Query to find the setting and add it to the minimum value

Similar Questions

• PL/SQL loop to find the minimum value

  I want to find the minimum value from a table using the pl/sql loop

  I have data format below.

  1 ABC 2

  1 ABC 20

  1 ABC 500

  1 ABC 2000

  XYZ 2 250

  JKL 3 300

  MNP 3 350

  3 KLM 400

  I wrote the code below. His does not work. Please suggest.

  Set serveroutput on
  declare
  x number: = 3;
  y VARCHAR2 (3): = 'ABC ';
  fmin number: = 0;
  number of Fmax: = 0;
  Start
  for rec in (select sal from test
  where id = name and x = y) loop

  
  If rec.sal > fmin then
  fmin: = rec.sal;
  on the other
  FMAX: = rec.sal;
  fmin: = fmax.
  end if;
  end loop;
  dbms_output.put_line (Fmax);
  end;
  /

  I want to output 2 on top of code.

  Thanks in advance

  Why PL/SQL? SELECT MIN (SAL) OF TEST will be more rapid and much less coding. In any case:

  declare

  number of v_min_sal;

  Start

  for v_rec in a loop (select sal from emp)

  If nvl (v_min_sal, v_rec.sal + 1) > v_rec.sal

  then

  v_min_sal: = v_rec.sal;

  end if;

  end loop;

  dbms_output.put_line (' lowest salaray is "' |") v_min_sal | '"');

  end;

  /

  The lowest Salaray is "800".

  PL/SQL procedure successfully completed.

  SQL >

  SY.

• SQL - find the minimum value for each separate record...

  Hi all
  
  I have a table like this in SQL Server
  
  Date of sale of product
  A date
  A date
  A date
  B date of
  B date of
  C date
  C date
  C date
  
  I would like to write a query to find the minimum date (i.e. the date
  the first sale) for each product
  
  Thus, the expected results would be
  
  Date of sale of product
  A date min
  B date of min
  C date of min
  
  How can I do this using SQL Server?
  
  any help is greatly appreciated!
  
  Thank you!
  
  

  Product SELECTION, MIN (sale_date)
  From your_table
  GROUP BY product

  Etienne

• Find the minimum value of the table in time...

  Firstly that it is not "find the min value in the table.

  It is:

  I have a table that changes its values at each iteration, and I want to compare the new values with previous values and make a new array with the minimum values...

  In C++, it would be like this:

  int main() {}

  int array [8];

  int min [8];

  int i;

  for (i = 0; i<>

  min [i] = 1000000; Initialize minimum table with a high value

  }

  {while (1)}

  Array = update_array ();

  for (i = 0; i<>

  If (array [i]<>

  min [i] = array [i];

  }

  }

  do things...

  }

  return 0;

  }

  IM new to labview and it always confuses me a lot...

  Thanks in advance.

  Using the function Max & Min regular (not table Max & min as you know) with tables and a good will of employment registry change.  Max Min &, as most of the digital functions, is polymorphic and works witt tables as well as scalars.

  Lynn

  

• Query to find the 2 values in column 1

  Hello
  
  I have a table like

  create table table1 (col1 NUMBER, col2 VARCHAR2(4), col3 varchar2(4));
  
  Sample Data:
  
  select COL1, NVL(COL2,'---') col2, NVL(COL3,'---') col3
  from table1;
  
  COL1                   COL2 COL3 
  ---------------------- ---- ---- 
  10                     A10Q ---  
  10                     A10R ---  
  20                     ---  A10Q 
  20                     ---  A10R 
  30                     A10Q ---  
  30                     A10R ---  
  30                     ---  A10Q 
  30                     ---  A10R 
  40                     A10Q ---  
  40                     ---  A10R 
  50                     A10Q ---  
  
   11 rows selected 

  The user enters 2 values, for example A10Q and A10R. I don't need only the records that have the two values.
  So I need lines of the sample of data where COL1 = 10,20,30 and 40. 50 must be returned as it has only A10Q and not A10R.
  I just need COL1 values.
  
