Regular expression in oracle for hyphen

Similar Questions

• Validation using regular expressions or oracle fn

  Hello

  I want to apply validation to a column. I'm trying to see if I can use the regexp_replace function to find a boss and see if I can replace it to a better format. Can someone help me with these rules?

  1. only the characters a - z, A - Z, 0-9, ', - is allowed. If there are no other characters, then these characters must be removed.

  2. name should not begin with a symbol.

  3. If there is any symbol permitted in the name, (for example the hyphen) then the hyphen should be preceded and followed by a space.

  I would like to know if the above can be obtained by regular expressions or any other function will be useful to achieve the same.

  
  Thank you very much

  Cherkaoui

  HI, Charan,

  Whenever you have a problem, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) of all the tables involved, so that people who want to help you can recreate the problem and test their ideas.

  Also post the exact results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.  Post in this case, maybe 5 or 10 strings, and what you would like to see (a string corrected, or a 'yes' / 'No' flag saying if this string follows rules.)

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

  2784427 wrote:

  Hello

  I want to apply validation to a column. I'm trying to see if I can use the regexp_replace function to find a boss and see if I can replace it to a better format. Can someone help me with these rules?

  1. only the characters a - z, A - Z, 0-9, ', - is allowed. If there are no other characters, then these characters must be removed.

  2. name should not begin with a symbol.

  3. If there is any symbol permitted in the name, (for example the hyphen) then the hyphen should be preceded and followed by a space.

  I would like to know if the above can be obtained by regular expressions or any other function will be useful to achieve the same.

  Thank you very much

  Cherkaoui

  Sorry, we don't know what you want to do.

  1 seems to mean you want to change the given string so that it follows the rules.  (What exactly are special characters?  Are there only 2 special characters: single quotation mark and hyphen?)

  2 seems to tell us that you want to check if it meets the rules

  3. can be a

  I'll assume that you want to modify the string so that the returned value corresponds to rules.  This means that if the given string violates, 2 symbols will be removed from the beginning of the string, and if it violates 3, then spaces will be added.

  I don't think that there is a way to do this with a regular expression.

  You can make each with a separate REGEXP_REPLACE corrections, and make all in the same query by one nesting inside each other, like this:

  SELECT REGEXP_REPLACE (REGEXP_REPLACE (REGEXP_REPLACE (: str)))

  , "[^ a-zA-Z0-9 cm-]"

  )

  , '^[''-]+'

  )

  , ' *([''-]) *'

  , ' \1 '

  ) AS new_str

  OF the double

  ;

  of course, I can't test it, until post you some sample data and the exact results you want from these data.

  Here, the inner REGEXP_REPLACE rule 1 applies.  It deletes all characters except a to z small letters, capital letters A to Z, numbers, spaces, single quotes and hyphens.

  Rule 2 applies the REGEXP_REPLACE middle.  It removes the single quotes and hyphens that appear at the beginning of the string.

  The external REGEXP_REPLACE rule 3.  It guarantees that each single quotation mark or a hyphen is preceded and followed by a space.  If there is already a space (or several spaces) before and/or after the special symbol, they are replaced by a single space.  If this isn't what you want, it can be fixed, but it will make the expression even messier.

  You might consider to write a user-defined function to normalize strings.  In a function procedure, you can apply the rules one after the other. you need not nesting complicated like that.  Of course, a user-defined function will be slower, but maybe it's not a problem.

  Still, the above query converts the string so that the production rules.

  If you just want to check whether a string conforms to the rules, you can compare the original string to the output of the above expression.  If they are identical, then the string is in accordance with the rules.

• Use matching of regular expressions to search for parentheses

  Hi all

  I am currently looking for a particular pattern in a string, I can't display the exact string, but say its something like that.        corresponds to regular_pattern (5000): 0

  I'm also looking for the a different model at the same time, so I have to use the corresponding regular expression and the | function.  I can't understand how to match this model because the regular expression function allows parentheses unless I put them in the legs, and that does not help me for this.

