Requirement of hierarchical query
Hi, I have two tables, emp_tab , that contains only information employee as below,emp_tab
-----------
EmpNo | empname | EmpType
-------------------------------------
10. SK | EMP
20. KS | MGR
30. NAR | ORG
and another table emp_tab_relation
emp_tab_relation
------------------------
relt_id | emp_id | prnt_relt_id
--------------------------------------
1. 20. null
2. 10. 1
3. 30. 1
That is to say, prnt emp_id is its relationship id
in this case 20 is the Manager and its relationship id is 1 and so that will be filled instead of prnt_relt_id.
now my requirement is I want a query to output as below,
EMPNAME | MGRNAME
-------------------------------
KS | NULL VALUE
SK | KS
NAR | KS
Thank you
with emp_tab as (
select 10 empno,'SK' empname,'EMP' emptype from dual union all
select 20,'KS','MGR' from dual union all
select 30,'NAR','ORG' from dual
),
emp_tab_relation as (
select 1 relt_id,20 emp_id,null prnt_relt_id from dual union all
select 2,10,1 from dual union all
select 3,30,1 from dual
)
--test data
SELECT empname,
prior empname
FROM emp_tab p
JOIN emp_tab_relation r
ON r.emp_id = p.empno
CONNECT BY prior relt_id = prnt_relt_id
START WITH prnt_relt_id IS NULL
Ravi Kumar
Tags: Database
Similar Questions
-
Query on hierarchical query in interactive report!
Hello
In Apex Oracle 5.1, I tried to use an interactive report to view details of employee based on a hierarchy. I used the query to display data below:
SELECT last_name, employe_id, manager_id, LEVEL
Employees
START WITH employee_id = 100
CONNECT BY PRIOR employee_id = manager_id
Brothers and SŒURS of ORDER BY last_name;
The output was as below:
LAST_NAME EMPLOYEE_ID MANAGER_ID LEVEL
------------------------- ----------- ---------- ----------
King 100 1
Cambrault 148 100 2
Bates 172 148 3
Bloom 169 148 3
Fox 170 148 3
Kumar 173 148 3
Ozer 168 148 3
Smith 171 148 3
De Haan 102 100 2
Hunold 103 102 3
Austin 105 103 4
Ernst 104 103 4
Lorentz 107 103 4
Pataballa 106 103 4
Errazuriz 147 100 2
Ande 166 147 3
Banda 167 147 3
...
Now, I would like to display data based on the connection of employees.
For example (based on above request): If an employee named - Cambrault is the login, only employees under him (Bates, Bloom, Fox, Kumar, Smith, Ozer) and its own contact information should appear in the report.
Please advise.
Kind regards
mebu
Mebu wrote:
I used a hierarchical query. But based on Login, I want to display only members under him.
For example: If Cambrault LOGIN, only employees under him (Bates, Bloom, Fox, Kumar, Smith, Ozer) and its own coordinates must display in Oracle Apex.
SELECT last_name, employe_id, manager_id, LEVEL
Employees
START WITH employee_id = 100
CONNECT BY PRIOR employee_id = manager_id
Brothers and SŒURS of ORDER BY last_name;
See what/when/where? How to get the answers from the forum
Describe the requirements clearly and completely, using the APEX, Oracle and terminology of web standard.
-
How to write a hierarchical query so that only the child nodes are displayed?
Hi all
I have a hierarchical query that I use in an area of tree demand APEX and there are nodes that have no children and I am trying to find a way to not display these nodes. Essentially if the user does not have to develop a lot of knots to know that nothing exists at the most detailed level.
