Querry
Hello
Can I use apple sim to the South?
doreen48 wrote:
Hello
Can I use apple sim to the South?
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Similar Questions
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I have a wireless negear connected my labtop unable hostname querry
I have a wireless negear connected my labtop cannot querry hostname. I have a connection, but I can't the internet upward
Hi, Melissa,
Repair and Winsock Reset catalog
- Click the Start button.
- Type Cmd in the search text box.
- Press Ctrl-Shift-Enter keyboard shortcut to run command as administrator prompt. Allow elevation request.
- Type netsh winsock reset in the command line shell, and then press the Enter key.
- Restart the computer.
Try to use the Mr. Fixit to reset the IP stack
How to reset the Protocol Internet (TCP/IP)
http://support.Microsoft.com/kb/299357
Press the Windows flag + R to open the run
Type www.yahoo.com
Press Ok
This should open a Web page
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SQL Querry has worked in the workshop of SQL but not in series AnyChart.
Hello
I use the following statement in SQL Workshop:
T3.fname | NULL, select ' ' | T3. Lname label, to_char (to_date (t1.total_time, 'sssss'), 'mi: ss') Week_2_Time, t2.total_weight week2_weight
evt_scr_board t1, evt_scr_board t2, t3 mem_profile
where t1.mem_serno = t2.mem_serno
and t1.evt_rnd = 1
and t2.evt_rnd = 2
and (t1.rx_cd = 'RX' and t1.evt_rnd = 1)
and (t2.rx_cd = 'RX' and t2.evt_rnd = 2)
and t3.mem_serno = t1.mem_serno
It produces the following as expected:
However when I run the same querry in a series of anychart page shows "No Data".
The querry works fine if I don't need to convert the number to a date format. Any help would be greatly appreciated.
Thank you!!!
Syntax for a series is:
SELECT link, label, value FROM ...
In your last example, sysdate week_2_time isn't a value or time.
The format below for your query would work, but I doubt that is what your waiting for.
SELECT NULL, 'Me', TO_NUMBER (TO_CHAR (SYSDATE, 'mmddyyyy')) week_2_time, 135 week_2_weight FROM DUAL
Jeff
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Need to retive querry sql data sysdate to data of last365 days.
Hello
I need sql querry to retrieve data based on this condition: date between previous 365 days and the date of the day.
date of sal EMP
1 200 03-mar-2011
1 200 03-mar-2008
1 200 06-mar-2012
1 200 03-mar-2003
1 200 03-mar-2004
1 200 03-mar-2005
and so on... a lot of files...
I need all data of employees of currentdate (sysdate) to previous data 365 days...
Published by: 937506 on June 7, 2012 04:26select * from employees where hiredate between (sysdate-365) and (sysdate);
This should help
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HP dc7900 Small Form Factor: «Graphics querry»
Hello:
I have a pc hp dc 7900 shape small factor. I would ask what graphics card is supported on this device close to 1 GB.
Please specify precise model of the graphics card as well as the brand because it's a desktop pc.
Thank you.
Kind regards
Mohsin
Hello:
I would go for the Radeon HD 6450 profile low with flat card, which is the graphics card in option on the Elite SFF 8200 with the same power 240W.
This one, if you can get it where you live.
http://www.Newegg.com/product/product.aspx?item=N82E16814121439
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Pouvez LabVIEW querry MAX for active devices?
Is there a way for LabVIEW for query MAX for active devices?
Given case at a time, a measuring instrument (for example a multimeter) is added to my test system, I would like to be able to get the name of MAX i/o device and then be able to communicate with this device without having to manually interact with MAX.
Thanks in advance.
Hi, AT,.
so, you are interested in the use of the VISAFindResources function?
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LEFTOUTER join querry which gives bad result
Hello
I have tables like below.when I perform a left outer join issue IDs and startdate he gives invalid results.when I write in request
It does not correct result because there is no data for 16 jan. It should give no results. But it shows all records. How do I solve this problem
SQL:
Select a.id, a.date, b.val, a.tot, b.net, b.cre
FROM table1 a
join table2 b left
"on a.id = b.id and a.date = b. and a.date ='02-Feb-2014."
