REGEXP_REPLACE remove the comma in double quotes

Similar Questions

• REGEXP_REPLACE remove the start and end quotes.

  Hello guys,.

  I have a problem with my regular expression and I hope someone can help me with this?

  Imagine the following sample_data:

  {code}

  WITH sample_data AS

  (

  SELECT "'[email protected] "' double UNION ALL e

  SELECT "'[email protected] ' double UNION ALL e

  SELECT ' [email protected] "' double UNION ALL e

  SELECT "'[email protected] "' double UNION ALL e

  SELECT ' [email protected] "' double UNION ALL e

  SELECT "'[email protected] ' like e dual FROM

  )

  SELECT e, REGEXP_REPLACE (e, '(^'')? (. *) (''$)', '\2')

  OF sample_data;

  {code}

  I would like to remove all the quotes of beginning and end of the email. I made previous regexp, but she does not return the correct result. I know not why, but for some reason, when my email ends with a quote, the main quotation is not deleted.

  Can someone help me with this?

  Thank you

  Another solution...

  WITH sample_data AS
           (SELECT '''[email protected]''' AS e FROM DUAL
            UNION ALL
            SELECT '''[email protected]' AS e FROM DUAL
            UNION ALL
            SELECT '[email protected]''' AS e FROM DUAL
            UNION ALL
            SELECT '''[email protected]''''' AS e FROM DUAL
            UNION ALL
            SELECT '[email protected]''' AS e FROM DUAL
            UNION ALL
            SELECT '''''[email protected]' AS e FROM DUAL)
  SELECT e, REGEXP_REPLACE (e, '(^''+)|(''+$)')
    FROM sample_data
  

• Regular expression, replace all commas between double quotes ONLY

  Hello

  I want to remove all commas between double quotes:

  I tried under model, but it does not replace all if we have more than one comma in double quotes.

  SELECT REGEXP_REPLACE (123, "45.6" Hello, "John, Mike, Marc", 456, "-Anne, Anna"', ' "([^"]*),([^"]*)" ', '"\1;\2" ', 1, 0) suite

  FROM DUAL;

  Result

  --------------------------------------------------------------------------

  123, '45; 6"," Hello, "John, Mike;" "Marc", 456, "Anne-; Anna.

  the first comma between 'John, Mike; Marc"is not replaced...

  Recursion can do if you insist on the SQL solution

  with

  correct (INP, orig, CNT, res, Step) as

  (select str,

  substr(STR,2),

  -case when substr (str, 1, 1) = ""' then 1 else 0 end,

  substr (STR, 1, 1),

  1

  of (select 123, '45.6,' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value' ' str of union double all the)

  Select "123456789" across double Union

  Select ' ""' of all the double union

  Select "" 123,456,789"" Union double all the

  Choose 123, '45.6,' Hello, ' John, Mike, Marc ", 456, 'Ann-Marie, Anna', 'unique value' ' double str

  )

  Union of all the

  Select the inp

  substr(orig,2),

  CNT + case when substr (orig, 1, 1) = ""' then 1 else 0 end,

  RES | cases where substr (orig, 1, 1) = ','

  so to case when mod(cnt,2) = 1

  then ' ~'

  else «»

  end

  of another substr (orig, 1, 1)

  end,

  Step + 1

  Rectifier

  where orig is not null

  )

  Select the inp, res

  Rectifier

  where the orig is null

  INP	RES
  ""	""
  123456789	123456789
  "123456789".	"123 ~ 456 ~ 789".
  123, '45.6' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value '.	"123," "45 ~ 6 ', Hello," John ~ Mike ~ Marc ", 456," Anne-~ Anna ',' single_value '.
  123, '45.6' Hello, ' John, Mike, Marc ", 456,"Ann-Marie, Anna","unique value ".	"123," "45 ~ 6 ', Hello," John ~ Mike ~ ~ ~ Marc ', 456,' Anne-Marie ~ Anna "," unique value ".

  Concerning

  Etbin

• How to remove the comma in 65 321...

  Hello

  I want to remove the commas of the variables.

  for example,.

  Str = 65 321

  herein, I need to remove the comma. My str therefore 65321. y at - it any accumulation of functions...

