Remove all commas in a string

I have a company name which can contain commas in one or more positions. I need to replace the comma with a space.

Example:

DOM, s travel and Dom, s Express

Need to read

S travel and DOM. DOM s Express

Thank you

Paul

> I need to replace the comma with a space.

Tags: Database

Similar Questions

Remove all occurrences of the string in the string

Hello.
We have a problem with the change of all occurrences of a string in string.
We know how to do the hard, but what would be the easiest?
We have a string like:
2014/00212, 2014/12312, 2013/23443 2014/20156
or simply as
2014/00212
or there may be several occurrences of substring in the form xxxx/xxxxxx.
How can we change channel:
14/00212, 14/12312, 13/23443 14/20156
Thank you.

If I understand you want to replace every 20 at the beginning of each part of the entire string.

The rooms are separated by a comma and consecutive space. He also begins with this separation.

The part of the year is separated by a slash from the rest of the part

Select

regexp_replace (' 2014/00212, 2014/12312, 2013/23443, 2014/20156 ')

', 20'

,'\1'

) r

of the double

R

", 14/00212, 14/12312, 13/23443 14/20156.

or simply

Select

Replace (' 2014/00212, 2014/12312, 2013/23443, 2014/20156 ')

', 20'

,', '

) r

of the double

R

", 14/00212, 14/12312, 13/23443 14/20156.

How to remove several commas in a string
Hello friends,

I have a string like "Myriam, pqrstu, prquste.

Need to convert to a seperated string comma as "pqrstu, Fund, Myriam, prquste.

I used RTRIM ('Myriam, pqrstu, Fund, prquste, ',' '), but commas between the chain is not deleted but only on the right side of the string

Select RTRIM ('Myriam, pqrstu, Fund, prquste,', ') twice;

I hold in a single select statement.

Please advice.

Thank you/Kumar
In the query, you answered, there is still a comma at the end of the chain...

Yes, because you wrote:

Need to convert to a seperated string comma as "pqrstu, Fund, Myriam, prquste.

in your original question. There is comma at the end, so my example.

However, you already fixed it ;)

Don't forget that my example will not work for more than 2 of the comma.
You may need to resort to the solution of Frank, but there is a risk of a loss of performance, based on the amount of data and your hardware.

Remove the comma (,) of chain
Hello friends,

I have a string something of this nature

Sting: ", 3456, 45454, 45454,"

Need to have just the values separated by commas: '3456,45454,45454'
Tried with replace, but go to-'34564545445454'

Select Replace (ltrim (RTRIM (replace (', 3456, 45454, 45454,', ',', ','), ',')), ",", ") twice;

Appreciate your help.

Thank you/Kumar
Almost there but your exterior replacement remove all commas. What you need is
```
select ltrim(RTRIM(replace(',3456,45454,,45454,', ',,', ','),','),',') from dual;
```
Replace it replaces all double commas with a single comma, then RTRIM strips off the commas from the end of the string and the LTRIM removes any comma out of the beginning of the string. Unfortunately this does not always work if you have more than two consecutive commas in your channel. In order to replace two or more commas with a single comma, you will need to use regexp_replace.

Regular expression, replace all commas between double quotes ONLY

Hello

I want to remove all commas between double quotes:

I tried under model, but it does not replace all if we have more than one comma in double quotes.

SELECT REGEXP_REPLACE (123, "45.6" Hello, "John, Mike, Marc", 456, "-Anne, Anna"', ' "([^"]*),([^"]*)" ', '"\1;\2" ', 1, 0) suite

FROM DUAL;

Result

--------------------------------------------------------------------------

123, '45; 6"," Hello, "John, Mike;" "Marc", 456, "Anne-; Anna.

the first comma between 'John, Mike; Marc"is not replaced...