  Any advice?

  Thank you

  Matt

  Have you tried to escape the bracket?

  

• Regular expressions in JavaScript for CP5?

  I can't have a regular expression in JavaScript window. First, CP 5 supports regular expressions?

  I'll answer my first question. Yes, he does. For a code example, see:

  http://www.Infosemantics.com.au/Adobe-Captivate-advanced-eLearning-tutorials/report-custom - Captivate-scorm-variables-with-javascript

• without using regular expressions in oracle 9i

  Hello all;
  
  I have the following below test data
  

    insert into p
        (id)
      values
        ('\G1\G2');  
    insert into p
        (id)
      values
        ('\A1\');
     insert into p
        (id)
      values
        ('\B1\B2\B3');
         insert into p
        (id)
      values
        ('\J1\J2\J3\J4');

  and this is the output I want however
  

  ID
  G1
  null
  B2
  J3

  the result is obtained by looking at the second to the last entry and extract...
  
  so for \G1\G2, the second to the last entry was G1, therefore, we have G1
  for \A1\ there is no second of the last entry and that is why it is null
  for \B1\B2\B3 the second to the last entry is B2

  user13328581 wrote:

  for \A1\ there is no second of the last entry and that is why it is null

  The entries are separated by------, right? Then id = \A1\ has two inputs A1 and NULL. I'll assume id = \A1. Then:

  with t as (
             select '\G1\G2' id from dual union all
             select '\A1' from dual union all
             select '\B1\B2\B3' from dual union all
             select '\J1\J2\J3\J4' from dual
            )
  -- end of on-the-fly data sample
  select  substr(id,instr(id,'\',-1,2) + 1,instr(id,'\',-1,1) - instr(id,'\',-1,2) - 1) id
    from  t
  /
  
  ID
  ------------
  G1
  
  B2
  J3
  
  SQL> 
  

  SY.

• regular expression to search for records with only numbers

  Hello
  
  I need a query to find only numebers. My collar is of type varchar and has values such as
  col1
  --------------------------
  1234456789
  madh144reddy
  123end
  end123
  
  I need ouput as only numbers EG
  o/p should be
  1234456789
  
  REGEXP_LIKE (col1, ' [[: digit :]]');]])

  Hello, sorry misunderstood, try:

  WITH test_tab AS (
  SELECT '1234456789' col1 FROM DUAL UNION ALL
  SELECT 'madh144reddy' FROM DUAL UNION ALL
  SELECT '123end' FROM DUAL UNION ALL
  SELECT 'end123' FROM DUAL)
  -- end test data
  SELECT *
    FROM test_tab
   WHERE REGEXP_LIKE(col1,'^[[:digit:]]+$');
  
  COL1
  ------------
  1234456789
  

• Indexing on search for regular expression for dynamic model

  Hi all
  
  Is it not possible to create an index for the regular expression search (REGEXP_LIKE) for the model 'dynamic '?
  
  If the model is static, we can create FBI, but is it possible for dynamic diagrams? Please notify.
  
  Kind regards
  Hari

  N °
  The best option is an Oracle text index.
  http://download.Oracle.com/docs/CD/E11882_01/text.112/e16594/TOC.htm

• The regular expression.

  Hello all, I need to learn the normal Oracle database expression. Peut
  anyones tell me where to find information - good sites that give the secrets ;)
  I already look but like some tips. Lydie

  James wrote:
  Hello all, I need to learn the normal Oracle database expression. Peut
  anyones tell me where to find information - good sites that give the secrets ;)
  I already look but like some tips. Lydie

  Hey James,.

