Querry

Hello

Can I use apple sim to the South?

doreen48 wrote:

Hello

Can I use apple sim to the South?

Mobile phone service provider support and features for iPhone in the United States and Canada - Apple supported

Tags: iPhone

Similar Questions

  • I have a wireless negear connected my labtop unable hostname querry

    I have a wireless negear connected my labtop cannot querry hostname. I have a connection, but I can't the internet upward

    Hi, Melissa,

    Repair and Winsock Reset catalog

    1. Click the Start button.
    2. Type Cmd in the search text box.
    3. Press Ctrl-Shift-Enter keyboard shortcut to run command as administrator prompt. Allow elevation request.
    4. Type netsh winsock reset in the command line shell, and then press the Enter key.
    5. Restart the computer.

    Try to use the Mr. Fixit to reset the IP stack

    How to reset the Protocol Internet (TCP/IP)

    http://support.Microsoft.com/kb/299357

    Press the Windows flag + R to open the run

    Type www.yahoo.com

    Press Ok

    This should open a Web page

  • SQL Querry has worked in the workshop of SQL but not in series AnyChart.

    Hello

    I use the following statement in SQL Workshop:

    T3.fname | NULL, select ' ' | T3. Lname label, to_char (to_date (t1.total_time, 'sssss'), 'mi: ss') Week_2_Time, t2.total_weight week2_weight

    evt_scr_board t1, evt_scr_board t2, t3 mem_profile

    where t1.mem_serno = t2.mem_serno

    and t1.evt_rnd = 1

    and t2.evt_rnd = 2

    and (t1.rx_cd = 'RX' and t1.evt_rnd = 1)

    and (t2.rx_cd = 'RX' and t2.evt_rnd = 2)

    and t3.mem_serno = t1.mem_serno

    It produces the following as expected:

    Screenshot 2014-11-14 09.34.09.png

    However when I run the same querry in a series of anychart page shows "No Data".

    Screenshot 2014-11-14 09.36.12.png

    The querry works fine if I don't need to convert the number to a date format. Any help would be greatly appreciated.

    Thank you!!!

    Syntax for a series is:

    SELECT link, label, value
    FROM ...
    

    In your last example, sysdate week_2_time isn't a value or time.

    The format below for your query would work, but I doubt that is what your waiting for.

    SELECT NULL,
           'Me',
           TO_NUMBER (TO_CHAR (SYSDATE, 'mmddyyyy')) week_2_time,
           135 week_2_weight
      FROM DUAL
    

    Jeff

  • Need to retive querry sql data sysdate to data of last365 days.

    Hello

    I need sql querry to retrieve data based on this condition: date between previous 365 days and the date of the day.

    date of sal EMP
    1 200 03-mar-2011
    1 200 03-mar-2008
    1 200 06-mar-2012
    1 200 03-mar-2003
    1 200 03-mar-2004
    1 200 03-mar-2005




    and so on... a lot of files...


    I need all data of employees of currentdate (sysdate) to previous data 365 days...

    Published by: 937506 on June 7, 2012 04:26
    select * from employees where hiredate between (sysdate-365) and (sysdate);
    

    This should help
    concerning

  • HP dc7900 Small Form Factor: «Graphics querry»

    Hello:

    I have a pc hp dc 7900 shape small factor. I would ask what graphics card is supported on this device close to 1 GB.

    Please specify precise model of the graphics card as well as the brand because it's a desktop pc.

    Thank you.

    Kind regards

    Mohsin

    Hello:

    I would go for the Radeon HD 6450 profile low with flat card, which is the graphics card in option on the Elite SFF 8200 with the same power 240W.

    This one, if you can get it where you live.

    http://www.Newegg.com/product/product.aspx?item=N82E16814121439

  • Pouvez LabVIEW querry MAX for active devices?

    Is there a way for LabVIEW for query MAX for active devices?

    Given case at a time, a measuring instrument (for example a multimeter) is added to my test system, I would like to be able to get the name of MAX i/o device and then be able to communicate with this device without having to manually interact with MAX.

    Thanks in advance.

    Hi, AT,.

    so, you are interested in the use of the VISAFindResources function?