Recursion can do if you insist on the SQL solution

with

correct (INP, orig, CNT, res, Step) as

(select str,

substr(STR,2),

-case when substr (str, 1, 1) = ""' then 1 else 0 end,

substr (STR, 1, 1),

of (select 123, '45.6,' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value' ' str of union double all the)

Select "123456789" across double Union

Select ' ""' of all the double union

Select "" 123,456,789"" Union double all the

Choose 123, '45.6,' Hello, ' John, Mike, Marc ", 456, 'Ann-Marie, Anna', 'unique value' ' double str

)

Union of all the

Select the inp

substr(orig,2),

CNT + case when substr (orig, 1, 1) = ""' then 1 else 0 end,

RES | cases where substr (orig, 1, 1) = ','

so to case when mod(cnt,2) = 1

then ' ~'

else «»

end

of another substr (orig, 1, 1)

end,

Step + 1

Rectifier

where orig is not null

)

Select the inp, res

Rectifier

where the orig is null

INP	RES
""	""
123456789	123456789
"123456789".	"123 ~ 456 ~ 789".
123, '45.6' Hello, ' John, Mike, Marc ", 456, '-Anne, Anna', 'single_value '.	"123," "45 ~ 6 ', Hello," John ~ Mike ~ Marc ", 456," Anne-~ Anna ',' single_value '.
123, '45.6' Hello, ' John, Mike, Marc ", 456,"Ann-Marie, Anna","unique value ".	"123," "45 ~ 6 ', Hello," John ~ Mike ~ ~ ~ Marc ', 456,' Anne-Marie ~ Anna "," unique value ".

Concerning

Etbin

REGEXP_REPLACE remove the comma in double quotes

Hello
I am trying to remove the comma of a string in double quotes, currently I can only remove a comma using under sql
SELECT REGEXP_REPLACE (' "" A, B, C, def "', '(") ([^ "|,"] +) (,) ([^ ""] +) ("") ',' \1\2 \4\5' ') FROM DUAL;
output: 'A B, C, def'
But I need the form "A B C def".

Hello

Jarkko Turpeinen wrote:

... I think that I stop to answer here, because I don't understand of course questions

Very understandable. If my assumption is correct, the question would be much clearer if OP gave an example that included a few commas inside the quotation marks and some outside, as in the example below.

Here's a way to implement what I have described in the answer #2 above:

VARIABLE input_txt VARCHAR2 (100)

EXEC: input_txt: = 1, '2', ' A, B, C, def ", 3" foo, bar '4 ';

WITH got_parts AS

(

SELECT LEVEL AS part_num

, REGEXP_SUBSTR (: input_txt)

, '[^"]*("|$)'

1

LEVEL

) AS part_txt

OF the double

CONNECT BY LEVEL<= 1="" +="" regexp_count="" (="">

, '"'

)

)

SELECT LISTAGG (CASE

WHEN MOD (part_num, 2) = 0

THEN REPLACE (part_txt, ',')

Of OTHER part_txt

END

) Within AS output_txt GROUP (ORDER BY part_num)

OF got_parts

;

Help Removeing all the commas of the results table.

Good afternoon al,.
I'm pretty new on Oracle SQL developer and need a little help to find the best way to replace all commas in a table of results with ' > '.
I run a select statement:
SELECT
WHERECLAUSEVALUE
Of
FDM_SAB. TDATAMAP
ORDER BY WHERECLAUSEVALUE ASC
To produce a very simple table with 1 column. (see bleow):
*
*
*
*
00000,50000
00000,50000
00000,50000
00000,50000
00000,50000
00000,50000
As you can see some of the results contains a comma then a space, I'm looking to replace the "," (comma and space) with ' > ' (greater-than sign in). I guess this is done at a point with the function replace but have had no luck so far.
Any help would be greatly appreciated. Thank you very much

Charlie
P.S. I'm new to this forum and this is my first post here; I apologize if my question is not clear or I don't give enough information.

Replace (columnname, ',' > ')

Should work for you.

