Problem to create CASE WHEN OBIEE

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  It's been more than 24 hours now that Skype has worked on my pc. When Microsoft will have their sh * t together and rectify the problem, they created with this program. Now it becomes ridiculous and smells of incompetence!

  Hello

  Be sure to contact the Skype Support like this might be a known issue and they might have the solution.
  There is also information and on the Skype Forums.

  There is an alert to update Skype system on the Skype homepage
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• I have problem with value NULL when the use CASE statement please help this question

  I have problem with value NULL when the use CASE statement please help this question

  
  

  Table: digital_val

  SNO cl C2

  1 San1 11

  2 22 San2

  Actual result: expected to A         B

  A            B                                                                           11        22

  11 NULL

  22 NULL

  
  

  
  

  query:

  Select case when c1 = "san1" then c2,.

  case If c1 = "san2" then c2 B

  of digital_val

  I'm more curious why, when you select 2 rows, you expect a result of row?

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  AS (SELECT 1 AS 'Sno', 'San1"C1, c2 FROM DUAL 11)

  UNION ALL

  2 SELECT AS 'Sno', 'San2"C1, c2 FROM DUAL 22)

  SELECT CASE WHEN c1 is "San1" THEN END AS A c2.

  CASE WHEN c1 = "San2" THEN END AS B c2

  OF digital_val;

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• Problem with case when try to alter the query from siimple

  Hello PL/SQL gurus and Experts.
  
  I'm stuck with a question (can be simple), but not gettings all headsway.
  

  select 365/day_num_yr Anul_Fact from Date where date_dt = trunc(sysdate -1) 

  value returns is as - 1.46
  
  need to write it in the form of case (I have to multiply it to some other outer query), I want to store variable ina and then use the same in an outside -.
  but when use the following syntax, then it always returns 0 and not the same output returned by the query above without the scabbard.

  select (case when date_dt =trunc(sysdate -1) then 365/day_num_yr else 0 END) Anul_Fact 

  Help kindly, I appericate your time and effort in advance.

  user555994 wrote:
  Problem is that I do not get the output as 1.46, even the output is coming like the 0 only if using the query - next

  select /*date_dt, sysdate - 1 prev_dt, trunc(sysdate - 1) trunc_prev_dt,*/
  case when date_dt = trunc(sysdate -1) then  365/day_num_yr
  else 0
  end num_day
  from date_dim;
  

  Completely, which seems to be a question of DATA. Have you checked if the table contains data for DATE_DT = SYSDATE - 1? Can you check if the data stored do not have hours and Minutes stored?

  Although I have provided examples of data, which is the same as the data in my main table and once I used the previous solution you provided and then also gives the result as same as those mentioned by you.

  I think it's something like -

  select date_dt, sysdate - 1 prev_dt, trunc(sysdate - 1) trunc_prev_dt,
  case when date_dt = trunc(sysdate -1) then  366/day_num_yr where day_num_yr=(select day_num_yr from date_dim where date_dt = trunc(sysdate -1))
  else 0
  end num_day
  from date_dim;
  

  Once we get the day_num_yr then he deviding by 366/day_num_yr :(
  but he does not like throwing an error ORA-95 - missing keyword

  Yes, it does not work

  -case when date_dt = trunc (sysdate-1) then 366/day_num_yr where day_num_yr = (select day_num_yr from the date_dim where date_dt = trunc (sysdate-1))

  due to a syntax of alien.
  I don't think that you really need. I already said, with the data in your Table, you will be having only * 1 * record with a Non - zero value. Thus, simply apply a filter to extract the corresponding record SYSDATE - 1 and you should get an output which is Non-zero. If you apply a where predicate, then would not need you a CASE statement. You can directly use something like below:

  select date_dt, sysdate - 1 prev_dt, trunc(sysdate - 1) trunc_prev_dt,
         365 / day_num_yr num_day
    from t4
   where date_dt = trunc(sysdate - 1);
  

  Published by: Jen K, September 7, 2012 16:00

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• Problem SQL querry (case statement...)

  Hi to everyone who reads this.
  
  I have a huge problem (at least for me) with a SQL I try to write in Oracle forms6 (yes I know... old app).
  
  OK, here it goes...
  
  We have a table like:
  

  create table temp (
    year     number 
    month    number,
    konto    number,
    DEBET    number, 
    KREDIT   number,
    date_tr  date,
    ind      number
  );

  The data in the table are:
  

   YEAR        MONTH    KONTO      DEBET     KREDIT DATE_TR  IND
  ---------- ---------- ----- ---------- ---------- -------- -
        2011          1 12101   4674,32           0 05.06.11
        2011          6 12101  -4674,32           0 05.06.11 R
        2011          6 12182   4674,32           0          R

  Now, to explain a little what I want to do...
  

  case when p_date > NVL(date_tr,'01012004') then
  date_tr is null;
  else
  ind is null
  end

  What I need is when p_date is entered by a user SQL should check if the date is less or greater than date_tr...
  in this case it should show only the record that has a null value in date_tr cullum.
  
  Or if it isn't... it should display records which is null in ind cullum.
  
  
  The main problem is that I do not know how to write the case statement in SQLs where clause... maybe someone can give me a hint
  or a partial code how do I solve this problem.
  
  Any ideas would be greatly apreciated.
  
  Thanks to you all!

