Remove the following lines
Hi all
with tbdate as
(
Select 6 March 2013 08:00 ' date1, n1 10 'x 1' oggetto in all double union '.
"Select 6 March 2013 08:10 ', 20 ' x 2' of all the double union
"Select 6 March 2013 08:20 ', 10 ' x 3' of all the double union
"Select 6 March 2013 08:30 ', 20 ' x 4' of all the double union
"Select 6 March 2013 08:40 ', 10 ' x 5' of all the double union
"Select 6 March 2013 08:50 ', 30 ' x 6' of all the double union
"Select 6 March 2013 09:00 ', 10 ' x 7' of all the double union
"Select 6 March 2013 09:10 ', 20 ' x 8' of the double
)
Select a.* tbdate one
How can I remove the lines where the total (date1 + numtodsinterval (n1, "MINUTE")) of the previous line does not match the line or the following lines?
With example maybe I'll be more clear
rank 1 03/06/2013 08:00 10 x 1 Yes
rank 2 03/06/2013 08:10 x 30 2 Yes because more time minutes (n1) of the largest previous = 08:10 equal this line
rank 3 03/06/2013 08:20 10 x 3 not because 08:10 + 30 = 08:40 previous line <>this line
rank 4 03/06/2013 08:30 20 x 4 not because 08:10(rows_2) + 30 = 08:40 of the previous lines (2 lines) <>this line
rank 5 03/06/2013 08:40 10 x 5 Yes
tier 6 03/06/2013 08:50 x 20 6 yes because 08:40 plus 10 = 08:50 from the previous row is this line
tier 7 03/06/2013 09:00 10 x 7 no
tier 8 03/06/2013 09:10 10 x 8 Yes
Thanks in advance
Hello
You build the correct path and connect (and then delete the others):
SQL dts@QUALIF > with tbdate like
() 2
3 select to_date (6 March 2013 08:00 ',' dd/mm/yyyy hh24:mi:ss') date1, n1 10 'x 1' oggetto in all double union '.
4 Select to_date (6 March 2013 08:10 ',' dd/mm/yyyy hh24:mi:ss'), 20, 'x 2' dual union all '.
5 Select to_date (6 March 2013 08:20 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 3' double union all '.
6 select to_date (6 March 2013 08:30 ',' mm/dd/yyyy hh24:mi:ss'), 20 'x 4' double union all '.
7 select to_date (6 March 2013 08:40 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 5' double union all '.
8 select to_date (6 March 2013 08:50 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 6' double union all '.
9 select to_date (6 March 2013 09:00 ',' dd/mm/yyyy hh24:mi:ss'), 10 'x 7' double union all '.
10. Select to_date (6 March 2013 09:10 ',' dd/mm/yyyy hh24:mi:ss'), 20 'x 8' from dual '.
(11), a title)
12. Select b.*, sys_connect_by_path (oggetto, '-') pth, connect_by_root (oggetto) r, prior (oggetto) p
tbdate 13 b
14 connect by date1 = prior date1 + prior n1 / 24 / 60
15 beginning with oggetto = 'x 1') '.
16. Select * from a;
DATE1 N1 OG PTH R P
-------- ---------- -- -------------------------------------------------- -- --
03.06.13 10 x1 -x1 x1
03.06.13 20 x 2 - x 1 - x 2 x 1 x 1
03.06.13 20 x 4 - x 1 - x 2 - x 4 x 1 x 2
03.06.13 20 x 6 - x 1 - x 2 - x 4 - x 6 x 1 x 4
03.06.13 20 x 8 - x 1 - x 2 - x 4 - x 6 - x 8 x 1 x 6
Tags: Database
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