If this isn't the case, please post what you've tried and show the results you get.

htmlText remove all line breaks
In my program, a user can enter any type of text using a RichTextEditor. The entered text has all its illegal xml characters replaced (< with & lt ;) etc.) This string is placed in an xml document. A component is custom, then receives the xml document, converts the html code in its original form and the applicable as the htmlText of a property control of text. This used to work properly. I need string conversions because there are some "metaStrings" which is not replaced according to certain criteria... which is the string {$DATE} would get replaced by the effective date when loading at a later date. As I said, used to work, and I had no problem display of text exactly as the user who created it. Now, for some reason, when I set the htmlText property, all line breaks are removed, of any type. < here > < /li > < li > for fleas. Remains of formatting, has increased the font size, color, etc., but there is no line breaks.

I have my chiseled loading code and the following output:

public static void loadHtmlText(textControl:Text,_textData:XML,_replaceMeta:Boolean_=_false):void
{
trace ("loading text html in a text component, loading", textData);
var html:String = textData.Html.toString ();
trace ("after parsing a string", html);
If (replaceMeta)
{
trace ('replacing');
HTML = html.replace(/\{\$DATE\}/,textData.Date);
Add sequences additional meta here for replacement
}
trace ("after the replacement", html);
textControl.htmlText = html;

textControl.validateNow (); force a commit
trace ("value that was set', textControl.htmlText");
}

and the following output:

text html in a text component loading, loading
< data >
< html > & lt; TEXTFORMAT LEADING = "2" & gt; & lt; P ALIGN = "LEFT" & gt; & lt; FONT FACE = "listFont" SIZE = "10" COLOR = "#0B333C" LETTERSPACING = "0" KERNING "0" = & gt; Line 1 & lt; / FONT & gt; & lt; /P & gt; & lt; / TEXTFORMAT & gt; & lt; TEXTFORMAT LEADING = "2" & gt; & lt; P ALIGN = "LEFT" & gt; & lt; FONT FACE = "listFont" SIZE = "10" COLOR = "#0B333C" LETTERSPACING = "0" KERNING "0" = & gt; Line 2 & lt; / FONT & gt; & lt; /P & gt; & lt; / TEXTFORMAT & gt; & lt; TEXTFORMAT LEADING = "2" & gt; & lt; P ALIGN = "LEFT" & gt; & lt; FONT FACE = "listFont" SIZE = "10" COLOR = "#0B333C" LETTERSPACING = "0" KERNING "0" = & gt; Line 3 & lt; / FONT & gt; & lt; /P & gt; & lt; / TEXTFORMAT & gt; < / Html >
NotSet < date > < / Date >
< / data >

after parsing a string
< TEXTFORMAT LEADING '2' = > line 1 < / POLICE > < / TEXTFORMAT > < TEXTFORMAT LEADING '2' = > line 2 < / FONTS > < / TEXTFORMAT > < TEXTFORMAT LEADING = "2" > < FONTS FACE = "listFont" SIZE = "10" COLOR = "#0B333C" LETTERSPACING = '0' KERNING '0' = > line 3 < / POLICE > < / TEXTFORMAT >

After replacing
< TEXTFORMAT LEADING '2' = > line 1 < / POLICE > < / TEXTFORMAT > < TEXTFORMAT LEADING '2' = > line 2 < / FONTS > < / TEXTFORMAT > < TEXTFORMAT LEADING = "2" > < FONTS FACE = "listFont" SIZE = "10" COLOR = "#0B333C" LETTERSPACING = '0' KERNING '0' = > line 3 < / POLICE > < / TEXTFORMAT >
set < TEXTFORMAT LEADING = "2" > line 1Line, 2Line 3 < / POLICE > < / TEXTFORMAT >

Uh, oops, all the strings wordwrapped, makes it impossible to read. There were three blocks adopted in
each of them said line 1 line 2 and line 3, respectively, and each of them must be on its own line.

After forcing the validation of the text control after setting this string, it has that one tag with all the text inside... 2Line 1Line line 3.

Any ideas?

It worked before, I did was move the parameter text in its own function, insead of a function called by the method of my custom component's data provider.