  Thanks in advance,

  Sathya N.

  stringwithoutcommas = stringwithcommas.split(",").join("");

• Remove the comma (,) of chain

  Hello friends,
  
  I have a string something of this nature
  
  Sting: ", 3456, 45454, 45454,"
  
  Need to have just the values separated by commas: '3456,45454,45454'
  Tried with replace, but go to-'34564545445454'
  
  Select Replace (ltrim (RTRIM (replace (', 3456, 45454, 45454,', ',', ','), ',')), ",", ") twice;
  
  
  
  Appreciate your help.
  
  
  Thank you/Kumar

  Almost there but your exterior replacement remove all commas. What you need is

  select ltrim(RTRIM(replace(',3456,45454,,45454,', ',,', ','),','),',') from dual;
  

  Replace it replaces all double commas with a single comma, then RTRIM strips off the commas from the end of the string and the LTRIM removes any comma out of the beginning of the string. Unfortunately this does not always work if you have more than two consecutive commas in your channel. In order to replace two or more commas with a single comma, you will need to use regexp_replace.

• Remove the comma from parting with something else in a file download

  I have a file which gets downloaded and then read and inserted into the database. The problem is when I read below records that should be of 3 indices, it breaks the index with the file delimited by commas in 5 index.

  «"", "", "Wonderful expanded s Cape, with 4/5 bedrooms 2 full wait. Eik, Lr, Grand Place, news»

  How can I replace the comma in the file once downloaded and use that delimiter in my ListToArray.

  < cfloop index = list "ind" = "" #readlistings # "delimiters =" #chr (13) ##chr (10) #">"
  < cfset i = ListToArray (ind, ",", true) / >
  < cfoutput >
  #i [4] #.
  < br > < br >
  < / cfoutput >

  < / cfloop >

  To recover the data of embedded quotes, you can use the following URL by passing your conataining the commas as the argument string.

  http://www.cflib.org/UDF/CSVtoArray

• Remove the commas (-) of numbers entered by the user in a field

  Hello world

  How can I filter the commas of a number entered by a user into a text input field? I'm doing calculations with these numbers entered, but if the user enters a comma, I get "NaN" (not a number) as the result of what the user has entered.

  I could prevent the user to enter commas in fields (I'm already restriciting enter letters and periods), but it would be nice if the user can always use commas.

  the code I have so far is:

          q4input = q4_mc.q4_ans.text;     
       q4_preCalc = (Number(q4input)*1000);     
       trace(q4_preCalc);

  Thanks in advance for your help.

  Rafael.

  Try:

  q4input = q4_mc.q4_ans.text.replace (",", "");

• remove the string in double paragraph

  Hi, I wandered if someone had the best way to search for a string and delete the repeated subsections.

  For example, the input string may look like:

  T2, T2, T3, T6

  but I want to delete one of the T2 repeated, so the output would be:

  T2, T3, T6

  Note that the input string can be any length and a multiple of 4. I went through all the string functions and find nothing to match what I'm asking. I tried to use "String subset" in a wired loop in an output table.

  Any help in the right direction would be appreciated!

  Here's a handy dandy little tool that does just that.  The strings must be delimited by commas.  It is in LV2009.  If you do not, save the file and send it to the thread Downconvert VI ask.

• Have a rocket w / 8 gb 8 GB; What is the best way to remove the mp3s in double...

  I looked through some 50 pages and did not find the answer.

  I have a 8 GB Fuze w / additional removable 8 GB.  By mistake I put a few same songs on both discs.  What is the best way to remove these and if I do not remove them, she also ruin added playlists?

  Thank you

  Connect it to your computer, set up 2 separate workstation boxes, one to an intern to exteranal and scroll down... delete the dupes of one of the disks and problem solved

  Edit: I forgot you questions about playlists of pesky things I barely use. Those that you might have to re-do.

• How to get the comma in the number format?

  Hi all

  I have a requirement to obtain a number with commas.

  I achieved this goal using the converter. (< groupingUsed = "true" integerOnly = "true" minFractionDigits af:convertNumber = '2' maxFractionDigits = "2" / >)
  My textbox is limited to 5, if I give the number like 12345 then it appears in the form 12,345.00 (which is expected)

  I want to change the same number from 5 to 6. so if I remove the number 5, the comma is also taking as a character and not allowing me do not enter 6 in the end.