The data are based on the Oracle Fusion FND tables but for example purposes here is enough data to illustrate my question:
create table APPL_TAXONOMY_HIERARCHY (SOURCE_MODULE_ID varchar2(30), TARGET_MODULE_ID varchar2(30)); create table APPL_TAXONOMY_TL (module_id varchar2(30), description varchar2(100), user_module_name varchar2(30), language varchar2(5)); create table APPL_TAXONOMY (MODULE_ID varchar2(30), MODULE_NAME varchar2(30), MODULE_TYPE varchar2(10), MODULE_KEY varchar2(30)); create table TABLES (table_name varchar2(30), module_key varchar2(30));
insert into APPL_TAXONOMY_TL values ('1', null, 'Oracle Fusion', 'US' ); insert into APPL_TAXONOMY_TL values ('2', null, 'Financials', 'US' ); insert into APPL_TAXONOMY_TL values ('3', null, 'Human Resources', 'US' ); insert into APPL_TAXONOMY_TL values ('20', null, 'Accounts Payable', 'US' ); insert into APPL_TAXONOMY_TL values ('10', null, 'General Ledger', 'US' ); insert into APPL_TAXONOMY_HIERARCHY values ('1', 'DDDDDDDD'); insert into APPL_TAXONOMY_HIERARCHY values ('2', '1'); insert into APPL_TAXONOMY_HIERARCHY values ('3', '1'); insert into APPL_TAXONOMY_HIERARCHY values ('4', '1'); insert into APPL_TAXONOMY_HIERARCHY values ('10', '2'); insert into APPL_TAXONOMY_HIERARCHY values ('20', '2'); insert into APPL_TAXONOMY values ('1', 'Fusion', 'PROD', 'Fusion'); insert into APPL_TAXONOMY values ('2', 'Financials', 'FAMILY', 'FIN'); insert into APPL_TAXONOMY values ('10', 'GL', 'APP', 'GL'); insert into APPL_TAXONOMY values ('3', 'Human Resources', 'FAMILY', 'HR'); insert into APPL_TAXONOMY values ('20', 'AP', 'APP', 'AP'); insert into tables values ('GL_JE_SOURCES_TL','GL'); insert into tables values ('GL_JE_CATEGORIES','GL');
My hierarchical query is as follows:
with MODULES as ( SELECT h.source_module_id, b.user_module_name, h.target_module_id FROM APPL_TAXONOMY_HIERARCHY H, APPL_TAXONOMY_TL B, APPL_TAXONOMY VL where H.source_module_id = b.module_id and b.module_id = vl.module_id and vl.module_type not in ('PAGE', 'LBA') UNION ALL select distinct table_name, table_name, regexp_substr(table_name,'[^_]+',1,1) from TABLES --needed as a link between TABLES and APPL_TAXONOMY union all select module_key as source_module_id, module_name as user_module_name, module_id as target_module_id from appl_taxonomy VL where VL.module_type = 'APP') SELECT case when connect_by_isleaf = 1 then 0 when level = 1 then 1 else -1 end as status, LEVEL, user_module_name as title, null as icon, ltrim(user_module_name, ' ') as value, null as tooltip, null as link FROM MODULES START WITH source_module_id = '1' CONNECT BY PRIOR source_module_id = target_module_id ORDER SIBLINGS BY user_module_name;
In Oracle APEX, this gives a tree with the appropriate data, you can see here:
https://Apex.Oracle.com/pls/Apex/f?p=32581:29 (username: guest, pw: app_1000);
The SQL of the query results are:
STATUS TITLE LEVEL VALUE ---------- ---------- ------------------------------ ------------------------------
1 1 oracle Fusion Oracle Fusion -1 2 financial tables Financials -1 3 accounts payable Accounts payable 0 4 AP AP -1 General Accounting 3 General Accounting -1 4 GL GL 0 5 GL_JE_CATEGORIES GL_JE_CATEGORIES 0 5 GL_JE_SOURCES_TL GL_JE_SOURCES_TL 0 2 human resources Human resources The lowest level is the name of the table to level 5. HR is not any level under level 2, in the same way, "AP" (level 4) has nothing below, i.e. no level 5 and that's why I don't want to show these nodes. Is this possible with the above query?
Thanks in advance for your suggestions!
John
Hello
The following query will include only the nodes of level = 5 and their ancestors (or descendants):
WITH modules LIKE
(
SELECT h.source_module_id
b.user_module_name AS the title
h.target_module_id
To appl_taxonomy_hierarchy:
appl_taxonomy_tl b
appl_taxonomy vl
WHERE h.source_module_id = b.module_id
AND b.module_id = vl.module_id
AND vl.module_type NOT IN ('PAGE', "LBA")
UNION ALL
SELECT DISTINCT
table-name
table_name
, REGEXP_SUBSTR (table_name, ' [^ _] +')
From the tables - required as a link between the TABLES and APPL_TAXONOMY
UNION ALL
SELECT module_key AS source_module_id
AS user_module_name module_name
module_id AS target_module_id
Of appl_taxonomy vl
WHERE vl.module_type = 'APP '.