In the tables below contains no data for the month of February but still im getting the incorrect data. He must not returnany files right?
Table1:
ID Date Val tot 1 January 1, 13 1 9 2 2 January 13 3 8 3 3 January 13 4 7 4 January 4, 13 5 6 5 5 January 13 6 5 Table2:
ID Date NET CRE 1 January 1, 13 1 9 2 13 January 13 3 8 3 3 January 13 4 7 4 January 4, 13 5 6 5 5 January 13 6 5 "It should not returnany files right?
Wrong, there is no where clause so it should return all the records in a padded with NULL values for b.
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Hi all, I have a few question
with tab (c1, c2, c_from, c_to) as)
Select 'donnees_1', 'data_2", 1, 3 of all the double union
Select the option 'data1_1', 'data1_2', 1, 2 all the double union
Select 'data2_1', 'data2_2', 1, 4 double
)
Select * from tab;
This query present a simple fact
C1 C2 C_FROM C_TO
------- ------- ---------- ----------
donnees_1 1 3 data_2
data1_1 data1_2 1 2
1 4 data2_2 data2_1
Data I expect is:
c1 c2 c3 donnees_1 data_2 1 donnees_1 data_2 2 donnees_1 data_2 3 data1_1 data1_2 1 data1_1 data1_2 2 data2_1 data2_2 1 data2_1 data2_2 2 data2_1 data2_2 3 data2_1 data22_2 4 I know I have to use connect by, but don't know how
Hello
In fact, you need not CONNECT BY for this problem or any other problem. Nothing you can do with CONNECT BY you can also do it with a WITH recursive clause. CONNECTION is much simpler for some problems, but not for this one.
Depending on your needs, here's a way:
WITH r (c1, c2, c_from, c_to, c3) AS
(
SELECT c1, c2, c_from, c_to
1 c3
TAB
UNION ALL
SELECT c1, c2, c_from, c_to
c3 + 1 AS c3
R
WHERE c3< c_to="" +="" 1="" -="">
)
SELECT c1, c2, c3
R
ORDER BY c1, c2, c3
;
Output:
C1 C2 C3
------- ------- ----------
data1_1 data1_2 1
data1_1 data1_2 2
data2_1 data2_2 1
data2_1 data2_2 2
data2_1 data2_2 3
data2_1 data2_2 4
data_2 donnees_1 1
data_2 donnees_1 2
donnees_1 data_2 3
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Any body help me please to write a SQL query to identify the DML which runs longer than 30 seconds, including user_ip, sql_text, time and weather, enforcement is a session blocking or not?.
I found the solution to get the desired output. Thanks a lot to you all. Here I am pasting my solution that can help you if you need any other body.
The query below will help you identify the user_ip, the Sql_text, and the runtime more than 30 seconds.
SELECT s.machine, S.USERNAME, s.sid, s.osuser, t.sql_id, sql_text, to_char(sl.start_time,'hh24:mi:ss') starttime, sl.elapsed_seconds,.
(sl.sofar/sl.totalwork)* 100%
v $ sqltext_with_newlines t, V$ SESSION s, v$ session_longops sl
where s.sid = sl.sid
and t.address = s.sql_address
and t.hash_value = s.sql_hash_value
and s.status = 'ACTIVE '.
and s.username <> 'SYSTEM '.
and sl.elapsed_seconds<>
This query will show you blocking sessions.
Select distinct s1.username | » @'|| S1.machine | "(INST =' | s1.inst_id |) ' SID = ' | S1.SID |')
blocks ' | S2. UserName | '@' || S2.machine | ' (INST =' | s1.inst_id |') SID =' | S2.SID |') '
LIKE blocking_status, s2.program, s3.sql_id, s3.sql_text gv$ lock l1, gv$ session s1, gv$ lock l2, gv$ session s2, s3 in v$ sql
where s1.sid = l1.sid
and s2.sid = l2.sid
and l1.block = 1
and l2.request > 0
and l1.id1 = l2.id1
and l2.id2 = l2.id2
and s2.sql_id = s3.sql_id;
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2 different counts in a single querry
I'm trying to get a separate account to ID who never had SESC as a means of payment and IDs that moved it. Although they had other methods of payment such as cash or card and then SESC.