  I wrote the query below, but wanted to know if there is a better way to write this

  select *
  from table1
  where col1 in (select col1 from table1 where (col2 = 'A10Q' or col3 = 'A10Q'))
  and (col2 = 'A10R' or col3 = 'A10R');
  
  COL1                   COL2 COL3 
  ---------------------- ---- ---- 
  10                     A10R      
  20                          A10R 
  30                          A10R 
  30                     A10R      
  40                          A10R 

  Kind regards
  Vikram

  Assuming that the values cannot be duplicated for any group of individuals col1, something like that maybe...

  select col1
  from table1
  where 'A10Q' in coalesce(col2, col3)
  or    'A10R' in coalesce(col2, col3)
  group by col1
  having count(*) = 2
  

  (not tested as you did not provide the data in a usable format)

• Query to find the distinct values

  Hi all

  Given, it's like

  with t as (select 1 eno, "AC_ACCOUNT" the double job_id)

  Union select 2 eno, 'AC_ACCOUNT' job_id of the double

  Union select 3 eno, 'AC_ACCOUNT' job_id of the double

  Union select 4 eno, 'AC_MGR' job_id of the double

  Union select 5 eno, 'AD_VP' job_id of the double

  Union select 6 eno, 'AC_MGR' job_id of the double

  Union select 7 eno, 'AC_MGR' job_id of the double

  Union select 8 eno, "FI_ACCOUNT" double job_id)

  Select * from t;

  It takes the job_id not duplicated output.

  For this release of data should be,

  AD_VP

  FI_ACCOUNT

  Is it possible to write a query without hard coding or using separate?

  Kind regards

  SoundariyaKumar.R

  Hello

  You could do like:

  SQL >

  SQL > with t as (select 1 eno, "AC_ACCOUNT" the double job_id)

  2 union select 2 eno, "AC_ACCOUNT" double job_id

  3 union select 3 eno, "AC_ACCOUNT" double job_id

  4 union select 4 eno, "AC_MGR" double job_id

  5 union select 5 eno, "AD_VP" double job_id

  6 union select 6 eno, "AC_MGR" double job_id

  7 union select 7 eno, "AC_MGR" double job_id

  8 union select 8 eno, "FI_ACCOUNT" double job_id)

  9 select job_id from group by job_id t having count ()) = 1;

  JOB_ID

  ----------

  AD_VP

  FI_ACCOUNT

  SQL >

• Find the minimum value in digital array that is greater than 0

  So far I have;

  $pfpp = min ($pflist);

  $pflist is the array of digital values and contains about 0.

  I need to change to $pfpp = min ($pflist); to return the lowest number which is greater than zero.

  I am stuck, can anyone help?

  Thank you

  Change the values in the table so I can't sort them in ascending order.

  Of course you can.  Or you can copy the table into a temporary array.

  $temp = $pflist;

  sort ($temp, SORT_NUMERIC)

  foreach ($temp as $value) {}

  If $value > 0; $number = $value; break;

  }

  echo "entry of zero smaller in pflist is $number";

• SQL query to find the total number of source based nonsource passangersbetween source and destination station and passenger station on the same chekindate

  Hello

  SQL query to find the total number of source based nonsource passangersbetween source and destination station and passenger station on the same chekindate.

  Please help on this script and let me know if you need more details.

  ---

  You use a SELECT statement.  Let me know if you need more details.

• Query to find the Pages and the list of permissions associated with a particular role in PS

  I want a query to find the Pages and the list of permissions associated with specific roles in PS.

  For example, if we see the role of manager accounts payable, it conatins Pages and the list of permissions.

  But, to get everything in EXCEL sheet by Manuel priocess's BIG job. So, can someone give me the query.

  Please try under queries

  The roles assigned to the list of Perm:

  SELECT B.ROLENAME

  OF PSCLASSDEFN A, PSROLECLASS B

  WHERE (A.CLASSID = B.CLASSID

  AND A.CLASSID =: 1).

  List of Perm pages can access:

  SELECT B.MENUNAME, B.BARNAME, B.BARITEMNAME, B.PNLITEMNAME, C.PAGEACCESSDESCR, B.DISPLAYONLY

  OF PSCLASSDEFN A, PSAUTHITEM B, PSPGEACCESSDESC C

  WHERE (A.CLASSID = B.CLASSID

  AND A.CLASSID =: 1

  AND B.BARITEMNAME > ' '

  AND B.AUTHORIZEDACTIONS = C.AUTHORIZEDACTIONS)

• query to find the dependent task, attached to the task on a response in OIM 11 g

  can someone help me to do a sql query to find the dependent task, attached to the task on a response in OIM 11 g
  
  Published by: user13331347 on Sep 3, 2012 14:09

  Use under query to find the dependent task in OIM 11 g: -.

