solution would be to use http://www.blackberry.com/developers/docs/6.0.0api/net/rim/device/api/system/EventLogger.html
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System.out.println in the controller log
Where can I find the exit from my System.out.println calls made in my controller? I looked in the logs and diagnostics but did not meet my output. When I run into JDeveloper, they are found in the built-in console OC4J tab. So I know they work. I can't find the on the server.
Thank you
Hello
You can take a look at the tables of FND_LOG_MESSAGES.
Please refer to the link below and configure the profile to the user level options and check.
http://oraclemaniac.com/2012/08/15/how-to-generate-logs-for-tracing-OAF-page-errors/
Thank you
Sandeep
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Custom defined function and "System.out.println".
Hello
After some cdf sample looking on the web and bring them to work on my development machine, I was wondering if the many order System.out.println (...) in the java classes indeed out there messages to. I wasn't able to find them in all the log files, I was looking at, IE. or ESSBASE. JOURNAL, or the exemple.log where I was testing the functions.
Someone at - it an idea where messages from System.out.println (...) Finally end and that there is a log file containing these messages.
VolkerHello
Try to run essbase in a command window (run it from the start menu or type essbase on windows OS) and not as a service, then you should see the output of the command in the window.
See you soon
John
http://John-Goodwin.blogspot.com/ -
How to find information printed by system.out?
Hi, I am a newbie in BB dev, I have an app that will be released some info using system.out.print, but I don't know where to check in real device or Simulator, can someone help?
In JDE when running in the menu "Build-> equip all and run" a new window will appear.
When you run your application - have a look at this new window (or frame).
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net.rim.device.api.system.EventLogger
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How do you see the System.out.print?
ButtonField getAdmire = new ButtonField("Button!", ButtonField.FIELD_HCENTER); getAdmire.setChangeListener(new FieldChangeListener() { public void fieldChanged(Field field, int context) { ButtonField buttonField = (ButtonField) field; System.out.println("Button pressed: " + buttonField.getLabel()); } });
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System.out.Print for display of floating numbers
Hello
The output if the code element ispackage newJava public class newJava{ public static void main(String[] args) { float a = 71/4; System.out.print(a); } }
The result is rounded a.0, but he must return to 17.75run: 17.0 BUILD SUCCESSFUL (total time: 0 seconds)
Thanks in advanceHe must return to 17.75
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Display of output with System.out.print
I think (hope) it is a relatively simple question... How can I get
Display the form "a b c".System.out.print("a"); System.out.print("b"); System.out.print("c");
Instead of
'a '.
b
c » ?jschell wrote:
851204 wrote:
I know that I was just using a, b and c as placeholders for objects. I say /had/ to write my code with 3 separate Print orders. How can I get each new string on the same line?As noted your example produces no output you suggested.
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In this case, your options are
1 modify the objects to remove the end of line of code.
2 consume objects as strings and delete the end of characters in the line of these chains, then print the result.Specifically, an easy way to remove breaks at the end of the strings is 'trim()' of the String class method. It will remove the spaces and the newlines from the beginning and the end of a string.
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Go to the general tab and select the Normal startup option and press Applay. OKRestart the computer... Now your computer will begin upward in Normal mode...
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where's my exit of System.out.print
Hello
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