Re: Replace all NULL values by '0' in the entire table at a time

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• How to replace a. null value in obiee report

  Hi gurus,

  In a single column, we get. as the data, how to replace. with the null value

  Please provide your inputs

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• using % for all null values or empty including

  Hello all;
  
  Below is the sample data
  

  create table t1
  (
  ID varchar2(200),
  time_create date
  );
  
  insert into t1
      (id, time_create)
    values
      ('A', sysdate);
    
    insert into t1
      (id, time_create)
    values
      ('B', sysdate);
      
      insert into t1
      (id, time_create)
      
      
    values
      (null, sysdate);
      

  I have the below sql statement
  

      
      select * from t1
      where t1.id like decode(:id, 'ALL', '%', :id);

  now I have a situation where if user input is EVERYTHING, I want to get all the results, including null values or values space, how can I change the decode statement to do.
  
  This is the output I want below for ALL
  

  ID  TIME_CREATE
  A   5/23/2011 11:14:23 PM
  B   5/23/2011 11:14:24 PM
       5/23/2011  11:14:25 PM

  Any help is appreciated. Thank you.

  Maybe:

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  Scott

• Load the process returns a null value but on refresh the values of loads? !!

  Hi all

  With the help of apex 4.1.1 oc4j 11g Linux

  I'm building a feature that allows you to register by e-mail.

  Page 1

  The user enters a name email address ,& the last statement name Insert is executed

  Select count (*) in c_email - if 0 then the person does not exist and is permitted

  of sor_notification_person

  where sor_notification_person. EMAIL_ADDRESS = P_S_EMAIL_ADDRESS;

  If c_email = 0 then

  -Package.procedure send email and fact the insert

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  P_S_LAST_NAME = > P_S_LAST_NAME,

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  Clicking or copying pasting the URL received in e-mail. I have on the loading process that verifies the checksum value in DB and fills in the data.

  declare

  number of CT ;

  P31_checksum(Varchar2) 30).

  E-mail varchar2 (90);

  What varchar2 (40);

  L_Name varchar2 (40);

  P31_TEST(Varchar2) 40).

  Start

  : P31_TEST := null;

  SELECT count ()*) in ct

  OF SOR_NOTIFICATION_PERSON

  où SOR_NOTIFICATION_PERSON. checksum =:C;

  DBMS_OUTPUT. put_line ()ct);

  if CT > 0

  then

  SELECT SOR_NOTIFICATION_PERSON. email_address SOR_NOTIFICATION_PERSON. name, SOR_NOTIFICATION_PERSON. last_name in l_name what Email

  OF SOR_NOTIFICATION_PERSON

  où SOR_NOTIFICATION_PERSON. checksum =:C;

  : P31_TEST := 'Y ';

  : P31_EMAIL_ADDRESS:= Email;

  : P31_FIRST_NAME := what;

  : P31_LAST_NAME:= l_name;

  else : P31_TEST := 'n';

  (- dbms_output. put_line () P31_TEST);

  end if;

  end ;

  Problem when I view the item hidden, I can see the value of checksum, but the P31_test is always null in load. When I hit refresh page P31_test valid and displays the value.

  The two elements are the value only when the value in session state is null.

  What could be the reason because it does not load even the process is defined as load before region / once per page visit...

  Thanks for your help.

  Okay - not sure then. On a new blank page I can have processes assign a value to the session state from the element and the element will have this value when the page is rendered (at least with this type of source). Work of dynamic actions. As I expect. I don't know what happens next 'unfair '.

  I'll only come back tomorrow, but here are a few tips:

  • create a workspace on apex.oracle.com and upload your page there. Share of the developer credentials and the name of workspace with us. In this way may inspect and do not need to do the back and forth until we reached something special we both lost from view.
  • When the page is loaded and you hit the session in the developer toolbar, what is the State of P31_TEST? Is it worth?
  • try to run the page in debug and see if you can spot something happens with the session state from P31_TEST - maybe you'll come across something

• Get Null value online by using the reference line.

  Hi guys,.

  I get the null value of the line everytime I use the reference line. Here is my code.

  String rowReference = pageContext.getParameter (OAWebBeanConstants.EVENT_SOURCE_ROW_REFERENCE);

  Line OARow = (OARow) am.findRowByRef (rowReference);

  System.out.println ("row" + Row);

  If (line! = null)

  {

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  String succStr = succObj.toString ();

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  }

  Thank you

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  If ('updateRecord".equals (pageContext.getParameter (OAWebBeanConstants.EVENT_PARAM)))

  {

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  }

• Find and replace all occurrences of a string within the current paragraph.

  I did so much work, and it's my last method to implement.

  I want to get the current active doc the current paragraph and replace all occurrences of a string inside this paragraph with another string.

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  «This is a sentence that.» This is another sentence. It is also another sentence. The sentence ".

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  I found a code with F_ApiFind and F_ApiGetTextRange to get the current text selection, but I can't think of a way to do it.

  Post edited by: Efstathios Chatzikyriakidis

  Problem solved people. Thank you.

• How to convert the Null value to 0 after the outer join?