  I've been watching this recently myself and I have a little
  my favorite sites. Appreciate the subtleties of the Regex - with any
  luck, you won't even have to learn any PL/SQL ;)

  Good introdution
  http://www.zytrax.com/tech/web/regex.htm
  
  Simple summary of Oracle's regular expressions
  http://www.regular-expressions.info/oracle.html
  
  Not forgetting the Wiki (contains table with vi
  equivalents - for those of us who use a real editor ;)
  http://en.wikipedia.org/wiki/Regular_expression
  
  This site should be one of your main ports of call for any Oracle issues.
  Good forums also - better software than Oracle themselves.
  http://www.orafaq.com/node/2404
  
  Morgan's Library - used to be psoug.org - don't know what happened - anyone?
  Daniel posts here from time to time
  http://www.morganslibrary.org/reference/regexp.html
  
  And,not forgetting the Oracle docco.
  http://docs.oracle.com/cd/B19306_01/appdev.102/b14251/adfns_regexp.htm
  http://docs.oracle.com/cd/B12037_01/appdev.101/b10795/adfns_re.htm
  Also look on OTN for a .pdf for introduction.
  

  HTH,

  Paul...

• Multiline - Regular Expression Match string

  I'm trying to understand the format of a regular expression to pull select off multi-line string lines and fill in these lines as the individual elements of an array of strings using regular expressions to Match. The total length of the multiline string may vary as well as the text in the string. The string can contain letters, numbers and special characters. I've attached an example VI. In the example of VI, I want to only return lines starting by "device #" in the table. The number of lines starting by "device #" can vary, but I want to capture them all.

  Or is there a better functioning to be used instead of the corresponding regular Expression that will give me the desired result?

  aaronb wrote:

  I'm trying to understand the format of a regular expression to pull select off multi-line string lines and fill in these lines as the individual elements of an array of strings using regular expressions to Match. The total length of the multiline string may vary as well as the text in the string. The string can contain letters, numbers and special characters. I've attached an example VI. In the example of VI, I want to only return lines starting by "device #" in the table. The number of lines starting by "device #" can vary, but I want to capture them all.

  Or is there a better functioning to be used instead of the corresponding regular Expression that will give me the desired result?

  Corresponding regular expression works well for this.

  

  Ben64

• Complex regular expressions without multiple passes

  Does anyone know of a tool that can handle more complex regular expressions without chaining of multiple copies of the VI regular expressions?

  For example, if I have a XML string as

  Power supply error has occurred.

  Sorensen SGA166/188

  and I am interested in the tag method to retry only, I could write a regular expression something like

  .*.*

  to parse the string inside the tag.

  kc64 wrote:

  For example, if I have a string like

  My email address is [email protected].  Please no spamming not me.

  and I am interested in the domain name of the email only address, I could write a regular expression something like

  @(\w)*\. (com: net | org)

  to parse the string 'gmail '.

  Forgive me if I am away from base, but I'm flying blind at the moment (not LV to test what I say).  You can add to the power of a regular expression using submatches or capture groups.  The regular expression you wrote will grab (I think) @gmail.com for the entire game.  Let's say you want to get 'gmail' without a second function call.  You can do the first group of a little dishonest selection by moving the * inside the parentheses.  Then, on the BD pull down on the bottom of the function of regular expression matching to expose a variable number of submatches (both should be in this case).  The first should be 'gmail '.   The second one should be "com."

  In summary, @(\w*)\.) (com: net | org) should give you gmail in the first submatch.  Of course, my Perl is a little rusty and LV cannot apply in the same way.

• Changeparticular the characters of a string using regular expressions...

  Hi all
  I'm writing a function using the function of expression regular oracles REGEXP_REPLACE but I could not succeed until now.
  
  My problem is as follows, I have a text in a column say "Scott Sdfdfs Sdfd" I want to replace all the s and S with X characters and make the text looks like "XdfXdf XdfdfX Xdfd".
  
  It is possible by using regular expressions in oracle?
  Can you give me some clue?
  
  Thank you

  select
    regexp_replace('sdfsdf Sdfdfs Sdfd',
                   's|S', 'X') Replaced
  from dual;
  

  REPLACED
  ------------------
  XdfXdf XdfdfX Xdfd 
  

• Oracle regular expressions - splits the string into words for

  Hello

  Nice day!