)
connect_by_results AS
(
SELECT THE CHECK BOX
WHEN CONNECT_BY_ISLEAF = 1 THEN 0
WHEN LEVEL = 1 THEN 1
OF ANOTHER-1
The END as status
LEVEL AS lvl
title
-, NULL AS icon
, LTRIM (title, "") AS the value
-, NULL as ToolTip
-, Link AS NULL
source_module_id
SYS_CONNECT_BY_PATH (source_module_id - or something unique
, ' ~' - or anything else that may occur in the unique key
) || ' ~' AS the path
ROWNUM AS sort_key
Modules
START WITH source_module_id = '1'
CONNECT BY PRIOR Source_module_id = target_module_id
Brothers and SŒURS of ORDER BY title
)
SELECT the status, lvl, title, value
-, icon, tooltip, link
OF connect_by_results m
WHEN THERE IS)
SELECT 1
OF connect_by_results
WHERE the lvl = 5
AND the path AS ' % ~' | m.source_module_id
|| '~%'
)
ORDER BY sort_key
;
You may notice that subqueries modules and the connect_by_results are essentially what you've posted originally. What was the main request is now called connect_by_results, and it has a couple of additional columns that are necessary in the new main request or the EXISTS subquery.
However, I am suspicious of the 'magic number' 5. Could you have a situation where the sheets you are interested in can be a different levels (for example, some level = 5 and then some, into another branch of the tree, at the LEVEL = 6, or 7 or 4)? If so, post an example. You have need of a Query of Yo-Yo, where you do a bottom-up CONNECT BY query to get the universe of interest, and then make a descendant CONNECT BY query on this set of results.
-
hierarchical query of VO in the ofa page
Hello
I try to use the hierarchical query in VO for the display of all levels of supervisors for employee and want to display in populist:
This is the query
REPLACE SELECT distinct (mgx.full_name, "',' ') supervisor_full_name;
XPP. Employee_number
OF per_assignments_x pax,.
per_people_x ppx,
per_people_x mgx,
per_positions pp,
per_jobs pj,
per_position_definitions ppd
WHERE ppx.person_id = pax.person_id
AND ppx.current_employee_flag = 'Y '.
AND mgx.person_id = pax.supervisor_id
AND pp.position_id = pax.position_id
AND pj.job_id = pax.job_id
AND ppd.position_definition_id = pp.position_definition_id
START WITH ppx.employee_number =: 1
CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6
I'm trying to get this VO implemented PR when I run the page in jdeveloper with parameter binding, it's getting error.
oracle.apps.fnd.framework.OAException: oracle.jbo.SQLStmtException: 27122 Houston: SQL error in the preparation of the statement.
I would like to delete the parameter binding and executing CO VO past these two statements may be:
START WITH ppx.employee_number =: 1
CONNECT BY PRIOR MGX.employee_number = ppx.employee_number AND LEVEL < 6
How can I do?
Thank you
MK
has worked?
-
Version: Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit Production
Hello
I can't just writing this hierarchical query.
CREATE TABLE resources ( resource_name VARCHAR2( 20 ) ,resource_id NUMBER ,resource_mgr_id NUMBER ); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Phupinder',29269,29298); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Terry',29298,NULL); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Matt',4876,32942); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Bryan',29429,29269); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Cathy',32942,4922); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Scott',4257,29429); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Joe',44026,4876); INSERT INTO resources(resource_name,resource_id,resource_mgr_id) VALUES ('Greg',4922,4257);
-
I'm trying to parse each string inside of individual characters. For this, I used the link by the hierarchical query clause. I am not able to use connect by correctly. Here is my example.
with the CBC as)
Select 1: the nurse, 'abc' double union all Str
Select 2: the nurse, '123' Str of all union double
Select 3: the nurse, "pqr xyz" dual union all Str
Select option 4: the nurse, 'john doe' double Str
)
Select the level, homobasidiomycetes, substr(s.str,level,1) as chr
s of the CBC
connect nocycle level < = length (homobasidiomycetes)
/
The above query returns 3 028 lines when I want that 21. Adding a distinct to select, it's what I want.
with the CBC as)
Select 1: the nurse, 'abc' double union all Str
Select 2: the nurse, '123' Str of all union double
Select 3: the nurse, "pqr xyz" dual union all Str
Select option 4: the nurse, 'john doe' double Str
)
Select distinct level, homobasidiomycetes, substr(s.str,level,1) as chr
s of the CBC
connect nocycle level < = length (homobasidiomycetes)
order by str, level
/
For a large data set I could end up with several million rows before the separate would lead. So, how can I restrict the connection by clause to go within each line.