  Hello guys
  
  My requirement is in fact 2 of outer join tables (that's how), and I got the outer join works very well, so in my report, I have values null of measures in another table of facts as a result of the outer join...
  
  Is there a way I can convert these nulls to 0?
  
  I realized that the null value is not stored in the table, it is just following the outer join because the NULL do not match records in other... So by default, I'm expected to get NULL values...
  
  Is there way to present these nulls to 0?
  
  Thanks a lot for your advice

  In response, the syntax will be:

  IFNULL (, 0)

  try and let us know how you go.
  See you soon
  Alastair

• the row_number() value another column in the same table

  Hi all
  I have NODE_DETAILS which has following of table columns
  
  MSLINK
  NODE_ID
  RNUM
  
  I update RNUM with row_number() value in ordering the mslink. I tried after update statement
  
  Update)
  Select / * + bypass_ujvc * / rnum has, row_number() over (order of mslink) NODE_DETAILS rrnum
  )
  set a = rrnum
  
  But he throws ORA-01732: non-legal data manipulation operation on this display error
  
  How can I update row_number() rnum column?
  
  Thank you
  Sujnan

  You can use MERGE

  SQL> create table node_details
    2  (mslink number
    3  ,node_id number
    4  ,rnum number
    5  )
    6  /
  
  Table created.
  
  SQL>
  SQL> insert into node_details
    2  select -rownum, rownum, null
    3    from all_objects
    4   where rownum <= 5
    5  /
  
  5 rows created.
  
  SQL>
  SQL> select *
    2    from node_details
    3  ;
  
      MSLINK    NODE_ID       RNUM
  ---------- ---------- ----------
          -1          1
          -2          2
          -3          3
          -4          4
          -5          5
  
  SQL>
  SQL> merge into node_details n
    2  using (select rowid rid,rnum a, row_number() over (order by mslink) rrnum from NODE_DETAILS) v
    3  on (v.rid = n.rowid)
    4  when matched then
    5     update set rnum = rrnum
    6  ;
  
  5 rows merged.
  
  SQL>
  SQL> select *
    2    from node_details
    3  ;
  
      MSLINK    NODE_ID       RNUM
  ---------- ---------- ----------
          -1          1          5
          -2          2          4
          -3          3          3
          -4          4          2
          -5          5          1
  
  SQL>
  SQL> 
  

• Analysis.Math.Statistics fails when NaN values are included in the entry tables

  Hi all..

  With the help of Measurement Studio to Version 8.9 of .net. We need calculate statistics on a table that contains a double. NaN values. When I do this I get NaN as the result of any of the statistical methods (average, STDS etc.) ... Interestingly, the Math.ArrayOperations methods look like they work. Any ideas?

  Thank you

  gdssoftware

  Hi GDSSoftware,

  You see this behavior because the statistical functions with Measurement Studio ignore not input values NaN - that is why, they will return results NaN.  To work around this problem, you will need to filter these NaN values out of your input array before performing statistical analysis on this subject.

  If you're working with .NET 3.5 and later versions, you can do this by using the following:

  Double [] vals = new double [] {0d, 6 d, 10 d, 4 d, double. NaN};
  Double [] nanless_vals = vals. Where (d =>! double.) IsNaN (d)). ToArray();

  If you use an earlier version of the .NET framework, you will need to perform a loop on the table with the following (or something similar):

  Double [] vals = new double [] {0d, 6 d, 10 d, 4 d, double. NaN};
  List nanless_list As new List();
  for (int i = 0; i)< vals.length;="">
  If (! double.) IsNaN (vals [i]))
  nanless_list. Add (Vals [i]);
  Double [] nanless_vals is nanless_list. ToArray();

  I hope this helps!

  Kind regards

  Stephanie R.

  National Instruments

• How to display the text tabled at run time values

  Hello
  I want to do a form in oracle 10g where I m using a for loop & I want to print each value in the text of the filed form which are generated by loop for.
  
  My loop generate values as a means
  123
  156
  789
  If my deposited text should print first
  123 then
  156 then
  789
  & clear text filed before printing the next value.
  How can I do this
  
  
  regards

  If I understand you want this;

  (Your REQUIREMENT to loop here) LOOP
  : text_item =: text_item | CHR (10) | : var;
  synchronize;
  END LOOP;

• We can add (sum) all lines by searching the entire table in a statement.

  Hello
  I have a table ' create table test1 (id number (5), name varchar2 (10), number (10,2)) pay "with the data.
  
  ID NAME SALARY
  1 AAAAAA 55000
  2 BATH 15430
  3 CARTER 15430
  4 DDDDD 25430
  5. EEEE 29830
  6 FFFFF 7645
  7 GIROU 6546
  8 9645 HHHHH
  9 IIIIII 7584
  
  I need a select query that gives the result like this is to say.., 10th should be the sum of all 9 lines...
  
  ID NAME SALARY
  1 AAAAAA 55000
  2 BATH 15430
  3 CARTER 15430
  4 DDDDD 25430
  5. EEEE 29830
  6 FFFFF 7645
  7 GIROU 6546
  8 9645 HHHHH
  9 IIIIII 7584
  10 172540 total

  Like this?