  If I remove the comma, then only it is allowed me to type 12346.

  I tried to delete the comma using javascript using the function that is called from clientListener below.

  < af:clientListener method = "removeComma" type = 'focus' / >
  function removeComma (evt) {}
  var currentValue = document.getElementById('r2:1:it8::content').value;
  var currentValue.replace = newValue (/ a, / g, ");
  document.getElementById('r2:1:it8::content').value = newValue;
  }

  Using this script comma was deleted at the time of change, but after changing the number and press ENTER key so I get no comma.

  I wrote this code in pagefragment and my version of jdev is 11.1.2.4.0.

  Help, please.

  Kind regards

  Shakur.

  Try to remove maximumLength = "5" inputText and use af:validateLength as:

• remove the decimal of an equation to send to a payment gateway

  I have a value currently shows a decimal number

  @$amount = $_POST ["amount"];

  I need the decimal to show until the $amount variable is sent to the payment gateway

  What is the best way to remove the comma from the variable

  so an example value

  250.59

  will be sent as 25059

  Thank you

  Replace the decimal "." with nothing else using str_replace().

  $amount = str_replace(".","",$amount);

  best,

  Shocker

• Double quotes in vars sub

  The following comand strives to define a substitution variable that keeps the double quotes.
  
  change the FinRptg.FinRptg database variable value CurFcstYr1 ' '2011 "";
  
  If the variable is "2011".
  
  What I want to do is the same thing, but using a variable. However, when I use the command:
  
  change the database to the CurFcstYr1 the FinRptg.FinRptg value variable ""$3 ";
  
  The variable is set to "$3".
  
  Is there a way I can set the variable substitution using the variable I pass in the MaxL script and have the double quotes. The reason why I'm doing this is because the report script that uses the subvar must double quotes, or he does not see the year.
  
  Thank you.

  Reading of:- Re: Maxl variable def with quotes
  It should give you the answer on how to do it.

  See you soon

  John
  http://John-Goodwin.blogspot.com/

• Remove the decimal point

  Hi all
  I want a query to remove the decimal point in a number.
  That is to say) 3.21 = 321
  .21 = 21
  1 = 1
  76.667 = 76667
  
  In all this I just want to remove the comma preceding.
  Please help me to write the query
  
  Thank you
  JO

  TO_NUMBER (Replace(3.21,'.'))

  Kind regards
  Florian...

• How to remove the character within a text.

  How to remove the character within a text.
  If I have a text like: "[4, 5, 6, 3, 9]" How can I remove the commas?
  Thank you
  and Merry Christmas.

  A possible technique would be to use a repetition structure that loop until all of the commas are removed:

  on mouseUp me
   
  theString = '[4, 5, 6, 3, 9].
   
  Repeat while theString contains «,»
  thePos = offset ("," rope)
  delete theString.char [thePos]
  end repeat
   
  put the rope
   
  end mouseUp

  However, this probably isn't the most effective technique if you are dealing with very long strings.

  If you use the JavaScript syntax, you can strip characters with a regular expression.

• remove the double quotes in a value

  DB version: 10g / 11g
  
  Table customer_address
  column: adresse_rue
  data in the example: 'MLK 1234 drive '.
  'dr North 150, st #600'
  'o Henry 15678 dr.
  
  Update: reader of MLK 1234
  150 north dr, st #600
  Dr. Henry o 15678
  
  I'm looking to remove the double quotes (""), if this is the first and the last character.
  
  It would be nice to get these lines with values begins and ends with double-quotes
  
  
  Thank you for your time
  
  Published by: nydba on March 22, 2012 09:02

  One way:

  with a as (select '"1234 MLK drive"' x from dual
             union select '5678 JFK drive' from dual)
  select a.*,substr(x,2,length(x)-2) from a
  where x like '"%"';
  
  X                SUBSTR(X,2,LENGTH(X)-2)
  ---------------- -----------------------
  "1234 MLK drive" 1234 MLK drive        
  

  There is probably a more efficient way with regular expressions.