Referring to the value of previous years

Hello

I have a calculation where I refer to the previous value. Using the function @prior is the prior value within this year there. But it does not work for next year, that is, the Member is not get calculated for next year. So I wrote a rule like that. Please post if this is the right way to do it, or is there another way. My period dimension consists of 52 weeks, rolling up to months, that roll up to quarters, then half the year, then the year.

Mnpr_Available_L1_L2
(IF (@ISMBR (& CurrFiscalYr))
(@PRIOR ("Mnpr_Available_L1_L2") + @PRIOR ("Attr forced/Mov Out (see the Sub-)" ")) +"Go-Live ";
ELSE IF (@ISMBR (& NextFiscalYr) AND @ISMBR (Wk1))
(& CurrFiscalYr-> Wk52-> 'Mnpr_Available_L1_L2' + & CurrFiscalYr->-> Wk52 "Attr forced / Out Mov (see the Sub-) '") + "Go-Live";
ELSE IF (@ISMBR (& NextFiscalYr) AND NOT @ISMBR (Wk1))
(@PRIOR ("Mnpr_Available_L1_L2") + @PRIOR ("Attr forced/Mov Out (see the Sub-)" ")) +"Go-Live ";
ENDIF ;)

Kind regards
Brig.

I advise you to separate datacopy piece in another fix. Your script copy data unnecessarily 52 times.

FIXMnpr_Available_L1_L2)
DATACOPY & CurrFiscalYr-> Wk52 to & NextFiscalYr-> begbalance;
ENDFIX

DIFFICULTY (& CurrFiscalYr, "Attr forced/Mov Out (see the Sub-)" ")
DATACOPY & CurrFiscalYr-> Wk52 to & NextFiscalYr-> begbalance;
ENDFIX

I think that, after copying the balance opening balance, you can use straight @prior without any specific conditions on the first month.

See you soon,.
Alp

Tags: Business Intelligence

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Insert into SAL (EXP_TYPE,EXP_DATE,"EXP_AMT") values ('Rent',to_date('04-APR-10','DD-MON-RR'),84.89);
Insert into SAL (EXP_TYPE,EXP_DATE,"EXP_AMT") values ('Rent',to_date('01-MAY-10','DD-MON-RR'),84.89);
Insert into SAL (EXP_TYPE,EXP_DATE,"EXP_AMT") values ('Salary',to_date('01-MAY-10','DD-MON-RR'),514.46);
    Any suggestions on how we can calculate the increase in % at run time?


    Thank you
    Ryan

    Hello

    ryansun wrote:
    Thank you Al, Frank!

    I am struggling with the math a bit part. Or maybe % increase is not the correct term. So what I want is the increase in rent and wages in terms of % over the previous year. Thus, for example the output below.

    The salary in 2012 is 8280
    The salary in 2011 is 4999

    so 8280-4999 = 3281

    3281 is 65.6% of 4999.

    The increase last year was 65.6% compared to the last years value while the output of two sqls 165,6%

    Right, Al and I assumed you wanted the percent of last year, not the percentages of increase... Subtract 100 if you want the percentage increase.

  • Find the stock quantity of the previous year with another way...

    Hello
    I have a table with the following structure:
    create table stock_qties_items
    
(subinv varchar2(10),item_code varchar2(10),period_name varchar2(5), qty_a number(5,2), qty_b number(5,2));
    
alter table stock_qties_items
    
add constraint stock_qties_items_pk primary key(subinv,item_code,period_name);
    and some data...
    insert into stock_qties_items
    
values('01','410010010','01-08',10.50,0);
    
insert into stock_qties_items
    
values('01','410010010','02-08',19.30,10.35);
    
insert into stock_qties_items
    
values('01','410010010','03-08',3,0);
    
insert into stock_qties_items
    
values('02','410010010','03-08',8.54,1.90);
    
insert into stock_qties_items
    
values('03','410010010','03-08',120.45,1.25);
    
insert into stock_qties_items
    
values('03','410010010','04-08',502.10,6.50);
    
insert into stock_qties_items
    
values('03','410010010','05-08',5.05,6.20);
    