Thanks for the help.
Wow, almost three months later, when my work schedule allows me actually to take over this problem, and I have the solution :-). It turns out, I don't know why, or if same Adobe knows about the bug, but if you have fonts using style sheets for all controls on your application, that is, I have a style statement request where I placed the police then redering text html of the text control is bug, usually just remove all line breaks. Why, I have no idea, he is simply. However, the same bug does not occur in the TextArea component. Still, I don't know why, seems silly to me, but as the solution to this problem, simply create a component TextArea, backgroundAlpha styles set to 0, its borderStyle to 'none', set the editable to false and boom, you have a component of scrolling text, which doesn't render the text html incorrectly.

Removes all characters except numbers

Hi all
I want to reformat to following phone numbers. As you can see it in what follows, I want to delete all characters except numbers and it does not start wirh 0 0 at the beginning of the f-number. And the length is 11. What do you recommend?
(543) 456-35-50 = > 05434563550
(555) 555-55-55 = > 05555555555
(210) 111-11 / 11 = > 02101111111
Thank you

Hello

3018678 wrote:

Hi all

I want to reformat to following phone numbers. As you can see it in what follows, I want to delete all characters except numbers and it does not start wirh 0 0 at the beginning of the f-number. And the length is 11. What do you recommend?

(543) 456-35-50-online 05434563550

(555) 555-55-55-online 05555555555

111-11 / 11 (210)-online 02101111111

Thank you

To remove all characters except the 10 digits, you can use REGEXP_REPLACE

REGEXP_REPLACE (str, '\D')

To put a "0" at the beginning of the string (if it isn't already begin with a '0'), you can use REGEXP_REPLACE even once:

REGEXP_REPLACE (REGEXP_REPLACE (str, '\D')

, '^([^0])'

, "0\1".

)

I don't think that there is a way to do both things wih a single integrated function call.

There is a requirement on the length being 11? What happens if that comes into conflict with one of the other requirements? For example, if the string is already long of 11 characters, but does not begin with a '0', do you want to add a "0", which makes 12 characters? What happens if the length, after removing the numbers no, is very small, say 1? (You can use LPAD adds however many ' 0 s you need.) If the length (after removing the numbers) is 12 or more? What happens if the string does not contain any what numbers at all?

If these things are questions, then post CREATE TABLE and INSERT statements for some examples of data, accurate results, you want that data, and explanations.

Check out the Forum FAQ: Re: 2. How can I ask a question on the forums?

remove all punctuation - only letters and numbers

Hello
How can I remove all the punctuation marks . As a result, only the letters and numbers stand ?

Example:
Chain before: "§ 67778 / % & $45-§§ 5FCGZZ-GZGUU(=&/+%/&%E$Dfcfhzb+++zvb).
String that follows: 67778455fcgzzgzguuedfcfhzbzvb
My Code so far:
REPLACE)
REPLACE)
REPLACE)
REPLACE)
REPLACE)
TRANSLATE)
LOWER (TRIM (DESIGNATION))
, '@-.', '@' )
, ' ', '')
, ' ', '')
, '', '')
, '-', '')
CHR (10), ")
Thank you for your help in advance

2890953 wrote:

How can I remove all signs of punctuation. Thus, only letters and numbers stand?

Example:

Chain before: "§%67778/%&45$$---§§$5FCGZZ-GZGUU (=&/+%/&%E$Dfcfhzb+++zvb.

String that follows: 67778455fcgzzgzguuedfcfhzbzvb

My Code so far:

REPLACE)

REPLACE)

REPLACE)

REPLACE)

REPLACE)

TRANSLATE)

LOWER (TRIM (DESIGNATION))

, '@-.', '@' )

, ' ', '')

, ' ', '')

, '', '')

, '-', '')

CHR (10), ")

In Oracle 10 and above, use regular expressions:

SQL > select

2 regexp_replace ("' §%67778/%&45$$---§§$5FCGZZ-GZGUU (=&/+%/&%E$ Dfcfhzb +++ zvb ',' [^ [: alnum:]]') s '")

3 of

4 double;

S

-----------------------------------

§6777845§§5FCGZZGZGUUEDfcfhzbzvb

How use Bridge to rename the batch to remove all characters after the 32nd character?

