Query - remove duplicate records, based on the value of a field

Hello


Please view the information below,
How to delete records when his number 0
AND these records (name) repeat with count > 0
existing data

 name                       loc                            count
------------------------------------------------------------------------

aaa          a1          10
aaa          a1          0
bbb          b1          0
ccc          c1          0
dcc          d1          11
dcc          d1          0

required output

---------


 name                       loc                            count
------------------------------------------------------------------------

aaa          a1          10
bbb          b1          0
ccc          c1          0
dcc          d1          11



remove these records -

-----------

aaa          a1          0
dcc          d1          0
Thank you.

I guess that loc always matches the name. Thus, to find the lines of stay is just a simple group of

with data as(
select 'aaa' name,'a1' loc,10 count from dual union all
select 'aaa','a1',0 from dual union all
select 'bbb','b1',0 from dual union all
select 'ccc','c1',0 from dual union all
select 'dcc','d1',11 from dual union all
select 'dcc','d1',0 from dual )

select
  name
, loc
, max(count) cnt
from data
group by
  name
, loc
order by
  name
, loc

NAME     LOC     CNT
aaa     a1     10
bbb     b1     0
ccc     c1     0
dcc     d1     11

to find that the other is just a minus

with data as(
select 'aaa' name,'a1' loc,10 count from dual union all
select 'aaa','a1',0 from dual union all
select 'bbb','b1',0 from dual union all
select 'ccc','c1',0 from dual union all
select 'dcc','d1',11 from dual union all
select 'dcc','d1',0 from dual )

select name,loc,count from data
minus
select
  name
, loc
, max(count) cnt
from data
group by
  name
, loc
order by
  name
, loc

NAME     LOC     COUNT
aaa     a1     0
dcc     d1     0

would be a delete

delete from data
where
(name,loc,count)
in
(select name,loc,count from data
minus ..

concerning

Tags: Database

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     res9.display = display.hidden;
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     res2.display = display.noPrint;
     res3.display = display.noPrint;
     res4.display = display.noPrint;
     res5.display = display.noPrint;
     res6.display = display.noPrint;
     res7.display = display.noPrint;
     res8.display = display.hidden;
     res9.display = display.hidden;
     res10.display = display.hidden;
     res11.display = display.hidden;
     res12.display = display.hidden;
     res13.display = display.hidden;
     res14.display = display.hidden;
     res15.display = display.hidden;
     res16.display = display.hidden;
     res17.display = display.hidden;
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     res2.display = display.noPrint;
     res3.display = display.noPrint;
     res4.display = display.noPrint;
     res5.display = display.noPrint;
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     res13.display = display.hidden;
     res14.display = display.hidden;
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