Assuming that the AI is the primary key, you could do this:
with src as ( select 1 as rn, 'abc' as str from dual union all select 2 as rn, '123' as str from dual union all select 3 as rn, 'pqr xyz' as str from dual union all select 4 as rn, 'john doe' as str from dual ) select level, s.str, substr(s.str,level,1) as chr from src s connect by level <= length(s.str) and prior rn = rn and prior dbms_random.value is not null;
See DBMS_RANDOM.value in a hierarchical solution for string to table? for an exchange of views around the case.
-
Dear all
I use Oracle Database 10g and I need a hierarchical query giving following release
KING
| __JONES
| | __SCOTT
| | __ADAMS
| | __FORD
| | __SMITH
| __BLAKE
| | __ALLEN
| | __WARD
| | __MARTIN
| | __TURNER
| | __JAMES
| __CLARK
| __MILLER
Best regards
Try this
SELECT CASE WHEN level > 1 THEN LPAD (': _ ', LEVEL,' |) ')
END | Ename AS ename_tree
WCP
START WITH mgr IS NULL
CONNECT BY PRIOR empno = mgr;
-
Support for hierarchical query
Hi all
I must be tired and can't think clearly, so I am a little confused the following query.
The environment is Oracle 9i:
Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
PL/SQL Release 9.2.0.8.0 - Production
CORE Production 9.2.0.8.0
AMT for HP - UX: 9.2.0.8.0 - Production Version
NLSRTL Version 9.2.0.8.0 - Production
Suppose I have the following data:
with mydata as
(
Select the code 1, code_high, null, 'John' cname 'Smith' csurname, 'X' union resp. double all the
Select 2 code, 1 code_high, cname 'Bill', 'White' csurname, RESP null in union double all the
Select 3 code, code_high 2, 'Fred' cname 'Reed' csurname, 'X' union resp. double all the
Select 4 code, code_high, null, 'Tim' cname 'Hackman' csurname, 'X' union resp. double all the
Select code 5, code_high 4, 'John', 'Reed' cname csurname resp null in union double all the
Select 6 code, code_high 5, cname 'Bill', 'Hakcman' csurname, 'X' union resp. double all the
Select the code 7, code_high 6, cname 'Fred' csurname 'White', null union resp. double all the
Select code 8, code_high 7, 'Bill' cname 'Smith' csurname, resp. union null double all the
Select 9 code, code_high 8, cname "Tom", "Reed" csurname, null double RESP
)
Select *.
of mydata;
CODE CODE_HIGH CNAME CSURNAME RESP
---------- ---------- ----- -------- ----
John Smith 1 X
2 1 bill White
3 2 Fred Reed X
4 Tim Hackman X
5 4 John Reed
6 5 bill Hakcman X
7 6 Fred white
8 7 bill Smith
9 8 Tom Reed
It is a hierarchical query where code_high represents the father.
I need to find in the hierarchy of higher level responsible for each code.
Suppose I want to find in the hierarchy, one with resp = 'X '.
Run the following query I find for the code = 9
Select phone, cname, csurname code
of mydata
When resp = 'X '.
and rownum = 1
Connect prior code_high = code
start with code = 9;
CODE CNAME CSURNAME
---------- ----- --------
Bill 6 Hakcman
Is there a way to get the full list with the loaded correspondents.
The expected results are:
CODE CODE_HIGH CNAME CSURNAME RESP. RESP_CODE RESP_NAME RESP_SURNAME
---------- ---------- ----- -------- ---- --------- --------- ------------
1 John Smith John Smith 1 X
2 1 bill White 1 John Smith
3 2 Fred Reed X 3 Fred Reed
Tim Hackman 4 X 4 Tim Hackman
5 4 John Smith 4 Tim Hackman
6 5 bill Hakcman Bill Hakcman 6 X
7 6 Fred White 6 Bill Hakcman
8 7 bill Smith 6 Bill Hakcman
9 8 Tom Reed 6 Bill Hakcman
Kind regards.
Alberto
Hi, Alberto.