insert into stock_qties_items
    
values('03','410010010','08-08',19.35,65.90);
    
insert into stock_qties_items
    
values('02','410010010','10-08',40.85,5.20);
    
insert into stock_qties_items
    
values('03','410010010','12-08',75.20,90.15);
    
insert into stock_qties_items
    
values('02','410010020','12-08',60.55,0.85);
    
insert into stock_qties_items
    
values('01','410010020','07-08',100.90,10.05);
    
insert into stock_qties_items
    
values('01','410010010','01-09',8.95,0.05);
    
insert into stock_qties_items
    
values('02','410010010','01-09',88.95,100.05);
    
insert into stock_qties_items
    
values('03','410010020','01-09',91.05,0.05);
    
insert into stock_qties_items
    
values('04','410010020','01-09',11.75,10.05);
    
insert into stock_qties_items
    
values('04','410010010','03-09',1.75,110.40);
    
insert into stock_qties_items
    
values('04','410010010','05-09',0.75,10.40);
    
insert into stock_qties_items
    
values('04','410010025','03-09',1.75,90.00);
    
insert into stock_qties_items
    
values('04','410010025','07-09',51.75,190.00);
    
insert into stock_qties_items
    
values('04','410010010','09-09',62.15,10.05);
    
insert into stock_qties_items
    
values('04','410010010','10-09',39.15,0);
    The goal is to find the stock for the current year and previous year. I have accomplished with the following...
    select period_year,
    
           item_code,
    
           sqi1 stock_prev_year,
    
           sum(stock_curr_year) stock_curr_year
    
    from
    
    (
    
    select  to_char(to_date(substr(period_name,4,2),'RRRR'),'RRRR') period_year,
    
         item_code,
    
      (select sum(qty_a+qty_b)
    
              from stock_qties_items sq
    
              where sq.item_code=sqi.item_code
    
             and to_char(to_date(to_number(substr(sqi.period_name,4,2)-1),'RRRR'),'RRRR')=
    
                    to_char(to_date(substr(sq.period_name,4,2),'RRRR'),'RRRR')
    
         ) sqi1,
    
         qty_a+qty_b stock_curr_year
    
     from stock_qties_items sqi
    
     )
    
     group by period_year,
    
           item_code,
    
           sqi1
    which generates the following output...
    PERIOD_YEAR ITEM_CODE  STOCK_PREV_YEAR STOCK_CURR_YEAR
    
----------- ---------- --------------- ---------------
    
2008        410010020                           172,35
    
2009        410010010           991,79          432,65
    
2008        410010010                           991,79
    
2009        410010025                            333,5
    
2009        410010020           172,35           112,9
    Y at - it another way to achieve the same result, given that this table has a few million records and in this request a few other tables parameter should be added...?

    Note: I use Db 10 g v.2
    Thank you
    SIM

    Using the LAG function:

    SQL> with t as (
  2  select to_char(to_date(substr(period_name,4,2),'RRRR'),'RRRR') period_year,
  3  ITEM_CODE, sum(qty_a+qty_b) STOCK
  4  from stock_qties_items
  5  group by to_char(to_date(substr(period_name,4,2),'RRRR'),'RRRR'), ITEM_CODE
  6  )
  7  select period_year, ITEM_CODE,
  8  lag(stock) over (partition by ITEM_CODE order by period_year) stock_prev_year,
  9  stock stock_curr_year
 10  from t
 11  order by item_code, period_year;

PERI ITEM_CODE  STOCK_PREV_YEAR STOCK_CURR_YEAR
---- ---------- --------------- ---------------
2008 410010010                           991,79
2009 410010010           991,79          432,65
2008 410010020                           172,35
2009 410010020           172,35           112,9
2009 410010025                            333,5

    Max
    [My Italian oracle Blog | http://oracleitalia.wordpress.com/2010/01/30/compilazione-condizionale-in-plsql/]

  • incremensum under condition (condition is the value of the sum of the previous line)

    Hello
    I know that is a little tricky but I need to know the credit of a client after each invoice.
    so if sum(invoice_val-previous_credit) > 0, then the credit is 0 credit else is previous_credit-invoice_val.
    As you can see to dermine the credit value of the current row, it is necessary to check the value of the previous row. Is it possible to somehow?