I would like to batch rename to remove all characters after the 32nd character. Is this possible?

Substitution string use with use of regular expressions is selected.

In the use of the search field
```
^(.{32})(.*)
```
In the field using replace
```
$1
```

"Remove all" snapshots causing startup problems. How to manually compile snapshots?

Hey guys,.
We run our production and test servers ESXi 3.5 with great success. However, like many others, we have struggling to find a good economic backup solution if we use a Perl script edited by for this. The script applies a snapshot and then copying the original files for the guests. In the end, the script removes the snapshot, and we're back in business. Most of the time, everything works perfectly. This morning, we arrived to find the extremely slow server with about 10 snapshots. Not realizing exactly what "remove all" done in terms of balooning, the size of the previous snapshots, we chose this selection. The Server shut down (I guess due to the increase in the size of the previous snapshots) and when we tried to restart, we encountered the error that you see in the attachment.
Look a bit more close to the data store, it seems that most of the snapshots for virtual disk 1 have been removed, but it has been left over. The other virtual disks 2-4 were intact. The server does not start and if I return to the .vmdks that are available, I've lost two weeks of a data value. Is it possible to manually apply the changes in snapshots to the .vmdks so that we can keep as many changes as possible on the 2-4 drives?
Thank you
Seth

OK - now I would use vmkfstools to each of the 4 drives clone.

the first is NOMADSERV01_1 - 000009.vmdk
```
 vmkfstools -i NOMADSERV01_1-000009.vmdk /nomadserv-disk1.vmdk
```
next is "NOMADSERV01_2 - 000009.vmdk".
```
  vmkfstools -i NOMADSERV01_2-000009.vmdk /nomadserv-disk2.vmdk
```
before you try, you must correct the snapshot of the string that was spoiled by the basediskalone running.

I think that the first two should work if you use the edited files, I have attached.

Then, two coming soon

___________________________________

VMX-settings- WS FAQ -[MOAcd | http://sanbarrow.com/moa241.html]- VMDK-manual

Remove all listeners - or another solution to the given problem

If the problem is the following:

Say we have a list of items displayed in a ListView. The elements can be made up of a string describing and above all, a list of IDs.

Then we have a group of checkboxes, each associated with a value ID. The check boxes are selected must be determined by the content of the list of the selected item in the ListView.

For example, the elements may be individuals, and IDS can refer to his hobbies or whatever - typical example. If you have a group of predefined leisure displays that you can check if the particular person has them or not.

Therefore, the behavior that we want to:

(1) when the selected item in the ListView is changed, update the boxes to display the ID of this item.

It is trivial. Simply add a listener on the selected ListView item and for each checkbox, set it to enabled if the list contains the corresponding id.

(2) when an any of the boxes is changed by the user, update the list of IDS to the selected ListView item.

This seems to be is not as trivial as it may seem. :)

The first thing I tried was:

Add a listener for invalidation fixed for each of the boxes. In Manager, a list of all ID-checked, and updated list of the current selected ListView with the latter item.

The problem here is him when you select an item in the ListView and behavior in 1) is called, the invalidation handler is called, thus updating list of the selected ListView item again before it has had the opportunity to update all the boxes!

Next thing I tried:

Do not add any fixed listener for the check boxes. (Instead, in 1), remove the check boxes for any listener, to update, and then add a listener that will call the behavior in 2).

The problem here is 'remove every listener of the boxes', given that on Observable removeListener() method takes a specific listener as a parameter - and we have no reference to that. (And the first time, we have not added even.)

So is there a way to tell an Observable, Hey, remove all listeners you have?

Or am I on the wrong track, and it is indeed obvious, another solution to this problem?

I don't see the need to remove the listeners - this seems dirty and a little prone to error.

