remove the midpoint of the list item (forms 6i)
Dear Sirs, I have list item consists of 10 items and I want to remove the number of article 4 and when I remove it, it's ok delete but show me the runtime with the place empty and I want to removepls tell me how to do
Yasser
Try this
try with Ctrl + Shift + <
Work of hope...
Tags: Oracle Development
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How to remove the list item empty forms of oracle?
Hello
How to remove the list item EMPTY forms of oracle?
I create two list items
(1) basic
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But when I select list or display the runtime display form element 3 element EMPTY automatically, but I add what it shows I want to delete! How?
He has named REQUIRED = NO item property
If you set YES and then it does not show. but you must give an initial value.
Hamid
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I have to disable in the menu toolbar-> topic GIS link by using cutom.pll
in the procedure event custom.pll I called
If event_name = 'WHEN-NEW-FORM-INSTANCE' then
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end if;
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Please give me a solution...
With respect,
MahaHi all
I got a solution using this code I can enable disable the menu and the menu list.
declare
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a MENUITEM;
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Mohan ReddyPublished by: MAHA REDDY on May 17, 2013 12:02 AM
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The list item file (oracle form 6i)
Hi all
I have a problem regarding complete recording in the list item
I have this code works in Oracle 10 g Forms Builder
DECLARE
REPORT NUMBER;
Problem EXCEPTION;
BEGIN
-to fill the
STATUS: = POPULATE_GROUP ('RG_PROD_DESC');
-Make sure that the select statement is executed successfully.
IF <>STATUS 0 THEN
PROBLEM;
ON THE OTHER
-to fill the list item
POPULATE_LIST (' DESCRIPTION ', 'RG_PROD_DESC' ");
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EXCEPTION
Problem WHEN THEN
MESSAGE ("we have a problem to query the table PRODUCT.');
END;
but when I try this code in Oracle Forms 6i, it did not work.
can someone help me in this matter?Try this way. I changed some of the code to test on my system.
DECLARE STATUS NUMBER; Problem EXCEPTION; list_id ITEM; BEGIN list_id :=Find_Item('Blockname.Listname'); -- to populate the group STATUS:=POPULATE_GROUP('RG_PROD_DESC'); -- Check that the select statement was executed successfully. CLEAR_LIST(list_id); POPULATE_LIST(list_id, 'RG_PROD_DESC'); EXCEPTION WHEN others THEN MESSAGE ('We have a problem to query the PRODUCT table.'); END;
Best regards
Franck Giri -
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This free utility that easily.
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How to get the value of the list item?
I have a problem with the list item object
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I am facing a problem with the list item in my form. In my form, I have a list item (tmd_stat) with 3 list of values as the item complete, incomplete and null.this lies in the control block.
I have a block (Detail) which is the database block.status_disp [point List] is one of the .an article on the value of list tmd_stat is filling with different values.
an alert message (you want to change the status? Yes/No) will appear when we change the list item. If I click YES then the list works and retail block point status_disp is filled with a different list of values. If I click on 'No' the list value will be set to changed value.i.e suppose that I'm changing the Complete incomplete list item, alert message will be displayed. If I click on 'No' the cursor is placed on incomplete but incomplete. How can I place the cursor on the full value.
Can you please give me the solution.
Thank youHello
Save the old value in a variable and then if the user clicks on No. then reassign this value to the list item.
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Switch poplist display of the list item selected for its value of list item
Is it possible to change the display in a poplist of the list item to its corresponding list item value?
For example, I have a list item is filled with a group of records. Name of the country (e.g., Canada) is the list item, and the country code (e.g. CA) is the value of a list item.
I want users to be able to see the names of countries, when the list is expanded. However, once users choose and click on a country, the country code must be included in the display.
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With the help of Oracle Developer Suite 10 G
Version of Forms - 9.0.4.3.0Hello
Welcome to the forum,Just an idea. Why you do not keep the country with the description at the time code. I mean, it's like you say you query group will be like this...
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So, I mean just change this query to concatenate the code with description. for ex.
SELECT code, code||' - '||description as description FROM table_name;
It will show you the code and the name in the list. So, it will not trigger etc.
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you want to add data dynamicallly in the list item.
Hello friends...
My data to see & I want to add that the list item data can add that?
Thank you...In this case, your list item can be a data point and then your gave values in the elements in the list property and has set some initial value too, no?
If so,.
Remove all items in the list by pressing ctrl SHIFT<>
Then give any character dummy in the list item and a space in the value that grant list them agenda.
Give the initial value also as space so as to avoid the warning...Now, try
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I would really appreciate it someone could help me.
I created a recordgroup for the list item and filled the same. All values are dispalyed correctly but in addion an empty record is appear. How can I remove the blank record? My syntax are as under:
declare
v_rg NUMBER;
v_GrpID RECORDGROUP;
Start
v_GrpID: = CREATE_GROUP_FROM_QUERY ('DRVCODE', ' SELECT led_name, led_name FROM master_ledger where cmp_code =: global .cmp_code ORDER BY 1');
v_rg: = POPULATE_GROUP (v_GrpID);
IF v_rg = 0 THEN
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END IF;I'm happy for you... Please mark my answer as correct ;-)
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Manutd65 wrote:
The iphone 4S has the function - it can remove the list of phone every 24 hours?
None of the iphone has this feature.
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Tried everything. Nothing works.
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[deleted - / viking] Thought I had it fixed, but apparently not.
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How is this related to Windows Update features, Beverley?
Put the primary address (or your own) in the field then put all others in the BCC field. See http://email.about.com/od/emailnetiquette/a/cc_and_bcc.htm
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I do a simple application, get the content of the list item selected ListView using CPP, in the main.qml file, I created a listview using XMLDataModel and I got the selected listview using dataModel.data (row) .attributeNameInXmlfile in qml. content as in the same way the ListView using cpp.please help me I want to get the content of the listitem selected.
Here is my code
hand. QML
import bb.cascades 1.0 Page { content: Container { id: mainContainer objectName: "container" // property alias selectedText: selectedTextField.text //property alias deselectedText: deselectedTextField.text ListView { objectName: "listView" dataModel: XmlDataModel { source: "models/items.xml" id: model } listItemComponents: [ ListItemComponent { type: "item" StandardListItem { title: ListItemData.title } } ] } TextField { id: selectedTextField objectName: "selectedTextField" text: "" } TextField { id: deselectedTextField objectName: "deselectedTextField" text: "" } } }
App.cpp
#include "app.hpp" #include
#include #include #include #include #include using namespace std; using namespace bb::cascades; QObject *textFieldSelected ; QObject *textFieldNotSelected; QObject *list; App::App() { QmlDocument *qml = QmlDocument::create("main.qml"); AbstractPane *root = qml->createRootNode (); list = root->findChild ("listView"); textFieldNotSelected = root->findChild ("deselectedTextField"); textFieldSelected = root->findChild ("selectedTextField"); QObject::connect(list,SIGNAL(selectionChanged (QVariantList, bool)),this,SLOT(changeText(QVariantList, bool))); Application::setScene(root); } void App::changeText(QVariantList indexPath,bool selected) { } App.HPP
#ifndef APP_H #define APP_H #include
#include #include /*! * @brief Application GUI object */ class App : public QObject { Q_OBJECT public: App(); public slots: void changeText(QVariantList ,bool ); }; #endif // ifndef APP_H Try this.
void App::changeText(QVariantList indexPath,bool selected) { XmlDataModel *model = (XmlDataModel *)list->dataModel(); QVariantMap map = model->data(indexPath).toMap(); // map is your data in QVariant qDebug() << map["title"].toString(); }
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