  • LEFTOUTER join querry which gives bad result

    Hello

    I have tables like below.when I perform a left outer join issue IDs and startdate he gives invalid results.when I write in request

    It does not correct result because there is no data for 16 jan. It should give no results. But it shows all records. How do I solve this problem

    SQL:

    Select a.id, a.date, b.val, a.tot, b.net, b.cre

    FROM table1 a

    join table2 b left

    "on a.id = b.id and a.date = b. and a.date ='02-Feb-2014."

    In the tables below contains no data for the month of February but still im getting the incorrect data. He must not returnany files right?

    Table1:

    IDDateValtot
    1January 1, 1319
    22 January 1338
    33 January 1347
    4January 4, 1356
    55 January 1365

    Table2:

    IDDateNETCRE
    1January 1, 1319
    213 January 1338
    33 January 1347
    4January 4, 1356
    55 January 1365

    "It should not returnany files right?

    Wrong, there is no where clause so it should return all the records in a padded with NULL values for b.

  • Querry with connection by

    Hi all, I have a few question

    with tab (c1, c2, c_from, c_to) as)

    Select 'donnees_1', 'data_2", 1, 3 of all the double union

    Select the option 'data1_1', 'data1_2', 1, 2 all the double union

    Select 'data2_1', 'data2_2', 1, 4 double

    )

    Select * from tab;

    This query present a simple fact

    C1 C2 C_FROM C_TO

    ------- ------- ---------- ----------

    donnees_1 1 3 data_2

    data1_1 data1_2 1 2

    1 4 data2_2 data2_1

    Data I expect is:

    c1 c2 c3
    donnees_1data_21
    donnees_1data_22
    donnees_1data_23
    data1_1data1_21
    data1_1data1_22
    data2_1data2_21
    data2_1data2_22
    data2_1data2_23
    data2_1data22_24

    I know I have to use connect by, but don't know how

    Hello

    In fact, you need not CONNECT BY for this problem or any other problem.  Nothing you can do with CONNECT BY you can also do it with a WITH recursive clause.  CONNECTION is much simpler for some problems, but not for this one.

    Depending on your needs, here's a way:

    WITH r (c1, c2, c_from, c_to, c3) AS

    (

    SELECT c1, c2, c_from, c_to

    1 c3

    TAB

    UNION ALL

    SELECT c1, c2, c_from, c_to

    c3 + 1 AS c3

    R

    WHERE c3< c_to="" +="" 1="" -="">

    )

    SELECT c1, c2, c3

    R

    ORDER BY c1, c2, c3

    ;

    Output:

    C1 C2 C3

    ------- ------- ----------

    data1_1 data1_2 1

    data1_1 data1_2 2

    data2_1 data2_2 1

    data2_1 data2_2 2

    data2_1 data2_2 3

    data2_1 data2_2 4

    data_2 donnees_1 1

    data_2 donnees_1 2

    donnees_1 data_2 3

  • Querry for get info

    Any body help me please to write a SQL query to identify the DML which runs longer than 30 seconds, including user_ip, sql_text, time and weather, enforcement is a session blocking or not?.

    I found the solution to get the desired output. Thanks a lot to you all. Here I am pasting my solution that can help you if you need any other body.

    The query below will help you identify the user_ip, the Sql_text, and the runtime more than 30 seconds.

    SELECT s.machine, S.USERNAME, s.sid, s.osuser, t.sql_id, sql_text, to_char(sl.start_time,'hh24:mi:ss') starttime, sl.elapsed_seconds,.

    (sl.sofar/sl.totalwork)* 100%

    v $ sqltext_with_newlines t, V$ SESSION s, v$ session_longops sl

    where s.sid = sl.sid

    and t.address = s.sql_address

    and t.hash_value = s.sql_hash_value

    and s.status = 'ACTIVE '.

    and s.username <> 'SYSTEM '.

    and sl.elapsed_seconds<>

    This query will show you blocking sessions.

    Select distinct s1.username | » @'|| S1.machine | "(INST =' | s1.inst_id |) ' SID = ' | S1.SID |')

    blocks ' | S2. UserName | '@' || S2.machine | ' (INST =' | s1.inst_id |') SID =' | S2.SID |') '

    LIKE blocking_status, s2.program, s3.sql_id, s3.sql_text gv$ lock l1, gv$ session s1, gv$ lock l2, gv$ session s2, s3 in v$ sql

    where s1.sid = l1.sid

    and s2.sid = l2.sid

    and l1.block = 1

    and l2.request > 0

    and l1.id1 = l2.id1

    and l2.id2 = l2.id2

    and s2.sql_id = s3.sql_id;

  • 2 different counts in a single querry

    I'm trying to get a separate account to ID who never had SESC as a means of payment and IDs that moved it. Although they had other methods of payment such as cash or card and then SESC.