  SELECT id, name, SUM(salary)
   FROM t1
  GROUP BY GROUPING SETS ((id,name,salary),());
  

• How to replace a "null" in the date field to zero

  Hi guys,.
  
  I'm a lil stuck with this problem.
  I have a requirement where I need to replace a null value in the date field to zero.
  For example,.
  
  Cancel_date Cancel_date
  20120301 20120301
  20120908 20120908
  value null-> > > > > 0
  
  
  Thank you
  Anita

  Hi, Anita,.

  0 is not a DATE, so you cannot view it in a DATE column.
  There is no '0' display problem in a VARCHAR2 column, so use TO_CHAR to display dates, even if the default format, it's exactly what you want.

  SELECT     NVL ( TO_CHAR (date_column, 'YYYYMMDD')
           , '0'             -- or '       0', if you want it right-justified
           )          AS date_string
  FROM     table_x
  ;
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Group by excluding null values

  I want to run a select using "group by". However, I would like the results to exclude all null values in my area. Like for example the code following, but excluding NULL values.

  Select the FIELD, count (FIELD)

  of MYDATA

  FIELD group;

  How can I do this?

  Hello

  Maybe I don't understand your complete problem, but what of this

  select FIELD, count(FIELD)
    from MYDATA
   where field is not null
   group by FIELD;
  

  concerning
  Kay

• Remove the NULL values and update the value according to the logic

  Hello

  The problem data

  CREATE TABLE VOLA (SRNO, NUMBER, zero

  NUMBER, A

  NUMBER);

  INSERTION of REM in VOLA

  TOGETHER TO DEFINE

  Insert in VOLA (SRNO, ONE) values (1,237.94);

  Insert in VOLA (SRNO, ONE) values (2, null);

  Insert in VOLA (SRNO, ONE) values (3,203.565);

  Insert in VOLA (SRNO, ONE) values (4,170.69);

  Insert in VOLA (SRNO, ONE) values (5,113.67);

  Insert in VOLA (SRNO, ONE) values (6,93.6);

  Insert in VOLA (SRNO, ONE) values (7,82.03);

  Insert in VOLA (SRNO, ONE) values (8,66.675);

  Insert in VOLA (SRNO, ONE) values (9,63.59);

  Insert in VOLA (SRNO, ONE) values (10,61.415);

  Insert in VOLA (SRNO, ONE) values (11,60.015);

  Insert in VOLA (SRNO, ONE) values (12,58.235);

  Insert in VOLA (SRNO, ONE) values (13,57.805);

  Insert in VOLA (SRNO, ONE) values (14,56.965);

  Insert in VOLA (SRNO, ONE) values (15, null);

  Insert in VOLA (SRNO, ONE) values (16, null);

  I have to remove the NULL values in column 1, the problem is that the position of the NULL values are not fixed, and it can be any position. If all the lines of the columns are null, then throw it away.

  If multiple NULL values are here so I have to do the math as follows to update null with the eigenvalues

  1. If the first line is null then take the 2nd value in row and update it.

  2. If the lines between both is null then take avg of prev and next value not null and refresh it.

  3. If the last value in the column is null, then then take prev and update, in this case last two are null, so I have to take value of prev 14 value line update in

  15th and 16th ranks.

  I want to put this pl/sql logic, somehow, that I thought have loop and counter aapproach and loops through the elements and check and update.

  But always looking for something better before looking to write code. No idea or help will be useful for me.

  I * think * you are looking for something like:

  WITH VOLA (SRNO, ONE)

  AS (select 1,237.94 from all the double union)

  Select 2, union null value double all the

  Select 3,203.565 from all the double union

  Select 4,170.69 from all the double union

  Select 5,113.67 from all the double union

  Select 6,93.6 from all the double union

  Select 7,82.03 from all the double union

  Select 8,66.675 from all the double union

  Select 9,63.59 from all the double union

  Select 10,61.415 from all the double union

  Select 11,60.015 from all the double union

  Select 12,58.235 from all the double union

  Select 13,57.805 from all the double union

  Select 14,56.965 from all the double union

  Choose 15, null of union double all the

  SELECT 16, NULL FROM dual)

  GET_VALUES (SELECT SRNO, ONE ACE,

  , LAST_VALUE (WE IGNORE NULLS) (ORDER BY SRNO CSA ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) AS PREVIOUS_VALUE

  , first_VALUE (ONE IGNORE NULLS) over (ORDER OF SRNO CSA ROWS BETWEEN 1 SUITE AND FOLLOWS without TERMINALS) AS NEXT_VALUE

  FROM VOLA)

  SELECT SRNO, ONE, CASE

  WHEN IT IS NOT NULL, THEN WE

  OTHER CASES

  WHEN PREVIOUS_VALUE IS NOT NULL AND IS NOT NULL THEN (PREVIOUS_VALUE + NEXT_VALUE) NEXT_VALUE / 2

  WHEN THE PREVIOUS_VALUE IS NOT NULL, THEN PREVIOUS_VALUE

  WHEN THE NEXT_VALUE IS NOT NULL, THEN NEXT_VALUE

  END

  END AS NEW_VALUE

  OF GET_VALUES

  /

  HTH