I know that you are using Oracle 9; That's why I mentioned that you would have to use a substitute for CONNECT_BY_ROOT. Before I could show how, I saw the solution of the Padders, which is probably simpler and more efficient for this work. Padders used REGEXP_SUBSTR, which is not available in Oracle 9, but you can use SUBSTR and INSTR instead.
Here is the solution of the Padders for Orcle 9:
WITH got_resp_path AS
(
SELECT m.*
RTRIM (SYS_CONNECT_BY_PATH (CASE
WHEN resp = 'X '.
THEN the code
END
, ' '
)
) AS resp_path
OF mydata m
START WITH code_high IS NULL
CONNECT BY code_high = code PRIOR
)
C. SELECT
r.code AS resp_code
r.cname AS resp_name
r.csurname AS resp_surname
OF got_resp_path c
JOIN mydata r ON r.code = TO_NUMBER (SUBSTR (c.resp_path
INSTR (c.resp_path
, ' '
-1
)
)
)
ORDER BY c.code
;
I agree that what you posted in your last post is not very satisfactory. Rather than make a CONNECT a separate query for each column of resp_ you want to view, you can modify it to get only the unique code and then use it in a join, as Padders, to get all the other columns you need.
-
Hello
Question:
In a hierarchical query, is it possible for a line having more than one immediate ancestor?Answer:
Isn't it? Surely this is Yes?
Thank you
Jason
Line may have ancestors as much as you want. It goes the same for successors.
SY.
-
Hierarchical data, how to aggregate over levels in hierarchical query?
Hello
I hope someone can help me.
I held in a data table ("" what part was built in what other part of when when? "')
ID parent_id build_in build_out
1 NULL NULL NULL
2/1 2010 2012
3 2 2011 2013
4 2 2013 NULL
What are the parts is stored in a separate table.
Now I want to know when when which part was built in the first level, in the example, I want to know that
1 was simply a part of 1
2 was part of 1 between 2010 and 2012
3 was part of 1 between 2011 and 2012
4 has never been a part of 1
I tried several approaches - if there is a fixed number of levels between the types, I am interested I can do using joins and more/less (similarly as some nvl). Unfortunately this is not always the case (some parts appear on several levels).
If I'm only interested in the parts that are never deleted, I can get by using a style of connect request and get the current configuration. But I can't seem to understand the time connecting part to the high level in such a query, or even filtering absurd combinations (like "4 in 1" in the example above). I could deal with the data recovered outside the database, but I prefer not.
Is there a way to obtain the hierarchical data with an aggregate (min, max) for all levels?What version of Oracle you are on?
In 11.2.x, you can use the recursive subquery factoring. Something like
with t (id, parent_id, build_in, build_out) as ( select 1, null, null, null from dual union all select 2, 1, 2010, 2012 from dual union all select 3, 2, 2011, 2013 from dual union all select 4, 2, 2013, null from dual ) , c1 (root_id, id, parent_id, build_in, build_out) as ( select id, id, parent_id, 0, 9999 from t where parent_id is null union all select root_id, t.id, t.parent_id , greatest(nvl(t.build_in,0), nvl(b.build_in,0)) , least(nvl(t.build_out,9999), nvl(b.build_out,9999)) from c1 b, t where b.id = t.parent_id ) select * from c1 where build_in < build_out ; ROOT_ID ID PARENT_ID BUILD_IN BUILD_OUT ------- ----- ---------- --------- ---------- 1 1 0 9999 1 2 1 2010 2012 1 3 2 2011 2012
With a hierarchical query by using the syntax connection, you could do something like
select * from ( select connect_by_root id as root, id , greatest(nvl(build_in,0), nvl(prior build_in,0)) as max_in, least(nvl(build_out,9999), nvl(prior build_out,9999)) as min_out from t start with parent_id is null connect by parent_id = prior id ) where max_in < min_out ;
but it is not powerful enough. This version compares the dates between a current and previous levels, but the recursive subquery is to compare the dates in the current level for the winners of the comparisons to the previous level. Not sure if it's an important distinction for your needs, however.
If you are on 11.2 I advise to use the recursive subquery factoring. If this isn't the case, you can try the link by version.
Kind regards
Bob -
Getting the line without the use of hierarchical query values
Hi all
I want to know the hierarchical values without using a hierarchical query. I have two tables EMP, DEPT
EMP table is to have two columns (empid, mgrid)
DEPT table is to have two columns (deptid, empid)
Data of the EMP
1,
2, 1
3, 2
4, 3
Data DEPT
10, 1
Each time, I gave deptid = 10, I need to know the this deptid empid then who is this empid (child levels as well). In this case, the output should be
1
2
3
4
I don't want to use hierarchical query.
