get a control with a certain name

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  Crisnray1994 said

  Husband hiding accounts email and user name and passwords for online dating sites

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• Try to copy a folder with subfolders, some don't copy, get the message that the folder names are too long under Windows 7

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  a. What are the data you're trying to move?
  b. what operating system (for example Windows files) files?
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  I hope this helps.

  Thank you, and in what concerns:
  Shekhar S - Microsoft technical support.

  Visit our Microsoft answers feedback Forum and let us know what you think.
  If this post can help solve your problem, please click the 'Mark as answer' or 'Useful' at the top of this message. Marking a post as answer, or relatively useful, you help others find the answer more quickly.

• Why I get two files with different names but the same image when I save in 2015 CC Photoshop?

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• Server data store will automatically get updated when the new file (with the same name) is placed in the landing area

  
  Hi guys,.

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• How can you fill ListBox with channel group name dynamically?

  I built a GUI in the 'View' pane that acts as a large table of contents. At the top of the GUI, there is a list box I want to dynamically fill with Group channel names loaded in my data portal (internal data). I can't generate the necessary code to do this. Currently, I use a ListBox control. Can I use an EnumListBox instead?

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  Attached is a screenshot of the GUI I hope it helps.

  Hey Nathan--

  Have we met yet?  Don't think that I will remember to see you post on the forums of tiara so far (or remember you I meet someone named Nathan in person recently).  Welcome to the forums of tiara!

  There are a few things that you need to change about your code snippet-

  1. The reason why you get the error "object required: ' [string: 'filename']' is because the Set command expects that the right side of an expression returns an object (you define your variable to)."  In your case, you return a string (the name of a group), not an object.  Simply remove the Set command.
  
  
  2. The ListBox.Items.Add () method requires two parameters - the first is the text of the item to insert in the list, and the second is a value to assign to this point (you can do single).

  As a result, to more directly match your code snippet to the labour code, follow these steps:

  Dim listNum, names
  We = 1 to GroupCount
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  NEXT

  Note that you can also use object programming oriented with the data object that represents the data portal, it is easier for you to avoid remembering variables such as GroupCount and GroupName DIAdem (that's me):

  Dim listNum
  
  We = 1 to Data.Root.ChannelGroups.Count
  
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  NEXT

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• How can I get the control specifies a reference (by the script)?

  By what method of property can I control that specifies a reference? (See an example of a reference to the code snippet).

  

  When I reference (ControlReferenceConstant in the script), I can't get control of the reference points to. I guess it's done with the property ' reference control bound to. " But I don't know how to convert the variant to the control. Conversion to the control class does not work. (See excerpt below). Conversion does not return an error, but the reference is not valid.

  

  A few details: the variant contains a reference to a control and has a name matching [2]. The type of reference data is just as well [3]. But the reference is 0, which is of course invalid digital show (seen in the probe and indicator).

  An entire book would be to iterate through all controls (indicators included as well as items in clusters and berries). The label could be the first check. But because they do not have to be unique is not enough. As a second step could be verified that the ReferenceConstant is listed by the property "nodes of control."(delede contrôle) reference ".

  [1] LV12 helps ControlReferenceConstant properties:

  http://zone.NI.com/reference/en-XX/help/371361J-01/lvscript/controlreferenceconstant_p/

  [2] get the variant name with:

  Select 'Type of Show' in the context menu of indicator varying or

  OpenG VI 'get name of data '.

  NIs in \Utility\VariantDataType\GetTypeInfo.vi VI

  [3] get the Refnum Type in the variant with

  NIs in \Utility\VariantDataType\GetRefnumInfo.vi VI

  If you look at using the property, you will see that it actually returns the data type of the node, not the actual control. That's way, you cannot use the reference in variant - it's not a real reference to a control.

  I think it's all just an oversight that no one added to the relevant property to the node, but there is a simpler solution for you that I think should work, that should come to him on the other side - for each control in the public Service, get the property [] of control reference nodes and it look for the reference of your node. If you found it, the node made reference to this control.

• The network connectivity status appears as only 'Local' error message ' there may be a problem with your domain name server (DNS) configuration "when trying to diagnose the problem.

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  of web_trans, web_info_trans, web_res_trans

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  Thus it seems still as a default since CF is essentially where, except for the return value play. Other query tools return results correctly so for me, it turns out be CF bug at a certain level.

  Actually I'm swinging to agree with you here, but not for the same reason.  CF actually * is * get all the columns back (as you say), it just doesn't expose a way to tell the difference between a column called 'x' and an another column called 'x', because the way to access the data in columns is simple queryname [columnName] [rowNumber] (or a Variant fo this, but all the amount of variations to that or abbrev. it).  This code shows how he has all four columns of the original two queries (being a stand-in for tables, in this case):

  
  Q1 = queryNew("");
  Q2 = queryNew("");
     
  queryAddColumn (q1, 'id', [1,2,3,4]);
  queryAddColumn (q1, "data", ["one", "two", "three", "four"]);
  queryAddColumn (q2, 'id', [1,2,3,4]);
  queryAddColumn (q2, "data", ["tahi", "rua", "toru", "wha"]); It's Maori, in case you are interested
  

  
  SELECT *.
  Q1, q2
  WHERE q1.id = q2.id
  
  

  So CF knows there are four columns (a call getMetadata (q3) get also demonstrates this), but it does not expose a way to approach the second (or even greater) column of the same name.  This is the bug/shortfall.

  However, relying on an underlying coldfusion.sql.QueryTable method, you can rename the columns, so:

  Then you're OK.

  I would be normally reluctant to recommend doing this, because these methods change from version to version of CF, but it's your call whether this approach will help you.

  To be honest, I'm with Owain who, even in SQL one generally doesn't work with columns with the same name, an alias them qualified with a table name/alias. As the table columns from of is not returned by SQL with the result set, it must be evidence against this by folding the columns in the first place.

  Also, I wonder at the bottom of the extraction of data, you don't really know the structure, that is to say, do SELECT *.  How can you know not even that is ours as the first column, second column, etc.?  I don't think that SQL applies in fact a contract that, t - it?  (I don't know).

  What are you actually do here?

  --

  Adam

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