  My requirement is to split the string into words.

  So I need to identify the new line character and the semicolon (;), comma and space like terminator for string entry.

  Please note that I am currently embedded blank and the comma as separator, as shown below.

  Select regexp_substr('test)
  TO
  string in words, "([^, [: blanc:]] +) (', 1, 1) double;"

  How to integrate the semicolons and line break characters in regular expression Oracle?

  Please notify.

  Thanks and greetings

  Sree

  This has nothing to do with REGEXP. Is SQL * more parser does not not a semicolon at the end of the line:

  SQL > select ' testto, mm\;
  ERROR:
  ORA-01756: city not properly finished chain

  SQL >

  Just break the chain:

  SQL > select regexp_substr ('testto, mm\;' |) '
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<= regexp_count('testto,mm\;'="" ||="">
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;' |') STRINGIN
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  Or modify SQL * more the character of endpoints:

  SQL > set sqlterm.
  SQL > select regexp_substr ('testto, mm\;)
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<=>
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;) STRINGINTOWO
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  SY.

• Looking for a good tesxtbook / and or Web site that explains regular expressions

  I need a manual, for about 70 euros or less, which includes an explanation of regular expressions. I picked up a few things from the text of Steve O'Hearn ora 1z0-047 and ora-docs and articles online, but I want to expand a little bit.

  Also if anyone know a good site that may have a little thorough but easy to read (think intermediate user even though I'm not sure I consider myself even that) promenade walk through regular expressions, please see it me.

  Thank you very much.

  Hello

  If you insist on the books, then:

  https://www.safaribooksonline.com/library/view/Oracle-regular-expressions/0596006012/

  http://www.ktipsntricks.com/data/eBooks/Oracle/Oracle%20regular%20expressions.PDF

  Greetings,

  SIM

• regular expressions for numbers demical in a comma-delimited list

  
  I have a table that lists the details of the occupation of the sites of a comma-delimited list:

  create table tenure_test)
  number of site_number
  tenure_detail varchar2 (255));

  insert into tenure_test values (1, ' Crown (Other) (0.15 ha), private (555.25 ha)');
  insert into tenure_test values (2, ' private (5.76 ha)');
  insert into tenure_test values (3, ' private (0.18 ha, Crown (3.25 hectares), Indeterminate (Leased) (5.85 ha)');)

  What I want to do is to use a regular expression to calculate the sum only numbers in the tenure_detail column.

  For example, for site_number 1, it would be 0.15 + 555.25 = 555,4

  I also have another regular expression that has just the numbers in a comma-delimited list.

  For site_number 1: 0.15, 555.25

  I tried this:

  Select site_number, tenure_detail, regexp_substr (tenure_detail, "[0-9] + \.") ([0-9] {2}') under the name test1

  of tenure_test;

  but it lists only the first number.

  Hello

  996454 wrote:

  I have a table that lists the details of the occupation of the sites of a comma-delimited list:

  create table tenure_test)
  number of site_number
  tenure_detail varchar2 (255));

  insert into tenure_test values (1, ' Crown (Other) (0.15 ha), private (555.25 ha)');
  insert into tenure_test values (2, ' private (5.76 ha)');
  insert into tenure_test values (3, ' private (0.18 ha, Crown (3.25 hectares), Indeterminate (Leased) (5.85 ha)');)

  What I want to do is to use a regular expression to calculate the sum only numbers in the tenure_detail column.

  For example, for site_number 1, it would be 0.15 + 555.25 = 555,4

  I also have another regular expression that has just the numbers in a comma-delimited list.

  For site_number 1: 0.15, 555.25

  I tried this:

  Select site_number, tenure_detail, regexp_substr (tenure_detail, "[0-9] + \.") ([0-9] {2}') under the name test1

  of tenure_test;

  but it lists only the first number.

