Regular expressions and phone number

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• Help with the Regular Expressions and regexp_replace

  Oh great guru Oracle can I can receive assistance
  
  I need to clean the phone numbers that have been entered in the table per_phones of Oracle e-Business. Some of the phone numbers have hyphens, some have spaces and some have tank. I just want to get out all the figures and then re - format the number.
  
  E.g.
  914-123-1234... out (914) 123-1234
  9141231234... new (914) 123-1234
  914 123 1234... (914) 123-1234
  MyPhone... just null
  (914)-123-1234... (914) 123-1234
  
  I really tried to understand the instructions of regular expressions, but for some reason, I can't understand it.

  For example:

  SQL> with sample_data as (
    2   select '914-123-1234' phone_number from dual union all
    3   select '9141231234'                from dual union all
    4   select '914 123 1234'              from dual union all
    5   select '(914)-123-1234'            from dual
    6  )
    7  select regexp_replace(
    8           regexp_replace(phone_number, '\D')
    9         , '(...)(...)(....)'
   10         , '(\1) \2-\3'
   11         ) as formatted_num
   12  from sample_data
   13  ;
  
  FORMATTED_NUM
  --------------------------------------------------------------------------------
  (914) 123-1234
  (914) 123-1234
  (914) 123-1234
  (914) 123-1234
   
  

• Regular expression for invalid number

  Hello world

  I use version oracle as follows:

  SQL > select * from v version $;

  BANNER
  ----------------------------------------------------------------
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - production
  PL/SQL Release 10.2.0.4.0 - Production
  CORE 10.2.0.4.0 Production
  AMT for 32-bit Windows: release 10.2.0.4.0 - Production
  NLSRTL Version 10.2.0.4.0 - Production

  ------------------------------------------------------------------------

  I use a regular expression to replace invalid values in a table.

  I got oracle error 'ORA-01722 invalid number '.

  My query looks like this:

  SELECT DISTINCT

  MRC_KEY,

  PURPOSE_CD,

  RESIDENCE_DESC,

  TO_NUMBER (regexp_replace (ICAP_GEN_MADAPTIVE, "..?")) 0? 0? (\d+) [-.] ((?', '\1')) as ICAP_GEN_MADAPTIVE,

  Of

  MRRC_INT

  I don't know what are invalid values in the table, so I can write regexp accordingly.

  Any guidance is appreciated!

  Thanks in advance

  J

  Hello

  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.  View of the code which is not what you want can be useful, but there niot enough by itself.
  See the FAQ forum: https://forums.oracle.com/message/9362002

  Let's look at what you do:

  REGEXP_REPLACE (icap_gen_madaptive

  , '[+. ]' || -exactly 1 of these characters

  '?0?0?' || -up to 2 ' 0 '

  '(\d+)' || -some numbers (it comes to \1)

  '[-.]?'    -0 or 1 of these characters

  , '\1'

  )

  Is it really what you want?  A group of figures don't match, as the patten must start with a sign more, a point or a space.  You want to allow a decimal point at the beginning and at the end, as in "." 9. '?  If there are numbers before and after the decimal point, as in "1.2", you want only the digints before the comma?  You never said what you want, but I'm guessing that these are things that you don't want.

  If the pattern is found, this changes only the schema, so a string like "FU + 123 BAR" more than the model + 9 "" changed to "9" and the resulting string. "" "" FU9BAR"would be passed TO_NUMBER.

  If the pattern is not found, as in "FOO", nothing is changed, and the entire string is passed to TO_NUMBER.

  I suspect you want to use instead of REGEXP_REPLACE REGEXP_SUBSTR, or, if there is stuff to ignore before and/or after the number you want to include in the model, so that REGEXP_REPLACE will be replaced by nothing.

  This looks like a good argument to use the NUMBER of columns to store numbers.

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  Thank you!

  Thank you, Jeff. That's what I was looking for. BUT my version of LabVIEW 8.5, does NOT say "functionfor example, the Match model does not support the parenthesis or vertical bars (|) characters.«» !

  See: http://zone.ni.com/reference/en-XX/help/371361D-01/glang/match_pattern/

  and http://zone.ni.com/reference/en-XX/help/371361D-01/glang/match_regular_expression/

  It is not mentioned in the help of special characters used for the match pattern : http://zone.ni.com/reference/en-XX/help/371361D-01/lvhowto/specialcharformatchpatt/

  The only place | has 'talked', it is in the sentence: "some regular expressions that use alternating (such as (. |))". \s)*) require significant resources to deal with when it is applied to the large input strings. "But I'm not processing a large chain.

  It seems that NEITHER fixed this omission. What version is your help?

  Ed

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• The Regular Expressions and GUID.

  Hello gurus, I hope you can help me!
  I need to select GUID from a table and to do this, I need the regular Expression. My
  Perl is not good and not good Regular Expression. My database is Oralce 11.2.0.2.0 and
  Linux (Oracle Version 6) is the operating system of the Machine. If you need further information,
  I'll look closely. Thank you. Jehangir.

  >

  Hi Jehangir and welcome to the forums.

  I need to select the GUID of a table and to do this,

  Well, the first thing we do is read the forum FAQ and also the post by BluShadow
  at the top of the messages on the home page of the forum. You should have provided code (DDL
  and DML) showing your particular problem, but since it's your first time, I'll be gentle ;)

  We have it done - clients have sometimes GUID as PKs, and we need to send data to
  their systems, but it is not as simple as it may first appear.

  GUID may arise in three formats.