    E.G.
    If the situation in the table is the following:
    ID_CLIENT     ID_invoice     invoice_VAL
8.789     220.227     120,47
8.789     238.342     109,76
8.789     246.388     121,69
8.789     258.163     137,45
8.789     268.969     138,67
8.789     295.455     145,16
8.789     311.395     138,92
8.789     327.104     138,96
8.789     340.793     -335,18
8.789     375.451     129,14
8.789     386.650     125,57
8.789     398.606     124,18
8.789     428.166     31,66
8.789     435.844     25,93
8.789     447.639     34,32
8.789     462.137     -43,64
8.789     475.613     -110,39
8.789     485.022     92,29
8.789     495.807     91,67
    I need something like this:
    ID_CLIENT     ID_invoice     invoice_VAL credit
8.789     220.227     120,47     0,00
8.789     238.342     109,76     0,00
8.789     246.388     121,69     0,00
8.789     258.163     137,45     0,00
8.789     268.969     138,67     0,00
8.789     295.455     145,16     0,00
8.789     311.395     138,92     0,00
8.789     327.104     138,96     0,00
8.789     340.793     -335,18     335,18
8.789     375.451     129,14     206,04
8.789     386.650     125,57     80,47
8.789     398.606     124,18     0,00
8.789     428.166     31,66     0,00
8.789     435.844     25,93     0,00
8.789     447.639     34,32     0,00
8.789     462.137     -43,64     43,64
8.789     475.613     -110,39     154,03
8.789     485.022     92,29     61,74
8.789     495.807     91,67     0,00
    Thank you very much

    Published by: 4ndr34 on January 28, 2010 13:38

    Hello

    4ndr34 wrote:
    Thanks, but the model is not available in oracle9 :(

    Are - that you mentioned before?
    It's a good idea to include your version number whenever you ask a question, especially if the version is as old as Oracle 9.

    Here's an analytical solution that must work at Oracle 9 (and more):

    WITH     e     AS
(
     SELECT     hiredate
     ,     CASE
               WHEN  job     IN ('PRESIDENT', 'SALESMAN')
               THEN  -sal
               ELSE  sal
          END     AS sal2
     ,     ROW_NUMBER () OVER ( ORDER BY  hiredate
                               ,            empno
                       ) AS rnum
     FROM     scott.emp
)
,     got_grp_start     AS
(
     SELECT     h.*
     ,     CASE
               WHEN  sal2 >= 0
               THEN  0
               WHEN  EXISTS ( SELECT    NULL
                                 FROM      e   l
                           JOIN      e   m     ON     m.rnum     >= l.rnum
                           WHERE     l.rnum     < h.rnum + 0     -- See note below
                           AND      m.rnum     < h.rnum + 0     -- See note below
                           GROUP BY      l.rnum
                           HAVING      SUM (m.sal2) < 0
                         )
               THEN  0
               ELSE  1
          END          AS grp_start
     FROM     e     h
)
,     got_grp          AS
(
     SELECT     got_grp_start.*
     ,     SUM (grp_start) OVER (ORDER BY rnum)     AS grp
     FROM     got_grp_start
)
SELECT     hiredate
,     sal2
,     GREATEST ( SUM (-sal2) OVER ( PARTITION BY  grp
                                        ORDER BY         rnum
                        )
           , 0
           )     AS credit
FROM     got_grp
ORDER BY     rnum
;

    The EXISTS subquery in got_grp_start does not work (at least in Oracle 10.2.0.3.0 or 11.1.0.6.0) if it refers to "h.rnum", but it does if it refers to "h.rnum + 0" or "h.rnum - 0". ".

    The sole purpose of subquery e is to produce a useful set of raw data, including a simple expression (rnum) that can be used in sorting. You probably have something like e, according to your actual table.

    If you need a separate calculation for, say, all the departments, and then add PARTITION BY analytical clauses.

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