  Here's one way:

  SELECT site_number

  SUM (TO_NUMBER (REGEXP_SUBSTR (tenure_detail

  , "\d+\.\d*" - see Note 1

  ) T

  LEVEL

  )

  )

  ), Total

  OF tenure_test

  CONNECT BY LEVEL<= regexp_count="" (="">

  , '\d+\.\d*'

  )

  AND PRIOR site_number = site_number

  AND PRIOR SYS_GUID () IS NOT NULL

  GROUP BY site_number

  ;

  Output:

  TOTAL OF SITE_NUMBER

  ----------- ----------

  1 555,4

  2 5.76

  3 9.28

  Note 1: what exactly makes a 'number '?  I'm assuming it's 1 or more digits, followed by a comma, followed by 0 or more numbers.  You can have a slightly different definition; in this case, change the arguments 2nd REGEXP_SUBSTR and REGEXP_COUNT.

  I guess also that site_number is unique.  If not, you will have to change the CONNECT BY and GROUP BY clauses, to refer to something (or a combination of things) which is unique.

  Relational databases are designed for each column of each row contain 1 single piece of information, not a list delimited with a variable number of elements.  It is so basic to the design of database he called the first normal form.  If your first followed table form normal, this query (and many other queries that involve that table) would be much simpler to write, more efficient to run and less likely to have bugs.  See if you can normalize this table.  Any effort that you have to spend now to normalize the table will pay very quickly.

  Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.

  Don't forget to tell what version of Oracle you are using.  I tried the query in Oracle 11.2 above.  You may need to CONNECT BY a little differently in earlier versions, and REGEXP_COUNT will not work in Oracle 10.

• Regular expression for invalid number

  Hello world

  I use version oracle as follows:

  SQL > select * from v version $;

  BANNER
  ----------------------------------------------------------------
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - production
  PL/SQL Release 10.2.0.4.0 - Production
  CORE 10.2.0.4.0 Production
  AMT for 32-bit Windows: release 10.2.0.4.0 - Production
  NLSRTL Version 10.2.0.4.0 - Production

  ------------------------------------------------------------------------

  I use a regular expression to replace invalid values in a table.

  I got oracle error 'ORA-01722 invalid number '.

  My query looks like this:

  SELECT DISTINCT

  MRC_KEY,

  PURPOSE_CD,

  RESIDENCE_DESC,

  TO_NUMBER (regexp_replace (ICAP_GEN_MADAPTIVE, "..?")) 0? 0? (\d+) [-.] ((?', '\1')) as ICAP_GEN_MADAPTIVE,

  Of

  MRRC_INT

  I don't know what are invalid values in the table, so I can write regexp accordingly.

  Any guidance is appreciated!

  Thanks in advance

  J

  Hello

  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.  View of the code which is not what you want can be useful, but there niot enough by itself.
  See the FAQ forum: https://forums.oracle.com/message/9362002

  Let's look at what you do:

  REGEXP_REPLACE (icap_gen_madaptive

  , '[+. ]' || -exactly 1 of these characters

  '?0?0?' || -up to 2 ' 0 '

  '(\d+)' || -some numbers (it comes to \1)

  '[-.]?'    -0 or 1 of these characters

  , '\1'

  )

  Is it really what you want?  A group of figures don't match, as the patten must start with a sign more, a point or a space.  You want to allow a decimal point at the beginning and at the end, as in "." 9. '?  If there are numbers before and after the decimal point, as in "1.2", you want only the digints before the comma?  You never said what you want, but I'm guessing that these are things that you don't want.

  If the pattern is found, this changes only the schema, so a string like "FU + 123 BAR" more than the model + 9 "" changed to "9" and the resulting string. "" "" FU9BAR"would be passed TO_NUMBER.

  If the pattern is not found, as in "FOO", nothing is changed, and the entire string is passed to TO_NUMBER.

  I suspect you want to use instead of REGEXP_REPLACE REGEXP_SUBSTR, or, if there is stuff to ignore before and/or after the number you want to include in the model, so that REGEXP_REPLACE will be replaced by nothing.

  This looks like a good argument to use the NUMBER of columns to store numbers.