What follows is doing what you want (I used a ChoiceBox for ease, but adapting to a list would be trivial), or if I'm missing a part of the question?

public class TestApp extends Application
{
    public static void main(String[] args) throws Exception
    {
        launch(args);
    }

    public void start(final Stage stage) throws Exception
    {
        VBox root = new VBox(10);
        root.setStyle("-fx-padding: 10");

        final ChoiceBox personChoiceBox = new ChoiceBox();
        personChoiceBox.getItems().addAll(
                new Person("Zonski", Hobby.coding, Hobby.rockClimbing),
                new Person("Tiny Dancer", Hobby.interpretiveDance),
                new Person("Mr Everything", Hobby.values())
        );
        root.getChildren().add(personChoiceBox);

        final Map hobbyCheckBoxes = new HashMap();
        for (final Hobby hobby : Hobby.values())
        {
            CheckBox checkBox = new CheckBox(hobby.name());
            root.getChildren().add(checkBox);
            hobbyCheckBoxes.put(hobby, checkBox);
            checkBox.selectedProperty().addListener(new ChangeListener()
            {
                public void changed(ObservableValue source, Boolean wasSelected, Boolean isSelected)
                {
                    Person person = personChoiceBox.getSelectionModel().getSelectedItem();
                    if (person != null)
                    {
                        if (isSelected)
                        {
                            if (!person.getHobbies().contains(hobby))
                            {
                                person.getHobbies().add(hobby);
                            }
                        }
                        else
                        {
                            person.getHobbies().remove(hobby);
                        }
                    }
                }
            });
        }

        personChoiceBox.getSelectionModel().selectedItemProperty().addListener(new ChangeListener()
        {
            public void changed(ObservableValue source, Person oldPerson, Person newPerson)
            {
                if (newPerson != null)
                {
                    for (Hobby hobby : hobbyCheckBoxes.keySet())
                    {
                        hobbyCheckBoxes.get(hobby).setSelected(newPerson.getHobbies().contains(hobby));
                    }
                }
                else
                {
                    for (CheckBox checkBox : hobbyCheckBoxes.values())
                    {
                        checkBox.setSelected(false);
                    }
                }
            }
        });

        stage.setScene(new Scene(root, 300, 300));
        stage.show();
    }

    //-------------------------------------------------------------------------

    private enum Hobby
    {
        rockClimbing, coding, interpretiveDance
    }

    private class Person
    {
        private String name;
        private List hobbies;

        private Person(String name, Hobby... hobbies)
        {
            this.name = name;
            this.hobbies = new ArrayList(Arrays.asList(hobbies));
        }

        public String getName()
        {
            return name;
        }

        public List getHobbies()
        {
            return hobbies;
        }

        public String toString()
        {
            return name;
        }
    }
}

Remove all bookmarks in the Document

Anyone happen to know how to delete all guides in a document? I am aware that I can use Ctrl + Alt + G and then press DELETE to remove the guides on a single page or spread, but in the whole document open (all pages at once)? I did research some and located the following script:
myDoc var = app.activeDocument;
If (myDoc.guides.length > 0) {myDoc.guides.everyItem () .remove () ;}
I am sorry to say that this script has not worked for me. This is the error message I received:
Error number: 1025
Error string: due to end of the declaration
Engine: by default
File: C:\Users\...etc.
Line: 1
Source: var myDoc = app.activeDocument;
If anyone knows a way around this or knows how to fix this text please let me know and anyone else that might interest you.

myDoc var = app.activeDocument;

If (myDoc.guides.length > 0) {}

myDoc.guides.everyItem () .remove ();

}

The same as that found like you. Works for me in CS5 Mac. Removes all the guides, including master pages. Just change one of the exisitng javascripts and do a save as to a new name.jsx.

Object - remove all properties

Is it possible to remove all the properties of an object that was created by obj:Object var?
Thank you

Hello
```
for (var name:String in obj)
{
  delete obj[name];
}
```
Mike

Remove all commas in a string

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