Problem with regexp_substr if the string with null values between commas.
Hi allMy version of DB is 10.1.0.5.0
I want to extract the string values using query below, but I am unable to provide the correct result.
WITH t AS ( select '123,1,3,22' col FROM DUAL
UNION ALL
SELECT '123,,2,1' FROM DUAL
UNION ALL
SELECT '5,1,2,,' FROM DUAL
)
SELECT regexp_substr(t.col,'[^,]*',1,1)
,regexp_substr(t.col,'[^,]*',1,2)
,regexp_substr(t.col,'[^,]*',1,3)
,regexp_substr(t.col,'[^,]*',1,4) FROM DUAL,t ;
My required result as below.123 1 3 22
123 2 1
5 1 2
Please help me to get the required result by using regular expressions.Thanks, Ram
Hello
In Oracle 10, you can do so by combining REGEXP_SUBSTR with something else like RTRIM:
SELECT RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 1), ',') AS part_1
, RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 2), ',') AS part_2
, RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 3), ',') AS part_3
, RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 4), ',') AS part_4
FROM t
;
Starting Oracle 11 REGEXP_SUBSTR alone can do.
But look at the first response; regular expressions will be probably less effective than less powerful features, especially when all channels have the same number of separators.
Published by: Frank Kulash on 29 December 2012 08:36
Tags: Database
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http://www.TalkApex.comHi, Martin,.
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BANNER --------------------------------------------------------------------------------
12 c Oracle database Release 12.1.0.1.0 - 64 bit Production PL/SQL Release 12.1.0.1.0 - Production CORE Production 12.1.0.1.0 AMT for 64-bit Windows: Version 12.1.0.1.0 - Production NLSRTL Version 12.1.0.1.0 - Production
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EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO - - - - - - - - -
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where column1 is null or :p1_filter like '%%'
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