    Payment as so much money card and the SESC has so below ID 1 (MOVED)
    ID 2 has had the SESC SESC so right
    ID 3 was money and SESC (MOVED)
    4 ID a SESC SESC only if
    CREATE TABLE DAN_GR_DELETE
    (ID    VARCHAR2(8),
    PAYMENT    VARCHAR2(8),
    ITEM VARCHAR2(8)) 
    
    
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'CREDIT','CAR');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'CASH','BUS');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'HECS','BIKE');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (2,'HECS','BIKE');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (2,'HECS','CAR');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (3,'CASH','BUS');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (3,'HECS','CAR');
    INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (4,'HECS','CAR');
    ID     PAYMENT     ITEM
    1     CREDIT     CAR
    1     CASH      BUS 
    1     HECS     BIKE
    2     HECS     BIKE
    2     HECS     CAR
    3     CASH      BUS 
    3     HECS     CAR
    4     HECS     CAR
    WANTED:
    MOVED     HECS
    2     2
    using the:
    Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi

    Ok. Can be...

    with tt as (SELECT distinct d.id, count(distinct payment) OVER (partition by id) cnt
                FROM DAN_GR_DELETE d)
    SELECT (select count(0)
            from tt
            where cnt = 1) HECS,
           (select count(0)
            from tt
            where cnt != 1) MOVED
    FROM DUAL
    
    HECS                    MOVED
    ----------------------- -----------------------
    2                       2
    
  • MAX value query and then add to existing querry

    Hi all

    Asked me to add some fields to add to an existing query.
    I'm having a problem with the initial query, so let's start first, and then maybe I'll be able to figure out how to add it in.
    Here is my sample data:
    CREATE TABLE TASK
    ( 
        TASK_TYPE     VARCHAR2 (50 BYTE),
        TASK_SEQ      VARCHAR2 (50 BYTE),
        COMPL_DATE    DATE,
        REQUIRED_TASK VARCHAR2 (100 BYTE)
    );
    
     
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('ABC',18, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('DEF',16, TO_DATE('12-MAR-12','DD-MON-YYYY'),'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('HIJ',12, TO_DATE('09-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('KLM',15, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('NOP',11, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('QRS',20, TO_DATE('29-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('TUV',13, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('WXY',19, TO_DATE('30-MAR-12','DD-MON-YYYY'), 'Y');
    INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('Z',24,   TO_DATE('04-APR-12','DD-MON-YYYY'), 'Y');
    My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,
    such as:
    {Europe}
    TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
    Z 24 4 4 2012 Y (DO NOT WANT THIS)
    I have this code that I thought would work, but not as of yet - it returns all rows and ranks eac as 1.
    {code}
     WITH DST AS
     (
      SELECT  TASK_TYPE,
              TASK_SEQ,
              COMPL_DATE,
              REQUIRED_TASK,
              RANK () OVER (PARTITION BY TASK_TYPE ORDER BY COMPL_DATE) rnk
      FROM TASK
      )
      SELECT * FROM DST
      WHERE rnk = 1
    {code}
    And this yields basically the same results:
    {code}
    SELECT  TASK_TYPE,
            TASK_SEQ,
            COMPL_DATE,
            REQUIRED_TASK
    FROM TASK
    WHERE (TASK_TYPE, TASK_SEQ) IN (SELECT TASK_TYPE, MAX(TASK_SEQ)
                                                    FROM TASK
                                                    GROUP BY TASK_TYPE )
    {code}
    
    Thanks for taking the time to look.
    
    G                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                

    Hello

    GMoney says:
    ... Here is my sample data:

    Thank you! It is very useful.