  SQL> with temp as
    2  (select 2011 YEAR,1 MONTH, 12101 KONTO, 4674,32 DEBET, 0 KREDIT, to_date('05.06.11','DD.MM.YY') DATE_TR, NULL IND from dual union all
    3  select 2011, 6, 12101, -4674,32, 0, to_date('05.06.11','DD.MM.YY'), 'R' from dual union all
    4  select 2011, 6, 12182,  4674,32, 0, NULL, 'R' from dual
    5  )
    6  SELECT *
    7  FROM   temp
    8  WHERE  CASE
    9           WHEN To_date('&dt, 'DD.MM.YYYY') > (SELECT MAX(date_tr)
   10                                               FROM   temp) THEN To_char(date_tr)
   11           ELSE ind
   12         END IS NULL;
  Enter value for dt: 30.06.2011
  
        YEAR      MONTH      KONTO       4674      DEBET     KREDIT DATE_TR   I
  ---------- ---------- ---------- ---------- ---------- ---------- --------- -
        2011          6      12182       4674         32          0           R
  
  SQL> /
  Enter value for dt: 30.05.2011
  
        YEAR      MONTH      KONTO       4674      DEBET     KREDIT DATE_TR   I
  ---------- ---------- ---------- ---------- ---------- ---------- --------- -
        2011          1      12101       4674         32          0 05-JUN-11
  
  SQL>
  

• Problem in creating the CHECK constraint

  When creating a table, I want to apply a CHECK constraint, that pension_amount must be in accordance with pension_code, I get the below error.

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            WHEN pension_code = 2 THEN pension_amount = 1500
         end)
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  ORA-00907: missing right parenthesis

  How I can solve this problem.

  Hello

  So you cann which adds another.

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    PENSION_AMOUNT  NUMBER(4),
    PENSION_CODE    NUMBER(1)
  )
  /
  
  ALTER TABLE PENSION_AMOUNT_CHECK ADD (
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  /
  

  * If the answer is correct, then mark it as a good answer

• Create cases with the file vi:s

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  Original title:

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• ORA-06592: not found CASE when executing CASE statement

  Hello

  I have a table of application where I built a form master detail (table with 33 columns, 13 is not hidden items and rest are hidden).

  When I run the page I get an error "error while rendering page, article. P10_TIME_SAVED_FREQUENCY, ORA-06592: not found when executing CASE statement CASE"

  Error:

  Error during rendering of the element on the page P8_MONEY_SAVED_FLAG.

  ORA-06592: not found CASE when executing CASE statement

  Technical information (only visible to developers)

  is_internal_error: true

  apex_error_code: WWV_FLOW_FORM. UNHANDLED_ERROR

  ora_sqlcode:-6592

  ora_sqlerrm: ORA-06592: not found CASE when executing CASE statement

  Component.type: APEX_APPLICATION_PAGE_ITEMS

  Component.ID: 13345536607188241

  Component.Name: P8_MONEY_SAVED_FLAG

  error_backtrace:

  ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 1751

  ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 4241

  ORA-06512: at "APEX_040200.WWV_FLOW_PLUGIN", line 1251

  ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 977

  ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 1406

  DEBUG:

  Exploitation forest exception in final_exception_handler:

  SQLERRM: ORA-20987: APEX - error during rendering of the element on the page P8_MONEY_SAVED_FLAG. -

  ORA-06592: not found CASE during the execution of the instruction BOX Backtrace: ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"

  line 853 ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"

  line 888 ORA-06512: at "APEX_040200.WWV_FLOW_DISP_PAGE_PLUGS"

  line of 3240 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"

  line of 1780 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"

  line of 1950 ORA-06512: at "APEX_040200.WWV_FLOW", line 6725

  How to solve this problem. Please advice

  Oracle Apex Vesion: 4.2.1

  Thank you

  BO123 wrote:

  Hello

  I have a table of application where I built a form master detail (table with 33 columns, 13 is not hidden items and rest are hidden).

  When I run the page I get an error "error while rendering page, article. P10_TIME_SAVED_FREQUENCY, ORA-06592: not found when executing CASE statement CASE"

  Error:

  Error during rendering of the element on the page P8_MONEY_SAVED_FLAG.

  ORA-06592: not found CASE when executing CASE statement

  Technical information (only visible to developers)

  is_internal_error: true

  apex_error_code: WWV_FLOW_FORM. UNHANDLED_ERROR

  ora_sqlcode:-6592

  ora_sqlerrm: ORA-06592: not found CASE when executing CASE statement

  Component.type: APEX_APPLICATION_PAGE_ITEMS

  Component.ID: 13345536607188241

  Component.Name: P8_MONEY_SAVED_FLAG

  error_backtrace:

  ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 1751

  ORA-06512: at "APEX_040200.WWV_FLOW_NATIVE_ITEM", line 4241

  ORA-06512: at "APEX_040200.WWV_FLOW_PLUGIN", line 1251

  ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 977

  ORA-06512: at "APEX_040200.WWV_FLOW_FORMS", line 1406

  DEBUG:

  Exploitation forest exception in final_exception_handler:

  SQLERRM: ORA-20987: APEX - error during rendering of the element on the page P8_MONEY_SAVED_FLAG. -

  ORA-06592: not found CASE during the execution of the instruction BOX Backtrace: ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"

  line 853 ORA-06512: at "APEX_040200.WWV_FLOW_ERROR"

  line 888 ORA-06512: at "APEX_040200.WWV_FLOW_DISP_PAGE_PLUGS"

  line of 3240 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"

  line of 1780 ORA-06512: at "APEX_040200.WWV_FLOW_PAGE"

  line of 1950 ORA-06512: at "APEX_040200.WWV_FLOW", line 6725

  How to solve this problem. Please advice

  Oracle Apex Vesion: 4.2.1

  Post a backtrace of the page see the request and the item type properties and the source / default to the value of the P8_MONEY_SAVED_FLAG element.

  Seems to be similar to ORA-06592 with the page only items appear, which also involved a master/detail form. Can you reproduce this on apex.oracle.com?