  Select pkg.pkg_name, mil.mil_name, rsc.rsc_data, rsc.sta_key, sta.sta_status, sta.sta_bucket, mil2.mil_name
  pkg pkg, tos tos, mil mil, mil mil2, rsc rsc, sta sta, rgm the rgm
  where pkg.pkg_key = tos.pkg_key
  and tos.tos_key = mil.tos_key
  and mil.mil_key = rsc.mil_key
  and rsc.sta_key = sta.sta_key
  and rgm.rsc_key = rsc.rsc_key
  and rgm.mil_key = mil2.mil_key
  order of pkg.pkg_name, mil.mil_name, rsc.rsc_data, sta.sta_status, mil2.mil_name

• Query to find the coordinates of employee salary

  Hello
  
  Could someone help write the query to find the salary of the employee details.
  
  Thanks in advance.

  This should help you get started:

  SELECT papf.full_name
  papf.email_address
  ppp.proposed_salary_n salary
  OF per_pay_proposals ppp
  per_all_assignments_f ADP
  per_all_people_f women's wear
  WHERE ppp.assignment_id = paaf.assignment_id
  AND paaf.assignment_type = 'E '.
  AND paaf.primary_flag = 'Y '.
  AND paaf.person_id = papf.person_id
  AND nvl (papf.current_employee_flag, 'n') = 'Y '.
  AND trunc (sysdate) BETWEEN
  PPP.change_date AND ppp.date_to
  AND trunc (sysdate) BETWEEN
  PAAF.effective_start_date AND paaf.effective_end_date
  AND trunc (sysdate) BETWEEN
  PAPF.effective_start_date AND papf.effective_end_date;

• What is the query to find the name of all applications for all EBS R12.1.3 modules?

  What is the query to find the name of all applications for all EBS R12.1.3 modules?

  With regard to:

  Mr. Shahzad Saleem

  Try:

  SELECT * FROM fnd_concurrent_programs_vl;

• Find the max value

  Hi team,

  I have the following query where I need to find the max value

  [code]

  with t as)

  Select 'L1' R_nm, R_Data 'Data', 'Obj' R_Obj, r_prec 'Wd', '2' double val

  Union of all the

  Select 'L1', 'Data', 'Obj', 'No', '4' double

  Union of all the

  Select 'L2', 'Data', 'Obj', 'No', '4' double)

  Select t.*, max (val) on rk (partition r_nm, r_data, r_obj) of t

  [/ code]

  My results should be

  [code]

  r_nm r_data r_obj r_prec rk val

  L1 Data Obj 1 2 Wd

  L1 data Obj 4 No.2

  L2 Data Yes 1 1 Obj

  [/ code]

  Thank you

  
  

  Hello

  It seems that you are not interested in the MAX at all.  Looks like you want to classify the lines, such as one that has the lowest value is assigned the number 1, the 2nd line with the lowest values gets 2,... and line with him gets N-th lowest value N.  If is not serious if the MAX is 4, 2 or 420.

  Here's a way to do it:

  SELECT T.*

  , RANK () OVER (PARTITION BY r_nm, r_obj)

  ORDER BY val

  ) AS rk

  T

  ORDER BY r_nm, r_obj

  val

  ;

  Depending on how you want to deal with links, you can use ROW_NUMBER or DENSE_RANK instead of RANK.

• Find the minimum date on multiple columns

  Hello
  
  I have two questions to find the minimum date on several columns:
  1. need a select query that should JOIN two tables and return any information (CASSEDTL) table with minimum date out of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE.
  2. need of an update query that should update all cases in the CASEDTL table with the minimum date of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE.
  
  The DDL:

  CREATE TABLE CASEMSTR 
  (   CASENBR     NUMBER,
      DATEISSUED  DATE,
      DATEPLACED  DATE,
      DATEENTERED DATE);
      
  CREATE TABLE CASEDTL 
  (   CASENBR     NUMBER,
      STATDATE    DATE,
      RCVDATE    DATE,
      MODDATE     DATE);
      
  INSERT INTO CASEMSTR VALUES (1, '1 JUL 2007', '1 JUL 2007', '12 JUL 2007');
  INSERT INTO CASEMSTR VALUES (2, '1 JAN 2008', '1 JAN 2008', '21 JAN 2008');
  INSERT INTO CASEMSTR VALUES (3, NULL, NULL, '3 DEC 2008');
  INSERT INTO CASEMSTR VALUES (4, '31 MAR 2009', NULL, '6 APR 2009');
  INSERT INTO CASEMSTR VALUES (5, NULL, '22 MAR 2009', '6 APR 2009');    
  INSERT INTO CASEMSTR VALUES (6, NULL, NULL, '16 JUL 2009');
  INSERT INTO CASEMSTR VALUES (7, '1 DEC 2008', '7 DEC 2008', '26 DEC 2008');
  INSERT INTO CASEMSTR VALUES (8, NULL, NULL, '17 MAY 2009');
  