    ... My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,
    such as:
    {Europe}
    TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
    Z 24 4 4 2012 Y (DO NOT WANT THIS)
    Be careful. The keyword tiny must code. (It must be spelled correctly, too.)
    What is the desired line or line that you don't want? If this is the desired line, so you were on the right track with your first attempt. Try this:

    WITH DST AS
     (
      SELECT  TASK_TYPE,
              TASK_SEQ,
              COMPL_DATE,
              REQUIRED_TASK,
              RANK () OVER (ORDER BY COMPL_DATE DESC) rnk
      FROM TASK
      )
      SELECT * FROM DST
      WHERE rnk = 1
    ;
    

    Exactly what you have published, with the exception of the analytical clause.
    'PARTITION BY task_type' means a separate set of numbers (starting with 1) assign to each separate task_type. Since task_type is unique, this means that each line is #1 in his own little world. If I understand the problem, you want (except ties) only 1 rank for the entire result set. This means you don't at all want a PARTITION BY clause. PARTITION BY is never required in any analytic function.
    "ORDER BY compl_date" means that the first compl_date gets rnk = 1. You want the latest comp_date to get #1, so you must specify descending order. Note that this has nothing to do with task_seq. It you want to display the line with the highest task_seq, then the rnk column would be defined as:

    RANK () OVER (ORDER BY task_seq DESC) rnk
    

    If you know that the line with the upper task_seqs is always compl_dates later, then it does not matter that you use. Remember to descending order.

  • Need Sql querry for this logic

    Empname MJ sex desg salary managerid dept ID
    2 B 2 JANUARY 12 M 10 20000 B1 SS
    3 C 2 JANUARY 12 M 90000 10 C1 SS
    4 D JANUARY 2, 12 M 15000 20 D1 SS
    5 E 2 JANUARY 12 F 20 14245 E1 SS
    6 JANUARY 2 F 12 F 2458 20 F1 SS
    7 G 2 JANUARY 12 F 4556 20 G1 SS
    8 JANUARY 2: 12 F SS 20 789 H1

    Write an sql to get the name of the employee who received the highest wages? It is the question of the interview...
    select empname
    from employees
    where salary in (select max(salary)
    from employees);
    
  • Querry needed sql for records between the current year first day and date of the day

    Hello

    I have a table like this...
    EmpID Empname MJ
    Test1 FRAMEWORK June 19, 2011
    Test2 AA 22 March 2011
    Test3 SS 22 October 2011
    TEST4 VV 1 January 2012
    TEST5 HH April 1, 2012
    Test6 AS June 18, 2012
    TEST7 St June 26, 2012
    TEST8 FRAMEWORK June 28, 2012

    My output like that...
    EmpID Empname MJ
    TEST4 VV 1 January 2012
    TEST5 HH April 1, 2012
    Test6 AS June 18, 2012
    TEST7 St June 26, 2012
    Logic:

    files between current year first and current Day (sysdate)

    Select * from emptable
    where MJ between trunc (sysdate, 'year') and trunc (sysdate)

    Published by: Kiran on June 25, 2012 23:56

  • User SQL querry

    Hi all

    Please help me with a query SQL that retrieves all off identity with Deprovisioning date less than or equal to the current date with the Mainframe it resources is disabled

    Thank you.

    Hello

    SELECT ost.ost_key, ost.ost_status, obj.obj_name, ost.obj_key
    The OST, obj
    WHERE
    OST.obj_key = obj.obj_key AND
    obj_name = "OIMRacfResourceObject";

    Get the ost for disabled state key and use the following Charly

    SELECT oiu.usr_key, usr.usr_last_name
    Of Ouedraogo, usr
    WHERE
    OIU.ost_key = "".
    OIU.usr_key = usr.usr_key

    Regards
    user12841694

  • VLAN Querry

    I have two vSwitches that connect to different networks:

    vSwitch0 (2 NIC team): connects to 10.0.0.x

    vSwtich1 (2 NIC team): connects to 192.168.2.x/24

    I need to virtualize servers on another 192.168.1.x/24 network.  I have all of the options in addition to getting another 2 cards NETWORK and configuring a vSwitch2?

    I can implement any form of VLANS on vSwitch1 so that I can accommodate the servers that I have on the 192.168.1.x/24 network?

    Any comments/help appreciated.

    Thank you

    Yes, you can change the current access port in a port trunking and then assign tags VLAN ports vSwitch groups. Create a new group of port by going to host and Cluster-> Configuration-> tab

    Network-> properties-> add-> Virtual Machine. You will see network Label and VLAN ID add your descriptive label, then the correct ID of VLAN. This will allow the vSwitch add and VLAN tags as needed. Virtual machines must be assigned to the appropriate network tag for the appropriate VLAN. It is the easiest way to use multiple VLANs with ESX. Here is a link that explains all the options.

Maybe you are looking for