Problem with regexp_substr if the string with null values between commas.

Hi all

My version of DB is 10.1.0.5.0
I want to extract the string values using query below, but I am unable to provide the correct result.
WITH t  AS ( select '123,1,3,22' col FROM DUAL
        UNION ALL
        SELECT '123,,2,1' FROM DUAL
        UNION ALL
        SELECT '5,1,2,,' FROM DUAL
        ) 
SELECT regexp_substr(t.col,'[^,]*',1,1)
      ,regexp_substr(t.col,'[^,]*',1,2)
      ,regexp_substr(t.col,'[^,]*',1,3)
      ,regexp_substr(t.col,'[^,]*',1,4) FROM DUAL,t   ;
My required result as below.
123     1      3      22
123            2       1
5       1      2        
Please help me to get the required result by using regular expressions.
Thanks, Ram

Hello

In Oracle 10, you can do so by combining REGEXP_SUBSTR with something else like RTRIM:

SELECT     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 1), ',')     AS part_1
,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 2), ',')     AS part_2
,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 3), ',')     AS part_3
,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 4), ',')     AS part_4
FROM     t
;

Starting Oracle 11 REGEXP_SUBSTR alone can do.

But look at the first response; regular expressions will be probably less effective than less powerful features, especially when all channels have the same number of separators.

Published by: Frank Kulash on 29 December 2012 08:36

Tags: Database

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    Kind regards.

    Published by: ASzo on 05/06/2013 12:37

    Published by: ASzo on 05/06/2013 12:38

    Published by: ASzo on 05/06/2013 12:42

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  • Add filter slot table form to show the lines with null values

    Hello

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    Hi, Ryan.

    Try a static LOV like this

    STATIC2:;,--- All ---;--- All ---
    

    and a Where clause, like this

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    Jeff

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