  The Oracle one - SELECT Sys_GUID() from DUAL which is just a string of 32 hexadecimal characters.
  Then the chain with the hyphen, then the string with dashes and {} at the beginning and end (see
  examples of data).

  with datax as
  (
    SELECT '79A864CCD8E44CD8B0A2765DF9EF337B' as guid  FROM DUAL  UNION ALL
    SELECT '79A864CFD8E44CD7B0A2765DF9EF337B' FROM DUAL UNION ALL
    SELECT '8gdfsgsgfdg' FROM DUAL UNION ALL  -- dummy for testing
    SELECT '21EC2020-3AEA-1069-A2DD-08002B30309D' FROM DUAL UNION ALL
    SELECT '21EC5550-3AEA-1069-A2FF-08002B30309D' FROM DUAL UNION All
    SELECT '{21CC2020-3AFA-1A69-A2DD-08002B30309D}' FROM DUAL
  )
  
  -- first one is the Oracle format
  select * from datax where regexp_like(guid, '[0-9a-fA-F]{32}'); -- Oracle select sys_guid();
  
  -- second one is with hyphens
  
  select * from datax where regexp_like(guid, '[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}');
  
  -- third one is with hyphens and curly brackets.
  
  select * from datax where regexp_like(guid, '^\{[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}\}$');
  
  -- This converts both of the last two formats back into Oracle format, which is what
  -- we use. Notice, that I haven't used regualar expressions to do this. Regexes are
  -- computationally expensive, and you should use Oracle's string furnctions if possible
  
  SELECT REPLACE(REPLACE(REPLACE(GUID, '{', ''), '}', ''), '-', '')  FROM Datax;
  

  HTH,

  Paul...

  Jehangir.

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• Need help on the regular expressions and query

  Hi guru s, I hope that you all made great!
  
  I have a scenario where I need to insert data into the table.
  
  I have three scenarios:
  

  select 'Kodali,Raj,S' str from dual
  union 
  select 'Alex Romano' from dual
  union 
  select 'ppppp' from dual
  
  Alex Romano
  Kodali,Raj,S
  ppppp

  What I want is now.
  
  1 Alex Romano
  is there space between the chain and then I want to insert in the last name and first name columns
  2 Xavier, Raj, S
  If there is a comma between the chain and I want to insert in the last name, first name and middle name
  3. If there is one channel then insert even in first name and last name.
  
  I wrote the request more early to manage only by commas and now I'm trying but not able to use this all scenarios
  Can you please help me.
  

  WITH t AS (
   
  select 'Kodali,Raj,S' str from dual
  union 
  select 'Alex Romano' from dual
  union 
  select 'ppppp' from dual
  
  ) 
  select DECODE(trim(a),NULL,'a',trim(a)),DECODE(trim(b),NULL,'b',trim(b)),decode(trim(c),NULL,'c' ,trim(c)) 
  from 
   (
    SELECT max(decode(level,1,regexp_substr(str,'[^,]+',1,level))) a --INTO lFNAME
            , max(decode(level,2,regexp_substr(str,'[^,]+',1,level))) b --INTO lLNAME
            , max(decode(level,3,regexp_substr(str,'[^,]+',1,level))) c --INTO lMNAME       
     FROM   t
    CONNECT BY regexp_substr(str,'[^,]+',1,level) IS NOT NULL
    GROUP BY str
  ) ;

  Currently I put a b and c if its null value.
  
  
  Thanks in advance!

  Hello
  You can do what you asked for in pure SQL like this:

  WITH     got_pos          AS
  (
       SELECT     str
       ,     INSTR (str, ',')     AS comma_pos
       ,     INSTR (str, ' ')     AS space_pos
       FROM     t
  )
  SELECT    str
  ,       CASE
             WHEN  comma_pos > 0
             THEN  REGEXP_SUBSTR (str, '\w+', 1, 2)
             WHEN  space_pos > 0
             THEN  SUBSTR (str, 1, space_pos - 1)
             ELSE  str
         END     AS fname
  ,       CASE
            WHEN  comma_pos > 0
            THEN  REGEXP_SUBSTR (str, '\w+', 1, 3)
            ELSE  TRIM (REGEXP_SUBSTR (str, ' \w+ '))
         END     AS mname
  ,       CASE
             WHEN  comma_pos > 0
             THEN  SUBSTR (str, 1, comma_pos - 1)
             ELSE  REGEXP_SUBSTR (str, '\w+$')
         END     AS lname
  FROM       got_pos
  ORDER BY  str
  ;
  

  But look how it is difficult, even for this simple example of data.

  I suggest you write a PL/SQL function to analyze the name. It will be much easier to deal with a combination of spaces and commas, the names of more than 3 words, etc.

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• Mask a number with regular expressions

  Hi @ll!
  
  Is it possible to hide a given number
  
  of "12345678" in "XXXX5678".
  or '987458' to 'XX7458 '.
  
  with Regular Expressions and without substr()? To display only the last four digits and the 'X' value for the rest. The size of the number is not always the same.

  Alex, I think the OP wanted the first 4 characters to hide ;)

  Something like that?

  select translate(substr('12345678',1,length('12345678')-4),'1234567890','XXXXXXXXXX')
                  || substr('12345678',length('12345678')-3)
            from dual
  /
  TRANSLAT
  --------
  XXXX5678
  

  More

  with test_data as
  (
  select '12345678' card_no from dual
  union all select '123456' from dual
  union all select '5678900' from dual
  ) -- End of test data
  select translate(substr(card_no,1,length(card_no)-4),'1234567890','XXXXXXXXXX') ||
            substr(card_no,length(card_no)-3)
      from test_data
  /
  
  TRANSLATE(SUBSTR
  ----------------
  XXXX5678
  XX3456
  XXX8900
  

  Arun-