Thanks in advance.
Thank you
PALYou can use the RECURSIVE subquery, if you are 11 GR 2, like this
SQL> with EMP (empid,mgrid) as 2 ( 3 select 1,null from dual union all 4 select 2, 1 from dual union all 5 select 3, 2 from dual union all 6 select 4, 3 from dual 7 ), 8 dept(deptid,empid) as 9 ( 10 select 10, 1 from dual 11 ), 12 t(empid,mgrid) as 13 ( 14 select empid,mgrid 15 from emp e 16 where empid in ( 17 select d.empid 18 from dept d 19 where deptid = 10 20 ) 21 union all 22 select e.empid,e.mgrid 23 from emp e, t 24 where e.mgrid = t.empid 25 ) 26 select * 27 from t; EMPID MGRID ---------- ---------- 1 2 1 3 2 4 3
Yet, the question is valid - why can't use you a hierarchical query?
Published by: JAC on May 29, 2013 12:37
-
Problems with views based on a hierarchical query
Datamodeler 3.1.3.706 (SQL Dev 3.2.10.09):
When you create a view that uses a hierarchical query, the query designer encounter various difficulties:
When pasting in the SQL code, if the notice is registered without first clicking the schema update button, the object in the entity-relationship diagram view provides a faithful representation of the view without errors, but when the reopening of the view, the code is missing.
Simple example with the classic emp table:
If you press the schema update button to refresh the display. He mangles connect it by the clause and the view gets marked with a warning/error icon in the diagram of the relationships, but the now decomposed code remains available on reopening of the query designer.SELECT level lev , emp.* FROM emp CONNECT BY prior empno = mgr START WITH mgr IS NULL
Same code as above after having clicked on the button of update of schema:
Other issues are met if the query contains a column CONNECT_BY_ % nickname hierarchical:SELECT Level lev , emp.* FROM emp CONNECT BY
In this case, paste in the code and clicking Update schema button or the OK button translates into a "unexpected Token' error analysis.SELECT level , emp.* , connect_by_root emp.ename root_ename FROM emp CONNECT BY prior empno = mgr START WITH mgr IS NULL;
These problems are encountered with the logic model and the relational.
Is this a known issue? I searched this forum but have not found any references to this.
Thank you
SentinelHi, Sentinel,
I logged a bug for this.
You can try 3.3 DM treat it better first problem, analysis of connect_by_root operator will pass if you do not alias.Philippe
-
Hierarchical query help need to Oracle
Hello
I'm in a deep trouble.
I want to do a hierarchical query in my TreeView table in oracle. But I want that the query retrieves information path between two nodes.
Review the table below.
------------------------------------------------------
Node ID | Name of the node. ID of the parent
-----------------------------------------------------
1A 0
2 1
3C0
4 2
-----------------------------------------------------
What I want is that I'll give you 2 node id in the request. One is the source node and the other is the destination node.
so if I put 1 node and node 4, I want to be the output
1-> 2-> 4
I want just a return line. Or there may be several rows but stands only the node of this path.
1
2
4
----
This means that I don't want to node 3 in the search result.
More if I have the source as 4 node and the node of destination as 1 then I will also get an output of the query as below-
4-> 2-> 1
This means that the search for the query for the result in a way directional bi.
If anyone can give me some information about who it's going to be great for me.
Published by: user13276471 on December 31, 2012 03:21Hello
Welcome to the forum!
Assuming you have 2 separate nodes: Node_A and: node_b, you can find the hierarchy from one to the other like this:
SELECT SYS_CONNECT_BY_PATH (node_id, ',') AS lineage FROM table_x WHERE node_id IN (:node_a, :node_b) AND LEVEL > 1 START WITH node_id IN (:node_a, :node_b) CONNECT BY parent_id = PRIOR node_id ;
It will work if: the Node_A is an ancestor of the: node_b, or if: node_b is an ancestor of the: Node_A.
If is the ancestor of the other, then it will produce 0 rows. -
Hello
I have data like this.
EMPID ENAME MANAGERID
1A
2 1
1 OF 3
4 2
5 2
6 3
4 OF 7
And I want to show the data in this way. SUPERMNAGERID is always 1, regardless of the fact that that which is his immediate superior.