Payment as so much money card and the SESC has so below ID 1 (MOVED)
ID 2 has had the SESC SESC so right
ID 3 was money and SESC (MOVED)
4 ID a SESC SESC only if
CREATE TABLE DAN_GR_DELETE (ID VARCHAR2(8), PAYMENT VARCHAR2(8), ITEM VARCHAR2(8)) INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'CREDIT','CAR'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'CASH','BUS'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (1,'HECS','BIKE'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (2,'HECS','BIKE'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (2,'HECS','CAR'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (3,'CASH','BUS'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (3,'HECS','CAR'); INSERT INTO DAN_GR_DELETE (ID,PAYMENT,ITEM) VALUES (4,'HECS','CAR');
WANTED:ID PAYMENT ITEM 1 CREDIT CAR 1 CASH BUS 1 HECS BIKE 2 HECS BIKE 2 HECS CAR 3 CASH BUS 3 HECS CAR 4 HECS CAR
using the:MOVED HECS 2 2
Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64biOk. Can be...
with tt as (SELECT distinct d.id, count(distinct payment) OVER (partition by id) cnt FROM DAN_GR_DELETE d) SELECT (select count(0) from tt where cnt = 1) HECS, (select count(0) from tt where cnt != 1) MOVED FROM DUAL
HECS MOVED ----------------------- ----------------------- 2 2
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MAX value query and then add to existing querry
Hi all
Asked me to add some fields to add to an existing query.
I'm having a problem with the initial query, so let's start first, and then maybe I'll be able to figure out how to add it in.
Here is my sample data:
My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,CREATE TABLE TASK ( TASK_TYPE VARCHAR2 (50 BYTE), TASK_SEQ VARCHAR2 (50 BYTE), COMPL_DATE DATE, REQUIRED_TASK VARCHAR2 (100 BYTE) ); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('ABC',18, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('DEF',16, TO_DATE('12-MAR-12','DD-MON-YYYY'),'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('HIJ',12, TO_DATE('09-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('KLM',15, TO_DATE('12-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('NOP',11, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('QRS',20, TO_DATE('29-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('TUV',13, TO_DATE('11-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('WXY',19, TO_DATE('30-MAR-12','DD-MON-YYYY'), 'Y'); INSERT INTO TASK (TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK) VALUES ('Z',24, TO_DATE('04-APR-12','DD-MON-YYYY'), 'Y');
such as:
{Europe}
TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
Z 24 4 4 2012 Y (DO NOT WANT THIS)I have this code that I thought would work, but not as of yet - it returns all rows and ranks eac as 1. {code} WITH DST AS ( SELECT TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK, RANK () OVER (PARTITION BY TASK_TYPE ORDER BY COMPL_DATE) rnk FROM TASK ) SELECT * FROM DST WHERE rnk = 1 {code} And this yields basically the same results: {code} SELECT TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK FROM TASK WHERE (TASK_TYPE, TASK_SEQ) IN (SELECT TASK_TYPE, MAX(TASK_SEQ) FROM TASK GROUP BY TASK_TYPE ) {code} Thanks for taking the time to look. G
Hello
GMoney says:
... Here is my sample data:Thank you! It is very useful.
... My desired output is the MAX (TASK_SEQ) based on the data set, the TASK_SEQ and the COMPL_DATE should always be recording albums that I'm trying to capture,
such as:
{Europe}
TASK_TYPE TASK_SEQ COMPL_DATE REQUIRED_TASK RNK
Z 24 4 4 2012 Y (DO NOT WANT THIS)
Be careful. The keyword tiny must code. (It must be spelled correctly, too.)
What is the desired line or line that you don't want? If this is the desired line, so you were on the right track with your first attempt. Try this:WITH DST AS ( SELECT TASK_TYPE, TASK_SEQ, COMPL_DATE, REQUIRED_TASK, RANK () OVER (ORDER BY COMPL_DATE DESC) rnk FROM TASK ) SELECT * FROM DST WHERE rnk = 1 ;
Exactly what you have published, with the exception of the analytical clause.
