REGEXP: Count the number of commas before a given tank
Hi guys,.I was wondering if this is possible? I want to count the number of commas ',' before a given string.
For example:
Let's say I have this string:
SELECT 'Hello',
dump('Hello {The ')
FROM dual;
Which returns:'HELLO' DUMP('HELLO{THE')
------------------ -----------------------------------
Hello Typ=96 Len=11: 72,101,108,108,111,32,123,84,104,101,32
I was wondering if it is possible to count all commas before the 123 tank? In this example, it should return 6Can anyone help?
Thank you
Something more in this sense then...
SQL> ed
Wrote file afiedt.buf
1 with t as (select dump('Hello {The ') as dmp from dual)
2 --
3 select length(regexp_replace(regexp_substr(dmp,'[^ ]+,123',1,1),'[^,]')) as str
4* from t
SQL> /
STR
----------
6
SQL>
Tags: Database
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