EMPID ENAME MANAGERID SUPERMNAGERID
1A
2-1-1
3-1-1
4-2-1
5-2-1
6-3-1
7-4-1
Your help on this would be really useful.
Edited by: user10827825 may 6, 2012 12:36Most inefficient way. If you want to use a hierarchical query, use START WITH and to get the "supermanager" use CONNECT_BY_ROOT:
WITH t AS (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID FROM DUAL UNION ALL SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID FROM DUAL UNION ALL SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID FROM DUAL UNION ALL SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID FROM DUAL UNION ALL SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID FROM DUAL UNION ALL SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID FROM DUAL UNION ALL SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID FROM DUAL ) SELECT EMPID, ENAME, MANAGER_ID, CONNECT_BY_ROOT EMPID FROM t START WITH MANAGER_ID IS NULL CONNECT BY MANAGER_ID = PRIOR EMPID ORDER BY EMPID;
Compare the number of lines hierarchy is generated by bot queries:
SQL> WITH t AS 2 (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID 3 FROM DUAL 4 UNION ALL 5 SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID 6 FROM DUAL 7 UNION ALL 8 SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID 9 FROM DUAL 10 UNION ALL 11 SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID 12 FROM DUAL 13 UNION ALL 14 SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID 15 FROM DUAL 16 UNION ALL 17 SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID 18 FROM DUAL 19 UNION ALL 20 SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID 21 FROM DUAL 22 ) 23 SELECT count(*) 24 FROM t 25 CONNECT BY PRIOR MANAGER_ID = EMPID 26 ORDER BY EMPID; COUNT(*) ---------- 18 SQL> WITH t AS 2 (SELECT 1 EMPID, 'A' ENAME, NULL MANAGER_ID 3 FROM DUAL 4 UNION ALL 5 SELECT 2 EMPID, 'B' ENAME, 1 MANAGER_ID 6 FROM DUAL 7 UNION ALL 8 SELECT 3 EMPID, 'C' ENAME, 1 MANAGER_ID 9 FROM DUAL 10 UNION ALL 11 SELECT 4 EMPID, 'D' ENAME, 2 MANAGER_ID 12 FROM DUAL 13 UNION ALL 14 SELECT 5 EMPID, 'E' ENAME, 2 MANAGER_ID 15 FROM DUAL 16 UNION ALL 17 SELECT 6 EMPID, 'F' ENAME, 3 MANAGER_ID 18 FROM DUAL 19 UNION ALL 20 SELECT 7 EMPID, 'G' ENAME, 4 MANAGER_ID 21 FROM DUAL 22 ) 23 SELECT count(*) 24 FROM t 25 START WITH MANAGER_ID IS NULL 26 CONNECT BY MANAGER_ID = PRIOR EMPID 27 ORDER BY EMPID; COUNT(*) ---------- 7 SQL>
Now imagine the table real a couple thousand lines.
SY.
-
Get the value of the root of a hierarchical query
I'm writing a hierarchical query for one of my paintings.
I need to know the value of the root by entering a value of sheet of any level.
for example: I enter a value which is at level 4. I need to find the value of the root without displaying the other levels.
Help, please.
Thank you.TRY THIS,
SELECT ename, PRIOR ename MGRNAME FROM emp WHERE ename = START WITH mgr IS NULL CONNECT BY PRIOR empno = mgr
Published by: NSK2KSN on August 9, 2010 18:10
Maybe you are looking for
-
Hi all, I sold my Macbook Pro and I forgot to logout iCloud, App Store, iMessage and FaceTime before I erase all the drives. Because I was able to locate the Macbook Pro I ask the person I sold it and I erase "find my iPhone". After that, I'm not abl
-
I need iCloud id * *.com
-
every time when I want to update my ios software .it shows the message "unable to check the updates.
-
I have divided my application in three applications. (1) USER INTERFACE (2) background (3) Library(contains Common code between UI and Background) UI and background are made but have no idea of the library. Rough idea, is that it contains the class t
-
How to put text on the image of blackberry?
I'm a Blackberry app. In my application I need to show show text in an image. So I used this code. tab1 = new LabelField ("Page 1", LabelField.FOCUSABLE |) LabelField.HIGHLIGHT_SELECT) {} protected void paintBackground (Graphics g) {}TODO self-genera