'PARTITION BY task_type' means a separate set of numbers (starting with 1) assign to each separate task_type. Since task_type is unique, this means that each line is #1 in his own little world. If I understand the problem, you want (except ties) only 1 rank for the entire result set. This means you don't at all want a PARTITION BY clause. PARTITION BY is never required in any analytic function.
"ORDER BY compl_date" means that the first compl_date gets rnk = 1. You want the latest comp_date to get #1, so you must specify descending order. Note that this has nothing to do with task_seq. It you want to display the line with the highest task_seq, then the rnk column would be defined as:RANK () OVER (ORDER BY task_seq DESC) rnk
If you know that the line with the upper task_seqs is always compl_dates later, then it does not matter that you use. Remember to descending order.
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Need Sql querry for this logic
Empname MJ sex desg salary managerid dept ID
2 B 2 JANUARY 12 M 10 20000 B1 SS
3 C 2 JANUARY 12 M 90000 10 C1 SS
4 D JANUARY 2, 12 M 15000 20 D1 SS
5 E 2 JANUARY 12 F 20 14245 E1 SS
6 JANUARY 2 F 12 F 2458 20 F1 SS
7 G 2 JANUARY 12 F 4556 20 G1 SS
8 JANUARY 2: 12 F SS 20 789 H1
Write an sql to get the name of the employee who received the highest wages? It is the question of the interview...select empname from employees where salary in (select max(salary) from employees);
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Querry needed sql for records between the current year first day and date of the day
Hello
I have a table like this...
EmpID Empname MJ
Test1 FRAMEWORK June 19, 2011
Test2 AA 22 March 2011
Test3 SS 22 October 2011
TEST4 VV 1 January 2012
TEST5 HH April 1, 2012
Test6 AS June 18, 2012
TEST7 St June 26, 2012
TEST8 FRAMEWORK June 28, 2012
My output like that...
EmpID Empname MJ
TEST4 VV 1 January 2012
TEST5 HH April 1, 2012
Test6 AS June 18, 2012
TEST7 St June 26, 2012
Logic:
files between current year first and current Day (sysdate)Select * from emptable
where MJ between trunc (sysdate, 'year') and trunc (sysdate)Published by: Kiran on June 25, 2012 23:56
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Hi all
Please help me with a query SQL that retrieves all off identity with Deprovisioning date less than or equal to the current date with the Mainframe it resources is disabled
Thank you.Hello
SELECT ost.ost_key, ost.ost_status, obj.obj_name, ost.obj_key
The OST, obj
WHERE
OST.obj_key = obj.obj_key AND
obj_name = "OIMRacfResourceObject";Get the ost for disabled state key and use the following Charly
SELECT oiu.usr_key, usr.usr_last_name
Of Ouedraogo, usr
WHERE
OIU.ost_key = "".
OIU.usr_key = usr.usr_keyRegards
user12841694 -
I have two vSwitches that connect to different networks:
vSwitch0 (2 NIC team): connects to 10.0.0.x
vSwtich1 (2 NIC team): connects to 192.168.2.x/24
I need to virtualize servers on another 192.168.1.x/24 network. I have all of the options in addition to getting another 2 cards NETWORK and configuring a vSwitch2?
I can implement any form of VLANS on vSwitch1 so that I can accommodate the servers that I have on the 192.168.1.x/24 network?
Any comments/help appreciated.
Thank you
Yes, you can change the current access port in a port trunking and then assign tags VLAN ports vSwitch groups. Create a new group of port by going to host and Cluster-> Configuration-> tab
Network-> properties-> add-> Virtual Machine. You will see network Label and VLAN ID add your descriptive label, then the correct ID of VLAN. This will allow the vSwitch add and VLAN tags as needed. Virtual machines must be assigned to the appropriate network tag for the appropriate VLAN. It is the easiest way to use multiple VLANs with ESX. Here is a link that explains all the options.
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