  INSERT INTO CASEDTL VALUES (1, '25 JUN 2007', NULL, '2 AUG 2009');
  INSERT INTO CASEDTL VALUES (2, '1 JAN 2008', NULL, '2 AUG 2009');
  INSERT INTO CASEDTL VALUES (3, '11 NOV 2008', NULL, '2 AUG 2009');
  INSERT INTO CASEDTL VALUES (4, '31 MAR 2009', NULL, '2 AUG 2009');
  INSERT INTO CASEDTL VALUES (5, '19 JUL 2009', NULL, '2 AUG 2009');    
  INSERT INTO CASEDTL VALUES (6, '13 JUN 2009', NULL, '16 JUL 2009');
  INSERT INTO CASEDTL VALUES (7, '7 DEC 2008', NULL, '16 JUL 2009');
  INSERT INTO CASEDTL VALUES (8, '14 MAY 2009', NULL, '16 JUL 2009');
  COMMIT;

  The initial query I have is

  SELECT CD.CASENBR, CM.DATEISSUED, CM.DATEPLACED, CM.DATEENTERED, CD.STATDATE, CD.RCVDATE, NULL "NEW RCV DT" 
  FROM CASEDTL CD
      INNER JOIN CASEMSTR CM
          ON CD.CASENBR = CM.CASENBR;

  Need to know what is the best way to complete the new Date of RRS? Receive a new date should be the minimum date of DATEISSUED, DATEPLACED, DATEENTERED and STATDATE. And also how do I write an update statement unique to upade date of receipt in the detail table?
  
  Any help would be appreciated! Thanks in advance!

  Where is the function LESS? Refer to manual SQL.

  HTH - Mark D Powell.

  put1 > desc multdate
   Name                                      Null?    Type
   ----------------------------------------- -------- ----------------------------
   COL1                                               DATE
   COL2                                               DATE
   COL3                                               DATE
  
  put1 > select * from multdate;
  11-AUG-09 10-AUG-09 01-AUG-09
  
  put1 > select least(col1, col2, col3) from multdate;
  01-AUG-09
  

  Published by: MarkDPowell on August 11, 2009 15:53 added example

• Find the average value of a buffer

  Hello

  In my VI Panel, I have a digital control, a button and a digital display.

  When the user, enter a number in numerical order and press the button, the digital display should show the average value of all the past 5 values entered in the digital control, for example:

  1st entry: 10-online average = 10 (as sum = 10)

  2nd type: 0-online average = 5 (as sum = 10 + 0 = 10)

  3rd enter: 5-online average = 5 (you get the idea...)

  4 enter: 1-average online = 4

  5 enter: 14-online medium = 6

  6 enter: 2-online average = 4.4 (sum = 0 + 5 + 1 + 14 + 2 = 22, because the 1st value is thrown)

  How to write this VI?

  Thank you!!

  You can also use arrays to hold the data in a registry change and find the average value of the last five items.

  

  Good luck

• Find the minimum distance between two SDO_GEOMETRY in Oracle Spatial?

  

  A circle (SDO_GEOMETRY)
  B - polygon (SDO_GEOMETRY)

  CASE:
  B contains A (or)
  The Interior of B.

  How to find the minimum distance between A and B in Oracle Spatial

  Hello guuid nameless person.

  What is

  my_answer := MDSYS.SDO_GEOM.SDO_DISTANCE(
     my_circle_geometry
    ,MDSYS.SDO_UTIL.POLYGONTOLINE(my_outer_polygon)
    ,my_tolerance
  );
  

  Now, you may need to pay attention to the holes in your polygon, would you the distance and an inner ring if it was closer to you?

  If the measure is only to outer rings, so something like

  my_answer := MDSYS.SDO_GEOM.SDO_DISTANCE(
     my_circle_geometry
    ,MDSYS.SDO_UTIL.POLYGONTOLINE(
        MDSYS.SDO_UTIL.EXTRACT(my_outer_polygon,1,1)
     )
    ,my_tolerance
  );
  

  And then also beware of the multipolygons as the foregoing only measured against the first polygon in the MultiPolygon.  You need to loop through the polygons of tests just the outer ring in this case.

  See you soon,.

  Paul